Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
area of trianglewith base 38and height 22 =418.00
| 418 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 38 × 22 = 418.00
|
perimeterof triangle with sides28, 10, 6 = 44
| 44 |
Step 1: Perimeter formula is a + b + c.
Step 2: 28 + 10 + 6 = 44
|
1** 4= 1
| 1 |
Step 1: Compute 1 ** 4.
Step 2: The result is 1.
|
(10) % 15 = 10
| 10 |
Step 1: Compute 10 % 15.
Step 2: The result is 10.
|
24- 29= -5
| -5 |
Step 1: Compute 24 - 29.
Step 2: The result is -5.
|
81 * 19 =1539
| 1,539 |
Step 1: Compute 81 * 19.
Step 2: The result is 1539.
|
hypotenuseofrighttrianglewith legs22 and 11= 24.60
| 24.6 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(22² + 11²) = sqrt(484 + 121) = sqrt(605) = 24.60
|
hypotenuse ofright triangle withlegs 21and 11 = 23.71
| 23.71 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(21² + 11²) = sqrt(441 + 121) = sqrt(562) = 23.71
|
69 +22 =91
| 91 |
Step 1: Compute 69 + 22.
Step 2: The result is 91.
|
perimeter of circlewith radius 20 = 125.66
| 125.66 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 20 = 125.66
|
hypotenuse ofright triangle with legs3and23 =23.19
| 23.19 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(3² + 23²) = sqrt(9 + 529) = sqrt(538) = 23.19
|
39 - 30=9
| 9 |
Step 1: Compute 39 - 30.
Step 2: The result is 9.
|
(13) +91 = 104
| 104 |
Step 1: Compute 13 + 91.
Step 2: The result is 104.
|
perimeter of circlewith radius 6= 37.70
| 37.7 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 6 = 37.70
|
85 % (7) =1
| 1 |
Step 1: Compute 85 % 7.
Step 2: The result is 1.
|
perimeter of rectanglewith width4 and height 12 = 32
| 32 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (4 + 12) = 2 × 16 = 32
|
perimeter ofrectangle with width 42 andheight 16= 116
| 116 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (42 + 16) = 2 × 58 = 116
|
93* 100 =9300
| 9,300 |
Step 1: Compute 93 * 100.
Step 2: The result is 9300.
|
64 - 98 = -34
| -34 |
Step 1: Compute 64 - 98.
Step 2: The result is -34.
|
(38)+79=117
| 117 |
Step 1: Compute 38 + 79.
Step 2: The result is 117.
|
72- 41 = 31
| 31 |
Step 1: Compute 72 - 41.
Step 2: The result is 31.
|
9** (3)= 729
| 729 |
Step 1: Compute 9 ** 3.
Step 2: The result is 729.
|
area of circlewith radius3= 28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
6 **(2)= 36
| 36 |
Step 1: Compute 6 ** 2.
Step 2: The result is 36.
|
area ofcircle with radius 19 = 1134.11
| 1,134.11 |
Step 1: Area formula is π × r².
Step 2: π × 19² = 3.14 × 361 = 1134.11
|
areaof circle with radius18 = 1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
area of circlewith radius 15 =706.86
| 706.86 |
Step 1: Area formula is π × r².
Step 2: π × 15² = 3.14 × 225 = 706.86
|
44 %2 =0
| 0 |
Step 1: Compute 44 % 2.
Step 2: The result is 0.
|
79 + 46 = 125
| 125 |
Step 1: Compute 79 + 46.
Step 2: The result is 125.
|
(31)- 79 = -48
| -48 |
Step 1: Compute 31 - 79.
Step 2: The result is -48.
|
97 %18= 7
| 7 |
Step 1: Compute 97 % 18.
Step 2: The result is 7.
|
areaofrectanglewithwidth7andheight 13 = 91
| 91 |
Step 1: Area formula is width × height.
Step 2: 7 × 13 = 91
|
perimeter of rectanglewith width 8 and height32 =80
| 80 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (8 + 32) = 2 × 40 = 80
|
area of rectangle with width 16and height 31 = 496
| 496 |
Step 1: Area formula is width × height.
Step 2: 16 × 31 = 496
|
(80) - (95)= -15
| -15 |
Step 1: Compute 80 - 95.
Step 2: The result is -15.
|
28 - 91= -63
| -63 |
Step 1: Compute 28 - 91.
Step 2: The result is -63.
|
areaof triangle with base22 and height30 =330.00
| 330 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 22 × 30 = 330.00
|
(70) *32 =2240
| 2,240 |
Step 1: Compute 70 * 32.
Step 2: The result is 2240.
|
6 ** 2 = 36
| 36 |
Step 1: Compute 6 ** 2.
Step 2: The result is 36.
|
43 - (81)= -38
| -38 |
Step 1: Compute 43 - 81.
Step 2: The result is -38.
|
160 / 20 = 8
| 8 |
Step 1: Compute 160 / 20.
Step 2: The result is 8.
|
areaof rectangle with width 8 and height 37 =296
| 296 |
Step 1: Area formula is width × height.
Step 2: 8 × 37 = 296
|
hypotenuseof righttriangle withlegs 14 and 30 =33.11
| 33.11 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(14² + 30²) = sqrt(196 + 900) = sqrt(1096) = 33.11
|
perimeter of circle withradius 16 = 100.53
| 100.53 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 16 = 100.53
|
(24)- 73=-49
| -49 |
Step 1: Compute 24 - 73.
Step 2: The result is -49.
|
perimeter of circle with radius 4 = 25.13
| 25.13 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 4 = 25.13
|
1 + 23 =24
| 24 |
Step 1: Compute 1 + 23.
Step 2: The result is 24.
|
11 /11 = 1
| 1 |
Step 1: Compute 11 / 11.
Step 2: The result is 1.
|
6 ** 2 =36
| 36 |
Step 1: Compute 6 ** 2.
Step 2: The result is 36.
|
area ofcircle withradius 9 =254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
74 -(67) = 7
| 7 |
Step 1: Compute 74 - 67.
Step 2: The result is 7.
|
40 /10 = 4
| 4 |
Step 1: Compute 40 / 10.
Step 2: The result is 4.
|
9 ** 4 = 6561
| 6,561 |
Step 1: Compute 9 ** 4.
Step 2: The result is 6561.
|
84 * (83) = 6972
| 6,972 |
Step 1: Compute 84 * 83.
Step 2: The result is 6972.
|
84 +98= 182
| 182 |
Step 1: Compute 84 + 98.
Step 2: The result is 182.
|
120 / 15 = 8
| 8 |
Step 1: Compute 120 / 15.
Step 2: The result is 8.
|
area of circle withradius 12=452.39
| 452.39 |
Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39
|
(46)+54 =100
| 100 |
Step 1: Compute 46 + 54.
Step 2: The result is 100.
|
61 * (65) = 3965
| 3,965 |
Step 1: Compute 61 * 65.
Step 2: The result is 3965.
|
area oftriangle withbase27 and height 28 = 378.00
| 378 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 27 × 28 = 378.00
|
(9) -55 = -46
| -46 |
Step 1: Compute 9 - 55.
Step 2: The result is -46.
|
perimeter of circlewith radius 1 = 6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
46 %7 = 4
| 4 |
Step 1: Compute 46 % 7.
Step 2: The result is 4.
|
perimeterofcircle with radius 4= 25.13
| 25.13 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 4 = 25.13
|
hypotenuse of righttrianglewith legs1 and 3 = 3.16
| 3.16 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(1² + 3²) = sqrt(1 + 9) = sqrt(10) = 3.16
|
10 * 3 = 30
| 30 |
Step 1: Compute 10 * 3.
Step 2: The result is 30.
|
perimeter of rectangle withwidth 48 andheight 18= 132
| 132 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (48 + 18) = 2 × 66 = 132
|
66 -38 = 28
| 28 |
Step 1: Compute 66 - 38.
Step 2: The result is 28.
|
perimeter ofcirclewith radius 5=31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
34 / (17)= 2
| 2 |
Step 1: Compute 34 / 17.
Step 2: The result is 2.
|
(27) / 3 = 9
| 9 |
Step 1: Compute 27 / 3.
Step 2: The result is 9.
|
perimeter of rectangle withwidth 47 and height10= 114
| 114 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (47 + 10) = 2 × 57 = 114
|
area oftrianglewithbase43 and height 21 = 451.50
| 451.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 43 × 21 = 451.50
|
area ofcircle withradius18= 1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
hypotenuseof righttrianglewith legs 6 and 13=14.32
| 14.32 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(6² + 13²) = sqrt(36 + 169) = sqrt(205) = 14.32
|
12 / 4= 3
| 3 |
Step 1: Compute 12 / 4.
Step 2: The result is 3.
|
9 **2 = 81
| 81 |
Step 1: Compute 9 ** 2.
Step 2: The result is 81.
|
area oftriangle with base 29 andheight27 = 391.50
| 391.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 29 × 27 = 391.50
|
hypotenuse ofrighttriangle withlegs21 and5 = 21.59
| 21.59 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(21² + 5²) = sqrt(441 + 25) = sqrt(466) = 21.59
|
perimeterofcirclewith radius16=100.53
| 100.53 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 16 = 100.53
|
areaof circle withradius 4 = 50.27
| 50.27 |
Step 1: Area formula is π × r².
Step 2: π × 4² = 3.14 × 16 = 50.27
|
61 % 11 = 6
| 6 |
Step 1: Compute 61 % 11.
Step 2: The result is 6.
|
(23) % (18) = 5
| 5 |
Step 1: Compute 23 % 18.
Step 2: The result is 5.
|
7 / 1 = 7
| 7 |
Step 1: Compute 7 / 1.
Step 2: The result is 7.
|
9 % 17= 9
| 9 |
Step 1: Compute 9 % 17.
Step 2: The result is 9.
|
area oftriangle with base16 and height 5 = 40.00
| 40 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 16 × 5 = 40.00
|
68 + (3) =71
| 71 |
Step 1: Compute 68 + 3.
Step 2: The result is 71.
|
19 + (91)= 110
| 110 |
Step 1: Compute 19 + 91.
Step 2: The result is 110.
|
14 * 26 = 364
| 364 |
Step 1: Compute 14 * 26.
Step 2: The result is 364.
|
areaof rectangle withwidth 47 and height 31 = 1457
| 1,457 |
Step 1: Area formula is width × height.
Step 2: 47 × 31 = 1457
|
100 - (50) =50
| 50 |
Step 1: Compute 100 - 50.
Step 2: The result is 50.
|
areaof rectangle with width19 andheight 36 = 684
| 684 |
Step 1: Area formula is width × height.
Step 2: 19 × 36 = 684
|
perimeter of rectanglewith width 39 andheight 6 =90
| 90 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (39 + 6) = 2 × 45 = 90
|
38+ (90) = 128
| 128 |
Step 1: Compute 38 + 90.
Step 2: The result is 128.
|
hypotenuse of righttrianglewith legs 7and 3 = 7.62
| 7.62 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(7² + 3²) = sqrt(49 + 9) = sqrt(58) = 7.62
|
area of circlewith radius 19 = 1134.11
| 1,134.11 |
Step 1: Area formula is π × r².
Step 2: π × 19² = 3.14 × 361 = 1134.11
|
8** 3 =512
| 512 |
Step 1: Compute 8 ** 3.
Step 2: The result is 512.
|
area of circle with radius 19 = 1134.11
| 1,134.11 |
Step 1: Area formula is π × r².
Step 2: π × 19² = 3.14 × 361 = 1134.11
|
hypotenuseof right triangle with legs26 and 12 = 28.64
| 28.64 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(26² + 12²) = sqrt(676 + 144) = sqrt(820) = 28.64
|
areaof triangle withbase47and height 42=987.00
| 987 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 47 × 42 = 987.00
|
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