Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
---|---|---|
(98)% (13) = 7
| 7 |
Step 1: Compute 98 % 13.
Step 2: The result is 7.
|
hypotenuse ofright triangle with legs22 and22 =31.11
| 31.11 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(22² + 22²) = sqrt(484 + 484) = sqrt(968) = 31.11
|
area oftriangle with base 23and height 17=195.50
| 195.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 23 × 17 = 195.50
|
48+(57) = 105
| 105 |
Step 1: Compute 48 + 57.
Step 2: The result is 105.
|
19 +18= 37
| 37 |
Step 1: Compute 19 + 18.
Step 2: The result is 37.
|
28 % (20)= 8
| 8 |
Step 1: Compute 28 % 20.
Step 2: The result is 8.
|
32 / 4= 8
| 8 |
Step 1: Compute 32 / 4.
Step 2: The result is 8.
|
perimeter of circle with radius 16= 100.53
| 100.53 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 16 = 100.53
|
area of rectangle withwidth 40and height11 =440
| 440 |
Step 1: Area formula is width × height.
Step 2: 40 × 11 = 440
|
areaof triangle with base 42 and height 34 =714.00
| 714 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 42 × 34 = 714.00
|
7 + 19=26
| 26 |
Step 1: Compute 7 + 19.
Step 2: The result is 26.
|
(31) - 88 = -57
| -57 |
Step 1: Compute 31 - 88.
Step 2: The result is -57.
|
8** 2 = 64
| 64 |
Step 1: Compute 8 ** 2.
Step 2: The result is 64.
|
(5)- 53 = -48
| -48 |
Step 1: Compute 5 - 53.
Step 2: The result is -48.
|
84 +(29) = 113
| 113 |
Step 1: Compute 84 + 29.
Step 2: The result is 113.
|
areaofrectangle withwidth 37 andheight16= 592
| 592 |
Step 1: Area formula is width × height.
Step 2: 37 × 16 = 592
|
hypotenuse ofrighttrianglewith legs 21 and 15= 25.81
| 25.81 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(21² + 15²) = sqrt(441 + 225) = sqrt(666) = 25.81
|
area of rectangle with width 34and height 29 =986
| 986 |
Step 1: Area formula is width × height.
Step 2: 34 × 29 = 986
|
20/10= 2
| 2 |
Step 1: Compute 20 / 10.
Step 2: The result is 2.
|
hypotenuse of right triangle withlegs 18 and 9= 20.12
| 20.12 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(18² + 9²) = sqrt(324 + 81) = sqrt(405) = 20.12
|
perimeter of circle withradius7 =43.98
| 43.98 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 7 = 43.98
|
hypotenuseofrighttriangle with legs26 and28 = 38.21
| 38.21 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(26² + 28²) = sqrt(676 + 784) = sqrt(1460) = 38.21
|
27/ (9) = 3
| 3 |
Step 1: Compute 27 / 9.
Step 2: The result is 3.
|
hypotenuse of right triangle with legs19 and 5 = 19.65
| 19.65 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(19² + 5²) = sqrt(361 + 25) = sqrt(386) = 19.65
|
6 %3 = 0
| 0 |
Step 1: Compute 6 % 3.
Step 2: The result is 0.
|
area of triangle withbase27 andheight 17 =229.50
| 229.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 27 × 17 = 229.50
|
perimeter of circle with radius 8 =50.27
| 50.27 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27
|
100 +41 = 141
| 141 |
Step 1: Compute 100 + 41.
Step 2: The result is 141.
|
perimeter of rectangle with width 46 andheight 7 = 106
| 106 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (46 + 7) = 2 × 53 = 106
|
area of rectangle withwidth 23 andheight 7 = 161
| 161 |
Step 1: Area formula is width × height.
Step 2: 23 × 7 = 161
|
74+ 43 = 117
| 117 |
Step 1: Compute 74 + 43.
Step 2: The result is 117.
|
hypotenuseof right triangle with legs 24and15= 28.30
| 28.3 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(24² + 15²) = sqrt(576 + 225) = sqrt(801) = 28.30
|
86 + 64 =150
| 150 |
Step 1: Compute 86 + 64.
Step 2: The result is 150.
|
10 /(10) = 1
| 1 |
Step 1: Compute 10 / 10.
Step 2: The result is 1.
|
2 **(4) = 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
(78)%6 = 0
| 0 |
Step 1: Compute 78 % 6.
Step 2: The result is 0.
|
area of circlewith radius10=314.16
| 314.16 |
Step 1: Area formula is π × r².
Step 2: π × 10² = 3.14 × 100 = 314.16
|
area of circlewith radius 6 = 113.10
| 113.1 |
Step 1: Area formula is π × r².
Step 2: π × 6² = 3.14 × 36 = 113.10
|
6 ** 3 = 216
| 216 |
Step 1: Compute 6 ** 3.
Step 2: The result is 216.
|
area of circle with radius11= 380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
(78)/ 13= 6
| 6 |
Step 1: Compute 78 / 13.
Step 2: The result is 6.
|
area of circle with radius 11= 380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
(12)/12 =1
| 1 |
Step 1: Compute 12 / 12.
Step 2: The result is 1.
|
hypotenuse of right triangle with legs 29 and 13 =31.78
| 31.78 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(29² + 13²) = sqrt(841 + 169) = sqrt(1010) = 31.78
|
190 / 19= 10
| 10 |
Step 1: Compute 190 / 19.
Step 2: The result is 10.
|
area of triangle withbase 5and height18 =45.00
| 45 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 5 × 18 = 45.00
|
(85) + (80) = 165
| 165 |
Step 1: Compute 85 + 80.
Step 2: The result is 165.
|
(2)*70= 140
| 140 |
Step 1: Compute 2 * 70.
Step 2: The result is 140.
|
(11) +94 =105
| 105 |
Step 1: Compute 11 + 94.
Step 2: The result is 105.
|
perimeter ofcircle with radius5= 31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
(7) **(2)=49
| 49 |
Step 1: Compute 7 ** 2.
Step 2: The result is 49.
|
(14) / (2) = 7
| 7 |
Step 1: Compute 14 / 2.
Step 2: The result is 7.
|
areaof circle withradius 10 = 314.16
| 314.16 |
Step 1: Area formula is π × r².
Step 2: π × 10² = 3.14 × 100 = 314.16
|
perimeteroftriangle with sides 32,28,41 = 101
| 101 |
Step 1: Perimeter formula is a + b + c.
Step 2: 32 + 28 + 41 = 101
|
32-(82) = -50
| -50 |
Step 1: Compute 32 - 82.
Step 2: The result is -50.
|
perimeter of trianglewith sides 32, 29, 41 =102
| 102 |
Step 1: Perimeter formula is a + b + c.
Step 2: 32 + 29 + 41 = 102
|
(1) %17= 1
| 1 |
Step 1: Compute 1 % 17.
Step 2: The result is 1.
|
area of circle with radius 2 = 12.57
| 12.57 |
Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57
|
area ofcircle with radius9 =254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
perimeter of trianglewith sides35,31,39 =105
| 105 |
Step 1: Perimeter formula is a + b + c.
Step 2: 35 + 31 + 39 = 105
|
perimeter ofrectangle with width 5and height 41=92
| 92 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (5 + 41) = 2 × 46 = 92
|
(26) * (69) =1794
| 1,794 |
Step 1: Compute 26 * 69.
Step 2: The result is 1794.
|
(31) +24 = 55
| 55 |
Step 1: Compute 31 + 24.
Step 2: The result is 55.
|
perimeterof circlewith radius 2 =12.57
| 12.57 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 2 = 12.57
|
23% (19) = 4
| 4 |
Step 1: Compute 23 % 19.
Step 2: The result is 4.
|
perimeterof triangle with sides 41, 45, 13= 99
| 99 |
Step 1: Perimeter formula is a + b + c.
Step 2: 41 + 45 + 13 = 99
|
7 **3 = 343
| 343 |
Step 1: Compute 7 ** 3.
Step 2: The result is 343.
|
perimeter ofcirclewith radius 14 = 87.96
| 87.96 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 14 = 87.96
|
perimeter of triangle withsides 40,47,2 =89
| 89 |
Step 1: Perimeter formula is a + b + c.
Step 2: 40 + 47 + 2 = 89
|
86 % (2) = 0
| 0 |
Step 1: Compute 86 % 2.
Step 2: The result is 0.
|
perimeter of triangle withsides 33,15,18 = 66
| 66 |
Step 1: Perimeter formula is a + b + c.
Step 2: 33 + 15 + 18 = 66
|
perimeterof rectangle with width 47andheight34 =162
| 162 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (47 + 34) = 2 × 81 = 162
|
hypotenuse ofrighttriangle with legs 3and 30 =30.15
| 30.15 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(3² + 30²) = sqrt(9 + 900) = sqrt(909) = 30.15
|
82+ 79= 161
| 161 |
Step 1: Compute 82 + 79.
Step 2: The result is 161.
|
perimeter of rectangle with width 45 and height 47= 184
| 184 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (45 + 47) = 2 × 92 = 184
|
area of rectanglewithwidth 12andheight 8=96
| 96 |
Step 1: Area formula is width × height.
Step 2: 12 × 8 = 96
|
perimeteroftriangle with sides 37, 47,48 = 132
| 132 |
Step 1: Perimeter formula is a + b + c.
Step 2: 37 + 47 + 48 = 132
|
areaof rectangle with width50 and height 1= 50
| 50 |
Step 1: Area formula is width × height.
Step 2: 50 × 1 = 50
|
areaof rectangle with width 41 andheight 17 = 697
| 697 |
Step 1: Area formula is width × height.
Step 2: 41 × 17 = 697
|
85 * 32 =2720
| 2,720 |
Step 1: Compute 85 * 32.
Step 2: The result is 2720.
|
area ofrectangle withwidth18 and height28 = 504
| 504 |
Step 1: Area formula is width × height.
Step 2: 18 × 28 = 504
|
2** 2 = 4
| 4 |
Step 1: Compute 2 ** 2.
Step 2: The result is 4.
|
perimeterofrectanglewithwidth 15 and height4 = 38
| 38 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (15 + 4) = 2 × 19 = 38
|
45+ (61) = 106
| 106 |
Step 1: Compute 45 + 61.
Step 2: The result is 106.
|
4 ** 3 =64
| 64 |
Step 1: Compute 4 ** 3.
Step 2: The result is 64.
|
perimeter of triangle with sides35, 38,28 = 101
| 101 |
Step 1: Perimeter formula is a + b + c.
Step 2: 35 + 38 + 28 = 101
|
hypotenuse of right triangle withlegs 23 and 30=37.80
| 37.8 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(23² + 30²) = sqrt(529 + 900) = sqrt(1429) = 37.80
|
perimeter ofcirclewith radius 20 = 125.66
| 125.66 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 20 = 125.66
|
7 - 38 =-31
| -31 |
Step 1: Compute 7 - 38.
Step 2: The result is -31.
|
50 - 67 = -17
| -17 |
Step 1: Compute 50 - 67.
Step 2: The result is -17.
|
areaoftrianglewith base35and height47=822.50
| 822.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 35 × 47 = 822.50
|
perimeterofrectangle with width 24 and height 7 = 62
| 62 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (24 + 7) = 2 × 31 = 62
|
46*28 = 1288
| 1,288 |
Step 1: Compute 46 * 28.
Step 2: The result is 1288.
|
42 - 15 =27
| 27 |
Step 1: Compute 42 - 15.
Step 2: The result is 27.
|
152/19 = 8
| 8 |
Step 1: Compute 152 / 19.
Step 2: The result is 8.
|
perimeterofrectangle with width 49 and height 24 = 146
| 146 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (49 + 24) = 2 × 73 = 146
|
perimeter oftrianglewith sides28, 38, 46 = 112
| 112 |
Step 1: Perimeter formula is a + b + c.
Step 2: 28 + 38 + 46 = 112
|
45 / 5 = 9
| 9 |
Step 1: Compute 45 / 5.
Step 2: The result is 9.
|
52 * 15=780
| 780 |
Step 1: Compute 52 * 15.
Step 2: The result is 780.
|
perimeter of circle withradius10= 62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
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