Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
hypotenuse of right trianglewith legs 22 and 8 =23.41
| 23.41 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(22² + 8²) = sqrt(484 + 64) = sqrt(548) = 23.41
|
7 * 6 =42
| 42 |
Step 1: Compute 7 * 6.
Step 2: The result is 42.
|
9 /(3) = 3
| 3 |
Step 1: Compute 9 / 3.
Step 2: The result is 3.
|
(18) * 60 =1080
| 1,080 |
Step 1: Compute 18 * 60.
Step 2: The result is 1080.
|
(126) / (18)= 7
| 7 |
Step 1: Compute 126 / 18.
Step 2: The result is 7.
|
perimeterof circlewith radius 2 = 12.57
| 12.57 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 2 = 12.57
|
areaof rectanglewithwidth 15 and height 41= 615
| 615 |
Step 1: Area formula is width × height.
Step 2: 15 × 41 = 615
|
65 %4 = 1
| 1 |
Step 1: Compute 65 % 4.
Step 2: The result is 1.
|
area of rectangle withwidth 30 and height 9 = 270
| 270 |
Step 1: Area formula is width × height.
Step 2: 30 × 9 = 270
|
15 / (5) = 3
| 3 |
Step 1: Compute 15 / 5.
Step 2: The result is 3.
|
90 +50 = 140
| 140 |
Step 1: Compute 90 + 50.
Step 2: The result is 140.
|
perimeter of triangle withsides 26, 23,34=83
| 83 |
Step 1: Perimeter formula is a + b + c.
Step 2: 26 + 23 + 34 = 83
|
areaofcircle withradius9 =254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
28 *(42)=1176
| 1,176 |
Step 1: Compute 28 * 42.
Step 2: The result is 1176.
|
(8) % (11) =8
| 8 |
Step 1: Compute 8 % 11.
Step 2: The result is 8.
|
108/ 18 =6
| 6 |
Step 1: Compute 108 / 18.
Step 2: The result is 6.
|
area of triangle with base 49 and height12 = 294.00
| 294 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 49 × 12 = 294.00
|
perimeter ofrectangle withwidth 48 andheight40 =176
| 176 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (48 + 40) = 2 × 88 = 176
|
4 % (9)= 4
| 4 |
Step 1: Compute 4 % 9.
Step 2: The result is 4.
|
71 * 21 = 1491
| 1,491 |
Step 1: Compute 71 * 21.
Step 2: The result is 1491.
|
perimeterofcircle withradius 3= 18.85
| 18.85 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85
|
perimeteroftriangle withsides34, 12, 33 =79
| 79 |
Step 1: Perimeter formula is a + b + c.
Step 2: 34 + 12 + 33 = 79
|
perimeterof circle withradius 8 = 50.27
| 50.27 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27
|
areaof circle with radius 17 = 907.92
| 907.92 |
Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92
|
12+(61)= 73
| 73 |
Step 1: Compute 12 + 61.
Step 2: The result is 73.
|
8 - 55 = -47
| -47 |
Step 1: Compute 8 - 55.
Step 2: The result is -47.
|
area oftriangle withbase15and height29 = 217.50
| 217.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 15 × 29 = 217.50
|
perimeter oftriangle with sides 6, 15, 36 =57
| 57 |
Step 1: Perimeter formula is a + b + c.
Step 2: 6 + 15 + 36 = 57
|
(1) ** 2 =1
| 1 |
Step 1: Compute 1 ** 2.
Step 2: The result is 1.
|
(4) ** 3 = 64
| 64 |
Step 1: Compute 4 ** 3.
Step 2: The result is 64.
|
53* (77) = 4081
| 4,081 |
Step 1: Compute 53 * 77.
Step 2: The result is 4081.
|
perimeter oftriangle with sides 9, 49, 9 = 67
| 67 |
Step 1: Perimeter formula is a + b + c.
Step 2: 9 + 49 + 9 = 67
|
16 % 14 =2
| 2 |
Step 1: Compute 16 % 14.
Step 2: The result is 2.
|
area ofrectangle with width2and height 6 =12
| 12 |
Step 1: Area formula is width × height.
Step 2: 2 × 6 = 12
|
11 % 17 = 11
| 11 |
Step 1: Compute 11 % 17.
Step 2: The result is 11.
|
20/(2) =10
| 10 |
Step 1: Compute 20 / 2.
Step 2: The result is 10.
|
5 ** (2)= 25
| 25 |
Step 1: Compute 5 ** 2.
Step 2: The result is 25.
|
perimeter ofrectangle with width 41and height24=130
| 130 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (41 + 24) = 2 × 65 = 130
|
perimeter of triangle with sides4,16, 44=64
| 64 |
Step 1: Perimeter formula is a + b + c.
Step 2: 4 + 16 + 44 = 64
|
areaof circle withradius 16= 804.25
| 804.25 |
Step 1: Area formula is π × r².
Step 2: π × 16² = 3.14 × 256 = 804.25
|
(27)- 89 =-62
| -62 |
Step 1: Compute 27 - 89.
Step 2: The result is -62.
|
hypotenuse ofright triangle with legs 24 and 2 = 24.08
| 24.08 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(24² + 2²) = sqrt(576 + 4) = sqrt(580) = 24.08
|
6 ** 3 = 216
| 216 |
Step 1: Compute 6 ** 3.
Step 2: The result is 216.
|
perimeterof circle with radius 17 = 106.81
| 106.81 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 17 = 106.81
|
9- 2= 7
| 7 |
Step 1: Compute 9 - 2.
Step 2: The result is 7.
|
126 / 14= 9
| 9 |
Step 1: Compute 126 / 14.
Step 2: The result is 9.
|
80 +53=133
| 133 |
Step 1: Compute 80 + 53.
Step 2: The result is 133.
|
hypotenuse of right trianglewith legs 15 and 1 = 15.03
| 15.03 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(15² + 1²) = sqrt(225 + 1) = sqrt(226) = 15.03
|
74 * 40 =2960
| 2,960 |
Step 1: Compute 74 * 40.
Step 2: The result is 2960.
|
(5) ** 4 = 625
| 625 |
Step 1: Compute 5 ** 4.
Step 2: The result is 625.
|
21 / 3= 7
| 7 |
Step 1: Compute 21 / 3.
Step 2: The result is 7.
|
8 ** 3 = 512
| 512 |
Step 1: Compute 8 ** 3.
Step 2: The result is 512.
|
hypotenuseof righttrianglewith legs 20 and10= 22.36
| 22.36 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(20² + 10²) = sqrt(400 + 100) = sqrt(500) = 22.36
|
perimeter of rectangle with width 46 and height 36=164
| 164 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (46 + 36) = 2 × 82 = 164
|
34 * 26= 884
| 884 |
Step 1: Compute 34 * 26.
Step 2: The result is 884.
|
perimeter of triangle with sides 1, 17,35=53
| 53 |
Step 1: Perimeter formula is a + b + c.
Step 2: 1 + 17 + 35 = 53
|
perimeterof rectanglewith width38andheight 21= 118
| 118 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (38 + 21) = 2 × 59 = 118
|
53+ (70) = 123
| 123 |
Step 1: Compute 53 + 70.
Step 2: The result is 123.
|
7 ** 3 = 343
| 343 |
Step 1: Compute 7 ** 3.
Step 2: The result is 343.
|
90 * 89 =8010
| 8,010 |
Step 1: Compute 90 * 89.
Step 2: The result is 8010.
|
area of trianglewithbase21 and height 15= 157.50
| 157.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 21 × 15 = 157.50
|
(9) ** 2 = 81
| 81 |
Step 1: Compute 9 ** 2.
Step 2: The result is 81.
|
6 - 59= -53
| -53 |
Step 1: Compute 6 - 59.
Step 2: The result is -53.
|
area of rectanglewithwidth48andheight 49= 2352
| 2,352 |
Step 1: Area formula is width × height.
Step 2: 48 × 49 = 2352
|
30/ 15 = 2
| 2 |
Step 1: Compute 30 / 15.
Step 2: The result is 2.
|
52 * 76= 3952
| 3,952 |
Step 1: Compute 52 * 76.
Step 2: The result is 3952.
|
4 ** (4) =256
| 256 |
Step 1: Compute 4 ** 4.
Step 2: The result is 256.
|
(60) - 82 = -22
| -22 |
Step 1: Compute 60 - 82.
Step 2: The result is -22.
|
perimeter of circle with radius 4 =25.13
| 25.13 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 4 = 25.13
|
39 % 18=3
| 3 |
Step 1: Compute 39 % 18.
Step 2: The result is 3.
|
hypotenuse ofright triangle with legs 28and22 = 35.61
| 35.61 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(28² + 22²) = sqrt(784 + 484) = sqrt(1268) = 35.61
|
area of triangle withbase47and height 10 = 235.00
| 235 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 47 × 10 = 235.00
|
perimeteroftrianglewithsides39,10, 24 = 73
| 73 |
Step 1: Perimeter formula is a + b + c.
Step 2: 39 + 10 + 24 = 73
|
48% 18 = 12
| 12 |
Step 1: Compute 48 % 18.
Step 2: The result is 12.
|
perimeter of circle with radius 9= 56.55
| 56.55 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 9 = 56.55
|
area of rectangle withwidth 31 and height23 =713
| 713 |
Step 1: Area formula is width × height.
Step 2: 31 × 23 = 713
|
area ofrectanglewith width 47 and height 29= 1363
| 1,363 |
Step 1: Area formula is width × height.
Step 2: 47 × 29 = 1363
|
27 * 31 =837
| 837 |
Step 1: Compute 27 * 31.
Step 2: The result is 837.
|
81- (1)= 80
| 80 |
Step 1: Compute 81 - 1.
Step 2: The result is 80.
|
perimeter of circle withradius 18 = 113.10
| 113.1 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 18 = 113.10
|
99 * (75)=7425
| 7,425 |
Step 1: Compute 99 * 75.
Step 2: The result is 7425.
|
hypotenuse ofright trianglewith legs4 and6 = 7.21
| 7.21 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(4² + 6²) = sqrt(16 + 36) = sqrt(52) = 7.21
|
(53) + 31 = 84
| 84 |
Step 1: Compute 53 + 31.
Step 2: The result is 84.
|
(1) * 75 =75
| 75 |
Step 1: Compute 1 * 75.
Step 2: The result is 75.
|
77+ 38 =115
| 115 |
Step 1: Compute 77 + 38.
Step 2: The result is 115.
|
areaof triangle with base7and height3 = 10.50
| 10.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 7 × 3 = 10.50
|
(24) % 8 = 0
| 0 |
Step 1: Compute 24 % 8.
Step 2: The result is 0.
|
(15) %(5) = 0
| 0 |
Step 1: Compute 15 % 5.
Step 2: The result is 0.
|
area of triangle with base 16 and height16 = 128.00
| 128 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 16 × 16 = 128.00
|
13% 3=1
| 1 |
Step 1: Compute 13 % 3.
Step 2: The result is 1.
|
perimeterofcircle withradius 10= 62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
perimeterofcircle withradius 12 = 75.40
| 75.4 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 12 = 75.40
|
areaof circlewithradius13=530.93
| 530.93 |
Step 1: Area formula is π × r².
Step 2: π × 13² = 3.14 × 169 = 530.93
|
perimeter oftriangle with sides 31, 40, 39 = 110
| 110 |
Step 1: Perimeter formula is a + b + c.
Step 2: 31 + 40 + 39 = 110
|
perimeter of triangle with sides 44,13,44 = 101
| 101 |
Step 1: Perimeter formula is a + b + c.
Step 2: 44 + 13 + 44 = 101
|
1 - (86) = -85
| -85 |
Step 1: Compute 1 - 86.
Step 2: The result is -85.
|
85 %17= 0
| 0 |
Step 1: Compute 85 % 17.
Step 2: The result is 0.
|
perimeter of circlewith radius 7 =43.98
| 43.98 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 7 = 43.98
|
18 / 2 =9
| 9 |
Step 1: Compute 18 / 2.
Step 2: The result is 9.
|
perimeter oftriangle with sides 49, 11, 4= 64
| 64 |
Step 1: Perimeter formula is a + b + c.
Step 2: 49 + 11 + 4 = 64
|
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