Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
48 -19 =29
| 29 |
Step 1: Compute 48 - 19.
Step 2: The result is 29.
|
2**3=8
| 8 |
Step 1: Compute 2 ** 3.
Step 2: The result is 8.
|
area ofcircle withradius 1= 3.14
| 3.14 |
Step 1: Area formula is π × r².
Step 2: π × 1² = 3.14 × 1 = 3.14
|
133 /(19) = 7
| 7 |
Step 1: Compute 133 / 19.
Step 2: The result is 7.
|
9**(3) = 729
| 729 |
Step 1: Compute 9 ** 3.
Step 2: The result is 729.
|
hypotenuse ofrighttriangle with legs 4 and 11=11.70
| 11.7 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(4² + 11²) = sqrt(16 + 121) = sqrt(137) = 11.70
|
hypotenuseof righttriangle with legs 30 and 24 = 38.42
| 38.42 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(30² + 24²) = sqrt(900 + 576) = sqrt(1476) = 38.42
|
perimeterof circle with radius 7=43.98
| 43.98 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 7 = 43.98
|
(55)+ (85)= 140
| 140 |
Step 1: Compute 55 + 85.
Step 2: The result is 140.
|
perimeterof circlewithradius 5 = 31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
area of circlewithradius19= 1134.11
| 1,134.11 |
Step 1: Area formula is π × r².
Step 2: π × 19² = 3.14 × 361 = 1134.11
|
hypotenuse of right trianglewith legs16 and27 = 31.38
| 31.38 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(16² + 27²) = sqrt(256 + 729) = sqrt(985) = 31.38
|
77 -(73) = 4
| 4 |
Step 1: Compute 77 - 73.
Step 2: The result is 4.
|
area of trianglewith base 43 and height 20= 430.00
| 430 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 43 × 20 = 430.00
|
perimeter of rectangle withwidth 45and height 21=132
| 132 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (45 + 21) = 2 × 66 = 132
|
areaof trianglewith base 25andheight 37= 462.50
| 462.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 25 × 37 = 462.50
|
14 + 96 = 110
| 110 |
Step 1: Compute 14 + 96.
Step 2: The result is 110.
|
73+ (97) =170
| 170 |
Step 1: Compute 73 + 97.
Step 2: The result is 170.
|
144 / 18= 8
| 8 |
Step 1: Compute 144 / 18.
Step 2: The result is 8.
|
79%18=7
| 7 |
Step 1: Compute 79 % 18.
Step 2: The result is 7.
|
perimeter ofrectangle withwidth5and height 17 =44
| 44 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (5 + 17) = 2 × 22 = 44
|
perimeter of circle with radius12 =75.40
| 75.4 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 12 = 75.40
|
87 -91=-4
| -4 |
Step 1: Compute 87 - 91.
Step 2: The result is -4.
|
48 %6 =0
| 0 |
Step 1: Compute 48 % 6.
Step 2: The result is 0.
|
25 -(99) = -74
| -74 |
Step 1: Compute 25 - 99.
Step 2: The result is -74.
|
perimeter of rectangle withwidth 29and height 23 = 104
| 104 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (29 + 23) = 2 × 52 = 104
|
(4) ** (3)= 64
| 64 |
Step 1: Compute 4 ** 3.
Step 2: The result is 64.
|
area of rectangle with width 27and height 35 = 945
| 945 |
Step 1: Area formula is width × height.
Step 2: 27 × 35 = 945
|
(54) *(80)= 4320
| 4,320 |
Step 1: Compute 54 * 80.
Step 2: The result is 4320.
|
hypotenuse of right triangle with legs 18and 22 =28.43
| 28.43 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(18² + 22²) = sqrt(324 + 484) = sqrt(808) = 28.43
|
perimeterofrectangle with width34andheight 14 =96
| 96 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (34 + 14) = 2 × 48 = 96
|
(1)** (3)=1
| 1 |
Step 1: Compute 1 ** 3.
Step 2: The result is 1.
|
area of circle with radius19 =1134.11
| 1,134.11 |
Step 1: Area formula is π × r².
Step 2: π × 19² = 3.14 × 361 = 1134.11
|
12 - (35) = -23
| -23 |
Step 1: Compute 12 - 35.
Step 2: The result is -23.
|
37+(28) = 65
| 65 |
Step 1: Compute 37 + 28.
Step 2: The result is 65.
|
94*(16)=1504
| 1,504 |
Step 1: Compute 94 * 16.
Step 2: The result is 1504.
|
97 % 19 = 2
| 2 |
Step 1: Compute 97 % 19.
Step 2: The result is 2.
|
60 % 18 = 6
| 6 |
Step 1: Compute 60 % 18.
Step 2: The result is 6.
|
(1) ** 3=1
| 1 |
Step 1: Compute 1 ** 3.
Step 2: The result is 1.
|
57- (81) = -24
| -24 |
Step 1: Compute 57 - 81.
Step 2: The result is -24.
|
perimeterof rectangle withwidth 29 andheight 3= 64
| 64 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (29 + 3) = 2 × 32 = 64
|
9 ** 4 = 6561
| 6,561 |
Step 1: Compute 9 ** 4.
Step 2: The result is 6561.
|
60 /(10)= 6
| 6 |
Step 1: Compute 60 / 10.
Step 2: The result is 6.
|
perimeter ofrectangle with width 31and height18=98
| 98 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (31 + 18) = 2 × 49 = 98
|
43 %19 = 5
| 5 |
Step 1: Compute 43 % 19.
Step 2: The result is 5.
|
99* 22 = 2178
| 2,178 |
Step 1: Compute 99 * 22.
Step 2: The result is 2178.
|
(50) + 29 =79
| 79 |
Step 1: Compute 50 + 29.
Step 2: The result is 79.
|
hypotenuseof righttriangle withlegs 20and 24 = 31.24
| 31.24 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(20² + 24²) = sqrt(400 + 576) = sqrt(976) = 31.24
|
perimeterof circle with radius 10= 62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
areaofcircle with radius 6=113.10
| 113.1 |
Step 1: Area formula is π × r².
Step 2: π × 6² = 3.14 × 36 = 113.10
|
58 + 32 = 90
| 90 |
Step 1: Compute 58 + 32.
Step 2: The result is 90.
|
56/(7)= 8
| 8 |
Step 1: Compute 56 / 7.
Step 2: The result is 8.
|
75 % 5 = 0
| 0 |
Step 1: Compute 75 % 5.
Step 2: The result is 0.
|
area of rectangle with width17 and height6 = 102
| 102 |
Step 1: Area formula is width × height.
Step 2: 17 × 6 = 102
|
65- 10 = 55
| 55 |
Step 1: Compute 65 - 10.
Step 2: The result is 55.
|
hypotenuseof right triangle with legs12 and 9= 15.00
| 15 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(12² + 9²) = sqrt(144 + 81) = sqrt(225) = 15.00
|
1 * 2= 2
| 2 |
Step 1: Compute 1 * 2.
Step 2: The result is 2.
|
area of triangle withbase35 and height 2 =35.00
| 35 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 35 × 2 = 35.00
|
perimeter ofcircle with radius 5 =31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
(31) -(2) =29
| 29 |
Step 1: Compute 31 - 2.
Step 2: The result is 29.
|
areaof triangle withbase 25 andheight 22 = 275.00
| 275 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 25 × 22 = 275.00
|
perimeter of rectanglewith width12and height 33 =90
| 90 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (12 + 33) = 2 × 45 = 90
|
perimeterofcircle with radius 4 = 25.13
| 25.13 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 4 = 25.13
|
area ofcirclewith radius17= 907.92
| 907.92 |
Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92
|
10/ 2 = 5
| 5 |
Step 1: Compute 10 / 2.
Step 2: The result is 5.
|
17- 68= -51
| -51 |
Step 1: Compute 17 - 68.
Step 2: The result is -51.
|
perimeteroftrianglewith sides 49, 49,16= 114
| 114 |
Step 1: Perimeter formula is a + b + c.
Step 2: 49 + 49 + 16 = 114
|
perimeter of rectangle with width39 and height 23 = 124
| 124 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (39 + 23) = 2 × 62 = 124
|
areaof rectangle with width 11and height 6 = 66
| 66 |
Step 1: Area formula is width × height.
Step 2: 11 × 6 = 66
|
14 % (13) = 1
| 1 |
Step 1: Compute 14 % 13.
Step 2: The result is 1.
|
hypotenuse of righttrianglewith legs 27 and28= 38.90
| 38.9 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(27² + 28²) = sqrt(729 + 784) = sqrt(1513) = 38.90
|
areaof circlewith radius15 = 706.86
| 706.86 |
Step 1: Area formula is π × r².
Step 2: π × 15² = 3.14 × 225 = 706.86
|
47 -78 = -31
| -31 |
Step 1: Compute 47 - 78.
Step 2: The result is -31.
|
36 + 67 = 103
| 103 |
Step 1: Compute 36 + 67.
Step 2: The result is 103.
|
hypotenuseofright triangle with legs 8 and 21 = 22.47
| 22.47 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(8² + 21²) = sqrt(64 + 441) = sqrt(505) = 22.47
|
perimeteroftrianglewith sides 42, 40,27 = 109
| 109 |
Step 1: Perimeter formula is a + b + c.
Step 2: 42 + 40 + 27 = 109
|
perimeter of trianglewith sides 10,42,5= 57
| 57 |
Step 1: Perimeter formula is a + b + c.
Step 2: 10 + 42 + 5 = 57
|
38 % 1 =0
| 0 |
Step 1: Compute 38 % 1.
Step 2: The result is 0.
|
perimeter of circle withradius 14= 87.96
| 87.96 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 14 = 87.96
|
perimeter of trianglewithsides41,44, 5 = 90
| 90 |
Step 1: Perimeter formula is a + b + c.
Step 2: 41 + 44 + 5 = 90
|
25%18=7
| 7 |
Step 1: Compute 25 % 18.
Step 2: The result is 7.
|
(2) - 71 =-69
| -69 |
Step 1: Compute 2 - 71.
Step 2: The result is -69.
|
perimeter ofrectangle withwidth3 andheight7 = 20
| 20 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (3 + 7) = 2 × 10 = 20
|
7 **(4) =2401
| 2,401 |
Step 1: Compute 7 ** 4.
Step 2: The result is 2401.
|
(55) +6 = 61
| 61 |
Step 1: Compute 55 + 6.
Step 2: The result is 61.
|
119/ (17) = 7
| 7 |
Step 1: Compute 119 / 17.
Step 2: The result is 7.
|
perimeterof circle with radius11=69.12
| 69.12 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 11 = 69.12
|
(93)- 68 = 25
| 25 |
Step 1: Compute 93 - 68.
Step 2: The result is 25.
|
areaof rectangle with width4 and height 9= 36
| 36 |
Step 1: Area formula is width × height.
Step 2: 4 × 9 = 36
|
36/ 6 = 6
| 6 |
Step 1: Compute 36 / 6.
Step 2: The result is 6.
|
area of trianglewithbase 7and height 44=154.00
| 154 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 7 × 44 = 154.00
|
area of triangle with base 40 andheight49 =980.00
| 980 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 40 × 49 = 980.00
|
perimeter of triangle withsides 30, 43, 1 =74
| 74 |
Step 1: Perimeter formula is a + b + c.
Step 2: 30 + 43 + 1 = 74
|
70 *8=560
| 560 |
Step 1: Compute 70 * 8.
Step 2: The result is 560.
|
areaof rectangle withwidth18 and height18 = 324
| 324 |
Step 1: Area formula is width × height.
Step 2: 18 × 18 = 324
|
perimeter of trianglewithsides49, 42, 6 = 97
| 97 |
Step 1: Perimeter formula is a + b + c.
Step 2: 49 + 42 + 6 = 97
|
(6)+ (67)= 73
| 73 |
Step 1: Compute 6 + 67.
Step 2: The result is 73.
|
4 **2 = 16
| 16 |
Step 1: Compute 4 ** 2.
Step 2: The result is 16.
|
perimeterof rectangle with width 29 and height 45 = 148
| 148 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (29 + 45) = 2 × 74 = 148
|
33% (2) = 1
| 1 |
Step 1: Compute 33 % 2.
Step 2: The result is 1.
|
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