Expression
stringlengths
5
66
Result
float64
-99
10k
Steps
stringlengths
47
107
20 * 90 = 1800
1,800
Step 1: Compute 20 * 90. Step 2: The result is 1800.
54 / 6 =9
9
Step 1: Compute 54 / 6. Step 2: The result is 9.
70 / 10 =7
7
Step 1: Compute 70 / 10. Step 2: The result is 7.
25 / 5= 5
5
Step 1: Compute 25 / 5. Step 2: The result is 5.
area of circle with radius 20= 1256.64
1,256.64
Step 1: Area formula is π × r². Step 2: π × 20² = 3.14 × 400 = 1256.64
(7) ** 2 =49
49
Step 1: Compute 7 ** 2. Step 2: The result is 49.
34 * 99=3366
3,366
Step 1: Compute 34 * 99. Step 2: The result is 3366.
5 ** (2) = 25
25
Step 1: Compute 5 ** 2. Step 2: The result is 25.
area of trianglewithbase 36 and height 31 = 558.00
558
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 36 × 31 = 558.00
6 **4 = 1296
1,296
Step 1: Compute 6 ** 4. Step 2: The result is 1296.
hypotenuseof right triangle withlegs 23 and 20 =30.48
30.48
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(23² + 20²) = sqrt(529 + 400) = sqrt(929) = 30.48
(28) * 3 =84
84
Step 1: Compute 28 * 3. Step 2: The result is 84.
perimeter oftriangle withsides 14, 36,3 =53
53
Step 1: Perimeter formula is a + b + c. Step 2: 14 + 36 + 3 = 53
perimeterofcircle withradius 6= 37.70
37.7
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 6 = 37.70
86 +(52)= 138
138
Step 1: Compute 86 + 52. Step 2: The result is 138.
hypotenuse ofright triangle with legs 27 and7 = 27.89
27.89
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(27² + 7²) = sqrt(729 + 49) = sqrt(778) = 27.89
area of circle with radius 17= 907.92
907.92
Step 1: Area formula is π × r². Step 2: π × 17² = 3.14 × 289 = 907.92
(1)**(2)= 1
1
Step 1: Compute 1 ** 2. Step 2: The result is 1.
perimeter ofcircle withradius11 = 69.12
69.12
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 11 = 69.12
(68)% (1)=0
0
Step 1: Compute 68 % 1. Step 2: The result is 0.
perimeter of rectangle with width 15 and height 6 = 42
42
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (15 + 6) = 2 × 21 = 42
areaof rectanglewith width 23 and height15 = 345
345
Step 1: Area formula is width × height. Step 2: 23 × 15 = 345
56- (36) =20
20
Step 1: Compute 56 - 36. Step 2: The result is 20.
hypotenuse of right trianglewith legs 18and 5 = 18.68
18.68
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(18² + 5²) = sqrt(324 + 25) = sqrt(349) = 18.68
18 * (71)= 1278
1,278
Step 1: Compute 18 * 71. Step 2: The result is 1278.
hypotenuseofright trianglewithlegs 6 and30 =30.59
30.59
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(6² + 30²) = sqrt(36 + 900) = sqrt(936) = 30.59
hypotenuse of righttriangle with legs 29and 24 = 37.64
37.64
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(29² + 24²) = sqrt(841 + 576) = sqrt(1417) = 37.64
10** 2 =100
100
Step 1: Compute 10 ** 2. Step 2: The result is 100.
area of rectangle withwidth 46 and height 40 = 1840
1,840
Step 1: Area formula is width × height. Step 2: 46 × 40 = 1840
49 -(72) = -23
-23
Step 1: Compute 49 - 72. Step 2: The result is -23.
perimeter oftrianglewith sides 28, 37, 35 = 100
100
Step 1: Perimeter formula is a + b + c. Step 2: 28 + 37 + 35 = 100
hypotenuseof righttrianglewithlegs11 and 12 = 16.28
16.28
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(11² + 12²) = sqrt(121 + 144) = sqrt(265) = 16.28
perimeter of triangle withsides 7, 4, 4 =15
15
Step 1: Perimeter formula is a + b + c. Step 2: 7 + 4 + 4 = 15
area of triangle with base 48andheight 5=120.00
120
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 48 × 5 = 120.00
area of rectangle withwidth 39 and height48 = 1872
1,872
Step 1: Area formula is width × height. Step 2: 39 × 48 = 1872
hypotenuseofright trianglewith legs 4 and 14 = 14.56
14.56
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(4² + 14²) = sqrt(16 + 196) = sqrt(212) = 14.56
area ofcircle with radius 8 = 201.06
201.06
Step 1: Area formula is π × r². Step 2: π × 8² = 3.14 × 64 = 201.06
4 %10 = 4
4
Step 1: Compute 4 % 10. Step 2: The result is 4.
perimeter of rectanglewith width 19 and height 2 = 42
42
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (19 + 2) = 2 × 21 = 42
area of triangle with base 7and height 43 = 150.50
150.5
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 7 × 43 = 150.50
perimeterof rectangle with width 24 and height44= 136
136
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (24 + 44) = 2 × 68 = 136
85* 85 =7225
7,225
Step 1: Compute 85 * 85. Step 2: The result is 7225.
(8)** 3 = 512
512
Step 1: Compute 8 ** 3. Step 2: The result is 512.
(7) * 87 = 609
609
Step 1: Compute 7 * 87. Step 2: The result is 609.
56% (8)= 0
0
Step 1: Compute 56 % 8. Step 2: The result is 0.
(86) * 76= 6536
6,536
Step 1: Compute 86 * 76. Step 2: The result is 6536.
areaofcirclewith radius 8 =201.06
201.06
Step 1: Area formula is π × r². Step 2: π × 8² = 3.14 × 64 = 201.06
hypotenuseof right triangle with legs20and 12 =23.32
23.32
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(20² + 12²) = sqrt(400 + 144) = sqrt(544) = 23.32
91 % 7 = 0
0
Step 1: Compute 91 % 7. Step 2: The result is 0.
area of triangle with base 4and height 2=4.00
4
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 4 × 2 = 4.00
13 * (76) = 988
988
Step 1: Compute 13 * 76. Step 2: The result is 988.
41 -58 = -17
-17
Step 1: Compute 41 - 58. Step 2: The result is -17.
(17)+ 63 =80
80
Step 1: Compute 17 + 63. Step 2: The result is 80.
(36) -11 = 25
25
Step 1: Compute 36 - 11. Step 2: The result is 25.
43 % (8)=3
3
Step 1: Compute 43 % 8. Step 2: The result is 3.
area ofcirclewith radius 9= 254.47
254.47
Step 1: Area formula is π × r². Step 2: π × 9² = 3.14 × 81 = 254.47
(67) -68= -1
-1
Step 1: Compute 67 - 68. Step 2: The result is -1.
perimeterof triangle with sides21, 12, 38 = 71
71
Step 1: Perimeter formula is a + b + c. Step 2: 21 + 12 + 38 = 71
13 +63 = 76
76
Step 1: Compute 13 + 63. Step 2: The result is 76.
83 %10= 3
3
Step 1: Compute 83 % 10. Step 2: The result is 3.
area oftriangle withbase 21and height17= 178.50
178.5
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 21 × 17 = 178.50
76 % (6)= 4
4
Step 1: Compute 76 % 6. Step 2: The result is 4.
perimeterofrectanglewithwidth32andheight 6 = 76
76
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (32 + 6) = 2 × 38 = 76
areaof triangle with base3and height 1= 1.50
1.5
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 3 × 1 = 1.50
areaofcirclewithradius 5 = 78.54
78.54
Step 1: Area formula is π × r². Step 2: π × 5² = 3.14 × 25 = 78.54
67 * 2 =134
134
Step 1: Compute 67 * 2. Step 2: The result is 134.
(17) * 43 = 731
731
Step 1: Compute 17 * 43. Step 2: The result is 731.
7**(3) = 343
343
Step 1: Compute 7 ** 3. Step 2: The result is 343.
40 % (4) = 0
0
Step 1: Compute 40 % 4. Step 2: The result is 0.
hypotenuse of right trianglewith legs 12and 6 = 13.42
13.42
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(12² + 6²) = sqrt(144 + 36) = sqrt(180) = 13.42
100 +(84) = 184
184
Step 1: Compute 100 + 84. Step 2: The result is 184.
area ofrectanglewithwidth 35and height 16=560
560
Step 1: Area formula is width × height. Step 2: 35 × 16 = 560
perimeter of trianglewith sides44, 14,23= 81
81
Step 1: Perimeter formula is a + b + c. Step 2: 44 + 14 + 23 = 81
6 / 1 = 6
6
Step 1: Compute 6 / 1. Step 2: The result is 6.
hypotenuse of right triangle with legs 30 and 15= 33.54
33.54
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(30² + 15²) = sqrt(900 + 225) = sqrt(1125) = 33.54
perimeteroftriangle withsides3, 26,7 = 36
36
Step 1: Perimeter formula is a + b + c. Step 2: 3 + 26 + 7 = 36
perimeter of circle with radius 2 = 12.57
12.57
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 2 = 12.57
8 ** 3 =512
512
Step 1: Compute 8 ** 3. Step 2: The result is 512.
(83)- 42 = 41
41
Step 1: Compute 83 - 42. Step 2: The result is 41.
98- 100 = -2
-2
Step 1: Compute 98 - 100. Step 2: The result is -2.
49 % 6 =1
1
Step 1: Compute 49 % 6. Step 2: The result is 1.
93 *55= 5115
5,115
Step 1: Compute 93 * 55. Step 2: The result is 5115.
perimeter oftrianglewithsides 2, 14, 25 = 41
41
Step 1: Perimeter formula is a + b + c. Step 2: 2 + 14 + 25 = 41
(24) + (18) = 42
42
Step 1: Compute 24 + 18. Step 2: The result is 42.
24- 98 = -74
-74
Step 1: Compute 24 - 98. Step 2: The result is -74.
area ofrectangle withwidth46 andheight 38= 1748
1,748
Step 1: Area formula is width × height. Step 2: 46 × 38 = 1748
78*(9) = 702
702
Step 1: Compute 78 * 9. Step 2: The result is 702.
perimeterof triangle withsides 30,14,12 = 56
56
Step 1: Perimeter formula is a + b + c. Step 2: 30 + 14 + 12 = 56
55 + (34) =89
89
Step 1: Compute 55 + 34. Step 2: The result is 89.
perimeter ofcirclewithradius 12 = 75.40
75.4
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 12 = 75.40
area of circle with radius9 = 254.47
254.47
Step 1: Area formula is π × r². Step 2: π × 9² = 3.14 × 81 = 254.47
(45)- 40= 5
5
Step 1: Compute 45 - 40. Step 2: The result is 5.
perimeter ofcircle with radius5=31.42
31.42
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 5 = 31.42
area of triangle with base 10 and height 40 = 200.00
200
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 10 × 40 = 200.00
perimeterof rectanglewithwidth11 and height15 = 52
52
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (11 + 15) = 2 × 26 = 52
perimeteroftrianglewithsides 5,6, 15= 26
26
Step 1: Perimeter formula is a + b + c. Step 2: 5 + 6 + 15 = 26
area of triangle with base 34and height 7= 119.00
119
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 34 × 7 = 119.00
9 ** (4) = 6561
6,561
Step 1: Compute 9 ** 4. Step 2: The result is 6561.
areaofrectangle with width13and height50 = 650
650
Step 1: Area formula is width × height. Step 2: 13 × 50 = 650
area oftrianglewithbase27 and height 26 =351.00
351
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 27 × 26 = 351.00