Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
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24 + (91)= 115
| 115 |
Step 1: Compute 24 + 91.
Step 2: The result is 115.
|
(26) %11 = 4
| 4 |
Step 1: Compute 26 % 11.
Step 2: The result is 4.
|
21 - 90=-69
| -69 |
Step 1: Compute 21 - 90.
Step 2: The result is -69.
|
perimeterofrectangle with width 40 andheight 29 =138
| 138 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (40 + 29) = 2 × 69 = 138
|
10** 4 = 10000
| 10,000 |
Step 1: Compute 10 ** 4.
Step 2: The result is 10000.
|
38 *(84)= 3192
| 3,192 |
Step 1: Compute 38 * 84.
Step 2: The result is 3192.
|
areaof circlewith radius 16 = 804.25
| 804.25 |
Step 1: Area formula is π × r².
Step 2: π × 16² = 3.14 × 256 = 804.25
|
perimeter of trianglewith sides36, 29,38=103
| 103 |
Step 1: Perimeter formula is a + b + c.
Step 2: 36 + 29 + 38 = 103
|
(36) - (48)= -12
| -12 |
Step 1: Compute 36 - 48.
Step 2: The result is -12.
|
perimeter ofrectangle with width 3 andheight 17 = 40
| 40 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (3 + 17) = 2 × 20 = 40
|
16*75 =1200
| 1,200 |
Step 1: Compute 16 * 75.
Step 2: The result is 1200.
|
perimeterofcirclewith radius 13 = 81.68
| 81.68 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 13 = 81.68
|
area ofcircle with radius 19 = 1134.11
| 1,134.11 |
Step 1: Area formula is π × r².
Step 2: π × 19² = 3.14 × 361 = 1134.11
|
45* 24= 1080
| 1,080 |
Step 1: Compute 45 * 24.
Step 2: The result is 1080.
|
hypotenuseof righttriangle with legs18 and19 = 26.17
| 26.17 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(18² + 19²) = sqrt(324 + 361) = sqrt(685) = 26.17
|
area of triangle with base 43and height 25= 537.50
| 537.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 43 × 25 = 537.50
|
74 + 93 = 167
| 167 |
Step 1: Compute 74 + 93.
Step 2: The result is 167.
|
areaofrectangle with width 37 andheight 39 =1443
| 1,443 |
Step 1: Area formula is width × height.
Step 2: 37 × 39 = 1443
|
area of rectanglewithwidth 16and height 1= 16
| 16 |
Step 1: Area formula is width × height.
Step 2: 16 × 1 = 16
|
area ofrectanglewith width 15andheight 34= 510
| 510 |
Step 1: Area formula is width × height.
Step 2: 15 × 34 = 510
|
39 % (20) = 19
| 19 |
Step 1: Compute 39 % 20.
Step 2: The result is 19.
|
86*6 =516
| 516 |
Step 1: Compute 86 * 6.
Step 2: The result is 516.
|
perimeterofcircle with radius 16 =100.53
| 100.53 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 16 = 100.53
|
9 ** 2 = 81
| 81 |
Step 1: Compute 9 ** 2.
Step 2: The result is 81.
|
(29) %(11) =7
| 7 |
Step 1: Compute 29 % 11.
Step 2: The result is 7.
|
areaofcircle with radius1= 3.14
| 3.14 |
Step 1: Area formula is π × r².
Step 2: π × 1² = 3.14 × 1 = 3.14
|
(4) *(28)= 112
| 112 |
Step 1: Compute 4 * 28.
Step 2: The result is 112.
|
area of rectangle with width 8 andheight 20=160
| 160 |
Step 1: Area formula is width × height.
Step 2: 8 × 20 = 160
|
(84) % (13) = 6
| 6 |
Step 1: Compute 84 % 13.
Step 2: The result is 6.
|
perimeter of triangle with sides 27, 4,15= 46
| 46 |
Step 1: Perimeter formula is a + b + c.
Step 2: 27 + 4 + 15 = 46
|
perimeterof triangle withsides 48,32,31= 111
| 111 |
Step 1: Perimeter formula is a + b + c.
Step 2: 48 + 32 + 31 = 111
|
perimeterof rectangle with width13 and height 33 = 92
| 92 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (13 + 33) = 2 × 46 = 92
|
30 % (11) = 8
| 8 |
Step 1: Compute 30 % 11.
Step 2: The result is 8.
|
93 *33 = 3069
| 3,069 |
Step 1: Compute 93 * 33.
Step 2: The result is 3069.
|
7 ** 4 = 2401
| 2,401 |
Step 1: Compute 7 ** 4.
Step 2: The result is 2401.
|
13 + (90) =103
| 103 |
Step 1: Compute 13 + 90.
Step 2: The result is 103.
|
(87)+ 95=182
| 182 |
Step 1: Compute 87 + 95.
Step 2: The result is 182.
|
(37)% 3= 1
| 1 |
Step 1: Compute 37 % 3.
Step 2: The result is 1.
|
(97) *60 = 5820
| 5,820 |
Step 1: Compute 97 * 60.
Step 2: The result is 5820.
|
52 * 28 = 1456
| 1,456 |
Step 1: Compute 52 * 28.
Step 2: The result is 1456.
|
10% 11 = 10
| 10 |
Step 1: Compute 10 % 11.
Step 2: The result is 10.
|
6 + 15 =21
| 21 |
Step 1: Compute 6 + 15.
Step 2: The result is 21.
|
120/(15)= 8
| 8 |
Step 1: Compute 120 / 15.
Step 2: The result is 8.
|
65- (63) =2
| 2 |
Step 1: Compute 65 - 63.
Step 2: The result is 2.
|
40 + 3 = 43
| 43 |
Step 1: Compute 40 + 3.
Step 2: The result is 43.
|
area of circle with radius 1 =3.14
| 3.14 |
Step 1: Area formula is π × r².
Step 2: π × 1² = 3.14 × 1 = 3.14
|
area of rectangle with width 38 and height 26 = 988
| 988 |
Step 1: Area formula is width × height.
Step 2: 38 × 26 = 988
|
areaofrectanglewith width 40 and height48= 1920
| 1,920 |
Step 1: Area formula is width × height.
Step 2: 40 × 48 = 1920
|
hypotenuse of right trianglewithlegs12and21 = 24.19
| 24.19 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(12² + 21²) = sqrt(144 + 441) = sqrt(585) = 24.19
|
area of rectanglewith width 8and height 7 = 56
| 56 |
Step 1: Area formula is width × height.
Step 2: 8 × 7 = 56
|
perimeter of triangle with sides37, 45, 1 = 83
| 83 |
Step 1: Perimeter formula is a + b + c.
Step 2: 37 + 45 + 1 = 83
|
(5) **3= 125
| 125 |
Step 1: Compute 5 ** 3.
Step 2: The result is 125.
|
37 *35 = 1295
| 1,295 |
Step 1: Compute 37 * 35.
Step 2: The result is 1295.
|
73 % 6 =1
| 1 |
Step 1: Compute 73 % 6.
Step 2: The result is 1.
|
12/ 4 = 3
| 3 |
Step 1: Compute 12 / 4.
Step 2: The result is 3.
|
perimeter of triangle withsides 20, 39, 25 = 84
| 84 |
Step 1: Perimeter formula is a + b + c.
Step 2: 20 + 39 + 25 = 84
|
area oftriangle with base49 andheight 12=294.00
| 294 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 49 × 12 = 294.00
|
area of circle with radius 11 =380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
perimeterofcirclewithradius 16 =100.53
| 100.53 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 16 = 100.53
|
44 / 11= 4
| 4 |
Step 1: Compute 44 / 11.
Step 2: The result is 4.
|
(3)** 3 = 27
| 27 |
Step 1: Compute 3 ** 3.
Step 2: The result is 27.
|
78 * 7 = 546
| 546 |
Step 1: Compute 78 * 7.
Step 2: The result is 546.
|
93%6= 3
| 3 |
Step 1: Compute 93 % 6.
Step 2: The result is 3.
|
area ofcirclewithradius 16= 804.25
| 804.25 |
Step 1: Area formula is π × r².
Step 2: π × 16² = 3.14 × 256 = 804.25
|
area ofcircle withradius 12 =452.39
| 452.39 |
Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39
|
(40) * 17 = 680
| 680 |
Step 1: Compute 40 * 17.
Step 2: The result is 680.
|
perimeter ofrectangle with width 35 and height20 =110
| 110 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (35 + 20) = 2 × 55 = 110
|
hypotenuse ofright triangle withlegs17 and3= 17.26
| 17.26 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(17² + 3²) = sqrt(289 + 9) = sqrt(298) = 17.26
|
area of triangle withbase 19 and height 25 =237.50
| 237.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 19 × 25 = 237.50
|
perimeterofcirclewith radius 16 = 100.53
| 100.53 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 16 = 100.53
|
hypotenuseof righttriangle with legs 10 and 17=19.72
| 19.72 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(10² + 17²) = sqrt(100 + 289) = sqrt(389) = 19.72
|
areaof rectangle with width 6and height 35 =210
| 210 |
Step 1: Area formula is width × height.
Step 2: 6 × 35 = 210
|
38 * 70 = 2660
| 2,660 |
Step 1: Compute 38 * 70.
Step 2: The result is 2660.
|
81+ (63) =144
| 144 |
Step 1: Compute 81 + 63.
Step 2: The result is 144.
|
perimeterof triangle withsides 32,20, 44=96
| 96 |
Step 1: Perimeter formula is a + b + c.
Step 2: 32 + 20 + 44 = 96
|
(7) ** 4 = 2401
| 2,401 |
Step 1: Compute 7 ** 4.
Step 2: The result is 2401.
|
perimeterof rectangle with width 24 and height 18 = 84
| 84 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (24 + 18) = 2 × 42 = 84
|
area ofcircle with radius 8= 201.06
| 201.06 |
Step 1: Area formula is π × r².
Step 2: π × 8² = 3.14 × 64 = 201.06
|
(6) ** 4 = 1296
| 1,296 |
Step 1: Compute 6 ** 4.
Step 2: The result is 1296.
|
hypotenuse of right triangle with legs 7 and14 = 15.65
| 15.65 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(7² + 14²) = sqrt(49 + 196) = sqrt(245) = 15.65
|
hypotenuseof right triangle withlegs 19 and 22=29.07
| 29.07 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(19² + 22²) = sqrt(361 + 484) = sqrt(845) = 29.07
|
perimeteroftrianglewithsides32, 34, 15 =81
| 81 |
Step 1: Perimeter formula is a + b + c.
Step 2: 32 + 34 + 15 = 81
|
(44) %5 = 4
| 4 |
Step 1: Compute 44 % 5.
Step 2: The result is 4.
|
perimeter of circle withradius 8 = 50.27
| 50.27 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27
|
perimeter of rectangle with width25and height 30= 110
| 110 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (25 + 30) = 2 × 55 = 110
|
68 / 17 = 4
| 4 |
Step 1: Compute 68 / 17.
Step 2: The result is 4.
|
(57) - 58 = -1
| -1 |
Step 1: Compute 57 - 58.
Step 2: The result is -1.
|
53- 78 = -25
| -25 |
Step 1: Compute 53 - 78.
Step 2: The result is -25.
|
60 % 7 = 4
| 4 |
Step 1: Compute 60 % 7.
Step 2: The result is 4.
|
hypotenuseof righttriangle with legs 4and27 = 27.29
| 27.29 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(4² + 27²) = sqrt(16 + 729) = sqrt(745) = 27.29
|
areaof rectangle with width 24and height48 =1152
| 1,152 |
Step 1: Area formula is width × height.
Step 2: 24 × 48 = 1152
|
hypotenuse of right triangle with legs24 and10 =26.00
| 26 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(24² + 10²) = sqrt(576 + 100) = sqrt(676) = 26.00
|
12* 22 = 264
| 264 |
Step 1: Compute 12 * 22.
Step 2: The result is 264.
|
area ofcirclewithradius 13 = 530.93
| 530.93 |
Step 1: Area formula is π × r².
Step 2: π × 13² = 3.14 × 169 = 530.93
|
perimeter oftriangle with sides 9, 8, 3 = 20
| 20 |
Step 1: Perimeter formula is a + b + c.
Step 2: 9 + 8 + 3 = 20
|
area of rectanglewith width 27and height 43 = 1161
| 1,161 |
Step 1: Area formula is width × height.
Step 2: 27 × 43 = 1161
|
area of triangle with base 17 and height 1 =8.50
| 8.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 17 × 1 = 8.50
|
10** 3 = 1000
| 1,000 |
Step 1: Compute 10 ** 3.
Step 2: The result is 1000.
|
area oftriangle with base3 andheight49 = 73.50
| 73.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 3 × 49 = 73.50
|
areaof rectangle with width 29andheight 33 = 957
| 957 |
Step 1: Area formula is width × height.
Step 2: 29 × 33 = 957
|
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