Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
24/ 3 = 8
| 8 |
Step 1: Compute 24 / 3.
Step 2: The result is 8.
|
(14) + 36 = 50
| 50 |
Step 1: Compute 14 + 36.
Step 2: The result is 50.
|
6 **2 =36
| 36 |
Step 1: Compute 6 ** 2.
Step 2: The result is 36.
|
(95)* 74= 7030
| 7,030 |
Step 1: Compute 95 * 74.
Step 2: The result is 7030.
|
71 % 3 =2
| 2 |
Step 1: Compute 71 % 3.
Step 2: The result is 2.
|
perimeter of circle with radius 5 = 31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
hypotenuseof right triangle with legs29 and 16 =33.12
| 33.12 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(29² + 16²) = sqrt(841 + 256) = sqrt(1097) = 33.12
|
23 * (99)= 2277
| 2,277 |
Step 1: Compute 23 * 99.
Step 2: The result is 2277.
|
(7)/ 7 =1
| 1 |
Step 1: Compute 7 / 7.
Step 2: The result is 1.
|
area ofrectangle with width 12 and height13= 156
| 156 |
Step 1: Area formula is width × height.
Step 2: 12 × 13 = 156
|
areaofcircle withradius 3 =28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
(18) * (18) = 324
| 324 |
Step 1: Compute 18 * 18.
Step 2: The result is 324.
|
area oftrianglewithbase13 and height 24 = 156.00
| 156 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 13 × 24 = 156.00
|
perimeter of circle with radius15 =94.25
| 94.25 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 15 = 94.25
|
area of rectangle with width 30 andheight 10 = 300
| 300 |
Step 1: Area formula is width × height.
Step 2: 30 × 10 = 300
|
94 - (84) = 10
| 10 |
Step 1: Compute 94 - 84.
Step 2: The result is 10.
|
perimeter ofrectangle with width 14and height27= 82
| 82 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (14 + 27) = 2 × 41 = 82
|
52 % 8 = 4
| 4 |
Step 1: Compute 52 % 8.
Step 2: The result is 4.
|
perimeter ofrectanglewith width 39 and height 50= 178
| 178 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (39 + 50) = 2 × 89 = 178
|
(23) - (95) =-72
| -72 |
Step 1: Compute 23 - 95.
Step 2: The result is -72.
|
(21) * 8 =168
| 168 |
Step 1: Compute 21 * 8.
Step 2: The result is 168.
|
perimeterof rectanglewith width 43 and height 34= 154
| 154 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (43 + 34) = 2 × 77 = 154
|
43 %17= 9
| 9 |
Step 1: Compute 43 % 17.
Step 2: The result is 9.
|
perimeterofrectangle withwidth 20 and height 41 = 122
| 122 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (20 + 41) = 2 × 61 = 122
|
14 +(93) = 107
| 107 |
Step 1: Compute 14 + 93.
Step 2: The result is 107.
|
(5)** 2 =25
| 25 |
Step 1: Compute 5 ** 2.
Step 2: The result is 25.
|
10* (66) = 660
| 660 |
Step 1: Compute 10 * 66.
Step 2: The result is 660.
|
40 * 38= 1520
| 1,520 |
Step 1: Compute 40 * 38.
Step 2: The result is 1520.
|
perimeteroftrianglewithsides 37, 23, 4 = 64
| 64 |
Step 1: Perimeter formula is a + b + c.
Step 2: 37 + 23 + 4 = 64
|
perimeter ofcircle with radius 15= 94.25
| 94.25 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 15 = 94.25
|
areaofrectangle with width8 and height36= 288
| 288 |
Step 1: Area formula is width × height.
Step 2: 8 × 36 = 288
|
29 + (42) =71
| 71 |
Step 1: Compute 29 + 42.
Step 2: The result is 71.
|
22- 51= -29
| -29 |
Step 1: Compute 22 - 51.
Step 2: The result is -29.
|
96 * 72= 6912
| 6,912 |
Step 1: Compute 96 * 72.
Step 2: The result is 6912.
|
(12)/ 2 = 6
| 6 |
Step 1: Compute 12 / 2.
Step 2: The result is 6.
|
perimeter of circle with radius 16= 100.53
| 100.53 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 16 = 100.53
|
35 % 12 =11
| 11 |
Step 1: Compute 35 % 12.
Step 2: The result is 11.
|
(23)* 87=2001
| 2,001 |
Step 1: Compute 23 * 87.
Step 2: The result is 2001.
|
areaof circlewith radius 16 = 804.25
| 804.25 |
Step 1: Area formula is π × r².
Step 2: π × 16² = 3.14 × 256 = 804.25
|
perimeterofcircle with radius11=69.12
| 69.12 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 11 = 69.12
|
8 / 2 = 4
| 4 |
Step 1: Compute 8 / 2.
Step 2: The result is 4.
|
areaof trianglewithbase46and height 48 =1104.00
| 1,104 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 46 × 48 = 1104.00
|
hypotenuse ofrighttriangle with legs26and 4 = 26.31
| 26.31 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(26² + 4²) = sqrt(676 + 16) = sqrt(692) = 26.31
|
area of triangle with base41 and height41= 840.50
| 840.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 41 × 41 = 840.50
|
42 %(1)=0
| 0 |
Step 1: Compute 42 % 1.
Step 2: The result is 0.
|
45 * (68) = 3060
| 3,060 |
Step 1: Compute 45 * 68.
Step 2: The result is 3060.
|
(4) **2= 16
| 16 |
Step 1: Compute 4 ** 2.
Step 2: The result is 16.
|
60%(3) = 0
| 0 |
Step 1: Compute 60 % 3.
Step 2: The result is 0.
|
63 % 7 =0
| 0 |
Step 1: Compute 63 % 7.
Step 2: The result is 0.
|
area ofrectangle with width 39 and height18= 702
| 702 |
Step 1: Area formula is width × height.
Step 2: 39 × 18 = 702
|
area of triangle withbase 3 andheight 24 = 36.00
| 36 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 3 × 24 = 36.00
|
2** 2 = 4
| 4 |
Step 1: Compute 2 ** 2.
Step 2: The result is 4.
|
area ofcircle with radius 2=12.57
| 12.57 |
Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57
|
3**3 =27
| 27 |
Step 1: Compute 3 ** 3.
Step 2: The result is 27.
|
40/(8) = 5
| 5 |
Step 1: Compute 40 / 8.
Step 2: The result is 5.
|
12 + (26)=38
| 38 |
Step 1: Compute 12 + 26.
Step 2: The result is 38.
|
perimeter of triangle with sides9, 44, 45 = 98
| 98 |
Step 1: Perimeter formula is a + b + c.
Step 2: 9 + 44 + 45 = 98
|
(6) **(4)= 1296
| 1,296 |
Step 1: Compute 6 ** 4.
Step 2: The result is 1296.
|
areaofcircle with radius 12 =452.39
| 452.39 |
Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39
|
2** 2 =4
| 4 |
Step 1: Compute 2 ** 2.
Step 2: The result is 4.
|
10 ** (4) = 10000
| 10,000 |
Step 1: Compute 10 ** 4.
Step 2: The result is 10000.
|
area of circle with radius12= 452.39
| 452.39 |
Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39
|
5** 3 = 125
| 125 |
Step 1: Compute 5 ** 3.
Step 2: The result is 125.
|
perimeterofcirclewith radius 6=37.70
| 37.7 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 6 = 37.70
|
24 %17 = 7
| 7 |
Step 1: Compute 24 % 17.
Step 2: The result is 7.
|
areaof rectanglewithwidth 22 andheight9 =198
| 198 |
Step 1: Area formula is width × height.
Step 2: 22 × 9 = 198
|
hypotenuse ofright trianglewith legs 27 and 18 = 32.45
| 32.45 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(27² + 18²) = sqrt(729 + 324) = sqrt(1053) = 32.45
|
8 ** 4 = 4096
| 4,096 |
Step 1: Compute 8 ** 4.
Step 2: The result is 4096.
|
perimeter of circle withradius 10 =62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
180 / 18 = 10
| 10 |
Step 1: Compute 180 / 18.
Step 2: The result is 10.
|
9**4=6561
| 6,561 |
Step 1: Compute 9 ** 4.
Step 2: The result is 6561.
|
area of circle with radius 11= 380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
56 %1 =0
| 0 |
Step 1: Compute 56 % 1.
Step 2: The result is 0.
|
(40) %(16) = 8
| 8 |
Step 1: Compute 40 % 16.
Step 2: The result is 8.
|
1**4 =1
| 1 |
Step 1: Compute 1 ** 4.
Step 2: The result is 1.
|
(4) -(34) =-30
| -30 |
Step 1: Compute 4 - 34.
Step 2: The result is -30.
|
area ofcircle withradius 12 =452.39
| 452.39 |
Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39
|
perimeter of rectangle with width1 and height 44 =90
| 90 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (1 + 44) = 2 × 45 = 90
|
(24)+ 16 =40
| 40 |
Step 1: Compute 24 + 16.
Step 2: The result is 40.
|
(5) ** 4 =625
| 625 |
Step 1: Compute 5 ** 4.
Step 2: The result is 625.
|
(22) + 98 = 120
| 120 |
Step 1: Compute 22 + 98.
Step 2: The result is 120.
|
area of triangle withbase28 and height 30 = 420.00
| 420 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 28 × 30 = 420.00
|
(82) +(48)=130
| 130 |
Step 1: Compute 82 + 48.
Step 2: The result is 130.
|
perimeter of rectanglewith width 37and height3 = 80
| 80 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (37 + 3) = 2 × 40 = 80
|
perimeter of circle withradius 3 =18.85
| 18.85 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85
|
27 + (43) = 70
| 70 |
Step 1: Compute 27 + 43.
Step 2: The result is 70.
|
area of rectanglewithwidth 26 and height 46 = 1196
| 1,196 |
Step 1: Area formula is width × height.
Step 2: 26 × 46 = 1196
|
32 * 93 = 2976
| 2,976 |
Step 1: Compute 32 * 93.
Step 2: The result is 2976.
|
area ofrectangle with width41 andheight 44 = 1804
| 1,804 |
Step 1: Area formula is width × height.
Step 2: 41 × 44 = 1804
|
perimeterofrectangle with width 24 andheight 13 = 74
| 74 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (24 + 13) = 2 × 37 = 74
|
(61)% (11) = 6
| 6 |
Step 1: Compute 61 % 11.
Step 2: The result is 6.
|
perimeter of triangle with sides 3, 6, 27= 36
| 36 |
Step 1: Perimeter formula is a + b + c.
Step 2: 3 + 6 + 27 = 36
|
144/18= 8
| 8 |
Step 1: Compute 144 / 18.
Step 2: The result is 8.
|
67 % 6 = 1
| 1 |
Step 1: Compute 67 % 6.
Step 2: The result is 1.
|
3 ** 3=27
| 27 |
Step 1: Compute 3 ** 3.
Step 2: The result is 27.
|
(99) + 22= 121
| 121 |
Step 1: Compute 99 + 22.
Step 2: The result is 121.
|
area of circlewithradius14=615.75
| 615.75 |
Step 1: Area formula is π × r².
Step 2: π × 14² = 3.14 × 196 = 615.75
|
area of rectangle with width 8and height 22 = 176
| 176 |
Step 1: Area formula is width × height.
Step 2: 8 × 22 = 176
|
perimeter of rectangle withwidth 7 andheight42 = 98
| 98 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (7 + 42) = 2 × 49 = 98
|
(32) %4 = 0
| 0 |
Step 1: Compute 32 % 4.
Step 2: The result is 0.
|
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