Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
(18) % 15 = 3
| 3 |
Step 1: Compute 18 % 15.
Step 2: The result is 3.
|
70 - 84 =-14
| -14 |
Step 1: Compute 70 - 84.
Step 2: The result is -14.
|
81+ (13) =94
| 94 |
Step 1: Compute 81 + 13.
Step 2: The result is 94.
|
perimeterof circle withradius 3= 18.85
| 18.85 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85
|
63 + 85 =148
| 148 |
Step 1: Compute 63 + 85.
Step 2: The result is 148.
|
areaof circlewith radius 3 =28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
(9) **3= 729
| 729 |
Step 1: Compute 9 ** 3.
Step 2: The result is 729.
|
(71) % (14)= 1
| 1 |
Step 1: Compute 71 % 14.
Step 2: The result is 1.
|
(2) ** 3 = 8
| 8 |
Step 1: Compute 2 ** 3.
Step 2: The result is 8.
|
(90) - (7) = 83
| 83 |
Step 1: Compute 90 - 7.
Step 2: The result is 83.
|
(69) +(21) = 90
| 90 |
Step 1: Compute 69 + 21.
Step 2: The result is 90.
|
55 + 17 = 72
| 72 |
Step 1: Compute 55 + 17.
Step 2: The result is 72.
|
hypotenuseof right triangle withlegs21 and 20 = 29.00
| 29 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(21² + 20²) = sqrt(441 + 400) = sqrt(841) = 29.00
|
area ofcircle with radius 5= 78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
area ofcircle with radius 3 =28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
53-(79)=-26
| -26 |
Step 1: Compute 53 - 79.
Step 2: The result is -26.
|
area of circle with radius 17 =907.92
| 907.92 |
Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92
|
hypotenuse ofright trianglewith legs 1 and 11 = 11.05
| 11.05 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(1² + 11²) = sqrt(1 + 121) = sqrt(122) = 11.05
|
areaofcirclewithradius 15 = 706.86
| 706.86 |
Step 1: Area formula is π × r².
Step 2: π × 15² = 3.14 × 225 = 706.86
|
(30) % 10 =0
| 0 |
Step 1: Compute 30 % 10.
Step 2: The result is 0.
|
perimeterof triangle with sides 4, 2, 3 = 9
| 9 |
Step 1: Perimeter formula is a + b + c.
Step 2: 4 + 2 + 3 = 9
|
perimeter of circle with radius6 = 37.70
| 37.7 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 6 = 37.70
|
perimeterof trianglewithsides28, 25, 29=82
| 82 |
Step 1: Perimeter formula is a + b + c.
Step 2: 28 + 25 + 29 = 82
|
180 / 18=10
| 10 |
Step 1: Compute 180 / 18.
Step 2: The result is 10.
|
44 - (100)= -56
| -56 |
Step 1: Compute 44 - 100.
Step 2: The result is -56.
|
perimeter of triangle with sides 47, 34,23 =104
| 104 |
Step 1: Perimeter formula is a + b + c.
Step 2: 47 + 34 + 23 = 104
|
92+10 =102
| 102 |
Step 1: Compute 92 + 10.
Step 2: The result is 102.
|
(5) ** (3)= 125
| 125 |
Step 1: Compute 5 ** 3.
Step 2: The result is 125.
|
perimeterof circle with radius 5=31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
57* 72= 4104
| 4,104 |
Step 1: Compute 57 * 72.
Step 2: The result is 4104.
|
91-52= 39
| 39 |
Step 1: Compute 91 - 52.
Step 2: The result is 39.
|
(4) / 1=4
| 4 |
Step 1: Compute 4 / 1.
Step 2: The result is 4.
|
areaofcirclewith radius 5 = 78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
perimeterof circlewith radius5 = 31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
area of circle withradius10= 314.16
| 314.16 |
Step 1: Area formula is π × r².
Step 2: π × 10² = 3.14 × 100 = 314.16
|
65 * 45=2925
| 2,925 |
Step 1: Compute 65 * 45.
Step 2: The result is 2925.
|
49 + 90 =139
| 139 |
Step 1: Compute 49 + 90.
Step 2: The result is 139.
|
(85) % (8)= 5
| 5 |
Step 1: Compute 85 % 8.
Step 2: The result is 5.
|
area of circle with radius 18 =1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
areaofrectangle withwidth5 and height3 = 15
| 15 |
Step 1: Area formula is width × height.
Step 2: 5 × 3 = 15
|
4 ** 2= 16
| 16 |
Step 1: Compute 4 ** 2.
Step 2: The result is 16.
|
(14) -88 =-74
| -74 |
Step 1: Compute 14 - 88.
Step 2: The result is -74.
|
perimeter of rectangle withwidth 38 andheight 36= 148
| 148 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (38 + 36) = 2 × 74 = 148
|
(40) / (4) = 10
| 10 |
Step 1: Compute 40 / 4.
Step 2: The result is 10.
|
perimeter of rectangle with width 44 andheight 6 = 100
| 100 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (44 + 6) = 2 × 50 = 100
|
(77) * 73 =5621
| 5,621 |
Step 1: Compute 77 * 73.
Step 2: The result is 5621.
|
15 /15 = 1
| 1 |
Step 1: Compute 15 / 15.
Step 2: The result is 1.
|
89*31 = 2759
| 2,759 |
Step 1: Compute 89 * 31.
Step 2: The result is 2759.
|
perimeter of rectanglewith width 30 and height 36 =132
| 132 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (30 + 36) = 2 × 66 = 132
|
(100) / (20) =5
| 5 |
Step 1: Compute 100 / 20.
Step 2: The result is 5.
|
3**(2)= 9
| 9 |
Step 1: Compute 3 ** 2.
Step 2: The result is 9.
|
hypotenuse of righttriangle withlegs 13 and20 = 23.85
| 23.85 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(13² + 20²) = sqrt(169 + 400) = sqrt(569) = 23.85
|
(39) *(97) = 3783
| 3,783 |
Step 1: Compute 39 * 97.
Step 2: The result is 3783.
|
(2)** 4 = 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
area ofrectanglewith width 5 and height41 = 205
| 205 |
Step 1: Area formula is width × height.
Step 2: 5 × 41 = 205
|
(52) * (32) = 1664
| 1,664 |
Step 1: Compute 52 * 32.
Step 2: The result is 1664.
|
hypotenuse of right trianglewith legs 13 and16 =20.62
| 20.62 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(13² + 16²) = sqrt(169 + 256) = sqrt(425) = 20.62
|
areaof circle withradius 2= 12.57
| 12.57 |
Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57
|
51+ (79) = 130
| 130 |
Step 1: Compute 51 + 79.
Step 2: The result is 130.
|
perimeter of rectangle with width 20 andheight 32= 104
| 104 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (20 + 32) = 2 × 52 = 104
|
perimeter of circlewith radius20= 125.66
| 125.66 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 20 = 125.66
|
(6) ** 4 =1296
| 1,296 |
Step 1: Compute 6 ** 4.
Step 2: The result is 1296.
|
20/4 = 5
| 5 |
Step 1: Compute 20 / 4.
Step 2: The result is 5.
|
area of circlewithradius17= 907.92
| 907.92 |
Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92
|
area ofrectangle with width 42 andheight 49 = 2058
| 2,058 |
Step 1: Area formula is width × height.
Step 2: 42 × 49 = 2058
|
5 **(3)=125
| 125 |
Step 1: Compute 5 ** 3.
Step 2: The result is 125.
|
58 +100 =158
| 158 |
Step 1: Compute 58 + 100.
Step 2: The result is 158.
|
area oftriangle with base15and height19 = 142.50
| 142.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 15 × 19 = 142.50
|
perimeterof triangle with sides24, 2, 26 = 52
| 52 |
Step 1: Perimeter formula is a + b + c.
Step 2: 24 + 2 + 26 = 52
|
65 -62 =3
| 3 |
Step 1: Compute 65 - 62.
Step 2: The result is 3.
|
73 + (24)= 97
| 97 |
Step 1: Compute 73 + 24.
Step 2: The result is 97.
|
perimeterof circle with radius 8 = 50.27
| 50.27 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27
|
areaofcircle with radius 18 = 1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
hypotenuse of right triangle with legs17 and29 = 33.62
| 33.62 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(17² + 29²) = sqrt(289 + 841) = sqrt(1130) = 33.62
|
perimeterof circle with radius 2=12.57
| 12.57 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 2 = 12.57
|
perimeter of rectangle with width 21 and height 28 =98
| 98 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (21 + 28) = 2 × 49 = 98
|
(31) +(30) = 61
| 61 |
Step 1: Compute 31 + 30.
Step 2: The result is 61.
|
area of circle withradius 11 = 380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
area ofcirclewithradius 11 = 380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
(15) * 97 =1455
| 1,455 |
Step 1: Compute 15 * 97.
Step 2: The result is 1455.
|
63% 20 = 3
| 3 |
Step 1: Compute 63 % 20.
Step 2: The result is 3.
|
perimeter of trianglewith sides 14, 35,3= 52
| 52 |
Step 1: Perimeter formula is a + b + c.
Step 2: 14 + 35 + 3 = 52
|
area of circle with radius 8 =201.06
| 201.06 |
Step 1: Area formula is π × r².
Step 2: π × 8² = 3.14 × 64 = 201.06
|
(77)% 13 = 12
| 12 |
Step 1: Compute 77 % 13.
Step 2: The result is 12.
|
area of rectangle withwidth39 and height36=1404
| 1,404 |
Step 1: Area formula is width × height.
Step 2: 39 × 36 = 1404
|
71 - 6 = 65
| 65 |
Step 1: Compute 71 - 6.
Step 2: The result is 65.
|
perimeterof trianglewith sides 50, 50, 23 =123
| 123 |
Step 1: Perimeter formula is a + b + c.
Step 2: 50 + 50 + 23 = 123
|
perimeterofcircle with radius2 = 12.57
| 12.57 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 2 = 12.57
|
area of triangle withbase20 and height 18= 180.00
| 180 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 20 × 18 = 180.00
|
74% 7 = 4
| 4 |
Step 1: Compute 74 % 7.
Step 2: The result is 4.
|
areaof triangle with base 39and height19 = 370.50
| 370.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 39 × 19 = 370.50
|
(37) + 32 =69
| 69 |
Step 1: Compute 37 + 32.
Step 2: The result is 69.
|
88 - (69) = 19
| 19 |
Step 1: Compute 88 - 69.
Step 2: The result is 19.
|
perimeterof circle with radius 18= 113.10
| 113.1 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 18 = 113.10
|
60 -(82) = -22
| -22 |
Step 1: Compute 60 - 82.
Step 2: The result is -22.
|
perimeter ofrectanglewith width 22and height 47 = 138
| 138 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (22 + 47) = 2 × 69 = 138
|
area of triangle with base2 and height 29 =29.00
| 29 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 2 × 29 = 29.00
|
(5)/5= 1
| 1 |
Step 1: Compute 5 / 5.
Step 2: The result is 1.
|
68+ (47) =115
| 115 |
Step 1: Compute 68 + 47.
Step 2: The result is 115.
|
70 * (50)= 3500
| 3,500 |
Step 1: Compute 70 * 50.
Step 2: The result is 3500.
|
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