Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
---|---|---|
20 * 90 = 1800
| 1,800 |
Step 1: Compute 20 * 90.
Step 2: The result is 1800.
|
54 / 6 =9
| 9 |
Step 1: Compute 54 / 6.
Step 2: The result is 9.
|
70 / 10 =7
| 7 |
Step 1: Compute 70 / 10.
Step 2: The result is 7.
|
25 / 5= 5
| 5 |
Step 1: Compute 25 / 5.
Step 2: The result is 5.
|
area of circle with radius 20= 1256.64
| 1,256.64 |
Step 1: Area formula is π × r².
Step 2: π × 20² = 3.14 × 400 = 1256.64
|
(7) ** 2 =49
| 49 |
Step 1: Compute 7 ** 2.
Step 2: The result is 49.
|
34 * 99=3366
| 3,366 |
Step 1: Compute 34 * 99.
Step 2: The result is 3366.
|
5 ** (2) = 25
| 25 |
Step 1: Compute 5 ** 2.
Step 2: The result is 25.
|
area of trianglewithbase 36 and height 31 = 558.00
| 558 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 36 × 31 = 558.00
|
6 **4 = 1296
| 1,296 |
Step 1: Compute 6 ** 4.
Step 2: The result is 1296.
|
hypotenuseof right triangle withlegs 23 and 20 =30.48
| 30.48 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(23² + 20²) = sqrt(529 + 400) = sqrt(929) = 30.48
|
(28) * 3 =84
| 84 |
Step 1: Compute 28 * 3.
Step 2: The result is 84.
|
perimeter oftriangle withsides 14, 36,3 =53
| 53 |
Step 1: Perimeter formula is a + b + c.
Step 2: 14 + 36 + 3 = 53
|
perimeterofcircle withradius 6= 37.70
| 37.7 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 6 = 37.70
|
86 +(52)= 138
| 138 |
Step 1: Compute 86 + 52.
Step 2: The result is 138.
|
hypotenuse ofright triangle with legs 27 and7 = 27.89
| 27.89 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(27² + 7²) = sqrt(729 + 49) = sqrt(778) = 27.89
|
area of circle with radius 17= 907.92
| 907.92 |
Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92
|
(1)**(2)= 1
| 1 |
Step 1: Compute 1 ** 2.
Step 2: The result is 1.
|
perimeter ofcircle withradius11 = 69.12
| 69.12 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 11 = 69.12
|
(68)% (1)=0
| 0 |
Step 1: Compute 68 % 1.
Step 2: The result is 0.
|
perimeter of rectangle with width 15 and height 6 = 42
| 42 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (15 + 6) = 2 × 21 = 42
|
areaof rectanglewith width 23 and height15 = 345
| 345 |
Step 1: Area formula is width × height.
Step 2: 23 × 15 = 345
|
56- (36) =20
| 20 |
Step 1: Compute 56 - 36.
Step 2: The result is 20.
|
hypotenuse of right trianglewith legs 18and 5 = 18.68
| 18.68 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(18² + 5²) = sqrt(324 + 25) = sqrt(349) = 18.68
|
18 * (71)= 1278
| 1,278 |
Step 1: Compute 18 * 71.
Step 2: The result is 1278.
|
hypotenuseofright trianglewithlegs 6 and30 =30.59
| 30.59 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(6² + 30²) = sqrt(36 + 900) = sqrt(936) = 30.59
|
hypotenuse of righttriangle with legs 29and 24 = 37.64
| 37.64 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(29² + 24²) = sqrt(841 + 576) = sqrt(1417) = 37.64
|
10** 2 =100
| 100 |
Step 1: Compute 10 ** 2.
Step 2: The result is 100.
|
area of rectangle withwidth 46 and height 40 = 1840
| 1,840 |
Step 1: Area formula is width × height.
Step 2: 46 × 40 = 1840
|
49 -(72) = -23
| -23 |
Step 1: Compute 49 - 72.
Step 2: The result is -23.
|
perimeter oftrianglewith sides 28, 37, 35 = 100
| 100 |
Step 1: Perimeter formula is a + b + c.
Step 2: 28 + 37 + 35 = 100
|
hypotenuseof righttrianglewithlegs11 and 12 = 16.28
| 16.28 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(11² + 12²) = sqrt(121 + 144) = sqrt(265) = 16.28
|
perimeter of triangle withsides 7, 4, 4 =15
| 15 |
Step 1: Perimeter formula is a + b + c.
Step 2: 7 + 4 + 4 = 15
|
area of triangle with base 48andheight 5=120.00
| 120 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 48 × 5 = 120.00
|
area of rectangle withwidth 39 and height48 = 1872
| 1,872 |
Step 1: Area formula is width × height.
Step 2: 39 × 48 = 1872
|
hypotenuseofright trianglewith legs 4 and 14 = 14.56
| 14.56 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(4² + 14²) = sqrt(16 + 196) = sqrt(212) = 14.56
|
area ofcircle with radius 8 = 201.06
| 201.06 |
Step 1: Area formula is π × r².
Step 2: π × 8² = 3.14 × 64 = 201.06
|
4 %10 = 4
| 4 |
Step 1: Compute 4 % 10.
Step 2: The result is 4.
|
perimeter of rectanglewith width 19 and height 2 = 42
| 42 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (19 + 2) = 2 × 21 = 42
|
area of triangle with base 7and height 43 = 150.50
| 150.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 7 × 43 = 150.50
|
perimeterof rectangle with width 24 and height44= 136
| 136 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (24 + 44) = 2 × 68 = 136
|
85* 85 =7225
| 7,225 |
Step 1: Compute 85 * 85.
Step 2: The result is 7225.
|
(8)** 3 = 512
| 512 |
Step 1: Compute 8 ** 3.
Step 2: The result is 512.
|
(7) * 87 = 609
| 609 |
Step 1: Compute 7 * 87.
Step 2: The result is 609.
|
56% (8)= 0
| 0 |
Step 1: Compute 56 % 8.
Step 2: The result is 0.
|
(86) * 76= 6536
| 6,536 |
Step 1: Compute 86 * 76.
Step 2: The result is 6536.
|
areaofcirclewith radius 8 =201.06
| 201.06 |
Step 1: Area formula is π × r².
Step 2: π × 8² = 3.14 × 64 = 201.06
|
hypotenuseof right triangle with legs20and 12 =23.32
| 23.32 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(20² + 12²) = sqrt(400 + 144) = sqrt(544) = 23.32
|
91 % 7 = 0
| 0 |
Step 1: Compute 91 % 7.
Step 2: The result is 0.
|
area of triangle with base 4and height 2=4.00
| 4 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 4 × 2 = 4.00
|
13 * (76) = 988
| 988 |
Step 1: Compute 13 * 76.
Step 2: The result is 988.
|
41 -58 = -17
| -17 |
Step 1: Compute 41 - 58.
Step 2: The result is -17.
|
(17)+ 63 =80
| 80 |
Step 1: Compute 17 + 63.
Step 2: The result is 80.
|
(36) -11 = 25
| 25 |
Step 1: Compute 36 - 11.
Step 2: The result is 25.
|
43 % (8)=3
| 3 |
Step 1: Compute 43 % 8.
Step 2: The result is 3.
|
area ofcirclewith radius 9= 254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
(67) -68= -1
| -1 |
Step 1: Compute 67 - 68.
Step 2: The result is -1.
|
perimeterof triangle with sides21, 12, 38 = 71
| 71 |
Step 1: Perimeter formula is a + b + c.
Step 2: 21 + 12 + 38 = 71
|
13 +63 = 76
| 76 |
Step 1: Compute 13 + 63.
Step 2: The result is 76.
|
83 %10= 3
| 3 |
Step 1: Compute 83 % 10.
Step 2: The result is 3.
|
area oftriangle withbase 21and height17= 178.50
| 178.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 21 × 17 = 178.50
|
76 % (6)= 4
| 4 |
Step 1: Compute 76 % 6.
Step 2: The result is 4.
|
perimeterofrectanglewithwidth32andheight 6 = 76
| 76 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (32 + 6) = 2 × 38 = 76
|
areaof triangle with base3and height 1= 1.50
| 1.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 3 × 1 = 1.50
|
areaofcirclewithradius 5 = 78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
67 * 2 =134
| 134 |
Step 1: Compute 67 * 2.
Step 2: The result is 134.
|
(17) * 43 = 731
| 731 |
Step 1: Compute 17 * 43.
Step 2: The result is 731.
|
7**(3) = 343
| 343 |
Step 1: Compute 7 ** 3.
Step 2: The result is 343.
|
40 % (4) = 0
| 0 |
Step 1: Compute 40 % 4.
Step 2: The result is 0.
|
hypotenuse of right trianglewith legs 12and 6 = 13.42
| 13.42 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(12² + 6²) = sqrt(144 + 36) = sqrt(180) = 13.42
|
100 +(84) = 184
| 184 |
Step 1: Compute 100 + 84.
Step 2: The result is 184.
|
area ofrectanglewithwidth 35and height 16=560
| 560 |
Step 1: Area formula is width × height.
Step 2: 35 × 16 = 560
|
perimeter of trianglewith sides44, 14,23= 81
| 81 |
Step 1: Perimeter formula is a + b + c.
Step 2: 44 + 14 + 23 = 81
|
6 / 1 = 6
| 6 |
Step 1: Compute 6 / 1.
Step 2: The result is 6.
|
hypotenuse of right triangle with legs 30 and 15= 33.54
| 33.54 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(30² + 15²) = sqrt(900 + 225) = sqrt(1125) = 33.54
|
perimeteroftriangle withsides3, 26,7 = 36
| 36 |
Step 1: Perimeter formula is a + b + c.
Step 2: 3 + 26 + 7 = 36
|
perimeter of circle with radius 2 = 12.57
| 12.57 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 2 = 12.57
|
8 ** 3 =512
| 512 |
Step 1: Compute 8 ** 3.
Step 2: The result is 512.
|
(83)- 42 = 41
| 41 |
Step 1: Compute 83 - 42.
Step 2: The result is 41.
|
98- 100 = -2
| -2 |
Step 1: Compute 98 - 100.
Step 2: The result is -2.
|
49 % 6 =1
| 1 |
Step 1: Compute 49 % 6.
Step 2: The result is 1.
|
93 *55= 5115
| 5,115 |
Step 1: Compute 93 * 55.
Step 2: The result is 5115.
|
perimeter oftrianglewithsides 2, 14, 25 = 41
| 41 |
Step 1: Perimeter formula is a + b + c.
Step 2: 2 + 14 + 25 = 41
|
(24) + (18) = 42
| 42 |
Step 1: Compute 24 + 18.
Step 2: The result is 42.
|
24- 98 = -74
| -74 |
Step 1: Compute 24 - 98.
Step 2: The result is -74.
|
area ofrectangle withwidth46 andheight 38= 1748
| 1,748 |
Step 1: Area formula is width × height.
Step 2: 46 × 38 = 1748
|
78*(9) = 702
| 702 |
Step 1: Compute 78 * 9.
Step 2: The result is 702.
|
perimeterof triangle withsides 30,14,12 = 56
| 56 |
Step 1: Perimeter formula is a + b + c.
Step 2: 30 + 14 + 12 = 56
|
55 + (34) =89
| 89 |
Step 1: Compute 55 + 34.
Step 2: The result is 89.
|
perimeter ofcirclewithradius 12 = 75.40
| 75.4 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 12 = 75.40
|
area of circle with radius9 = 254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
(45)- 40= 5
| 5 |
Step 1: Compute 45 - 40.
Step 2: The result is 5.
|
perimeter ofcircle with radius5=31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
area of triangle with base 10 and height 40 = 200.00
| 200 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 10 × 40 = 200.00
|
perimeterof rectanglewithwidth11 and height15 = 52
| 52 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (11 + 15) = 2 × 26 = 52
|
perimeteroftrianglewithsides 5,6, 15= 26
| 26 |
Step 1: Perimeter formula is a + b + c.
Step 2: 5 + 6 + 15 = 26
|
area of triangle with base 34and height 7= 119.00
| 119 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 34 × 7 = 119.00
|
9 ** (4) = 6561
| 6,561 |
Step 1: Compute 9 ** 4.
Step 2: The result is 6561.
|
areaofrectangle with width13and height50 = 650
| 650 |
Step 1: Area formula is width × height.
Step 2: 13 × 50 = 650
|
area oftrianglewithbase27 and height 26 =351.00
| 351 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 27 × 26 = 351.00
|
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.