Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
(12) / (4) = 3
| 3 |
Step 1: Compute 12 / 4.
Step 2: The result is 3.
|
area oftriangle with base 34 and height 35 = 595.00
| 595 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 34 × 35 = 595.00
|
81 / 9=9
| 9 |
Step 1: Compute 81 / 9.
Step 2: The result is 9.
|
60- 96 = -36
| -36 |
Step 1: Compute 60 - 96.
Step 2: The result is -36.
|
area of triangle with base 26 andheight 9= 117.00
| 117 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 26 × 9 = 117.00
|
hypotenuse ofright trianglewith legs30and 17 =34.48
| 34.48 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(30² + 17²) = sqrt(900 + 289) = sqrt(1189) = 34.48
|
perimeter of rectanglewithwidth 42 andheight 3 = 90
| 90 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (42 + 3) = 2 × 45 = 90
|
79 + 3=82
| 82 |
Step 1: Compute 79 + 3.
Step 2: The result is 82.
|
7% 3=1
| 1 |
Step 1: Compute 7 % 3.
Step 2: The result is 1.
|
perimeter oftrianglewith sides 43,41,5 = 89
| 89 |
Step 1: Perimeter formula is a + b + c.
Step 2: 43 + 41 + 5 = 89
|
perimeter of triangle withsides 22,42, 18 =82
| 82 |
Step 1: Perimeter formula is a + b + c.
Step 2: 22 + 42 + 18 = 82
|
perimeter ofrectangle with width 26 and height29 = 110
| 110 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (26 + 29) = 2 × 55 = 110
|
28 - (86) =-58
| -58 |
Step 1: Compute 28 - 86.
Step 2: The result is -58.
|
area of circlewith radius15=706.86
| 706.86 |
Step 1: Area formula is π × r².
Step 2: π × 15² = 3.14 × 225 = 706.86
|
perimeter of circlewithradius20=125.66
| 125.66 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 20 = 125.66
|
areaofcircle with radius 8 = 201.06
| 201.06 |
Step 1: Area formula is π × r².
Step 2: π × 8² = 3.14 × 64 = 201.06
|
(6)+ 99 =105
| 105 |
Step 1: Compute 6 + 99.
Step 2: The result is 105.
|
perimeter of rectangle withwidth 32 and height27 =118
| 118 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (32 + 27) = 2 × 59 = 118
|
perimeter of rectangle with width 3 and height 1 = 8
| 8 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (3 + 1) = 2 × 4 = 8
|
perimeterof circle with radius17= 106.81
| 106.81 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 17 = 106.81
|
51* (60) = 3060
| 3,060 |
Step 1: Compute 51 * 60.
Step 2: The result is 3060.
|
40 - 36 =4
| 4 |
Step 1: Compute 40 - 36.
Step 2: The result is 4.
|
area of rectanglewith width 38andheight 43 = 1634
| 1,634 |
Step 1: Area formula is width × height.
Step 2: 38 × 43 = 1634
|
13 -86 = -73
| -73 |
Step 1: Compute 13 - 86.
Step 2: The result is -73.
|
perimeter of circle withradius 20 = 125.66
| 125.66 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 20 = 125.66
|
2 ** 4 = 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
(71)* (15) = 1065
| 1,065 |
Step 1: Compute 71 * 15.
Step 2: The result is 1065.
|
63+ 85 = 148
| 148 |
Step 1: Compute 63 + 85.
Step 2: The result is 148.
|
58 %8= 2
| 2 |
Step 1: Compute 58 % 8.
Step 2: The result is 2.
|
hypotenuse ofrighttrianglewithlegs 27 and 22 = 34.83
| 34.83 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(27² + 22²) = sqrt(729 + 484) = sqrt(1213) = 34.83
|
(23)+ 47 =70
| 70 |
Step 1: Compute 23 + 47.
Step 2: The result is 70.
|
area of triangle with base 37 and height 24=444.00
| 444 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 37 × 24 = 444.00
|
perimeterof circle withradius 1 =6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
hypotenuse of right trianglewithlegs 2 and 17 =17.12
| 17.12 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(2² + 17²) = sqrt(4 + 289) = sqrt(293) = 17.12
|
perimeter of circle withradius 11= 69.12
| 69.12 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 11 = 69.12
|
69 +52= 121
| 121 |
Step 1: Compute 69 + 52.
Step 2: The result is 121.
|
63* 7 =441
| 441 |
Step 1: Compute 63 * 7.
Step 2: The result is 441.
|
40 -(9) =31
| 31 |
Step 1: Compute 40 - 9.
Step 2: The result is 31.
|
perimeterofcircle withradius19= 119.38
| 119.38 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 19 = 119.38
|
area of triangle withbase 29 andheight 30 = 435.00
| 435 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 29 × 30 = 435.00
|
(45) % 18 =9
| 9 |
Step 1: Compute 45 % 18.
Step 2: The result is 9.
|
45%8= 5
| 5 |
Step 1: Compute 45 % 8.
Step 2: The result is 5.
|
6 ** (3) = 216
| 216 |
Step 1: Compute 6 ** 3.
Step 2: The result is 216.
|
hypotenuse of right triangle with legs 8 and 3 =8.54
| 8.54 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(8² + 3²) = sqrt(64 + 9) = sqrt(73) = 8.54
|
(3)**(3)=27
| 27 |
Step 1: Compute 3 ** 3.
Step 2: The result is 27.
|
area of circle with radius4 = 50.27
| 50.27 |
Step 1: Area formula is π × r².
Step 2: π × 4² = 3.14 × 16 = 50.27
|
area of rectangle with width 38 and height 24= 912
| 912 |
Step 1: Area formula is width × height.
Step 2: 38 × 24 = 912
|
33/ 11= 3
| 3 |
Step 1: Compute 33 / 11.
Step 2: The result is 3.
|
32- 26 = 6
| 6 |
Step 1: Compute 32 - 26.
Step 2: The result is 6.
|
area of circlewith radius 9= 254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
perimeterofrectangle withwidth13 and height 13 = 52
| 52 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (13 + 13) = 2 × 26 = 52
|
perimeter ofcirclewith radius13= 81.68
| 81.68 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 13 = 81.68
|
area ofcirclewith radius10 =314.16
| 314.16 |
Step 1: Area formula is π × r².
Step 2: π × 10² = 3.14 × 100 = 314.16
|
area of trianglewith base14 andheight 24 =168.00
| 168 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 14 × 24 = 168.00
|
(96) + 56 = 152
| 152 |
Step 1: Compute 96 + 56.
Step 2: The result is 152.
|
37+ 63 =100
| 100 |
Step 1: Compute 37 + 63.
Step 2: The result is 100.
|
area ofcirclewithradius 13 =530.93
| 530.93 |
Step 1: Area formula is π × r².
Step 2: π × 13² = 3.14 × 169 = 530.93
|
area of rectangle with width 11and height 36 = 396
| 396 |
Step 1: Area formula is width × height.
Step 2: 11 × 36 = 396
|
perimeter ofcircle with radius 18 =113.10
| 113.1 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 18 = 113.10
|
perimeter ofrectangle with width 34and height 48 = 164
| 164 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (34 + 48) = 2 × 82 = 164
|
(41) %(19) = 3
| 3 |
Step 1: Compute 41 % 19.
Step 2: The result is 3.
|
area of circle with radius 9= 254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
9 + 65 = 74
| 74 |
Step 1: Compute 9 + 65.
Step 2: The result is 74.
|
perimeterof rectangle with width 49and height 7 = 112
| 112 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (49 + 7) = 2 × 56 = 112
|
(9) ** 4 =6561
| 6,561 |
Step 1: Compute 9 ** 4.
Step 2: The result is 6561.
|
56 /(14) = 4
| 4 |
Step 1: Compute 56 / 14.
Step 2: The result is 4.
|
93 + 79 = 172
| 172 |
Step 1: Compute 93 + 79.
Step 2: The result is 172.
|
hypotenuse ofrighttrianglewithlegs 15and 1=15.03
| 15.03 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(15² + 1²) = sqrt(225 + 1) = sqrt(226) = 15.03
|
3 ** 4= 81
| 81 |
Step 1: Compute 3 ** 4.
Step 2: The result is 81.
|
(64) +5 =69
| 69 |
Step 1: Compute 64 + 5.
Step 2: The result is 69.
|
area ofrectangle with width 27 and height10 =270
| 270 |
Step 1: Area formula is width × height.
Step 2: 27 × 10 = 270
|
areaof circle with radius 5 =78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
95 / 19 = 5
| 5 |
Step 1: Compute 95 / 19.
Step 2: The result is 5.
|
hypotenuse of righttriangle with legs 4 and 15 = 15.52
| 15.52 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(4² + 15²) = sqrt(16 + 225) = sqrt(241) = 15.52
|
(18) / 9 =2
| 2 |
Step 1: Compute 18 / 9.
Step 2: The result is 2.
|
perimeterof triangle with sides 15, 35, 10 = 60
| 60 |
Step 1: Perimeter formula is a + b + c.
Step 2: 15 + 35 + 10 = 60
|
area oftriangle withbase43 andheight25 = 537.50
| 537.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 43 × 25 = 537.50
|
64 / 16 = 4
| 4 |
Step 1: Compute 64 / 16.
Step 2: The result is 4.
|
62 * 69 = 4278
| 4,278 |
Step 1: Compute 62 * 69.
Step 2: The result is 4278.
|
(65) -94 =-29
| -29 |
Step 1: Compute 65 - 94.
Step 2: The result is -29.
|
perimeter of rectangle with width 39 and height 32 = 142
| 142 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (39 + 32) = 2 × 71 = 142
|
(72) / 12 = 6
| 6 |
Step 1: Compute 72 / 12.
Step 2: The result is 6.
|
hypotenuseof righttrianglewith legs 12and 17 = 20.81
| 20.81 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(12² + 17²) = sqrt(144 + 289) = sqrt(433) = 20.81
|
38 + (64) = 102
| 102 |
Step 1: Compute 38 + 64.
Step 2: The result is 102.
|
2 / 1 =2
| 2 |
Step 1: Compute 2 / 1.
Step 2: The result is 2.
|
hypotenuseof right trianglewith legs 4 and 19= 19.42
| 19.42 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(4² + 19²) = sqrt(16 + 361) = sqrt(377) = 19.42
|
(18)/3 = 6
| 6 |
Step 1: Compute 18 / 3.
Step 2: The result is 6.
|
13 -67= -54
| -54 |
Step 1: Compute 13 - 67.
Step 2: The result is -54.
|
(8)** 4=4096
| 4,096 |
Step 1: Compute 8 ** 4.
Step 2: The result is 4096.
|
(9) **2 = 81
| 81 |
Step 1: Compute 9 ** 2.
Step 2: The result is 81.
|
perimeter of rectangle with width 12 and height 46 = 116
| 116 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (12 + 46) = 2 × 58 = 116
|
areaof rectangle with width 11 and height39 = 429
| 429 |
Step 1: Area formula is width × height.
Step 2: 11 × 39 = 429
|
area of rectangle with width 38and height 29 = 1102
| 1,102 |
Step 1: Area formula is width × height.
Step 2: 38 × 29 = 1102
|
hypotenuseof right triangle with legs 4and27 =27.29
| 27.29 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(4² + 27²) = sqrt(16 + 729) = sqrt(745) = 27.29
|
100 + 94 = 194
| 194 |
Step 1: Compute 100 + 94.
Step 2: The result is 194.
|
areaof circle with radius8 =201.06
| 201.06 |
Step 1: Area formula is π × r².
Step 2: π × 8² = 3.14 × 64 = 201.06
|
perimeterof rectangle withwidth 18 and height 42 = 120
| 120 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (18 + 42) = 2 × 60 = 120
|
area ofrectanglewith width29 and height50 = 1450
| 1,450 |
Step 1: Area formula is width × height.
Step 2: 29 × 50 = 1450
|
52 -61 = -9
| -9 |
Step 1: Compute 52 - 61.
Step 2: The result is -9.
|
perimeter of triangle with sides 26, 28,41= 95
| 95 |
Step 1: Perimeter formula is a + b + c.
Step 2: 26 + 28 + 41 = 95
|
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