Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
area ofcircle with radius4 =50.27
| 50.27 |
Step 1: Area formula is π × r².
Step 2: π × 4² = 3.14 × 16 = 50.27
|
perimeter of circle withradius 15 = 94.25
| 94.25 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 15 = 94.25
|
45+ (70) = 115
| 115 |
Step 1: Compute 45 + 70.
Step 2: The result is 115.
|
area of triangle with base 10 and height22 = 110.00
| 110 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 10 × 22 = 110.00
|
(42) / 14 = 3
| 3 |
Step 1: Compute 42 / 14.
Step 2: The result is 3.
|
area of circle with radius18= 1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
hypotenuse of right triangle with legs 15 and2 = 15.13
| 15.13 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(15² + 2²) = sqrt(225 + 4) = sqrt(229) = 15.13
|
area of trianglewithbase 25and height22= 275.00
| 275 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 25 × 22 = 275.00
|
70 + (31)= 101
| 101 |
Step 1: Compute 70 + 31.
Step 2: The result is 101.
|
perimeter of circlewith radius 16 = 100.53
| 100.53 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 16 = 100.53
|
83% 3 = 2
| 2 |
Step 1: Compute 83 % 3.
Step 2: The result is 2.
|
32 -(4)=28
| 28 |
Step 1: Compute 32 - 4.
Step 2: The result is 28.
|
perimeter of circlewith radius3 = 18.85
| 18.85 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85
|
(28) - 77 = -49
| -49 |
Step 1: Compute 28 - 77.
Step 2: The result is -49.
|
87 -32= 55
| 55 |
Step 1: Compute 87 - 32.
Step 2: The result is 55.
|
6** (2)=36
| 36 |
Step 1: Compute 6 ** 2.
Step 2: The result is 36.
|
perimeter of triangle with sides 26, 42,43= 111
| 111 |
Step 1: Perimeter formula is a + b + c.
Step 2: 26 + 42 + 43 = 111
|
area of triangle with base 43 and height27= 580.50
| 580.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 43 × 27 = 580.50
|
area ofcircle with radius 5 = 78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
perimeter oftrianglewith sides43, 1,4 = 48
| 48 |
Step 1: Perimeter formula is a + b + c.
Step 2: 43 + 1 + 4 = 48
|
100 % (7) = 2
| 2 |
Step 1: Compute 100 % 7.
Step 2: The result is 2.
|
(3)** 2=9
| 9 |
Step 1: Compute 3 ** 2.
Step 2: The result is 9.
|
8/ (2) =4
| 4 |
Step 1: Compute 8 / 2.
Step 2: The result is 4.
|
area ofcirclewithradius17 = 907.92
| 907.92 |
Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92
|
84 %5= 4
| 4 |
Step 1: Compute 84 % 5.
Step 2: The result is 4.
|
(88) %(20) =8
| 8 |
Step 1: Compute 88 % 20.
Step 2: The result is 8.
|
area of trianglewithbase 50 and height 36 = 900.00
| 900 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 50 × 36 = 900.00
|
(58) * 60= 3480
| 3,480 |
Step 1: Compute 58 * 60.
Step 2: The result is 3480.
|
area ofcircle with radius 8 = 201.06
| 201.06 |
Step 1: Area formula is π × r².
Step 2: π × 8² = 3.14 × 64 = 201.06
|
(97) % 13 = 6
| 6 |
Step 1: Compute 97 % 13.
Step 2: The result is 6.
|
21 / 7= 3
| 3 |
Step 1: Compute 21 / 7.
Step 2: The result is 3.
|
areaoftriangle with base 9andheight13 =58.50
| 58.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 9 × 13 = 58.50
|
area of rectangle with width 41 and height49=2009
| 2,009 |
Step 1: Area formula is width × height.
Step 2: 41 × 49 = 2009
|
areaoftriangle withbase 34 and height 39 = 663.00
| 663 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 34 × 39 = 663.00
|
perimeter of circle with radius 19 =119.38
| 119.38 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 19 = 119.38
|
37+ 50= 87
| 87 |
Step 1: Compute 37 + 50.
Step 2: The result is 87.
|
hypotenuseofrighttrianglewith legs 13 and 15 = 19.85
| 19.85 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(13² + 15²) = sqrt(169 + 225) = sqrt(394) = 19.85
|
(7)* 62= 434
| 434 |
Step 1: Compute 7 * 62.
Step 2: The result is 434.
|
perimeter oftriangle withsides16, 29,28= 73
| 73 |
Step 1: Perimeter formula is a + b + c.
Step 2: 16 + 29 + 28 = 73
|
perimeter of circle withradius11 =69.12
| 69.12 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 11 = 69.12
|
(8)/ (8) =1
| 1 |
Step 1: Compute 8 / 8.
Step 2: The result is 1.
|
2 **3= 8
| 8 |
Step 1: Compute 2 ** 3.
Step 2: The result is 8.
|
6%(2) = 0
| 0 |
Step 1: Compute 6 % 2.
Step 2: The result is 0.
|
(89) %16 =9
| 9 |
Step 1: Compute 89 % 16.
Step 2: The result is 9.
|
areaofrectangle withwidth 34 and height16 = 544
| 544 |
Step 1: Area formula is width × height.
Step 2: 34 × 16 = 544
|
areaof trianglewith base 37 andheight46= 851.00
| 851 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 37 × 46 = 851.00
|
136 /17= 8
| 8 |
Step 1: Compute 136 / 17.
Step 2: The result is 8.
|
hypotenuse of righttriangle with legs 1 and28 = 28.02
| 28.02 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(1² + 28²) = sqrt(1 + 784) = sqrt(785) = 28.02
|
(83) + 72 = 155
| 155 |
Step 1: Compute 83 + 72.
Step 2: The result is 155.
|
45* 33 = 1485
| 1,485 |
Step 1: Compute 45 * 33.
Step 2: The result is 1485.
|
(30) + (27) = 57
| 57 |
Step 1: Compute 30 + 27.
Step 2: The result is 57.
|
perimeter oftriangle with sides 36, 5, 43 = 84
| 84 |
Step 1: Perimeter formula is a + b + c.
Step 2: 36 + 5 + 43 = 84
|
7 ** (3) = 343
| 343 |
Step 1: Compute 7 ** 3.
Step 2: The result is 343.
|
hypotenuse of right trianglewith legs 12and 4 = 12.65
| 12.65 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(12² + 4²) = sqrt(144 + 16) = sqrt(160) = 12.65
|
perimeter ofcircle with radius 15 =94.25
| 94.25 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 15 = 94.25
|
perimeterof circle withradius 13 =81.68
| 81.68 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 13 = 81.68
|
99 * 98= 9702
| 9,702 |
Step 1: Compute 99 * 98.
Step 2: The result is 9702.
|
perimeterof circle with radius17 = 106.81
| 106.81 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 17 = 106.81
|
hypotenuseofright triangle withlegs17and 22 = 27.80
| 27.8 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(17² + 22²) = sqrt(289 + 484) = sqrt(773) = 27.80
|
perimeter of circlewith radius 10 = 62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
perimeter of trianglewith sides 4,34,20 = 58
| 58 |
Step 1: Perimeter formula is a + b + c.
Step 2: 4 + 34 + 20 = 58
|
perimeter of triangle withsides 6,39,42 = 87
| 87 |
Step 1: Perimeter formula is a + b + c.
Step 2: 6 + 39 + 42 = 87
|
(2)** 4 = 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
(60) * 26=1560
| 1,560 |
Step 1: Compute 60 * 26.
Step 2: The result is 1560.
|
25 %15= 10
| 10 |
Step 1: Compute 25 % 15.
Step 2: The result is 10.
|
(9) ** 2= 81
| 81 |
Step 1: Compute 9 ** 2.
Step 2: The result is 81.
|
area ofrectangle with width 21 and height 41 =861
| 861 |
Step 1: Area formula is width × height.
Step 2: 21 × 41 = 861
|
perimeter of circlewithradius 13 = 81.68
| 81.68 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 13 = 81.68
|
areaoftrianglewith base 15 andheight 28 = 210.00
| 210 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 15 × 28 = 210.00
|
3/ (1) = 3
| 3 |
Step 1: Compute 3 / 1.
Step 2: The result is 3.
|
40/ 4 = 10
| 10 |
Step 1: Compute 40 / 4.
Step 2: The result is 10.
|
hypotenuse of right triangle with legs 29 and 3= 29.15
| 29.15 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(29² + 3²) = sqrt(841 + 9) = sqrt(850) = 29.15
|
area ofrectangle with width38and height 2=76
| 76 |
Step 1: Area formula is width × height.
Step 2: 38 × 2 = 76
|
area of triangle with base 25 and height47 = 587.50
| 587.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 25 × 47 = 587.50
|
perimeter of rectangle withwidth 20 and height 16 = 72
| 72 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (20 + 16) = 2 × 36 = 72
|
20 -85 = -65
| -65 |
Step 1: Compute 20 - 85.
Step 2: The result is -65.
|
(50) % 9 = 5
| 5 |
Step 1: Compute 50 % 9.
Step 2: The result is 5.
|
perimeterof rectangle with width20 andheight 7 = 54
| 54 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (20 + 7) = 2 × 27 = 54
|
area oftriangle with base47and height 40= 940.00
| 940 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 47 × 40 = 940.00
|
perimeter of rectangle withwidth40and height 25 = 130
| 130 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (40 + 25) = 2 × 65 = 130
|
24 %13 =11
| 11 |
Step 1: Compute 24 % 13.
Step 2: The result is 11.
|
area of triangle with base 15 and height 13 = 97.50
| 97.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 15 × 13 = 97.50
|
68 - 50= 18
| 18 |
Step 1: Compute 68 - 50.
Step 2: The result is 18.
|
7 ** (4)=2401
| 2,401 |
Step 1: Compute 7 ** 4.
Step 2: The result is 2401.
|
(28) /7 = 4
| 4 |
Step 1: Compute 28 / 7.
Step 2: The result is 4.
|
(2) ** 3= 8
| 8 |
Step 1: Compute 2 ** 3.
Step 2: The result is 8.
|
area oftriangle with base20 and height 34 = 340.00
| 340 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 20 × 34 = 340.00
|
perimeter of rectangle with width 46 and height 38 =168
| 168 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (46 + 38) = 2 × 84 = 168
|
perimeter ofrectangle withwidth 50 and height14=128
| 128 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (50 + 14) = 2 × 64 = 128
|
perimeterof circle with radius3=18.85
| 18.85 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85
|
(12) * (90)=1080
| 1,080 |
Step 1: Compute 12 * 90.
Step 2: The result is 1080.
|
perimeter of trianglewithsides 47,35, 4 = 86
| 86 |
Step 1: Perimeter formula is a + b + c.
Step 2: 47 + 35 + 4 = 86
|
92 * 93 = 8556
| 8,556 |
Step 1: Compute 92 * 93.
Step 2: The result is 8556.
|
perimeter of rectanglewithwidth49 and height 43 = 184
| 184 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (49 + 43) = 2 × 92 = 184
|
38 -(84)=-46
| -46 |
Step 1: Compute 38 - 84.
Step 2: The result is -46.
|
10 ** 4=10000
| 10,000 |
Step 1: Compute 10 ** 4.
Step 2: The result is 10000.
|
10**3 = 1000
| 1,000 |
Step 1: Compute 10 ** 3.
Step 2: The result is 1000.
|
area of rectangle withwidth 22 and height28 =616
| 616 |
Step 1: Area formula is width × height.
Step 2: 22 × 28 = 616
|
(8) * 60 =480
| 480 |
Step 1: Compute 8 * 60.
Step 2: The result is 480.
|
perimeterofrectangle with width 38 and height 40 = 156
| 156 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (38 + 40) = 2 × 78 = 156
|
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