Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
(50)+27 = 77
| 77 |
Step 1: Compute 50 + 27.
Step 2: The result is 77.
|
areaofcircle with radius18= 1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
hypotenuse of right trianglewith legs16 and 13 = 20.62
| 20.62 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(16² + 13²) = sqrt(256 + 169) = sqrt(425) = 20.62
|
perimeter of circlewith radius 9 =56.55
| 56.55 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 9 = 56.55
|
perimeter of triangle withsides 37, 18, 14 = 69
| 69 |
Step 1: Perimeter formula is a + b + c.
Step 2: 37 + 18 + 14 = 69
|
(20) - (15) =5
| 5 |
Step 1: Compute 20 - 15.
Step 2: The result is 5.
|
21 + 8 = 29
| 29 |
Step 1: Compute 21 + 8.
Step 2: The result is 29.
|
(10) **4 = 10000
| 10,000 |
Step 1: Compute 10 ** 4.
Step 2: The result is 10000.
|
(75) - 6 = 69
| 69 |
Step 1: Compute 75 - 6.
Step 2: The result is 69.
|
area of circlewith radius 16= 804.25
| 804.25 |
Step 1: Area formula is π × r².
Step 2: π × 16² = 3.14 × 256 = 804.25
|
(7)* (57) = 399
| 399 |
Step 1: Compute 7 * 57.
Step 2: The result is 399.
|
area of triangle withbase37 andheight 34= 629.00
| 629 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 37 × 34 = 629.00
|
perimeter of rectangle with width45 and height 21 =132
| 132 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (45 + 21) = 2 × 66 = 132
|
perimeter of circlewith radius 4 =25.13
| 25.13 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 4 = 25.13
|
area ofcircle with radius 15 = 706.86
| 706.86 |
Step 1: Area formula is π × r².
Step 2: π × 15² = 3.14 × 225 = 706.86
|
7/ 1 =7
| 7 |
Step 1: Compute 7 / 1.
Step 2: The result is 7.
|
perimeter of rectangle with width33 and height 4 = 74
| 74 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (33 + 4) = 2 × 37 = 74
|
perimeter ofrectanglewith width41 and height 24 =130
| 130 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (41 + 24) = 2 × 65 = 130
|
perimeter of triangle with sides 24,18, 4=46
| 46 |
Step 1: Perimeter formula is a + b + c.
Step 2: 24 + 18 + 4 = 46
|
hypotenuse of righttriangle withlegs 11 and 5 = 12.08
| 12.08 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(11² + 5²) = sqrt(121 + 25) = sqrt(146) = 12.08
|
34 %15 =4
| 4 |
Step 1: Compute 34 % 15.
Step 2: The result is 4.
|
area oftriangle with base 48 and height29= 696.00
| 696 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 48 × 29 = 696.00
|
area of triangle with base 4andheight 13 = 26.00
| 26 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 4 × 13 = 26.00
|
perimeter ofcircle withradius 18 =113.10
| 113.1 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 18 = 113.10
|
22 * (83)= 1826
| 1,826 |
Step 1: Compute 22 * 83.
Step 2: The result is 1826.
|
39- 8 = 31
| 31 |
Step 1: Compute 39 - 8.
Step 2: The result is 31.
|
(8)** 3=512
| 512 |
Step 1: Compute 8 ** 3.
Step 2: The result is 512.
|
perimeter oftrianglewithsides27,32,20= 79
| 79 |
Step 1: Perimeter formula is a + b + c.
Step 2: 27 + 32 + 20 = 79
|
(57) -(94) = -37
| -37 |
Step 1: Compute 57 - 94.
Step 2: The result is -37.
|
perimeterof rectangle withwidth 46 andheight 30= 152
| 152 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (46 + 30) = 2 × 76 = 152
|
(21) -(47) = -26
| -26 |
Step 1: Compute 21 - 47.
Step 2: The result is -26.
|
44* 62 = 2728
| 2,728 |
Step 1: Compute 44 * 62.
Step 2: The result is 2728.
|
area of rectangle withwidth 9 and height50 = 450
| 450 |
Step 1: Area formula is width × height.
Step 2: 9 × 50 = 450
|
hypotenuse of right triangle withlegs 12 and 17 =20.81
| 20.81 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(12² + 17²) = sqrt(144 + 289) = sqrt(433) = 20.81
|
perimeter of rectanglewithwidth35and height 16 = 102
| 102 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (35 + 16) = 2 × 51 = 102
|
(67)+(93)=160
| 160 |
Step 1: Compute 67 + 93.
Step 2: The result is 160.
|
perimeter of circle with radius 1 = 6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
50 % 3 =2
| 2 |
Step 1: Compute 50 % 3.
Step 2: The result is 2.
|
perimeter of circle with radius 19=119.38
| 119.38 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 19 = 119.38
|
62- 82 = -20
| -20 |
Step 1: Compute 62 - 82.
Step 2: The result is -20.
|
72 %10 =2
| 2 |
Step 1: Compute 72 % 10.
Step 2: The result is 2.
|
33+ 81 =114
| 114 |
Step 1: Compute 33 + 81.
Step 2: The result is 114.
|
perimeter of circle with radius 13 = 81.68
| 81.68 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 13 = 81.68
|
(49) / 7= 7
| 7 |
Step 1: Compute 49 / 7.
Step 2: The result is 7.
|
hypotenuseof right trianglewithlegs 6and 25= 25.71
| 25.71 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(6² + 25²) = sqrt(36 + 625) = sqrt(661) = 25.71
|
95 -69= 26
| 26 |
Step 1: Compute 95 - 69.
Step 2: The result is 26.
|
80 - 37= 43
| 43 |
Step 1: Compute 80 - 37.
Step 2: The result is 43.
|
area of triangle with base 47 and height26 =611.00
| 611 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 47 × 26 = 611.00
|
area of rectangle with width 42 and height21= 882
| 882 |
Step 1: Area formula is width × height.
Step 2: 42 × 21 = 882
|
39 % 7 = 4
| 4 |
Step 1: Compute 39 % 7.
Step 2: The result is 4.
|
10 ** (2) = 100
| 100 |
Step 1: Compute 10 ** 2.
Step 2: The result is 100.
|
area oftrianglewithbase 34 and height15= 255.00
| 255 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 34 × 15 = 255.00
|
68 -45 = 23
| 23 |
Step 1: Compute 68 - 45.
Step 2: The result is 23.
|
76 + (2)=78
| 78 |
Step 1: Compute 76 + 2.
Step 2: The result is 78.
|
10 ** (2)= 100
| 100 |
Step 1: Compute 10 ** 2.
Step 2: The result is 100.
|
hypotenuseof right triangle with legs 3 and 13 = 13.34
| 13.34 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(3² + 13²) = sqrt(9 + 169) = sqrt(178) = 13.34
|
perimeter of triangle withsides 50, 4,38 = 92
| 92 |
Step 1: Perimeter formula is a + b + c.
Step 2: 50 + 4 + 38 = 92
|
59 %4 =3
| 3 |
Step 1: Compute 59 % 4.
Step 2: The result is 3.
|
45% 14 =3
| 3 |
Step 1: Compute 45 % 14.
Step 2: The result is 3.
|
42 / (6)= 7
| 7 |
Step 1: Compute 42 / 6.
Step 2: The result is 7.
|
(45) %(4)=1
| 1 |
Step 1: Compute 45 % 4.
Step 2: The result is 1.
|
(56)* (29)=1624
| 1,624 |
Step 1: Compute 56 * 29.
Step 2: The result is 1624.
|
(84)/12 = 7
| 7 |
Step 1: Compute 84 / 12.
Step 2: The result is 7.
|
(2)** 4 = 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
perimeter of rectangle with width19 and height 10 =58
| 58 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (19 + 10) = 2 × 29 = 58
|
areaofcirclewithradius 9=254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
areaof circlewith radius 14 = 615.75
| 615.75 |
Step 1: Area formula is π × r².
Step 2: π × 14² = 3.14 × 196 = 615.75
|
perimeterofrectangle withwidth21 and height 29 =100
| 100 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (21 + 29) = 2 × 50 = 100
|
hypotenuse of righttrianglewith legs 9 and 10 = 13.45
| 13.45 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(9² + 10²) = sqrt(81 + 100) = sqrt(181) = 13.45
|
3 -54= -51
| -51 |
Step 1: Compute 3 - 54.
Step 2: The result is -51.
|
100 / 10 =10
| 10 |
Step 1: Compute 100 / 10.
Step 2: The result is 10.
|
perimeteroftriangle with sides 37,3, 39 = 79
| 79 |
Step 1: Perimeter formula is a + b + c.
Step 2: 37 + 3 + 39 = 79
|
(76) % (13) = 11
| 11 |
Step 1: Compute 76 % 13.
Step 2: The result is 11.
|
perimeterof triangle with sides43,14, 11 = 68
| 68 |
Step 1: Perimeter formula is a + b + c.
Step 2: 43 + 14 + 11 = 68
|
area of rectangle with width 15 and height42 = 630
| 630 |
Step 1: Area formula is width × height.
Step 2: 15 × 42 = 630
|
(15)+(35)=50
| 50 |
Step 1: Compute 15 + 35.
Step 2: The result is 50.
|
(47) *75 =3525
| 3,525 |
Step 1: Compute 47 * 75.
Step 2: The result is 3525.
|
perimeter of triangle with sides 15, 32, 27= 74
| 74 |
Step 1: Perimeter formula is a + b + c.
Step 2: 15 + 32 + 27 = 74
|
(60)/ (10) =6
| 6 |
Step 1: Compute 60 / 10.
Step 2: The result is 6.
|
6 ** 4= 1296
| 1,296 |
Step 1: Compute 6 ** 4.
Step 2: The result is 1296.
|
perimeter of rectangle withwidth 23 andheight 14 = 74
| 74 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (23 + 14) = 2 × 37 = 74
|
hypotenuse of right trianglewith legs18 and 13 = 22.20
| 22.2 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(18² + 13²) = sqrt(324 + 169) = sqrt(493) = 22.20
|
(52) -(68) =-16
| -16 |
Step 1: Compute 52 - 68.
Step 2: The result is -16.
|
area oftriangle withbase 29 and height 35 = 507.50
| 507.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 29 × 35 = 507.50
|
(34) + 91 = 125
| 125 |
Step 1: Compute 34 + 91.
Step 2: The result is 125.
|
15% 4 = 3
| 3 |
Step 1: Compute 15 % 4.
Step 2: The result is 3.
|
14 /2 = 7
| 7 |
Step 1: Compute 14 / 2.
Step 2: The result is 7.
|
perimeter of trianglewith sides 4, 33,23 = 60
| 60 |
Step 1: Perimeter formula is a + b + c.
Step 2: 4 + 33 + 23 = 60
|
area oftriangle withbase 21 and height17= 178.50
| 178.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 21 × 17 = 178.50
|
area oftriangle withbase 4and height 28=56.00
| 56 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 4 × 28 = 56.00
|
13 %5 = 3
| 3 |
Step 1: Compute 13 % 5.
Step 2: The result is 3.
|
perimeter of rectangle withwidth 43 andheight 26 = 138
| 138 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (43 + 26) = 2 × 69 = 138
|
areaof rectanglewith width 50 and height 48 =2400
| 2,400 |
Step 1: Area formula is width × height.
Step 2: 50 × 48 = 2400
|
area ofcirclewith radius 11 =380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
5- (75) =-70
| -70 |
Step 1: Compute 5 - 75.
Step 2: The result is -70.
|
63 * 12 = 756
| 756 |
Step 1: Compute 63 * 12.
Step 2: The result is 756.
|
96 -(17) = 79
| 79 |
Step 1: Compute 96 - 17.
Step 2: The result is 79.
|
hypotenuse ofright triangle with legs5 and29 = 29.43
| 29.43 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(5² + 29²) = sqrt(25 + 841) = sqrt(866) = 29.43
|
area of circlewith radius 12 = 452.39
| 452.39 |
Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39
|
perimeterof circlewith radius 18 =113.10
| 113.1 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 18 = 113.10
|
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