Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
5 ** 4 = 625
| 625 |
Step 1: Compute 5 ** 4.
Step 2: The result is 625.
|
61 %3 = 1
| 1 |
Step 1: Compute 61 % 3.
Step 2: The result is 1.
|
12 /6 =2
| 2 |
Step 1: Compute 12 / 6.
Step 2: The result is 2.
|
(12)% 1 = 0
| 0 |
Step 1: Compute 12 % 1.
Step 2: The result is 0.
|
hypotenuse ofrighttriangle with legs3 and 12 = 12.37
| 12.37 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(3² + 12²) = sqrt(9 + 144) = sqrt(153) = 12.37
|
area of trianglewith base 47 andheight6 = 141.00
| 141 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 47 × 6 = 141.00
|
perimeteroftriangle with sides 45,43, 26= 114
| 114 |
Step 1: Perimeter formula is a + b + c.
Step 2: 45 + 43 + 26 = 114
|
perimeterofrectangle withwidth 4 andheight 24 = 56
| 56 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (4 + 24) = 2 × 28 = 56
|
perimeterofrectanglewithwidth 27 and height 47 =148
| 148 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (27 + 47) = 2 × 74 = 148
|
hypotenuseofright triangle withlegs7 and 7 =9.90
| 9.9 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(7² + 7²) = sqrt(49 + 49) = sqrt(98) = 9.90
|
39%4= 3
| 3 |
Step 1: Compute 39 % 4.
Step 2: The result is 3.
|
perimeter of circle withradius 8 = 50.27
| 50.27 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27
|
4 ** (3) =64
| 64 |
Step 1: Compute 4 ** 3.
Step 2: The result is 64.
|
61 * (54)=3294
| 3,294 |
Step 1: Compute 61 * 54.
Step 2: The result is 3294.
|
hypotenuse ofright triangle withlegs24and 17= 29.41
| 29.41 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(24² + 17²) = sqrt(576 + 289) = sqrt(865) = 29.41
|
area of circle withradius 13 = 530.93
| 530.93 |
Step 1: Area formula is π × r².
Step 2: π × 13² = 3.14 × 169 = 530.93
|
(58)% 12 = 10
| 10 |
Step 1: Compute 58 % 12.
Step 2: The result is 10.
|
41-11=30
| 30 |
Step 1: Compute 41 - 11.
Step 2: The result is 30.
|
perimeter of rectanglewith width 40 and height10 = 100
| 100 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (40 + 10) = 2 × 50 = 100
|
area ofcirclewithradius7 = 153.94
| 153.94 |
Step 1: Area formula is π × r².
Step 2: π × 7² = 3.14 × 49 = 153.94
|
perimeter of circle with radius 1 = 6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
(12)/12 =1
| 1 |
Step 1: Compute 12 / 12.
Step 2: The result is 1.
|
27% 11 =5
| 5 |
Step 1: Compute 27 % 11.
Step 2: The result is 5.
|
70 + 69 = 139
| 139 |
Step 1: Compute 70 + 69.
Step 2: The result is 139.
|
perimeter oftriangle with sides2,6, 13 =21
| 21 |
Step 1: Perimeter formula is a + b + c.
Step 2: 2 + 6 + 13 = 21
|
25/ 5 = 5
| 5 |
Step 1: Compute 25 / 5.
Step 2: The result is 5.
|
(96) / (16) = 6
| 6 |
Step 1: Compute 96 / 16.
Step 2: The result is 6.
|
perimeter of circle with radius 8 = 50.27
| 50.27 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27
|
(74) -51 = 23
| 23 |
Step 1: Compute 74 - 51.
Step 2: The result is 23.
|
hypotenuseofrighttriangle with legs21 and 23 =31.14
| 31.14 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(21² + 23²) = sqrt(441 + 529) = sqrt(970) = 31.14
|
area of circle withradius 18 = 1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
area of trianglewith base 7 and height 28 = 98.00
| 98 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 7 × 28 = 98.00
|
8 ** 2 =64
| 64 |
Step 1: Compute 8 ** 2.
Step 2: The result is 64.
|
74 + 36= 110
| 110 |
Step 1: Compute 74 + 36.
Step 2: The result is 110.
|
58 % 14 = 2
| 2 |
Step 1: Compute 58 % 14.
Step 2: The result is 2.
|
perimeterof triangle withsides34,5, 11 = 50
| 50 |
Step 1: Perimeter formula is a + b + c.
Step 2: 34 + 5 + 11 = 50
|
perimeterof rectangle with width 22 and height16 =76
| 76 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (22 + 16) = 2 × 38 = 76
|
88 -47 = 41
| 41 |
Step 1: Compute 88 - 47.
Step 2: The result is 41.
|
perimeter of circle with radius18 = 113.10
| 113.1 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 18 = 113.10
|
area of circle with radius 10 = 314.16
| 314.16 |
Step 1: Area formula is π × r².
Step 2: π × 10² = 3.14 × 100 = 314.16
|
(2) ** (4) = 16
| 16 |
Step 1: Compute 2 ** 4.
Step 2: The result is 16.
|
90/15= 6
| 6 |
Step 1: Compute 90 / 15.
Step 2: The result is 6.
|
perimeter of circle withradius 5 =31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
hypotenuseof right trianglewith legs 2 and 18=18.11
| 18.11 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(2² + 18²) = sqrt(4 + 324) = sqrt(328) = 18.11
|
(38) - 86 = -48
| -48 |
Step 1: Compute 38 - 86.
Step 2: The result is -48.
|
6 ** 2 = 36
| 36 |
Step 1: Compute 6 ** 2.
Step 2: The result is 36.
|
area of triangle with base 29and height 45= 652.50
| 652.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 29 × 45 = 652.50
|
(22) + 43 = 65
| 65 |
Step 1: Compute 22 + 43.
Step 2: The result is 65.
|
hypotenuse ofright triangle withlegs 2and30 = 30.07
| 30.07 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(2² + 30²) = sqrt(4 + 900) = sqrt(904) = 30.07
|
43 + 58= 101
| 101 |
Step 1: Compute 43 + 58.
Step 2: The result is 101.
|
perimeter of rectanglewith width 6 andheight 33 =78
| 78 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (6 + 33) = 2 × 39 = 78
|
(96) * 70 = 6720
| 6,720 |
Step 1: Compute 96 * 70.
Step 2: The result is 6720.
|
hypotenuse of right triangle with legs 24 and 24=33.94
| 33.94 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(24² + 24²) = sqrt(576 + 576) = sqrt(1152) = 33.94
|
perimeterofcirclewith radius7= 43.98
| 43.98 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 7 = 43.98
|
40 / 5 = 8
| 8 |
Step 1: Compute 40 / 5.
Step 2: The result is 8.
|
area of triangle withbase30 andheight 12 = 180.00
| 180 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 30 × 12 = 180.00
|
perimeter of circle with radius 20 = 125.66
| 125.66 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 20 = 125.66
|
(1) **(3) = 1
| 1 |
Step 1: Compute 1 ** 3.
Step 2: The result is 1.
|
perimeterof circle with radius 5 =31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
24/ (6)= 4
| 4 |
Step 1: Compute 24 / 6.
Step 2: The result is 4.
|
48* 75 =3600
| 3,600 |
Step 1: Compute 48 * 75.
Step 2: The result is 3600.
|
(22) * 29 = 638
| 638 |
Step 1: Compute 22 * 29.
Step 2: The result is 638.
|
perimeter of triangle withsides 41, 4, 8= 53
| 53 |
Step 1: Perimeter formula is a + b + c.
Step 2: 41 + 4 + 8 = 53
|
perimeter of rectangle with width35 and height 20= 110
| 110 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (35 + 20) = 2 × 55 = 110
|
perimeteroftrianglewithsides4,33, 7 =44
| 44 |
Step 1: Perimeter formula is a + b + c.
Step 2: 4 + 33 + 7 = 44
|
68 % 16 = 4
| 4 |
Step 1: Compute 68 % 16.
Step 2: The result is 4.
|
area ofcircle with radius5 = 78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
24 / (3) =8
| 8 |
Step 1: Compute 24 / 3.
Step 2: The result is 8.
|
(37) % 19= 18
| 18 |
Step 1: Compute 37 % 19.
Step 2: The result is 18.
|
perimeter of circlewithradius 6 = 37.70
| 37.7 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 6 = 37.70
|
area oftrianglewithbase 8and height 50 = 200.00
| 200 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 8 × 50 = 200.00
|
areaoftriangle withbase46andheight48 =1104.00
| 1,104 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 46 × 48 = 1104.00
|
area of rectangle with width 24 and height 37 =888
| 888 |
Step 1: Area formula is width × height.
Step 2: 24 × 37 = 888
|
area ofcircle withradius17= 907.92
| 907.92 |
Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92
|
hypotenuse ofright trianglewith legs13 and23 = 26.42
| 26.42 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(13² + 23²) = sqrt(169 + 529) = sqrt(698) = 26.42
|
perimeter of rectangle withwidth 39and height23 = 124
| 124 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (39 + 23) = 2 × 62 = 124
|
100/(10)= 10
| 10 |
Step 1: Compute 100 / 10.
Step 2: The result is 10.
|
hypotenuse ofright triangle with legs13and15 =19.85
| 19.85 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(13² + 15²) = sqrt(169 + 225) = sqrt(394) = 19.85
|
34+(82)= 116
| 116 |
Step 1: Compute 34 + 82.
Step 2: The result is 116.
|
perimeter oftriangle with sides 17,15, 29= 61
| 61 |
Step 1: Perimeter formula is a + b + c.
Step 2: 17 + 15 + 29 = 61
|
(93) % 2=1
| 1 |
Step 1: Compute 93 % 2.
Step 2: The result is 1.
|
79* 40 =3160
| 3,160 |
Step 1: Compute 79 * 40.
Step 2: The result is 3160.
|
39 - (53) = -14
| -14 |
Step 1: Compute 39 - 53.
Step 2: The result is -14.
|
(73) +6 = 79
| 79 |
Step 1: Compute 73 + 6.
Step 2: The result is 79.
|
perimeter of circle with radius 9= 56.55
| 56.55 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 9 = 56.55
|
perimeter ofrectangle with width 25and height 18 = 86
| 86 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (25 + 18) = 2 × 43 = 86
|
62+71= 133
| 133 |
Step 1: Compute 62 + 71.
Step 2: The result is 133.
|
162 / 18 =9
| 9 |
Step 1: Compute 162 / 18.
Step 2: The result is 9.
|
perimeterofrectanglewith width 39 and height46=170
| 170 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (39 + 46) = 2 × 85 = 170
|
(24) / 4 = 6
| 6 |
Step 1: Compute 24 / 4.
Step 2: The result is 6.
|
62 +(24) = 86
| 86 |
Step 1: Compute 62 + 24.
Step 2: The result is 86.
|
(96) -(40) = 56
| 56 |
Step 1: Compute 96 - 40.
Step 2: The result is 56.
|
(35) + (88)= 123
| 123 |
Step 1: Compute 35 + 88.
Step 2: The result is 123.
|
perimeter of rectangle withwidth 36 and height22 =116
| 116 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (36 + 22) = 2 × 58 = 116
|
hypotenuseof righttriangle with legs 9and 12= 15.00
| 15 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(9² + 12²) = sqrt(81 + 144) = sqrt(225) = 15.00
|
2 ** 2=4
| 4 |
Step 1: Compute 2 ** 2.
Step 2: The result is 4.
|
48*13 = 624
| 624 |
Step 1: Compute 48 * 13.
Step 2: The result is 624.
|
perimeter of rectanglewith width36 and height 3= 78
| 78 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (36 + 3) = 2 × 39 = 78
|
(65) % 15 = 5
| 5 |
Step 1: Compute 65 % 15.
Step 2: The result is 5.
|
area of triangle with base 16 andheight 9 =72.00
| 72 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 16 × 9 = 72.00
|
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