Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
perimeter oftrianglewith sides 15,38,23 =76
| 76 |
Step 1: Perimeter formula is a + b + c.
Step 2: 15 + 38 + 23 = 76
|
area of rectangle with width 1andheight24= 24
| 24 |
Step 1: Area formula is width × height.
Step 2: 1 × 24 = 24
|
perimeter ofrectanglewith width 41and height13 = 108
| 108 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (41 + 13) = 2 × 54 = 108
|
perimeterof circle withradius 11 = 69.12
| 69.12 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 11 = 69.12
|
area ofcirclewithradius 19=1134.11
| 1,134.11 |
Step 1: Area formula is π × r².
Step 2: π × 19² = 3.14 × 361 = 1134.11
|
perimeter of triangle with sides40, 12,50 = 102
| 102 |
Step 1: Perimeter formula is a + b + c.
Step 2: 40 + 12 + 50 = 102
|
(70)+4=74
| 74 |
Step 1: Compute 70 + 4.
Step 2: The result is 74.
|
(4) - 93= -89
| -89 |
Step 1: Compute 4 - 93.
Step 2: The result is -89.
|
area of triangle withbase18 and height10 = 90.00
| 90 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 18 × 10 = 90.00
|
69 + (43)=112
| 112 |
Step 1: Compute 69 + 43.
Step 2: The result is 112.
|
(10) ** 2 = 100
| 100 |
Step 1: Compute 10 ** 2.
Step 2: The result is 100.
|
44 -49 =-5
| -5 |
Step 1: Compute 44 - 49.
Step 2: The result is -5.
|
hypotenuse of right trianglewith legs 17 and2 = 17.12
| 17.12 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(17² + 2²) = sqrt(289 + 4) = sqrt(293) = 17.12
|
78 + (41) = 119
| 119 |
Step 1: Compute 78 + 41.
Step 2: The result is 119.
|
perimeterof rectanglewithwidth 43and height 45 = 176
| 176 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (43 + 45) = 2 × 88 = 176
|
16/(4) =4
| 4 |
Step 1: Compute 16 / 4.
Step 2: The result is 4.
|
(9) ** (3) = 729
| 729 |
Step 1: Compute 9 ** 3.
Step 2: The result is 729.
|
hypotenuse of right trianglewithlegs 26and 7 =26.93
| 26.93 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(26² + 7²) = sqrt(676 + 49) = sqrt(725) = 26.93
|
(38) / (19) =2
| 2 |
Step 1: Compute 38 / 19.
Step 2: The result is 2.
|
area ofrectangle with width 48 and height 25 =1200
| 1,200 |
Step 1: Area formula is width × height.
Step 2: 48 × 25 = 1200
|
areaofrectangle with width 42 and height 10 = 420
| 420 |
Step 1: Area formula is width × height.
Step 2: 42 × 10 = 420
|
areaof rectangle with width 29 and height41 = 1189
| 1,189 |
Step 1: Area formula is width × height.
Step 2: 29 × 41 = 1189
|
perimeter of circlewith radius7= 43.98
| 43.98 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 7 = 43.98
|
area ofrectangle with width 48and height 20 = 960
| 960 |
Step 1: Area formula is width × height.
Step 2: 48 × 20 = 960
|
perimeter ofrectangle withwidth 44 and height37 = 162
| 162 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (44 + 37) = 2 × 81 = 162
|
78 +13= 91
| 91 |
Step 1: Compute 78 + 13.
Step 2: The result is 91.
|
10 % 6 =4
| 4 |
Step 1: Compute 10 % 6.
Step 2: The result is 4.
|
area ofrectangle with width 36 and height43 = 1548
| 1,548 |
Step 1: Area formula is width × height.
Step 2: 36 × 43 = 1548
|
(4)+ 6= 10
| 10 |
Step 1: Compute 4 + 6.
Step 2: The result is 10.
|
37 +20=57
| 57 |
Step 1: Compute 37 + 20.
Step 2: The result is 57.
|
8% 4= 0
| 0 |
Step 1: Compute 8 % 4.
Step 2: The result is 0.
|
perimeterof circle withradius 16 = 100.53
| 100.53 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 16 = 100.53
|
areaoftrianglewith base41and height 32 = 656.00
| 656 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 41 × 32 = 656.00
|
54% 13 = 2
| 2 |
Step 1: Compute 54 % 13.
Step 2: The result is 2.
|
perimeter of rectangle with width 20 and height45= 130
| 130 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (20 + 45) = 2 × 65 = 130
|
30/ 15 = 2
| 2 |
Step 1: Compute 30 / 15.
Step 2: The result is 2.
|
area ofcircle with radius 17= 907.92
| 907.92 |
Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92
|
2 *76 = 152
| 152 |
Step 1: Compute 2 * 76.
Step 2: The result is 152.
|
1 ** (2) =1
| 1 |
Step 1: Compute 1 ** 2.
Step 2: The result is 1.
|
perimeterof triangle withsides30,8, 48 = 86
| 86 |
Step 1: Perimeter formula is a + b + c.
Step 2: 30 + 8 + 48 = 86
|
16*25 =400
| 400 |
Step 1: Compute 16 * 25.
Step 2: The result is 400.
|
perimeter ofrectangle with width 45 and height21 = 132
| 132 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (45 + 21) = 2 × 66 = 132
|
6**4 = 1296
| 1,296 |
Step 1: Compute 6 ** 4.
Step 2: The result is 1296.
|
hypotenuse of righttrianglewithlegs 12and 5 = 13.00
| 13 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(12² + 5²) = sqrt(144 + 25) = sqrt(169) = 13.00
|
hypotenuseof righttrianglewith legs25 and 28 = 37.54
| 37.54 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(25² + 28²) = sqrt(625 + 784) = sqrt(1409) = 37.54
|
7% 10 = 7
| 7 |
Step 1: Compute 7 % 10.
Step 2: The result is 7.
|
perimeterof circle with radius12 = 75.40
| 75.4 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 12 = 75.40
|
(41)* (74) =3034
| 3,034 |
Step 1: Compute 41 * 74.
Step 2: The result is 3034.
|
62 -71 =-9
| -9 |
Step 1: Compute 62 - 71.
Step 2: The result is -9.
|
68 + (2) = 70
| 70 |
Step 1: Compute 68 + 2.
Step 2: The result is 70.
|
areaof circle withradius5 = 78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
hypotenuse of right triangle with legs 27and3 = 27.17
| 27.17 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(27² + 3²) = sqrt(729 + 9) = sqrt(738) = 27.17
|
17%14= 3
| 3 |
Step 1: Compute 17 % 14.
Step 2: The result is 3.
|
(98)+40 =138
| 138 |
Step 1: Compute 98 + 40.
Step 2: The result is 138.
|
89 + (31) =120
| 120 |
Step 1: Compute 89 + 31.
Step 2: The result is 120.
|
perimeterof circle with radius 6= 37.70
| 37.7 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 6 = 37.70
|
28- 34 =-6
| -6 |
Step 1: Compute 28 - 34.
Step 2: The result is -6.
|
(39) %7= 4
| 4 |
Step 1: Compute 39 % 7.
Step 2: The result is 4.
|
93% 4= 1
| 1 |
Step 1: Compute 93 % 4.
Step 2: The result is 1.
|
(19) / (19) =1
| 1 |
Step 1: Compute 19 / 19.
Step 2: The result is 1.
|
3** (2)= 9
| 9 |
Step 1: Compute 3 ** 2.
Step 2: The result is 9.
|
2 ** 4 = 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
(36)/ 9 = 4
| 4 |
Step 1: Compute 36 / 9.
Step 2: The result is 4.
|
area of rectanglewithwidth 30andheight30 =900
| 900 |
Step 1: Area formula is width × height.
Step 2: 30 × 30 = 900
|
perimeterofrectangle with width 38andheight45=166
| 166 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (38 + 45) = 2 × 83 = 166
|
40 / 5 = 8
| 8 |
Step 1: Compute 40 / 5.
Step 2: The result is 8.
|
46 % 19 = 8
| 8 |
Step 1: Compute 46 % 19.
Step 2: The result is 8.
|
area oftrianglewithbase49 and height 9= 220.50
| 220.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 49 × 9 = 220.50
|
35 % 1 = 0
| 0 |
Step 1: Compute 35 % 1.
Step 2: The result is 0.
|
perimeterof circle withradius 9= 56.55
| 56.55 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 9 = 56.55
|
area of trianglewithbase 40 andheight45 =900.00
| 900 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 40 × 45 = 900.00
|
perimeter of trianglewithsides 41, 34, 7 =82
| 82 |
Step 1: Perimeter formula is a + b + c.
Step 2: 41 + 34 + 7 = 82
|
7** 2=49
| 49 |
Step 1: Compute 7 ** 2.
Step 2: The result is 49.
|
(61) -88 =-27
| -27 |
Step 1: Compute 61 - 88.
Step 2: The result is -27.
|
8/(4) = 2
| 2 |
Step 1: Compute 8 / 4.
Step 2: The result is 2.
|
hypotenuse of right trianglewith legs 15 and22 = 26.63
| 26.63 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(15² + 22²) = sqrt(225 + 484) = sqrt(709) = 26.63
|
83 -80= 3
| 3 |
Step 1: Compute 83 - 80.
Step 2: The result is 3.
|
59 + (55) = 114
| 114 |
Step 1: Compute 59 + 55.
Step 2: The result is 114.
|
areaof rectanglewith width 15and height 32 = 480
| 480 |
Step 1: Area formula is width × height.
Step 2: 15 × 32 = 480
|
hypotenuseof right triangle withlegs 15 and15 = 21.21
| 21.21 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(15² + 15²) = sqrt(225 + 225) = sqrt(450) = 21.21
|
perimeter ofcircle with radius 16 =100.53
| 100.53 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 16 = 100.53
|
area of circle withradius 15= 706.86
| 706.86 |
Step 1: Area formula is π × r².
Step 2: π × 15² = 3.14 × 225 = 706.86
|
areaof circlewith radius 16 = 804.25
| 804.25 |
Step 1: Area formula is π × r².
Step 2: π × 16² = 3.14 × 256 = 804.25
|
perimeter of rectanglewithwidth29 and height32 = 122
| 122 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (29 + 32) = 2 × 61 = 122
|
perimeterofcircle with radius 12 = 75.40
| 75.4 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 12 = 75.40
|
7 **3 =343
| 343 |
Step 1: Compute 7 ** 3.
Step 2: The result is 343.
|
perimeterof trianglewith sides 37, 14,9= 60
| 60 |
Step 1: Perimeter formula is a + b + c.
Step 2: 37 + 14 + 9 = 60
|
(90) - 25 =65
| 65 |
Step 1: Compute 90 - 25.
Step 2: The result is 65.
|
25 %16= 9
| 9 |
Step 1: Compute 25 % 16.
Step 2: The result is 9.
|
area of circle withradius11= 380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
area of triangle withbase 27 andheight 5= 67.50
| 67.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 27 × 5 = 67.50
|
hypotenuse ofrighttriangle withlegs24and12 = 26.83
| 26.83 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(24² + 12²) = sqrt(576 + 144) = sqrt(720) = 26.83
|
13 * 100 = 1300
| 1,300 |
Step 1: Compute 13 * 100.
Step 2: The result is 1300.
|
areaof circlewith radius11 = 380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
93% 14 = 9
| 9 |
Step 1: Compute 93 % 14.
Step 2: The result is 9.
|
perimeterof circlewith radius 3 = 18.85
| 18.85 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85
|
areaof rectangle with width 9 and height 18 =162
| 162 |
Step 1: Area formula is width × height.
Step 2: 9 × 18 = 162
|
64/ (16) =4
| 4 |
Step 1: Compute 64 / 16.
Step 2: The result is 4.
|
perimeter ofrectangle with width27 and height 43 = 140
| 140 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (27 + 43) = 2 × 70 = 140
|
area of circle withradius 4= 50.27
| 50.27 |
Step 1: Area formula is π × r².
Step 2: π × 4² = 3.14 × 16 = 50.27
|
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