Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
---|---|---|
53+(98) =151
| 151 |
Step 1: Compute 53 + 98.
Step 2: The result is 151.
|
37+21 = 58
| 58 |
Step 1: Compute 37 + 21.
Step 2: The result is 58.
|
hypotenuseof righttriangle withlegs 18and 12 =21.63
| 21.63 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(18² + 12²) = sqrt(324 + 144) = sqrt(468) = 21.63
|
3%18=3
| 3 |
Step 1: Compute 3 % 18.
Step 2: The result is 3.
|
perimeterof trianglewith sides 15, 36, 32= 83
| 83 |
Step 1: Perimeter formula is a + b + c.
Step 2: 15 + 36 + 32 = 83
|
(61)+ 26 = 87
| 87 |
Step 1: Compute 61 + 26.
Step 2: The result is 87.
|
20 /(10)=2
| 2 |
Step 1: Compute 20 / 10.
Step 2: The result is 2.
|
(90)* (45) = 4050
| 4,050 |
Step 1: Compute 90 * 45.
Step 2: The result is 4050.
|
48 + (74)=122
| 122 |
Step 1: Compute 48 + 74.
Step 2: The result is 122.
|
(21) - (8)= 13
| 13 |
Step 1: Compute 21 - 8.
Step 2: The result is 13.
|
perimeter ofrectangle with width 16 and height 3= 38
| 38 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (16 + 3) = 2 × 19 = 38
|
(65) + 59 = 124
| 124 |
Step 1: Compute 65 + 59.
Step 2: The result is 124.
|
37+ 78 = 115
| 115 |
Step 1: Compute 37 + 78.
Step 2: The result is 115.
|
perimeter of triangle with sides18,11,28= 57
| 57 |
Step 1: Perimeter formula is a + b + c.
Step 2: 18 + 11 + 28 = 57
|
66 -90= -24
| -24 |
Step 1: Compute 66 - 90.
Step 2: The result is -24.
|
perimeter of rectanglewith width 5 and height 32=74
| 74 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (5 + 32) = 2 × 37 = 74
|
7** 3 = 343
| 343 |
Step 1: Compute 7 ** 3.
Step 2: The result is 343.
|
perimeter oftriangle withsides 49, 2, 39 = 90
| 90 |
Step 1: Perimeter formula is a + b + c.
Step 2: 49 + 2 + 39 = 90
|
(48) *(28) =1344
| 1,344 |
Step 1: Compute 48 * 28.
Step 2: The result is 1344.
|
(99) -23 = 76
| 76 |
Step 1: Compute 99 - 23.
Step 2: The result is 76.
|
56 % (9)=2
| 2 |
Step 1: Compute 56 % 9.
Step 2: The result is 2.
|
perimeter of rectangle with width11 and height 4= 30
| 30 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (11 + 4) = 2 × 15 = 30
|
77 -30 =47
| 47 |
Step 1: Compute 77 - 30.
Step 2: The result is 47.
|
(82)+ 88 =170
| 170 |
Step 1: Compute 82 + 88.
Step 2: The result is 170.
|
(85)*35 = 2975
| 2,975 |
Step 1: Compute 85 * 35.
Step 2: The result is 2975.
|
hypotenuse of right triangle with legs8 and 4= 8.94
| 8.94 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(8² + 4²) = sqrt(64 + 16) = sqrt(80) = 8.94
|
6** 4=1296
| 1,296 |
Step 1: Compute 6 ** 4.
Step 2: The result is 1296.
|
56* 50=2800
| 2,800 |
Step 1: Compute 56 * 50.
Step 2: The result is 2800.
|
90 % 9 = 0
| 0 |
Step 1: Compute 90 % 9.
Step 2: The result is 0.
|
areaofcirclewith radius16=804.25
| 804.25 |
Step 1: Area formula is π × r².
Step 2: π × 16² = 3.14 × 256 = 804.25
|
perimeterof rectanglewith width 37and height 15 = 104
| 104 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (37 + 15) = 2 × 52 = 104
|
(72) / (12) = 6
| 6 |
Step 1: Compute 72 / 12.
Step 2: The result is 6.
|
(11) - 95= -84
| -84 |
Step 1: Compute 11 - 95.
Step 2: The result is -84.
|
80 + (47) = 127
| 127 |
Step 1: Compute 80 + 47.
Step 2: The result is 127.
|
perimeter of circle withradius 1 = 6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
(1)** 2=1
| 1 |
Step 1: Compute 1 ** 2.
Step 2: The result is 1.
|
(56) / (8) =7
| 7 |
Step 1: Compute 56 / 8.
Step 2: The result is 7.
|
area ofcirclewithradius 9 = 254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
(70) /10 = 7
| 7 |
Step 1: Compute 70 / 10.
Step 2: The result is 7.
|
area of circle with radius15 = 706.86
| 706.86 |
Step 1: Area formula is π × r².
Step 2: π × 15² = 3.14 × 225 = 706.86
|
area of triangle with base 12 and height16= 96.00
| 96 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 12 × 16 = 96.00
|
2**4 = 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
81 + 50 = 131
| 131 |
Step 1: Compute 81 + 50.
Step 2: The result is 131.
|
perimeter of trianglewith sides 11,44, 1 = 56
| 56 |
Step 1: Perimeter formula is a + b + c.
Step 2: 11 + 44 + 1 = 56
|
74 *4= 296
| 296 |
Step 1: Compute 74 * 4.
Step 2: The result is 296.
|
1 ** 3 =1
| 1 |
Step 1: Compute 1 ** 3.
Step 2: The result is 1.
|
area ofcirclewithradius19 = 1134.11
| 1,134.11 |
Step 1: Area formula is π × r².
Step 2: π × 19² = 3.14 × 361 = 1134.11
|
perimeterof triangle with sides19, 6, 26 = 51
| 51 |
Step 1: Perimeter formula is a + b + c.
Step 2: 19 + 6 + 26 = 51
|
areaof circle with radius 9= 254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
perimeter of trianglewithsides 4,1, 5 = 10
| 10 |
Step 1: Perimeter formula is a + b + c.
Step 2: 4 + 1 + 5 = 10
|
perimeter of rectanglewith width 5andheight 12 = 34
| 34 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (5 + 12) = 2 × 17 = 34
|
40 / 20 = 2
| 2 |
Step 1: Compute 40 / 20.
Step 2: The result is 2.
|
45 /9 = 5
| 5 |
Step 1: Compute 45 / 9.
Step 2: The result is 5.
|
area oftrianglewith base 16 and height 47 = 376.00
| 376 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 16 × 47 = 376.00
|
hypotenuse of right triangle withlegs7 and 20 = 21.19
| 21.19 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(7² + 20²) = sqrt(49 + 400) = sqrt(449) = 21.19
|
20 *43 =860
| 860 |
Step 1: Compute 20 * 43.
Step 2: The result is 860.
|
hypotenuseofright triangle with legs 13 and 9= 15.81
| 15.81 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(13² + 9²) = sqrt(169 + 81) = sqrt(250) = 15.81
|
(6) **3 = 216
| 216 |
Step 1: Compute 6 ** 3.
Step 2: The result is 216.
|
area of circle with radius 5=78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
area of rectanglewithwidth 11andheight 17=187
| 187 |
Step 1: Area formula is width × height.
Step 2: 11 × 17 = 187
|
35+ 50 = 85
| 85 |
Step 1: Compute 35 + 50.
Step 2: The result is 85.
|
9 ** 4 = 6561
| 6,561 |
Step 1: Compute 9 ** 4.
Step 2: The result is 6561.
|
area of circlewithradius 2= 12.57
| 12.57 |
Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57
|
(20) %(10)=0
| 0 |
Step 1: Compute 20 % 10.
Step 2: The result is 0.
|
3 ** 4=81
| 81 |
Step 1: Compute 3 ** 4.
Step 2: The result is 81.
|
hypotenuse of righttrianglewith legs 30 and 28 =41.04
| 41.04 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(30² + 28²) = sqrt(900 + 784) = sqrt(1684) = 41.04
|
(36) % 5=1
| 1 |
Step 1: Compute 36 % 5.
Step 2: The result is 1.
|
(98) * (83)= 8134
| 8,134 |
Step 1: Compute 98 * 83.
Step 2: The result is 8134.
|
perimeter of triangle with sides 34, 20,6 = 60
| 60 |
Step 1: Perimeter formula is a + b + c.
Step 2: 34 + 20 + 6 = 60
|
perimeter of triangle with sides 5, 30,46 =81
| 81 |
Step 1: Perimeter formula is a + b + c.
Step 2: 5 + 30 + 46 = 81
|
perimeterof circle withradius 9= 56.55
| 56.55 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 9 = 56.55
|
perimeter ofrectangle with width 12 and height 36= 96
| 96 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (12 + 36) = 2 × 48 = 96
|
4** (3) =64
| 64 |
Step 1: Compute 4 ** 3.
Step 2: The result is 64.
|
60/ (6) = 10
| 10 |
Step 1: Compute 60 / 6.
Step 2: The result is 10.
|
hypotenuse ofright triangle with legs29 and 1= 29.02
| 29.02 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(29² + 1²) = sqrt(841 + 1) = sqrt(842) = 29.02
|
perimeteroftrianglewith sides 47, 17, 2 =66
| 66 |
Step 1: Perimeter formula is a + b + c.
Step 2: 47 + 17 + 2 = 66
|
perimeter of trianglewith sides 49,8, 12 = 69
| 69 |
Step 1: Perimeter formula is a + b + c.
Step 2: 49 + 8 + 12 = 69
|
perimeterof triangle with sides17, 41,15= 73
| 73 |
Step 1: Perimeter formula is a + b + c.
Step 2: 17 + 41 + 15 = 73
|
63 + (55) = 118
| 118 |
Step 1: Compute 63 + 55.
Step 2: The result is 118.
|
(59) %2 = 1
| 1 |
Step 1: Compute 59 % 2.
Step 2: The result is 1.
|
42 -57= -15
| -15 |
Step 1: Compute 42 - 57.
Step 2: The result is -15.
|
areaof circle with radius 13 = 530.93
| 530.93 |
Step 1: Area formula is π × r².
Step 2: π × 13² = 3.14 × 169 = 530.93
|
perimeter of circle withradius 18 = 113.10
| 113.1 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 18 = 113.10
|
perimeterof circle withradius15 = 94.25
| 94.25 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 15 = 94.25
|
perimeter of circle withradius 8 =50.27
| 50.27 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27
|
area ofcircle with radius 13 = 530.93
| 530.93 |
Step 1: Area formula is π × r².
Step 2: π × 13² = 3.14 × 169 = 530.93
|
(78) / 13 = 6
| 6 |
Step 1: Compute 78 / 13.
Step 2: The result is 6.
|
74 -(61) =13
| 13 |
Step 1: Compute 74 - 61.
Step 2: The result is 13.
|
perimeterof triangle with sides 5, 21,42 = 68
| 68 |
Step 1: Perimeter formula is a + b + c.
Step 2: 5 + 21 + 42 = 68
|
40 %13= 1
| 1 |
Step 1: Compute 40 % 13.
Step 2: The result is 1.
|
50 + 75 = 125
| 125 |
Step 1: Compute 50 + 75.
Step 2: The result is 125.
|
area of rectanglewith width 26and height 44 =1144
| 1,144 |
Step 1: Area formula is width × height.
Step 2: 26 × 44 = 1144
|
perimeter of circlewith radius11 = 69.12
| 69.12 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 11 = 69.12
|
area of circle with radius 4= 50.27
| 50.27 |
Step 1: Area formula is π × r².
Step 2: π × 4² = 3.14 × 16 = 50.27
|
area of rectangle with width49 and height 24 = 1176
| 1,176 |
Step 1: Area formula is width × height.
Step 2: 49 × 24 = 1176
|
(10)** 3=1000
| 1,000 |
Step 1: Compute 10 ** 3.
Step 2: The result is 1000.
|
54 + 89=143
| 143 |
Step 1: Compute 54 + 89.
Step 2: The result is 143.
|
perimeter oftriangle withsides 31, 38, 20 = 89
| 89 |
Step 1: Perimeter formula is a + b + c.
Step 2: 31 + 38 + 20 = 89
|
perimeter of rectangle with width 15and height18 =66
| 66 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (15 + 18) = 2 × 33 = 66
|
area ofrectanglewithwidth 37 and height 37 = 1369
| 1,369 |
Step 1: Area formula is width × height.
Step 2: 37 × 37 = 1369
|
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