Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
hypotenuseof righttriangle with legs2 and22= 22.09
| 22.09 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(2² + 22²) = sqrt(4 + 484) = sqrt(488) = 22.09
|
areaofrectangle with width48 and height5 = 240
| 240 |
Step 1: Area formula is width × height.
Step 2: 48 × 5 = 240
|
area of triangle withbase27 and height 14=189.00
| 189 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 27 × 14 = 189.00
|
64 %14 =8
| 8 |
Step 1: Compute 64 % 14.
Step 2: The result is 8.
|
perimeter ofrectanglewith width16 and height4 =40
| 40 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (16 + 4) = 2 × 20 = 40
|
perimeter of rectangle withwidth 49andheight 21= 140
| 140 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (49 + 21) = 2 × 70 = 140
|
(88)/ 11 = 8
| 8 |
Step 1: Compute 88 / 11.
Step 2: The result is 8.
|
18+ 55 =73
| 73 |
Step 1: Compute 18 + 55.
Step 2: The result is 73.
|
perimeter of circle with radius5 =31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
82 * 97= 7954
| 7,954 |
Step 1: Compute 82 * 97.
Step 2: The result is 7954.
|
perimeterof triangle with sides 19,19,46= 84
| 84 |
Step 1: Perimeter formula is a + b + c.
Step 2: 19 + 19 + 46 = 84
|
perimeter of circle with radius 14= 87.96
| 87.96 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 14 = 87.96
|
2** (3)= 8
| 8 |
Step 1: Compute 2 ** 3.
Step 2: The result is 8.
|
86 +36 = 122
| 122 |
Step 1: Compute 86 + 36.
Step 2: The result is 122.
|
perimeter ofrectangle with width37 and height 2= 78
| 78 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (37 + 2) = 2 × 39 = 78
|
45 * 52= 2340
| 2,340 |
Step 1: Compute 45 * 52.
Step 2: The result is 2340.
|
area of rectangle with width 31 and height 15 =465
| 465 |
Step 1: Area formula is width × height.
Step 2: 31 × 15 = 465
|
perimeter of trianglewith sides 49, 17, 45 = 111
| 111 |
Step 1: Perimeter formula is a + b + c.
Step 2: 49 + 17 + 45 = 111
|
area of trianglewithbase 35 and height29= 507.50
| 507.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 35 × 29 = 507.50
|
(28) +26 = 54
| 54 |
Step 1: Compute 28 + 26.
Step 2: The result is 54.
|
area of circle with radius2 =12.57
| 12.57 |
Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57
|
area of rectanglewith width16 and height14 = 224
| 224 |
Step 1: Area formula is width × height.
Step 2: 16 × 14 = 224
|
80 / (10)= 8
| 8 |
Step 1: Compute 80 / 10.
Step 2: The result is 8.
|
hypotenuse of righttrianglewith legs5 and22 = 22.56
| 22.56 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(5² + 22²) = sqrt(25 + 484) = sqrt(509) = 22.56
|
area of circle with radius 7= 153.94
| 153.94 |
Step 1: Area formula is π × r².
Step 2: π × 7² = 3.14 × 49 = 153.94
|
3** 3= 27
| 27 |
Step 1: Compute 3 ** 3.
Step 2: The result is 27.
|
3 * (15) = 45
| 45 |
Step 1: Compute 3 * 15.
Step 2: The result is 45.
|
92 % 1 = 0
| 0 |
Step 1: Compute 92 % 1.
Step 2: The result is 0.
|
97 %20 = 17
| 17 |
Step 1: Compute 97 % 20.
Step 2: The result is 17.
|
area of circle with radius20 = 1256.64
| 1,256.64 |
Step 1: Area formula is π × r².
Step 2: π × 20² = 3.14 × 400 = 1256.64
|
(52) % 10= 2
| 2 |
Step 1: Compute 52 % 10.
Step 2: The result is 2.
|
perimeter of triangle withsides 3, 41,41 = 85
| 85 |
Step 1: Perimeter formula is a + b + c.
Step 2: 3 + 41 + 41 = 85
|
hypotenuseofrighttriangle with legs 22 and 18= 28.43
| 28.43 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(22² + 18²) = sqrt(484 + 324) = sqrt(808) = 28.43
|
(21) / 3 = 7
| 7 |
Step 1: Compute 21 / 3.
Step 2: The result is 7.
|
hypotenuseof right triangle withlegs 4and24 =24.33
| 24.33 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(4² + 24²) = sqrt(16 + 576) = sqrt(592) = 24.33
|
perimeter ofrectangle with width 13 and height9=44
| 44 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (13 + 9) = 2 × 22 = 44
|
areaofcircle withradius18 =1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
94+ 25 = 119
| 119 |
Step 1: Compute 94 + 25.
Step 2: The result is 119.
|
(6) /1 =6
| 6 |
Step 1: Compute 6 / 1.
Step 2: The result is 6.
|
hypotenuseof right triangle with legs 7 and6= 9.22
| 9.22 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(7² + 6²) = sqrt(49 + 36) = sqrt(85) = 9.22
|
area of rectangle withwidth20andheight40=800
| 800 |
Step 1: Area formula is width × height.
Step 2: 20 × 40 = 800
|
area of triangle with base 39and height 20 =390.00
| 390 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 39 × 20 = 390.00
|
perimeter oftriangle with sides 3, 20, 13 =36
| 36 |
Step 1: Perimeter formula is a + b + c.
Step 2: 3 + 20 + 13 = 36
|
areaofrectangle with width16 andheight39 =624
| 624 |
Step 1: Area formula is width × height.
Step 2: 16 × 39 = 624
|
area of rectanglewithwidth20andheight25= 500
| 500 |
Step 1: Area formula is width × height.
Step 2: 20 × 25 = 500
|
area of trianglewith base 2 and height 6= 6.00
| 6 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 2 × 6 = 6.00
|
34-(83) = -49
| -49 |
Step 1: Compute 34 - 83.
Step 2: The result is -49.
|
area of rectangle withwidth4 andheight 3 = 12
| 12 |
Step 1: Area formula is width × height.
Step 2: 4 × 3 = 12
|
area oftriangle withbase27and height4= 54.00
| 54 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 27 × 4 = 54.00
|
(69)* (54)= 3726
| 3,726 |
Step 1: Compute 69 * 54.
Step 2: The result is 3726.
|
areaof circlewithradius13 = 530.93
| 530.93 |
Step 1: Area formula is π × r².
Step 2: π × 13² = 3.14 × 169 = 530.93
|
perimeter ofcircle withradius2= 12.57
| 12.57 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 2 = 12.57
|
areaofcircle withradius10=314.16
| 314.16 |
Step 1: Area formula is π × r².
Step 2: π × 10² = 3.14 × 100 = 314.16
|
75 / 15 =5
| 5 |
Step 1: Compute 75 / 15.
Step 2: The result is 5.
|
6 % 1= 0
| 0 |
Step 1: Compute 6 % 1.
Step 2: The result is 0.
|
2 ** 4= 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
96* 72 = 6912
| 6,912 |
Step 1: Compute 96 * 72.
Step 2: The result is 6912.
|
16 % 11=5
| 5 |
Step 1: Compute 16 % 11.
Step 2: The result is 5.
|
7** 4 = 2401
| 2,401 |
Step 1: Compute 7 ** 4.
Step 2: The result is 2401.
|
25 % 2= 1
| 1 |
Step 1: Compute 25 % 2.
Step 2: The result is 1.
|
perimeter of triangle with sides3, 29,46=78
| 78 |
Step 1: Perimeter formula is a + b + c.
Step 2: 3 + 29 + 46 = 78
|
area ofrectanglewith width5 and height 31 = 155
| 155 |
Step 1: Area formula is width × height.
Step 2: 5 × 31 = 155
|
hypotenuse ofright trianglewith legs 3 and 14= 14.32
| 14.32 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(3² + 14²) = sqrt(9 + 196) = sqrt(205) = 14.32
|
(97) % 7 = 6
| 6 |
Step 1: Compute 97 % 7.
Step 2: The result is 6.
|
hypotenuse of right triangle withlegs 29and19=34.67
| 34.67 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(29² + 19²) = sqrt(841 + 361) = sqrt(1202) = 34.67
|
16 * (38) = 608
| 608 |
Step 1: Compute 16 * 38.
Step 2: The result is 608.
|
(50)- (100) = -50
| -50 |
Step 1: Compute 50 - 100.
Step 2: The result is -50.
|
10 ** 4 = 10000
| 10,000 |
Step 1: Compute 10 ** 4.
Step 2: The result is 10000.
|
area of circlewith radius3 =28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
(56)/ 7 = 8
| 8 |
Step 1: Compute 56 / 7.
Step 2: The result is 8.
|
36% 16 = 4
| 4 |
Step 1: Compute 36 % 16.
Step 2: The result is 4.
|
24*(92) = 2208
| 2,208 |
Step 1: Compute 24 * 92.
Step 2: The result is 2208.
|
hypotenuseofright trianglewith legs 9 and16 =18.36
| 18.36 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(9² + 16²) = sqrt(81 + 256) = sqrt(337) = 18.36
|
perimeter of circle with radius 9 = 56.55
| 56.55 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 9 = 56.55
|
81 * (66) =5346
| 5,346 |
Step 1: Compute 81 * 66.
Step 2: The result is 5346.
|
(15) /15 = 1
| 1 |
Step 1: Compute 15 / 15.
Step 2: The result is 1.
|
area of triangle with base24and height6=72.00
| 72 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 24 × 6 = 72.00
|
16 % 5=1
| 1 |
Step 1: Compute 16 % 5.
Step 2: The result is 1.
|
area oftrianglewith base 11 andheight 32=176.00
| 176 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 11 × 32 = 176.00
|
hypotenuseof right triangle with legs 16and 19 = 24.84
| 24.84 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(16² + 19²) = sqrt(256 + 361) = sqrt(617) = 24.84
|
perimeter of circlewithradius 17 = 106.81
| 106.81 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 17 = 106.81
|
perimeteroftrianglewith sides 39, 44, 21 = 104
| 104 |
Step 1: Perimeter formula is a + b + c.
Step 2: 39 + 44 + 21 = 104
|
areaofcircle with radius 1= 3.14
| 3.14 |
Step 1: Area formula is π × r².
Step 2: π × 1² = 3.14 × 1 = 3.14
|
78 * 73 =5694
| 5,694 |
Step 1: Compute 78 * 73.
Step 2: The result is 5694.
|
4 - 76 = -72
| -72 |
Step 1: Compute 4 - 76.
Step 2: The result is -72.
|
55/11= 5
| 5 |
Step 1: Compute 55 / 11.
Step 2: The result is 5.
|
80/(20) =4
| 4 |
Step 1: Compute 80 / 20.
Step 2: The result is 4.
|
(47)% (18)= 11
| 11 |
Step 1: Compute 47 % 18.
Step 2: The result is 11.
|
(62) + 7 = 69
| 69 |
Step 1: Compute 62 + 7.
Step 2: The result is 69.
|
area of triangle with base 22and height28 = 308.00
| 308 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 22 × 28 = 308.00
|
perimeter of triangle with sides 28, 10, 47 =85
| 85 |
Step 1: Perimeter formula is a + b + c.
Step 2: 28 + 10 + 47 = 85
|
(3) ** 2 = 9
| 9 |
Step 1: Compute 3 ** 2.
Step 2: The result is 9.
|
(26) * 64=1664
| 1,664 |
Step 1: Compute 26 * 64.
Step 2: The result is 1664.
|
areaof trianglewith base49 and height15 =367.50
| 367.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 49 × 15 = 367.50
|
33*39 = 1287
| 1,287 |
Step 1: Compute 33 * 39.
Step 2: The result is 1287.
|
80%14 =10
| 10 |
Step 1: Compute 80 % 14.
Step 2: The result is 10.
|
area of circle with radius 2 = 12.57
| 12.57 |
Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57
|
(14) +69 = 83
| 83 |
Step 1: Compute 14 + 69.
Step 2: The result is 83.
|
areaoftriangle withbase 48 andheight 8 = 192.00
| 192 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 48 × 8 = 192.00
|
area ofcirclewithradius2 = 12.57
| 12.57 |
Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57
|
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