Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
areaoftriangle with base25and height 47= 587.50
| 587.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 25 × 47 = 587.50
|
2 % 5= 2
| 2 |
Step 1: Compute 2 % 5.
Step 2: The result is 2.
|
hypotenuse ofrighttriangle withlegs 27 and 30 = 40.36
| 40.36 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(27² + 30²) = sqrt(729 + 900) = sqrt(1629) = 40.36
|
(80) /(10)= 8
| 8 |
Step 1: Compute 80 / 10.
Step 2: The result is 8.
|
hypotenuse of righttrianglewithlegs5and30=30.41
| 30.41 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(5² + 30²) = sqrt(25 + 900) = sqrt(925) = 30.41
|
1** 3 = 1
| 1 |
Step 1: Compute 1 ** 3.
Step 2: The result is 1.
|
12 % 2 =0
| 0 |
Step 1: Compute 12 % 2.
Step 2: The result is 0.
|
14 / (2)= 7
| 7 |
Step 1: Compute 14 / 2.
Step 2: The result is 7.
|
area ofrectanglewith width37 andheight 18 =666
| 666 |
Step 1: Area formula is width × height.
Step 2: 37 × 18 = 666
|
44* 57 = 2508
| 2,508 |
Step 1: Compute 44 * 57.
Step 2: The result is 2508.
|
perimeterof triangle with sides43, 26,3 = 72
| 72 |
Step 1: Perimeter formula is a + b + c.
Step 2: 43 + 26 + 3 = 72
|
perimeter oftrianglewith sides 25,25, 20=70
| 70 |
Step 1: Perimeter formula is a + b + c.
Step 2: 25 + 25 + 20 = 70
|
26 + 33 = 59
| 59 |
Step 1: Compute 26 + 33.
Step 2: The result is 59.
|
perimeter of rectanglewithwidth11and height 40 =102
| 102 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (11 + 40) = 2 × 51 = 102
|
perimeter ofcircle withradius 8= 50.27
| 50.27 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27
|
hypotenuse of right triangle withlegs 26and2 = 26.08
| 26.08 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(26² + 2²) = sqrt(676 + 4) = sqrt(680) = 26.08
|
perimeter ofcirclewithradius 11= 69.12
| 69.12 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 11 = 69.12
|
(1) **(2)= 1
| 1 |
Step 1: Compute 1 ** 2.
Step 2: The result is 1.
|
96 + (59)=155
| 155 |
Step 1: Compute 96 + 59.
Step 2: The result is 155.
|
areaoftriangle with base 49 and height 16 = 392.00
| 392 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 49 × 16 = 392.00
|
(7) ** 4 =2401
| 2,401 |
Step 1: Compute 7 ** 4.
Step 2: The result is 2401.
|
perimeter of circle withradius 1 = 6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
5 ** 3 =125
| 125 |
Step 1: Compute 5 ** 3.
Step 2: The result is 125.
|
perimeter of trianglewith sides48, 12, 40 = 100
| 100 |
Step 1: Perimeter formula is a + b + c.
Step 2: 48 + 12 + 40 = 100
|
57*59= 3363
| 3,363 |
Step 1: Compute 57 * 59.
Step 2: The result is 3363.
|
(84) +82 =166
| 166 |
Step 1: Compute 84 + 82.
Step 2: The result is 166.
|
86+ 82= 168
| 168 |
Step 1: Compute 86 + 82.
Step 2: The result is 168.
|
areaof circle with radius 19 =1134.11
| 1,134.11 |
Step 1: Area formula is π × r².
Step 2: π × 19² = 3.14 × 361 = 1134.11
|
perimeter of trianglewith sides 12,43, 25=80
| 80 |
Step 1: Perimeter formula is a + b + c.
Step 2: 12 + 43 + 25 = 80
|
area of triangle with base4 and height 36 = 72.00
| 72 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 4 × 36 = 72.00
|
(5) + 72 =77
| 77 |
Step 1: Compute 5 + 72.
Step 2: The result is 77.
|
perimeter oftriangle with sides50,35, 24 = 109
| 109 |
Step 1: Perimeter formula is a + b + c.
Step 2: 50 + 35 + 24 = 109
|
areaof circle withradius 12= 452.39
| 452.39 |
Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39
|
perimeter of triangle with sides 27, 12,6 = 45
| 45 |
Step 1: Perimeter formula is a + b + c.
Step 2: 27 + 12 + 6 = 45
|
52 *80 =4160
| 4,160 |
Step 1: Compute 52 * 80.
Step 2: The result is 4160.
|
perimeter of rectangle withwidth 8andheight17 = 50
| 50 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (8 + 17) = 2 × 25 = 50
|
area of triangle withbase 42 and height 31 =651.00
| 651 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 42 × 31 = 651.00
|
58 - (10) =48
| 48 |
Step 1: Compute 58 - 10.
Step 2: The result is 48.
|
perimeterof rectanglewith width 22 and height 49=142
| 142 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (22 + 49) = 2 × 71 = 142
|
(28) -62 =-34
| -34 |
Step 1: Compute 28 - 62.
Step 2: The result is -34.
|
areaofcircle withradius 17 = 907.92
| 907.92 |
Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92
|
39 +79 = 118
| 118 |
Step 1: Compute 39 + 79.
Step 2: The result is 118.
|
perimeteroftriangle withsides 33, 28, 1= 62
| 62 |
Step 1: Perimeter formula is a + b + c.
Step 2: 33 + 28 + 1 = 62
|
(3) **3 = 27
| 27 |
Step 1: Compute 3 ** 3.
Step 2: The result is 27.
|
20*2 = 40
| 40 |
Step 1: Compute 20 * 2.
Step 2: The result is 40.
|
(11) +21= 32
| 32 |
Step 1: Compute 11 + 21.
Step 2: The result is 32.
|
58 % 9 = 4
| 4 |
Step 1: Compute 58 % 9.
Step 2: The result is 4.
|
35* 77 = 2695
| 2,695 |
Step 1: Compute 35 * 77.
Step 2: The result is 2695.
|
96- 46 = 50
| 50 |
Step 1: Compute 96 - 46.
Step 2: The result is 50.
|
areaof trianglewithbase36 andheight23= 414.00
| 414 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 36 × 23 = 414.00
|
perimeter of rectangle with width 37 andheight 45 = 164
| 164 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (37 + 45) = 2 × 82 = 164
|
perimeterofrectanglewith width19 and height 5= 48
| 48 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (19 + 5) = 2 × 24 = 48
|
12- 4 = 8
| 8 |
Step 1: Compute 12 - 4.
Step 2: The result is 8.
|
areaofcircle with radius 5 =78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
area of rectangle with width41 and height26 =1066
| 1,066 |
Step 1: Area formula is width × height.
Step 2: 41 × 26 = 1066
|
perimeter of trianglewithsides 30,40, 29 = 99
| 99 |
Step 1: Perimeter formula is a + b + c.
Step 2: 30 + 40 + 29 = 99
|
hypotenuse of righttriangle withlegs 28 and 26 = 38.21
| 38.21 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(28² + 26²) = sqrt(784 + 676) = sqrt(1460) = 38.21
|
(5)/ 1 = 5
| 5 |
Step 1: Compute 5 / 1.
Step 2: The result is 5.
|
(86)+ 10= 96
| 96 |
Step 1: Compute 86 + 10.
Step 2: The result is 96.
|
perimeter of trianglewith sides 45, 21, 1=67
| 67 |
Step 1: Perimeter formula is a + b + c.
Step 2: 45 + 21 + 1 = 67
|
120 /(12)=10
| 10 |
Step 1: Compute 120 / 12.
Step 2: The result is 10.
|
(12)*80=960
| 960 |
Step 1: Compute 12 * 80.
Step 2: The result is 960.
|
72 - (51) = 21
| 21 |
Step 1: Compute 72 - 51.
Step 2: The result is 21.
|
area oftriangle withbase 13 andheight8 = 52.00
| 52 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 13 × 8 = 52.00
|
hypotenuseof righttriangle with legs 19and 21= 28.32
| 28.32 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(19² + 21²) = sqrt(361 + 441) = sqrt(802) = 28.32
|
area of triangle withbase13 and height 45= 292.50
| 292.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 13 × 45 = 292.50
|
hypotenuse of right triangle with legs 25and 15= 29.15
| 29.15 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(25² + 15²) = sqrt(625 + 225) = sqrt(850) = 29.15
|
perimeter of rectangle with width34and height 27= 122
| 122 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (34 + 27) = 2 × 61 = 122
|
area oftrianglewithbase17 and height 1 = 8.50
| 8.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 17 × 1 = 8.50
|
8 %2=0
| 0 |
Step 1: Compute 8 % 2.
Step 2: The result is 0.
|
perimeter ofrectangle with width 33 andheight 2 = 70
| 70 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (33 + 2) = 2 × 35 = 70
|
areaof rectangle with width 44 and height 44 = 1936
| 1,936 |
Step 1: Area formula is width × height.
Step 2: 44 × 44 = 1936
|
(68) / 17=4
| 4 |
Step 1: Compute 68 / 17.
Step 2: The result is 4.
|
area ofrectangle with width 3andheight 41= 123
| 123 |
Step 1: Area formula is width × height.
Step 2: 3 × 41 = 123
|
(65) / (13) =5
| 5 |
Step 1: Compute 65 / 13.
Step 2: The result is 5.
|
area of triangle with base 18 and height 38= 342.00
| 342 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 18 × 38 = 342.00
|
area of circle with radius 2=12.57
| 12.57 |
Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57
|
31+97= 128
| 128 |
Step 1: Compute 31 + 97.
Step 2: The result is 128.
|
(1)-(28) = -27
| -27 |
Step 1: Compute 1 - 28.
Step 2: The result is -27.
|
6- 84 = -78
| -78 |
Step 1: Compute 6 - 84.
Step 2: The result is -78.
|
38- (19)= 19
| 19 |
Step 1: Compute 38 - 19.
Step 2: The result is 19.
|
area of triangle with base 11 andheight 15= 82.50
| 82.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 11 × 15 = 82.50
|
74*(62) =4588
| 4,588 |
Step 1: Compute 74 * 62.
Step 2: The result is 4588.
|
12+ 55= 67
| 67 |
Step 1: Compute 12 + 55.
Step 2: The result is 67.
|
area of circlewith radius 12 = 452.39
| 452.39 |
Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39
|
area of rectangle with width 36 and height23 = 828
| 828 |
Step 1: Area formula is width × height.
Step 2: 36 × 23 = 828
|
area of triangle withbase49 andheight 12 = 294.00
| 294 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 49 × 12 = 294.00
|
areaof rectangle withwidth 3 and height 19= 57
| 57 |
Step 1: Area formula is width × height.
Step 2: 3 × 19 = 57
|
perimeteroftriangle with sides26, 14, 14 = 54
| 54 |
Step 1: Perimeter formula is a + b + c.
Step 2: 26 + 14 + 14 = 54
|
7 ** 2 =49
| 49 |
Step 1: Compute 7 ** 2.
Step 2: The result is 49.
|
4 ** 3= 64
| 64 |
Step 1: Compute 4 ** 3.
Step 2: The result is 64.
|
(2) **4 = 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
areaof trianglewith base 25andheight44= 550.00
| 550 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 25 × 44 = 550.00
|
7** (2)= 49
| 49 |
Step 1: Compute 7 ** 2.
Step 2: The result is 49.
|
2 ** 2 =4
| 4 |
Step 1: Compute 2 ** 2.
Step 2: The result is 4.
|
hypotenuse ofright triangle withlegs 7 and23 =24.04
| 24.04 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(7² + 23²) = sqrt(49 + 529) = sqrt(578) = 24.04
|
68 / (17) = 4
| 4 |
Step 1: Compute 68 / 17.
Step 2: The result is 4.
|
perimeter ofcircle with radius 5 = 31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
areaofrectanglewith width 4and height 11= 44
| 44 |
Step 1: Area formula is width × height.
Step 2: 4 × 11 = 44
|
perimeter of trianglewithsides45, 16, 2 = 63
| 63 |
Step 1: Perimeter formula is a + b + c.
Step 2: 45 + 16 + 2 = 63
|
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