Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
area oftriangle with base19 and height 22= 209.00
| 209 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 19 × 22 = 209.00
|
area ofcircle with radius13 = 530.93
| 530.93 |
Step 1: Area formula is π × r².
Step 2: π × 13² = 3.14 × 169 = 530.93
|
5-3 = 2
| 2 |
Step 1: Compute 5 - 3.
Step 2: The result is 2.
|
area of circlewith radius 9 = 254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
32 + (35) =67
| 67 |
Step 1: Compute 32 + 35.
Step 2: The result is 67.
|
(128)/(16) = 8
| 8 |
Step 1: Compute 128 / 16.
Step 2: The result is 8.
|
areaof triangle withbase38and height 35 = 665.00
| 665 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 38 × 35 = 665.00
|
152/19=8
| 8 |
Step 1: Compute 152 / 19.
Step 2: The result is 8.
|
area of circlewith radius 12 = 452.39
| 452.39 |
Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39
|
41 * 87= 3567
| 3,567 |
Step 1: Compute 41 * 87.
Step 2: The result is 3567.
|
perimeter of rectanglewith width45 and height 2 = 94
| 94 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (45 + 2) = 2 × 47 = 94
|
68* 36 = 2448
| 2,448 |
Step 1: Compute 68 * 36.
Step 2: The result is 2448.
|
area ofrectangle with width32 and height 24=768
| 768 |
Step 1: Area formula is width × height.
Step 2: 32 × 24 = 768
|
area ofcirclewithradius 15 = 706.86
| 706.86 |
Step 1: Area formula is π × r².
Step 2: π × 15² = 3.14 × 225 = 706.86
|
(30) * 96=2880
| 2,880 |
Step 1: Compute 30 * 96.
Step 2: The result is 2880.
|
area of circle with radius 14 =615.75
| 615.75 |
Step 1: Area formula is π × r².
Step 2: π × 14² = 3.14 × 196 = 615.75
|
perimeterofcircle with radius 10 = 62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
73 % (17) = 5
| 5 |
Step 1: Compute 73 % 17.
Step 2: The result is 5.
|
perimeterof triangle with sides 18, 1, 3 = 22
| 22 |
Step 1: Perimeter formula is a + b + c.
Step 2: 18 + 1 + 3 = 22
|
areaof circle with radius 20 = 1256.64
| 1,256.64 |
Step 1: Area formula is π × r².
Step 2: π × 20² = 3.14 × 400 = 1256.64
|
(18)/ 3 = 6
| 6 |
Step 1: Compute 18 / 3.
Step 2: The result is 6.
|
92-23 = 69
| 69 |
Step 1: Compute 92 - 23.
Step 2: The result is 69.
|
93 - 14 = 79
| 79 |
Step 1: Compute 93 - 14.
Step 2: The result is 79.
|
5 ** 3 =125
| 125 |
Step 1: Compute 5 ** 3.
Step 2: The result is 125.
|
area of triangle with base43 andheight 7 = 150.50
| 150.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 43 × 7 = 150.50
|
12 % (13) = 12
| 12 |
Step 1: Compute 12 % 13.
Step 2: The result is 12.
|
perimeteroftrianglewithsides 41, 20,47= 108
| 108 |
Step 1: Perimeter formula is a + b + c.
Step 2: 41 + 20 + 47 = 108
|
98* 13 = 1274
| 1,274 |
Step 1: Compute 98 * 13.
Step 2: The result is 1274.
|
area oftriangle with base 40and height 15= 300.00
| 300 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 40 × 15 = 300.00
|
perimeter of triangle withsides 28, 6,46 =80
| 80 |
Step 1: Perimeter formula is a + b + c.
Step 2: 28 + 6 + 46 = 80
|
perimeter of circlewithradius7= 43.98
| 43.98 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 7 = 43.98
|
72 +43= 115
| 115 |
Step 1: Compute 72 + 43.
Step 2: The result is 115.
|
perimeter of triangle withsides24, 20, 24 =68
| 68 |
Step 1: Perimeter formula is a + b + c.
Step 2: 24 + 20 + 24 = 68
|
90+(51) = 141
| 141 |
Step 1: Compute 90 + 51.
Step 2: The result is 141.
|
perimeterof rectangle with width 49and height35= 168
| 168 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (49 + 35) = 2 × 84 = 168
|
area of rectangle withwidth 31 andheight 34 = 1054
| 1,054 |
Step 1: Area formula is width × height.
Step 2: 31 × 34 = 1054
|
52 -12= 40
| 40 |
Step 1: Compute 52 - 12.
Step 2: The result is 40.
|
area of rectangle with width 40and height40= 1600
| 1,600 |
Step 1: Area formula is width × height.
Step 2: 40 × 40 = 1600
|
area of circle with radius3 =28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
3 ** (2) = 9
| 9 |
Step 1: Compute 3 ** 2.
Step 2: The result is 9.
|
40 + 56 = 96
| 96 |
Step 1: Compute 40 + 56.
Step 2: The result is 96.
|
55 %15 = 10
| 10 |
Step 1: Compute 55 % 15.
Step 2: The result is 10.
|
area ofcirclewith radius1 = 3.14
| 3.14 |
Step 1: Area formula is π × r².
Step 2: π × 1² = 3.14 × 1 = 3.14
|
100 /20= 5
| 5 |
Step 1: Compute 100 / 20.
Step 2: The result is 5.
|
perimeter of rectangle with width30 andheight 39= 138
| 138 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (30 + 39) = 2 × 69 = 138
|
99/ 11 = 9
| 9 |
Step 1: Compute 99 / 11.
Step 2: The result is 9.
|
area of circle with radius 17= 907.92
| 907.92 |
Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92
|
perimeter ofrectangle with width37andheight29 = 132
| 132 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (37 + 29) = 2 × 66 = 132
|
hypotenuse of righttriangle withlegs 5 and 4 = 6.40
| 6.4 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(5² + 4²) = sqrt(25 + 16) = sqrt(41) = 6.40
|
36*79 = 2844
| 2,844 |
Step 1: Compute 36 * 79.
Step 2: The result is 2844.
|
area of trianglewithbase 20 and height18 =180.00
| 180 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 20 × 18 = 180.00
|
area of triangle withbase 44 and height5= 110.00
| 110 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 44 × 5 = 110.00
|
area of rectangle with width 42and height 4 = 168
| 168 |
Step 1: Area formula is width × height.
Step 2: 42 × 4 = 168
|
(81) - 10 = 71
| 71 |
Step 1: Compute 81 - 10.
Step 2: The result is 71.
|
areaofrectanglewith width 14and height 50 =700
| 700 |
Step 1: Area formula is width × height.
Step 2: 14 × 50 = 700
|
area of circle withradius 16 = 804.25
| 804.25 |
Step 1: Area formula is π × r².
Step 2: π × 16² = 3.14 × 256 = 804.25
|
34- (55) =-21
| -21 |
Step 1: Compute 34 - 55.
Step 2: The result is -21.
|
perimeter of rectangle with width 44 andheight 39 = 166
| 166 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (44 + 39) = 2 × 83 = 166
|
(96)% 14 = 12
| 12 |
Step 1: Compute 96 % 14.
Step 2: The result is 12.
|
area of triangle with base 7 and height 16= 56.00
| 56 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 7 × 16 = 56.00
|
area of circle with radius 15= 706.86
| 706.86 |
Step 1: Area formula is π × r².
Step 2: π × 15² = 3.14 × 225 = 706.86
|
2 ** (3) =8
| 8 |
Step 1: Compute 2 ** 3.
Step 2: The result is 8.
|
area ofrectangle withwidth47 and height 30 =1410
| 1,410 |
Step 1: Area formula is width × height.
Step 2: 47 × 30 = 1410
|
hypotenuseof righttriangle with legs 16and20=25.61
| 25.61 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(16² + 20²) = sqrt(256 + 400) = sqrt(656) = 25.61
|
perimeter oftriangle with sides 30, 6, 32= 68
| 68 |
Step 1: Perimeter formula is a + b + c.
Step 2: 30 + 6 + 32 = 68
|
60 % (3)=0
| 0 |
Step 1: Compute 60 % 3.
Step 2: The result is 0.
|
perimeter of rectanglewithwidth 12and height 2 =28
| 28 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (12 + 2) = 2 × 14 = 28
|
areaoftrianglewith base9 and height 3 = 13.50
| 13.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 9 × 3 = 13.50
|
50 % 17 = 16
| 16 |
Step 1: Compute 50 % 17.
Step 2: The result is 16.
|
perimeter of circlewith radius 10 =62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
perimeter of trianglewith sides11, 43, 29 = 83
| 83 |
Step 1: Perimeter formula is a + b + c.
Step 2: 11 + 43 + 29 = 83
|
perimeterof circle withradius 6 =37.70
| 37.7 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 6 = 37.70
|
area ofrectangle with width19 and height36= 684
| 684 |
Step 1: Area formula is width × height.
Step 2: 19 × 36 = 684
|
area of circle withradius 18 = 1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
area ofcircle withradius 3=28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
area ofcircle withradius 18= 1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
31 *(1)= 31
| 31 |
Step 1: Compute 31 * 1.
Step 2: The result is 31.
|
5 ** 3= 125
| 125 |
Step 1: Compute 5 ** 3.
Step 2: The result is 125.
|
15 /5 = 3
| 3 |
Step 1: Compute 15 / 5.
Step 2: The result is 3.
|
hypotenuse ofright triangle with legs 8 and19 = 20.62
| 20.62 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(8² + 19²) = sqrt(64 + 361) = sqrt(425) = 20.62
|
39 - (7) = 32
| 32 |
Step 1: Compute 39 - 7.
Step 2: The result is 32.
|
perimeter of circle with radius 9= 56.55
| 56.55 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 9 = 56.55
|
perimeter of triangle withsides10,16, 47 = 73
| 73 |
Step 1: Perimeter formula is a + b + c.
Step 2: 10 + 16 + 47 = 73
|
1**3 = 1
| 1 |
Step 1: Compute 1 ** 3.
Step 2: The result is 1.
|
39* (82) = 3198
| 3,198 |
Step 1: Compute 39 * 82.
Step 2: The result is 3198.
|
perimeter of circle withradius6 = 37.70
| 37.7 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 6 = 37.70
|
hypotenuseof righttriangle withlegs 26 and 12= 28.64
| 28.64 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(26² + 12²) = sqrt(676 + 144) = sqrt(820) = 28.64
|
50/ (10)=5
| 5 |
Step 1: Compute 50 / 10.
Step 2: The result is 5.
|
area of circlewithradius14 = 615.75
| 615.75 |
Step 1: Area formula is π × r².
Step 2: π × 14² = 3.14 × 196 = 615.75
|
area oftriangle with base36 and height 14=252.00
| 252 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 36 × 14 = 252.00
|
area of triangle with base 2andheight45 = 45.00
| 45 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 2 × 45 = 45.00
|
18 / 2 =9
| 9 |
Step 1: Compute 18 / 2.
Step 2: The result is 9.
|
hypotenuse of righttriangle with legs 19and 29 = 34.67
| 34.67 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(19² + 29²) = sqrt(361 + 841) = sqrt(1202) = 34.67
|
(29) -69= -40
| -40 |
Step 1: Compute 29 - 69.
Step 2: The result is -40.
|
(13)%(3) = 1
| 1 |
Step 1: Compute 13 % 3.
Step 2: The result is 1.
|
(40) / (5) =8
| 8 |
Step 1: Compute 40 / 5.
Step 2: The result is 8.
|
area of triangle withbase 41 andheight 12 = 246.00
| 246 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 41 × 12 = 246.00
|
area of circlewithradius 13=530.93
| 530.93 |
Step 1: Area formula is π × r².
Step 2: π × 13² = 3.14 × 169 = 530.93
|
52% 2 =0
| 0 |
Step 1: Compute 52 % 2.
Step 2: The result is 0.
|
78 %11 =1
| 1 |
Step 1: Compute 78 % 11.
Step 2: The result is 1.
|
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