Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
areaof rectanglewith width 37 and height 11 = 407
| 407 |
Step 1: Area formula is width × height.
Step 2: 37 × 11 = 407
|
perimeterof rectanglewithwidth 10and height42= 104
| 104 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (10 + 42) = 2 × 52 = 104
|
hypotenuse ofright trianglewith legs29 and15= 32.65
| 32.65 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(29² + 15²) = sqrt(841 + 225) = sqrt(1066) = 32.65
|
(84) / (12)= 7
| 7 |
Step 1: Compute 84 / 12.
Step 2: The result is 7.
|
(8) / (1) = 8
| 8 |
Step 1: Compute 8 / 1.
Step 2: The result is 8.
|
perimeterofrectangle with width 22and height 6 = 56
| 56 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (22 + 6) = 2 × 28 = 56
|
perimeterof circle withradius 19= 119.38
| 119.38 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 19 = 119.38
|
(84) * 52= 4368
| 4,368 |
Step 1: Compute 84 * 52.
Step 2: The result is 4368.
|
areaof circle with radius 19 = 1134.11
| 1,134.11 |
Step 1: Area formula is π × r².
Step 2: π × 19² = 3.14 × 361 = 1134.11
|
7 ** (4)=2401
| 2,401 |
Step 1: Compute 7 ** 4.
Step 2: The result is 2401.
|
36 + 3 =39
| 39 |
Step 1: Compute 36 + 3.
Step 2: The result is 39.
|
perimeter of circle with radius 3 = 18.85
| 18.85 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85
|
perimeter of triangle with sides 40, 21, 40=101
| 101 |
Step 1: Perimeter formula is a + b + c.
Step 2: 40 + 21 + 40 = 101
|
area of rectangle with width 7 and height42= 294
| 294 |
Step 1: Area formula is width × height.
Step 2: 7 × 42 = 294
|
areaof rectanglewith width46 and height 3=138
| 138 |
Step 1: Area formula is width × height.
Step 2: 46 × 3 = 138
|
(4) * (73) = 292
| 292 |
Step 1: Compute 4 * 73.
Step 2: The result is 292.
|
areaoftriangle with base 27 and height46 = 621.00
| 621 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 27 × 46 = 621.00
|
areaof triangle with base 18 and height 7 = 63.00
| 63 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 18 × 7 = 63.00
|
(71)% 4 = 3
| 3 |
Step 1: Compute 71 % 4.
Step 2: The result is 3.
|
19% 19 = 0
| 0 |
Step 1: Compute 19 % 19.
Step 2: The result is 0.
|
7 **(2) = 49
| 49 |
Step 1: Compute 7 ** 2.
Step 2: The result is 49.
|
(7) ** 4 = 2401
| 2,401 |
Step 1: Compute 7 ** 4.
Step 2: The result is 2401.
|
area of rectangle with width 17and height 44 = 748
| 748 |
Step 1: Area formula is width × height.
Step 2: 17 × 44 = 748
|
52 * 83 = 4316
| 4,316 |
Step 1: Compute 52 * 83.
Step 2: The result is 4316.
|
perimeterofrectangle with width 20 andheight46 = 132
| 132 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (20 + 46) = 2 × 66 = 132
|
perimeter of circle withradius 19 = 119.38
| 119.38 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 19 = 119.38
|
(93)* 78 = 7254
| 7,254 |
Step 1: Compute 93 * 78.
Step 2: The result is 7254.
|
perimeter of rectangle withwidth 43and height4 = 94
| 94 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (43 + 4) = 2 × 47 = 94
|
3** 2= 9
| 9 |
Step 1: Compute 3 ** 2.
Step 2: The result is 9.
|
area of rectangle withwidth5and height 40=200
| 200 |
Step 1: Area formula is width × height.
Step 2: 5 × 40 = 200
|
(99) -87 = 12
| 12 |
Step 1: Compute 99 - 87.
Step 2: The result is 12.
|
perimeterofcircle with radius 19 = 119.38
| 119.38 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 19 = 119.38
|
perimeter of rectangle with width 34and height 43= 154
| 154 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (34 + 43) = 2 × 77 = 154
|
perimeter of circle withradius1= 6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
91 % 4=3
| 3 |
Step 1: Compute 91 % 4.
Step 2: The result is 3.
|
(76)-78=-2
| -2 |
Step 1: Compute 76 - 78.
Step 2: The result is -2.
|
(5) **2 = 25
| 25 |
Step 1: Compute 5 ** 2.
Step 2: The result is 25.
|
100/ 20=5
| 5 |
Step 1: Compute 100 / 20.
Step 2: The result is 5.
|
75 + 77 =152
| 152 |
Step 1: Compute 75 + 77.
Step 2: The result is 152.
|
perimeter of circle with radius8 =50.27
| 50.27 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27
|
perimeter of triangle with sides40, 26, 6 = 72
| 72 |
Step 1: Perimeter formula is a + b + c.
Step 2: 40 + 26 + 6 = 72
|
area of trianglewith base16 and height 42 = 336.00
| 336 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 16 × 42 = 336.00
|
hypotenuse of righttriangle with legs 9 and 11 =14.21
| 14.21 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(9² + 11²) = sqrt(81 + 121) = sqrt(202) = 14.21
|
area of rectangle with width2 and height 5 = 10
| 10 |
Step 1: Area formula is width × height.
Step 2: 2 × 5 = 10
|
perimeter ofrectanglewith width 29and height 24 =106
| 106 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (29 + 24) = 2 × 53 = 106
|
perimeter of trianglewith sides 24, 19,18 = 61
| 61 |
Step 1: Perimeter formula is a + b + c.
Step 2: 24 + 19 + 18 = 61
|
(6) **(4) = 1296
| 1,296 |
Step 1: Compute 6 ** 4.
Step 2: The result is 1296.
|
area oftrianglewithbase 42and height 45=945.00
| 945 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 42 × 45 = 945.00
|
perimeter of triangle with sides 7,12,23=42
| 42 |
Step 1: Perimeter formula is a + b + c.
Step 2: 7 + 12 + 23 = 42
|
(10) **2= 100
| 100 |
Step 1: Compute 10 ** 2.
Step 2: The result is 100.
|
area of rectanglewithwidth 29 and height35= 1015
| 1,015 |
Step 1: Area formula is width × height.
Step 2: 29 × 35 = 1015
|
13 * 37=481
| 481 |
Step 1: Compute 13 * 37.
Step 2: The result is 481.
|
areaof circle with radius 3= 28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
71 * (70) =4970
| 4,970 |
Step 1: Compute 71 * 70.
Step 2: The result is 4970.
|
48-(85) =-37
| -37 |
Step 1: Compute 48 - 85.
Step 2: The result is -37.
|
perimeter of circle withradius 18 = 113.10
| 113.1 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 18 = 113.10
|
89-(40) =49
| 49 |
Step 1: Compute 89 - 40.
Step 2: The result is 49.
|
16 % 10= 6
| 6 |
Step 1: Compute 16 % 10.
Step 2: The result is 6.
|
areaof rectangle withwidth 22 andheight 6 = 132
| 132 |
Step 1: Area formula is width × height.
Step 2: 22 × 6 = 132
|
perimeter ofrectanglewithwidth20 and height 50 = 140
| 140 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (20 + 50) = 2 × 70 = 140
|
hypotenuseof right triangle with legs 15and 10 = 18.03
| 18.03 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(15² + 10²) = sqrt(225 + 100) = sqrt(325) = 18.03
|
areaof rectangle withwidth50and height 7 = 350
| 350 |
Step 1: Area formula is width × height.
Step 2: 50 × 7 = 350
|
8 ** 2 = 64
| 64 |
Step 1: Compute 8 ** 2.
Step 2: The result is 64.
|
perimeterof rectanglewith width 50 and height 7 = 114
| 114 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (50 + 7) = 2 × 57 = 114
|
(7)- 84=-77
| -77 |
Step 1: Compute 7 - 84.
Step 2: The result is -77.
|
perimeter ofcircle withradius 7= 43.98
| 43.98 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 7 = 43.98
|
10 ** 3 = 1000
| 1,000 |
Step 1: Compute 10 ** 3.
Step 2: The result is 1000.
|
perimeterof circlewith radius5 =31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
perimeterofrectangle withwidth2 and height25=54
| 54 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (2 + 25) = 2 × 27 = 54
|
hypotenuse of righttriangle with legs 7and13 = 14.76
| 14.76 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(7² + 13²) = sqrt(49 + 169) = sqrt(218) = 14.76
|
perimeteroftriangle with sides 21, 32, 45 = 98
| 98 |
Step 1: Perimeter formula is a + b + c.
Step 2: 21 + 32 + 45 = 98
|
28 *27 = 756
| 756 |
Step 1: Compute 28 * 27.
Step 2: The result is 756.
|
area of circlewithradius11 =380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
perimeter ofrectangle with width 28and height25 =106
| 106 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (28 + 25) = 2 × 53 = 106
|
perimeter of triangle with sides 3, 45, 41 = 89
| 89 |
Step 1: Perimeter formula is a + b + c.
Step 2: 3 + 45 + 41 = 89
|
18 /9= 2
| 2 |
Step 1: Compute 18 / 9.
Step 2: The result is 2.
|
(2)** 4= 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
9 *35= 315
| 315 |
Step 1: Compute 9 * 35.
Step 2: The result is 315.
|
81 % 5 = 1
| 1 |
Step 1: Compute 81 % 5.
Step 2: The result is 1.
|
perimeterof rectangle with width 27 and height21= 96
| 96 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (27 + 21) = 2 × 48 = 96
|
perimeter of triangle withsides16, 45,48 = 109
| 109 |
Step 1: Perimeter formula is a + b + c.
Step 2: 16 + 45 + 48 = 109
|
74 * (28) =2072
| 2,072 |
Step 1: Compute 74 * 28.
Step 2: The result is 2072.
|
perimeter ofrectangle with width 18 and height 49 = 134
| 134 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (18 + 49) = 2 × 67 = 134
|
hypotenuseofrighttriangle withlegs12and 21 =24.19
| 24.19 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(12² + 21²) = sqrt(144 + 441) = sqrt(585) = 24.19
|
8** (3) =512
| 512 |
Step 1: Compute 8 ** 3.
Step 2: The result is 512.
|
98* 18 =1764
| 1,764 |
Step 1: Compute 98 * 18.
Step 2: The result is 1764.
|
perimeter of triangle with sides 43,43,9= 95
| 95 |
Step 1: Perimeter formula is a + b + c.
Step 2: 43 + 43 + 9 = 95
|
areaof circlewith radius 11 = 380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
30 / 15 = 2
| 2 |
Step 1: Compute 30 / 15.
Step 2: The result is 2.
|
(35)-87=-52
| -52 |
Step 1: Compute 35 - 87.
Step 2: The result is -52.
|
perimeter ofrectanglewith width 13 andheight 38 = 102
| 102 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (13 + 38) = 2 × 51 = 102
|
area ofcirclewith radius 16 = 804.25
| 804.25 |
Step 1: Area formula is π × r².
Step 2: π × 16² = 3.14 × 256 = 804.25
|
8**3 = 512
| 512 |
Step 1: Compute 8 ** 3.
Step 2: The result is 512.
|
2 ** 2 =4
| 4 |
Step 1: Compute 2 ** 2.
Step 2: The result is 4.
|
95 % 14 = 11
| 11 |
Step 1: Compute 95 % 14.
Step 2: The result is 11.
|
perimeter ofcircle withradius 12 = 75.40
| 75.4 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 12 = 75.40
|
98 % 16=2
| 2 |
Step 1: Compute 98 % 16.
Step 2: The result is 2.
|
hypotenuse of right trianglewith legs15 and 8 =17.00
| 17 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(15² + 8²) = sqrt(225 + 64) = sqrt(289) = 17.00
|
area ofrectangle with width 19 andheight39 = 741
| 741 |
Step 1: Area formula is width × height.
Step 2: 19 × 39 = 741
|
(55)% (5)=0
| 0 |
Step 1: Compute 55 % 5.
Step 2: The result is 0.
|
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