Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
perimeter of triangle with sides 9,1,31 = 41
| 41 |
Step 1: Perimeter formula is a + b + c.
Step 2: 9 + 1 + 31 = 41
|
perimeter of rectanglewithwidth 41 and height 33= 148
| 148 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (41 + 33) = 2 × 74 = 148
|
30-85= -55
| -55 |
Step 1: Compute 30 - 85.
Step 2: The result is -55.
|
areaofcircle with radius9 = 254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
3 ** 3= 27
| 27 |
Step 1: Compute 3 ** 3.
Step 2: The result is 27.
|
hypotenuseof right triangle withlegs 22 and29 = 36.40
| 36.4 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(22² + 29²) = sqrt(484 + 841) = sqrt(1325) = 36.40
|
69*77=5313
| 5,313 |
Step 1: Compute 69 * 77.
Step 2: The result is 5313.
|
89 % 5 = 4
| 4 |
Step 1: Compute 89 % 5.
Step 2: The result is 4.
|
perimeter of rectanglewithwidth 6and height 7=26
| 26 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (6 + 7) = 2 × 13 = 26
|
5 **4= 625
| 625 |
Step 1: Compute 5 ** 4.
Step 2: The result is 625.
|
areaof circle with radius 7 =153.94
| 153.94 |
Step 1: Area formula is π × r².
Step 2: π × 7² = 3.14 × 49 = 153.94
|
22%5 = 2
| 2 |
Step 1: Compute 22 % 5.
Step 2: The result is 2.
|
65%8 = 1
| 1 |
Step 1: Compute 65 % 8.
Step 2: The result is 1.
|
52- 40 =12
| 12 |
Step 1: Compute 52 - 40.
Step 2: The result is 12.
|
100 + 43= 143
| 143 |
Step 1: Compute 100 + 43.
Step 2: The result is 143.
|
hypotenuse of righttriangle with legs 11 and1 =11.05
| 11.05 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(11² + 1²) = sqrt(121 + 1) = sqrt(122) = 11.05
|
area ofrectanglewithwidth 27 and height18 =486
| 486 |
Step 1: Area formula is width × height.
Step 2: 27 × 18 = 486
|
32 % 5 =2
| 2 |
Step 1: Compute 32 % 5.
Step 2: The result is 2.
|
hypotenuse of righttrianglewithlegs 22 and 14 =26.08
| 26.08 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(22² + 14²) = sqrt(484 + 196) = sqrt(680) = 26.08
|
perimeter ofrectanglewithwidth 33and height 11 = 88
| 88 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (33 + 11) = 2 × 44 = 88
|
15- (58)= -43
| -43 |
Step 1: Compute 15 - 58.
Step 2: The result is -43.
|
perimeterof circlewithradius18 = 113.10
| 113.1 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 18 = 113.10
|
area of rectanglewithwidth43 and height 44=1892
| 1,892 |
Step 1: Area formula is width × height.
Step 2: 43 × 44 = 1892
|
area oftriangle with base 18andheight 41=369.00
| 369 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 18 × 41 = 369.00
|
perimeter of rectangle with width 47andheight 8=110
| 110 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (47 + 8) = 2 × 55 = 110
|
area of rectangle with width 31 andheight 12= 372
| 372 |
Step 1: Area formula is width × height.
Step 2: 31 × 12 = 372
|
5 ** 3 = 125
| 125 |
Step 1: Compute 5 ** 3.
Step 2: The result is 125.
|
areaof rectangle with width 4 and height 40 = 160
| 160 |
Step 1: Area formula is width × height.
Step 2: 4 × 40 = 160
|
hypotenuse of righttriangle with legs 30 and 7 = 30.81
| 30.81 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(30² + 7²) = sqrt(900 + 49) = sqrt(949) = 30.81
|
(71) - 3 = 68
| 68 |
Step 1: Compute 71 - 3.
Step 2: The result is 68.
|
perimeter of rectangle withwidth 43 and height 26 = 138
| 138 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (43 + 26) = 2 × 69 = 138
|
10 % (5) =0
| 0 |
Step 1: Compute 10 % 5.
Step 2: The result is 0.
|
hypotenuse ofright triangle with legs24 and 15 =28.30
| 28.3 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(24² + 15²) = sqrt(576 + 225) = sqrt(801) = 28.30
|
79 % (18) = 7
| 7 |
Step 1: Compute 79 % 18.
Step 2: The result is 7.
|
areaof rectangle with width 14 and height 34 =476
| 476 |
Step 1: Area formula is width × height.
Step 2: 14 × 34 = 476
|
16/ (16) = 1
| 1 |
Step 1: Compute 16 / 16.
Step 2: The result is 1.
|
area of rectangle with width 10and height7=70
| 70 |
Step 1: Area formula is width × height.
Step 2: 10 × 7 = 70
|
area ofrectanglewith width 30and height 4 = 120
| 120 |
Step 1: Area formula is width × height.
Step 2: 30 × 4 = 120
|
perimeter of circle with radius 19 =119.38
| 119.38 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 19 = 119.38
|
areaof circle with radius2 = 12.57
| 12.57 |
Step 1: Area formula is π × r².
Step 2: π × 2² = 3.14 × 4 = 12.57
|
area of triangle with base27 andheight 28 = 378.00
| 378 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 27 × 28 = 378.00
|
(94)+ 10 = 104
| 104 |
Step 1: Compute 94 + 10.
Step 2: The result is 104.
|
75% (8)= 3
| 3 |
Step 1: Compute 75 % 8.
Step 2: The result is 3.
|
perimeter oftrianglewith sides 33, 40,19=92
| 92 |
Step 1: Perimeter formula is a + b + c.
Step 2: 33 + 40 + 19 = 92
|
perimeterof trianglewith sides44, 21, 14 =79
| 79 |
Step 1: Perimeter formula is a + b + c.
Step 2: 44 + 21 + 14 = 79
|
area oftrianglewith base24and height36 = 432.00
| 432 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 24 × 36 = 432.00
|
perimeterof triangle withsides 30, 41, 36=107
| 107 |
Step 1: Perimeter formula is a + b + c.
Step 2: 30 + 41 + 36 = 107
|
72 - 17 =55
| 55 |
Step 1: Compute 72 - 17.
Step 2: The result is 55.
|
34%8= 2
| 2 |
Step 1: Compute 34 % 8.
Step 2: The result is 2.
|
areaof triangle withbase14 and height 38 = 266.00
| 266 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 14 × 38 = 266.00
|
area oftrianglewithbase 38andheight 16= 304.00
| 304 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 38 × 16 = 304.00
|
perimeter ofrectangle with width 12 andheight47 =118
| 118 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (12 + 47) = 2 × 59 = 118
|
56 % (6)=2
| 2 |
Step 1: Compute 56 % 6.
Step 2: The result is 2.
|
hypotenuseofright triangle withlegs 25 and 30= 39.05
| 39.05 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(25² + 30²) = sqrt(625 + 900) = sqrt(1525) = 39.05
|
5**(2) =25
| 25 |
Step 1: Compute 5 ** 2.
Step 2: The result is 25.
|
63 + (65) =128
| 128 |
Step 1: Compute 63 + 65.
Step 2: The result is 128.
|
area ofcirclewith radius12 = 452.39
| 452.39 |
Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39
|
areaofcircle with radius6 =113.10
| 113.1 |
Step 1: Area formula is π × r².
Step 2: π × 6² = 3.14 × 36 = 113.10
|
perimeter of rectanglewithwidth 15 andheight 42 = 114
| 114 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (15 + 42) = 2 × 57 = 114
|
areaof rectangle withwidth 21 and height 17 = 357
| 357 |
Step 1: Area formula is width × height.
Step 2: 21 × 17 = 357
|
perimeter of triangle with sides19,29, 29 = 77
| 77 |
Step 1: Perimeter formula is a + b + c.
Step 2: 19 + 29 + 29 = 77
|
14/ 2 = 7
| 7 |
Step 1: Compute 14 / 2.
Step 2: The result is 7.
|
perimeterofcircle with radius6 =37.70
| 37.7 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 6 = 37.70
|
26 + 70 = 96
| 96 |
Step 1: Compute 26 + 70.
Step 2: The result is 96.
|
(5) - 14 = -9
| -9 |
Step 1: Compute 5 - 14.
Step 2: The result is -9.
|
76 + 96 = 172
| 172 |
Step 1: Compute 76 + 96.
Step 2: The result is 172.
|
54 + 2= 56
| 56 |
Step 1: Compute 54 + 2.
Step 2: The result is 56.
|
hypotenuseof right trianglewith legs29 and 13 = 31.78
| 31.78 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(29² + 13²) = sqrt(841 + 169) = sqrt(1010) = 31.78
|
(56) / 7=8
| 8 |
Step 1: Compute 56 / 7.
Step 2: The result is 8.
|
10 %17 =10
| 10 |
Step 1: Compute 10 % 17.
Step 2: The result is 10.
|
(74) *(95) = 7030
| 7,030 |
Step 1: Compute 74 * 95.
Step 2: The result is 7030.
|
18-(56) = -38
| -38 |
Step 1: Compute 18 - 56.
Step 2: The result is -38.
|
1 %(13)= 1
| 1 |
Step 1: Compute 1 % 13.
Step 2: The result is 1.
|
perimeter of rectangle with width 2 andheight 26 =56
| 56 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (2 + 26) = 2 × 28 = 56
|
hypotenuseof righttriangle with legs27 and 3=27.17
| 27.17 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(27² + 3²) = sqrt(729 + 9) = sqrt(738) = 27.17
|
area of rectanglewith width 39 and height 13 =507
| 507 |
Step 1: Area formula is width × height.
Step 2: 39 × 13 = 507
|
perimeterof trianglewithsides50, 7, 12 =69
| 69 |
Step 1: Perimeter formula is a + b + c.
Step 2: 50 + 7 + 12 = 69
|
areaof trianglewith base11 andheight 19 = 104.50
| 104.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 11 × 19 = 104.50
|
29 + 75 = 104
| 104 |
Step 1: Compute 29 + 75.
Step 2: The result is 104.
|
(49) %(4) =1
| 1 |
Step 1: Compute 49 % 4.
Step 2: The result is 1.
|
hypotenuseofrighttrianglewith legs 19and 29 = 34.67
| 34.67 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(19² + 29²) = sqrt(361 + 841) = sqrt(1202) = 34.67
|
perimeter of circlewith radius2=12.57
| 12.57 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 2 = 12.57
|
24/ (4) = 6
| 6 |
Step 1: Compute 24 / 4.
Step 2: The result is 6.
|
24 + (77) = 101
| 101 |
Step 1: Compute 24 + 77.
Step 2: The result is 101.
|
perimeter of triangle with sides 41,16, 44 = 101
| 101 |
Step 1: Perimeter formula is a + b + c.
Step 2: 41 + 16 + 44 = 101
|
14 / 2=7
| 7 |
Step 1: Compute 14 / 2.
Step 2: The result is 7.
|
(95) +14 = 109
| 109 |
Step 1: Compute 95 + 14.
Step 2: The result is 109.
|
61-(84) =-23
| -23 |
Step 1: Compute 61 - 84.
Step 2: The result is -23.
|
areaof triangle with base 43 andheight 45 =967.50
| 967.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 43 × 45 = 967.50
|
perimeteroftriangle withsides 43, 44, 31= 118
| 118 |
Step 1: Perimeter formula is a + b + c.
Step 2: 43 + 44 + 31 = 118
|
(11)% (1) = 0
| 0 |
Step 1: Compute 11 % 1.
Step 2: The result is 0.
|
(2)%8 = 2
| 2 |
Step 1: Compute 2 % 8.
Step 2: The result is 2.
|
hypotenuse ofrighttriangle withlegs 9and 26= 27.51
| 27.51 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(9² + 26²) = sqrt(81 + 676) = sqrt(757) = 27.51
|
areaof rectangle with width 35 and height 23= 805
| 805 |
Step 1: Area formula is width × height.
Step 2: 35 × 23 = 805
|
95 + 97= 192
| 192 |
Step 1: Compute 95 + 97.
Step 2: The result is 192.
|
area of trianglewith base 24and height41 = 492.00
| 492 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 24 × 41 = 492.00
|
hypotenuse of right triangle with legs10and12 =15.62
| 15.62 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(10² + 12²) = sqrt(100 + 144) = sqrt(244) = 15.62
|
(91) - (31) = 60
| 60 |
Step 1: Compute 91 - 31.
Step 2: The result is 60.
|
(64) /8 =8
| 8 |
Step 1: Compute 64 / 8.
Step 2: The result is 8.
|
110 / (11) = 10
| 10 |
Step 1: Compute 110 / 11.
Step 2: The result is 10.
|
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