Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
---|---|---|
(35)/ 7 =5
| 5 |
Step 1: Compute 35 / 7.
Step 2: The result is 5.
|
perimeteroftriangle with sides 47,8, 47 = 102
| 102 |
Step 1: Perimeter formula is a + b + c.
Step 2: 47 + 8 + 47 = 102
|
area oftriangle with base1 and height 22 =11.00
| 11 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 1 × 22 = 11.00
|
8 ** 3 = 512
| 512 |
Step 1: Compute 8 ** 3.
Step 2: The result is 512.
|
area of circlewith radius 20= 1256.64
| 1,256.64 |
Step 1: Area formula is π × r².
Step 2: π × 20² = 3.14 × 400 = 1256.64
|
5** (4) =625
| 625 |
Step 1: Compute 5 ** 4.
Step 2: The result is 625.
|
82 *83= 6806
| 6,806 |
Step 1: Compute 82 * 83.
Step 2: The result is 6806.
|
areaof circle withradius15 = 706.86
| 706.86 |
Step 1: Area formula is π × r².
Step 2: π × 15² = 3.14 × 225 = 706.86
|
8 **3 = 512
| 512 |
Step 1: Compute 8 ** 3.
Step 2: The result is 512.
|
area of rectangle with width 11 andheight 40 = 440
| 440 |
Step 1: Area formula is width × height.
Step 2: 11 × 40 = 440
|
97+73 =170
| 170 |
Step 1: Compute 97 + 73.
Step 2: The result is 170.
|
46* 28 =1288
| 1,288 |
Step 1: Compute 46 * 28.
Step 2: The result is 1288.
|
perimeter ofcirclewithradius 1= 6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
7 / 1 =7
| 7 |
Step 1: Compute 7 / 1.
Step 2: The result is 7.
|
perimeter ofrectangle with width43and height4 = 94
| 94 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (43 + 4) = 2 × 47 = 94
|
hypotenuseofright triangle withlegs12and15 = 19.21
| 19.21 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(12² + 15²) = sqrt(144 + 225) = sqrt(369) = 19.21
|
81 +55 =136
| 136 |
Step 1: Compute 81 + 55.
Step 2: The result is 136.
|
21 *(20) =420
| 420 |
Step 1: Compute 21 * 20.
Step 2: The result is 420.
|
perimeterof circle withradius 5 = 31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
area ofrectangle with width36 andheight 44 =1584
| 1,584 |
Step 1: Area formula is width × height.
Step 2: 36 × 44 = 1584
|
area of triangle withbase 29 and height 3= 43.50
| 43.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 29 × 3 = 43.50
|
(96) / 16 = 6
| 6 |
Step 1: Compute 96 / 16.
Step 2: The result is 6.
|
97 - 60 = 37
| 37 |
Step 1: Compute 97 - 60.
Step 2: The result is 37.
|
area of circle with radius 2 = 12.57
| 12.57 |
Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57
|
area of triangle withbase 13and height 37 = 240.50
| 240.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 13 × 37 = 240.50
|
(77)* (89) =6853
| 6,853 |
Step 1: Compute 77 * 89.
Step 2: The result is 6853.
|
61 + (81) = 142
| 142 |
Step 1: Compute 61 + 81.
Step 2: The result is 142.
|
96 % 8 =0
| 0 |
Step 1: Compute 96 % 8.
Step 2: The result is 0.
|
areaofcircle with radius 18 =1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
area of circle withradius11= 380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
15 / 15= 1
| 1 |
Step 1: Compute 15 / 15.
Step 2: The result is 1.
|
(65) - 84 =-19
| -19 |
Step 1: Compute 65 - 84.
Step 2: The result is -19.
|
37+(5) = 42
| 42 |
Step 1: Compute 37 + 5.
Step 2: The result is 42.
|
91 %11 = 3
| 3 |
Step 1: Compute 91 % 11.
Step 2: The result is 3.
|
2*37 =74
| 74 |
Step 1: Compute 2 * 37.
Step 2: The result is 74.
|
60 - 90 =-30
| -30 |
Step 1: Compute 60 - 90.
Step 2: The result is -30.
|
perimeter of trianglewith sides 28, 47, 3= 78
| 78 |
Step 1: Perimeter formula is a + b + c.
Step 2: 28 + 47 + 3 = 78
|
21%(4) =1
| 1 |
Step 1: Compute 21 % 4.
Step 2: The result is 1.
|
22/ 11 = 2
| 2 |
Step 1: Compute 22 / 11.
Step 2: The result is 2.
|
area of rectangle with width 45 and height 41 = 1845
| 1,845 |
Step 1: Area formula is width × height.
Step 2: 45 × 41 = 1845
|
perimeterofcircle with radius15 = 94.25
| 94.25 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 15 = 94.25
|
perimeter ofrectanglewith width 38 and height 46= 168
| 168 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (38 + 46) = 2 × 84 = 168
|
hypotenuse ofrighttrianglewith legs 5 and 29 = 29.43
| 29.43 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(5² + 29²) = sqrt(25 + 841) = sqrt(866) = 29.43
|
hypotenuse of righttriangle withlegs13and12 = 17.69
| 17.69 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(13² + 12²) = sqrt(169 + 144) = sqrt(313) = 17.69
|
perimeter of rectangle withwidth9andheight 44= 106
| 106 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (9 + 44) = 2 × 53 = 106
|
190 / 19 = 10
| 10 |
Step 1: Compute 190 / 19.
Step 2: The result is 10.
|
perimeter of trianglewith sides 45,1,20 = 66
| 66 |
Step 1: Perimeter formula is a + b + c.
Step 2: 45 + 1 + 20 = 66
|
perimeter of circle withradius7 =43.98
| 43.98 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 7 = 43.98
|
perimeterof triangle with sides 17, 17, 30= 64
| 64 |
Step 1: Perimeter formula is a + b + c.
Step 2: 17 + 17 + 30 = 64
|
perimeter oftriangle withsides34, 24, 35 =93
| 93 |
Step 1: Perimeter formula is a + b + c.
Step 2: 34 + 24 + 35 = 93
|
66 -74= -8
| -8 |
Step 1: Compute 66 - 74.
Step 2: The result is -8.
|
70%16 =6
| 6 |
Step 1: Compute 70 % 16.
Step 2: The result is 6.
|
(54)+(79) =133
| 133 |
Step 1: Compute 54 + 79.
Step 2: The result is 133.
|
112 / 14 = 8
| 8 |
Step 1: Compute 112 / 14.
Step 2: The result is 8.
|
60 - 28 =32
| 32 |
Step 1: Compute 60 - 28.
Step 2: The result is 32.
|
18/ 2 = 9
| 9 |
Step 1: Compute 18 / 2.
Step 2: The result is 9.
|
area oftriangle withbase6 and height 27= 81.00
| 81 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 6 × 27 = 81.00
|
97 + 57 =154
| 154 |
Step 1: Compute 97 + 57.
Step 2: The result is 154.
|
(100) / 10 =10
| 10 |
Step 1: Compute 100 / 10.
Step 2: The result is 10.
|
area of rectangle with width 18 and height 13 =234
| 234 |
Step 1: Area formula is width × height.
Step 2: 18 × 13 = 234
|
(28) / 14 =2
| 2 |
Step 1: Compute 28 / 14.
Step 2: The result is 2.
|
58 - 64= -6
| -6 |
Step 1: Compute 58 - 64.
Step 2: The result is -6.
|
89 +80 = 169
| 169 |
Step 1: Compute 89 + 80.
Step 2: The result is 169.
|
56 -45 =11
| 11 |
Step 1: Compute 56 - 45.
Step 2: The result is 11.
|
50 / 5 = 10
| 10 |
Step 1: Compute 50 / 5.
Step 2: The result is 10.
|
97 * 89=8633
| 8,633 |
Step 1: Compute 97 * 89.
Step 2: The result is 8633.
|
(44) + 10 =54
| 54 |
Step 1: Compute 44 + 10.
Step 2: The result is 54.
|
15 % 15=0
| 0 |
Step 1: Compute 15 % 15.
Step 2: The result is 0.
|
25 + (7) = 32
| 32 |
Step 1: Compute 25 + 7.
Step 2: The result is 32.
|
area of circlewithradius4 = 50.27
| 50.27 |
Step 1: Area formula is π × r².
Step 2: π × 4² = 3.14 × 16 = 50.27
|
hypotenuse of righttrianglewith legs8and 26 = 27.20
| 27.2 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(8² + 26²) = sqrt(64 + 676) = sqrt(740) = 27.20
|
43 +96 =139
| 139 |
Step 1: Compute 43 + 96.
Step 2: The result is 139.
|
perimeter of circle with radius8 = 50.27
| 50.27 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27
|
areaof triangle withbase41 and height4= 82.00
| 82 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 41 × 4 = 82.00
|
area ofrectangle with width27 andheight 44 =1188
| 1,188 |
Step 1: Area formula is width × height.
Step 2: 27 × 44 = 1188
|
65/ (13) = 5
| 5 |
Step 1: Compute 65 / 13.
Step 2: The result is 5.
|
area of circle with radius 3= 28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
perimeterof circle withradius 10 = 62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
(48)/ (6) = 8
| 8 |
Step 1: Compute 48 / 6.
Step 2: The result is 8.
|
6 **(4)=1296
| 1,296 |
Step 1: Compute 6 ** 4.
Step 2: The result is 1296.
|
(76) /(19) = 4
| 4 |
Step 1: Compute 76 / 19.
Step 2: The result is 4.
|
hypotenuse of righttrianglewith legs 5 and17 =17.72
| 17.72 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(5² + 17²) = sqrt(25 + 289) = sqrt(314) = 17.72
|
areaof rectangle withwidth 30andheight36 =1080
| 1,080 |
Step 1: Area formula is width × height.
Step 2: 30 × 36 = 1080
|
hypotenuseof righttrianglewith legs 20 and12= 23.32
| 23.32 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(20² + 12²) = sqrt(400 + 144) = sqrt(544) = 23.32
|
25+ 88=113
| 113 |
Step 1: Compute 25 + 88.
Step 2: The result is 113.
|
68 *15=1020
| 1,020 |
Step 1: Compute 68 * 15.
Step 2: The result is 1020.
|
(9) /(1)= 9
| 9 |
Step 1: Compute 9 / 1.
Step 2: The result is 9.
|
66/ 11 = 6
| 6 |
Step 1: Compute 66 / 11.
Step 2: The result is 6.
|
9/ 1 = 9
| 9 |
Step 1: Compute 9 / 1.
Step 2: The result is 9.
|
(22) * 69 = 1518
| 1,518 |
Step 1: Compute 22 * 69.
Step 2: The result is 1518.
|
perimeter of trianglewithsides28, 22,5=55
| 55 |
Step 1: Perimeter formula is a + b + c.
Step 2: 28 + 22 + 5 = 55
|
(6) +23= 29
| 29 |
Step 1: Compute 6 + 23.
Step 2: The result is 29.
|
perimeteroftrianglewith sides 6,49, 47 =102
| 102 |
Step 1: Perimeter formula is a + b + c.
Step 2: 6 + 49 + 47 = 102
|
(4) %17 = 4
| 4 |
Step 1: Compute 4 % 17.
Step 2: The result is 4.
|
perimeterof rectangle withwidth18andheight29= 94
| 94 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (18 + 29) = 2 × 47 = 94
|
hypotenuse ofright triangle with legs 3 and 13= 13.34
| 13.34 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(3² + 13²) = sqrt(9 + 169) = sqrt(178) = 13.34
|
perimeter of trianglewith sides38,8,22=68
| 68 |
Step 1: Perimeter formula is a + b + c.
Step 2: 38 + 8 + 22 = 68
|
perimeter oftriangle with sides44,11, 8=63
| 63 |
Step 1: Perimeter formula is a + b + c.
Step 2: 44 + 11 + 8 = 63
|
perimeter of trianglewith sides 21,4,37= 62
| 62 |
Step 1: Perimeter formula is a + b + c.
Step 2: 21 + 4 + 37 = 62
|
perimeter of rectangle with width 31and height37 =136
| 136 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (31 + 37) = 2 × 68 = 136
|
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