Datasets:
FlameF0X
/
Math-2

Dataset card Data Studio Files
xet
Community
1
Expression
stringlengths
5
66
Result
float64
-99
10k
Steps
stringlengths
47
107
area ofrectangle withwidth 28 and height 37 =1036
1,036
Step 1: Area formula is width × height. Step 2: 28 × 37 = 1036
perimeter oftriangle with sides 36, 12, 23 = 71
71
Step 1: Perimeter formula is a + b + c. Step 2: 36 + 12 + 23 = 71
68 /17= 4
4
Step 1: Compute 68 / 17. Step 2: The result is 4.
perimeter of rectangle withwidth 38and height12 = 100
100
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (38 + 12) = 2 × 50 = 100
(72)*93=6696
6,696
Step 1: Compute 72 * 93. Step 2: The result is 6696.
hypotenuse ofrighttrianglewithlegs 18 and6=18.97
18.97
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(18² + 6²) = sqrt(324 + 36) = sqrt(360) = 18.97
perimeterof triangle with sides23, 50, 15 = 88
88
Step 1: Perimeter formula is a + b + c. Step 2: 23 + 50 + 15 = 88
72 %(2) = 0
0
Step 1: Compute 72 % 2. Step 2: The result is 0.
32 + (53)=85
85
Step 1: Compute 32 + 53. Step 2: The result is 85.
area of rectangle with width38 and height 47=1786
1,786
Step 1: Area formula is width × height. Step 2: 38 × 47 = 1786
perimeter of rectangle withwidth 44and height 7 =102
102
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (44 + 7) = 2 × 51 = 102
12 -10 =2
2
Step 1: Compute 12 - 10. Step 2: The result is 2.
69* (44) = 3036
3,036
Step 1: Compute 69 * 44. Step 2: The result is 3036.
perimeteroftrianglewithsides 8, 21,28= 57
57
Step 1: Perimeter formula is a + b + c. Step 2: 8 + 21 + 28 = 57
area of triangle with base3andheight 39 =58.50
58.5
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 3 × 39 = 58.50
92 + 88 = 180
180
Step 1: Compute 92 + 88. Step 2: The result is 180.
87+(99) = 186
186
Step 1: Compute 87 + 99. Step 2: The result is 186.
83* 75 =6225
6,225
Step 1: Compute 83 * 75. Step 2: The result is 6225.
3 ** 2 = 9
9
Step 1: Compute 3 ** 2. Step 2: The result is 9.
190 / 19 =10
10
Step 1: Compute 190 / 19. Step 2: The result is 10.
perimeterof rectangle with width 23 and height30 = 106
106
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (23 + 30) = 2 × 53 = 106
5+26 = 31
31
Step 1: Compute 5 + 26. Step 2: The result is 31.
19 /19 = 1
1
Step 1: Compute 19 / 19. Step 2: The result is 1.
76- 26 =50
50
Step 1: Compute 76 - 26. Step 2: The result is 50.
2 - 85= -83
-83
Step 1: Compute 2 - 85. Step 2: The result is -83.
perimeter of circle withradius4 = 25.13
25.13
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 4 = 25.13
area of circlewith radius 18 = 1017.88
1,017.88
Step 1: Area formula is π × r². Step 2: π × 18² = 3.14 × 324 = 1017.88
perimeter of trianglewith sides 7, 13, 36 =56
56
Step 1: Perimeter formula is a + b + c. Step 2: 7 + 13 + 36 = 56
94 + 80 = 174
174
Step 1: Compute 94 + 80. Step 2: The result is 174.
areaof circle withradius7=153.94
153.94
Step 1: Area formula is π × r². Step 2: π × 7² = 3.14 × 49 = 153.94
perimeter of triangle with sides 30,3, 27 = 60
60
Step 1: Perimeter formula is a + b + c. Step 2: 30 + 3 + 27 = 60
21/7 = 3
3
Step 1: Compute 21 / 7. Step 2: The result is 3.
perimeterofrectangle with width 34andheight 11 = 90
90
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (34 + 11) = 2 × 45 = 90
perimeter of trianglewith sides 5, 10,31 = 46
46
Step 1: Perimeter formula is a + b + c. Step 2: 5 + 10 + 31 = 46
27+23 = 50
50
Step 1: Compute 27 + 23. Step 2: The result is 50.
areaofrectangle withwidth 1 andheight 30 =30
30
Step 1: Area formula is width × height. Step 2: 1 × 30 = 30
8 / (2) = 4
4
Step 1: Compute 8 / 2. Step 2: The result is 4.
area of triangle withbase32 andheight 20 = 320.00
320
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 32 × 20 = 320.00
areaof circlewith radius 14 =615.75
615.75
Step 1: Area formula is π × r². Step 2: π × 14² = 3.14 × 196 = 615.75
perimeter oftrianglewithsides 35, 44,29 =108
108
Step 1: Perimeter formula is a + b + c. Step 2: 35 + 44 + 29 = 108
93* 88= 8184
8,184
Step 1: Compute 93 * 88. Step 2: The result is 8184.
(75)* 58= 4350
4,350
Step 1: Compute 75 * 58. Step 2: The result is 4350.
area of circle withradius 6 = 113.10
113.1
Step 1: Area formula is π × r². Step 2: π × 6² = 3.14 × 36 = 113.10
38 %17 =4
4
Step 1: Compute 38 % 17. Step 2: The result is 4.
perimeter ofcirclewithradius10=62.83
62.83
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 10 = 62.83
(35)/ 7 = 5
5
Step 1: Compute 35 / 7. Step 2: The result is 5.
hypotenuse ofright trianglewith legs14and 5 = 14.87
14.87
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(14² + 5²) = sqrt(196 + 25) = sqrt(221) = 14.87
(79)-39=40
40
Step 1: Compute 79 - 39. Step 2: The result is 40.
(162) / 18 = 9
9
Step 1: Compute 162 / 18. Step 2: The result is 9.
area of circle withradius 13 = 530.93
530.93
Step 1: Area formula is π × r². Step 2: π × 13² = 3.14 × 169 = 530.93
28 * 8 =224
224
Step 1: Compute 28 * 8. Step 2: The result is 224.
3 ** 4=81
81
Step 1: Compute 3 ** 4. Step 2: The result is 81.
(23)- (77) = -54
-54
Step 1: Compute 23 - 77. Step 2: The result is -54.
9 / (9) =1
1
Step 1: Compute 9 / 9. Step 2: The result is 1.
1 ** (4)= 1
1
Step 1: Compute 1 ** 4. Step 2: The result is 1.
perimeter oftriangle withsides 6,12, 30 = 48
48
Step 1: Perimeter formula is a + b + c. Step 2: 6 + 12 + 30 = 48
hypotenuse of right triangle withlegs6 and 13= 14.32
14.32
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(6² + 13²) = sqrt(36 + 169) = sqrt(205) = 14.32
perimeter of triangle with sides 34, 33, 18=85
85
Step 1: Perimeter formula is a + b + c. Step 2: 34 + 33 + 18 = 85
perimeter of trianglewith sides 33, 34,17= 84
84
Step 1: Perimeter formula is a + b + c. Step 2: 33 + 34 + 17 = 84
(1)** (2) = 1
1
Step 1: Compute 1 ** 2. Step 2: The result is 1.
8** (4) =4096
4,096
Step 1: Compute 8 ** 4. Step 2: The result is 4096.
hypotenuseof right triangle withlegs10 and 11 =14.87
14.87
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(10² + 11²) = sqrt(100 + 121) = sqrt(221) = 14.87
hypotenuseof right triangle with legs 10 and 14 = 17.20
17.2
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(10² + 14²) = sqrt(100 + 196) = sqrt(296) = 17.20
perimeterof triangle withsides 41, 23, 5= 69
69
Step 1: Perimeter formula is a + b + c. Step 2: 41 + 23 + 5 = 69
21- (12) = 9
9
Step 1: Compute 21 - 12. Step 2: The result is 9.
area of rectangle with width 35 andheight 5=175
175
Step 1: Area formula is width × height. Step 2: 35 × 5 = 175
(10) **(2)=100
100
Step 1: Compute 10 ** 2. Step 2: The result is 100.
perimeter of triangle with sides 15,7, 25=47
47
Step 1: Perimeter formula is a + b + c. Step 2: 15 + 7 + 25 = 47
61 + (52) = 113
113
Step 1: Compute 61 + 52. Step 2: The result is 113.
hypotenuseof right triangle withlegs28 and 14 = 31.30
31.3
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(28² + 14²) = sqrt(784 + 196) = sqrt(980) = 31.30
perimeterof circlewith radius16 = 100.53
100.53
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 16 = 100.53
13-33 =-20
-20
Step 1: Compute 13 - 33. Step 2: The result is -20.
hypotenuseof righttriangle with legs16 and 26 = 30.53
30.53
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(16² + 26²) = sqrt(256 + 676) = sqrt(932) = 30.53
hypotenuse of right trianglewith legs 1and11= 11.05
11.05
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(1² + 11²) = sqrt(1 + 121) = sqrt(122) = 11.05
perimeter ofcircle with radius15 = 94.25
94.25
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 15 = 94.25
perimeter ofcircle withradius4 = 25.13
25.13
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 4 = 25.13
area ofrectangle with width 15 andheight 21 = 315
315
Step 1: Area formula is width × height. Step 2: 15 × 21 = 315
23+93 =116
116
Step 1: Compute 23 + 93. Step 2: The result is 116.
hypotenuse of right trianglewith legs 13and 8 = 15.26
15.26
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(13² + 8²) = sqrt(169 + 64) = sqrt(233) = 15.26
(39) %2 = 1
1
Step 1: Compute 39 % 2. Step 2: The result is 1.
42/ 6= 7
7
Step 1: Compute 42 / 6. Step 2: The result is 7.
84 % 19 =8
8
Step 1: Compute 84 % 19. Step 2: The result is 8.
hypotenuse ofright triangle with legs 8and2 =8.25
8.25
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(8² + 2²) = sqrt(64 + 4) = sqrt(68) = 8.25
areaof trianglewith base 26and height 25= 325.00
325
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 26 × 25 = 325.00
39+ 47 =86
86
Step 1: Compute 39 + 47. Step 2: The result is 86.
2 ** (2)= 4
4
Step 1: Compute 2 ** 2. Step 2: The result is 4.
hypotenuseof righttriangle withlegs 6and13=14.32
14.32
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(6² + 13²) = sqrt(36 + 169) = sqrt(205) = 14.32
(60) * 69 = 4140
4,140
Step 1: Compute 60 * 69. Step 2: The result is 4140.
(9)**(4)= 6561
6,561
Step 1: Compute 9 ** 4. Step 2: The result is 6561.
hypotenuse of right triangle with legs 4 and21 =21.38
21.38
Step 1: Hypotenuse formula is sqrt(a² + b²). Step 2: sqrt(4² + 21²) = sqrt(16 + 441) = sqrt(457) = 21.38
area oftriangle with base 25 and height 49 = 612.50
612.5
Step 1: Area formula is 0.5 × base × height. Step 2: 0.5 × 25 × 49 = 612.50
9 ** 3 = 729
729
Step 1: Compute 9 ** 3. Step 2: The result is 729.
36 - 28= 8
8
Step 1: Compute 36 - 28. Step 2: The result is 8.
(9) % 13 = 9
9
Step 1: Compute 9 % 13. Step 2: The result is 9.
perimeter of rectangle with width 17 and height 50 = 134
134
Step 1: Perimeter formula is 2 × (width + height). Step 2: 2 × (17 + 50) = 2 × 67 = 134
84 % 4 = 0
0
Step 1: Compute 84 % 4. Step 2: The result is 0.
perimeterofcirclewith radius 15 =94.25
94.25
Step 1: Perimeter formula is 2 × π × r. Step 2: 2 × 3.14 × 15 = 94.25
(30)+(59) = 89
89
Step 1: Compute 30 + 59. Step 2: The result is 89.
perimeter of triangle with sides 50, 27, 47 = 124
124
Step 1: Perimeter formula is a + b + c. Step 2: 50 + 27 + 47 = 124
58+ 33 = 91
91
Step 1: Compute 58 + 33. Step 2: The result is 91.