Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
area ofrectangle with width 12 and height 6 = 72
| 72 |
Step 1: Area formula is width × height.
Step 2: 12 × 6 = 72
|
9+70= 79
| 79 |
Step 1: Compute 9 + 70.
Step 2: The result is 79.
|
perimeter of circle withradius8 = 50.27
| 50.27 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 8 = 50.27
|
perimeter of triangle with sides31, 18, 39 = 88
| 88 |
Step 1: Perimeter formula is a + b + c.
Step 2: 31 + 18 + 39 = 88
|
34 % 19 = 15
| 15 |
Step 1: Compute 34 % 19.
Step 2: The result is 15.
|
perimeter of circle with radius 6 = 37.70
| 37.7 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 6 = 37.70
|
perimeter of triangle withsides 23, 47, 5= 75
| 75 |
Step 1: Perimeter formula is a + b + c.
Step 2: 23 + 47 + 5 = 75
|
areaof circle withradius9 = 254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
(9) ** 4= 6561
| 6,561 |
Step 1: Compute 9 ** 4.
Step 2: The result is 6561.
|
(6) ** (3)= 216
| 216 |
Step 1: Compute 6 ** 3.
Step 2: The result is 216.
|
areaoftrianglewith base 28 andheight 11=154.00
| 154 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 28 × 11 = 154.00
|
hypotenuse of righttriangle with legs1and4 = 4.12
| 4.12 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(1² + 4²) = sqrt(1 + 16) = sqrt(17) = 4.12
|
19- 7 = 12
| 12 |
Step 1: Compute 19 - 7.
Step 2: The result is 12.
|
36- 89 = -53
| -53 |
Step 1: Compute 36 - 89.
Step 2: The result is -53.
|
66 +79= 145
| 145 |
Step 1: Compute 66 + 79.
Step 2: The result is 145.
|
28/4 = 7
| 7 |
Step 1: Compute 28 / 4.
Step 2: The result is 7.
|
76* (94) =7144
| 7,144 |
Step 1: Compute 76 * 94.
Step 2: The result is 7144.
|
8 / (8) = 1
| 1 |
Step 1: Compute 8 / 8.
Step 2: The result is 1.
|
hypotenuse ofright triangle with legs 2and 24=24.08
| 24.08 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(2² + 24²) = sqrt(4 + 576) = sqrt(580) = 24.08
|
99* 64=6336
| 6,336 |
Step 1: Compute 99 * 64.
Step 2: The result is 6336.
|
perimeter of triangle with sides48, 4, 11 = 63
| 63 |
Step 1: Perimeter formula is a + b + c.
Step 2: 48 + 4 + 11 = 63
|
(10)** (2)= 100
| 100 |
Step 1: Compute 10 ** 2.
Step 2: The result is 100.
|
perimeterofcircle withradius 18 =113.10
| 113.1 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 18 = 113.10
|
6 + 18 = 24
| 24 |
Step 1: Compute 6 + 18.
Step 2: The result is 24.
|
(54) / 9 =6
| 6 |
Step 1: Compute 54 / 9.
Step 2: The result is 6.
|
75- 33 = 42
| 42 |
Step 1: Compute 75 - 33.
Step 2: The result is 42.
|
43 - 38= 5
| 5 |
Step 1: Compute 43 - 38.
Step 2: The result is 5.
|
(98)- (29) = 69
| 69 |
Step 1: Compute 98 - 29.
Step 2: The result is 69.
|
areaoftriangle with base1andheight 23= 11.50
| 11.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 1 × 23 = 11.50
|
perimeter oftrianglewith sides 37, 6, 1 = 44
| 44 |
Step 1: Perimeter formula is a + b + c.
Step 2: 37 + 6 + 1 = 44
|
hypotenuseof right trianglewithlegs 9and 4 = 9.85
| 9.85 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(9² + 4²) = sqrt(81 + 16) = sqrt(97) = 9.85
|
72 % (20) =12
| 12 |
Step 1: Compute 72 % 20.
Step 2: The result is 12.
|
perimeterof circle withradius11 = 69.12
| 69.12 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 11 = 69.12
|
perimeter of triangle with sides 16,15, 29 =60
| 60 |
Step 1: Perimeter formula is a + b + c.
Step 2: 16 + 15 + 29 = 60
|
perimeter ofrectangle with width 32 andheight 40= 144
| 144 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (32 + 40) = 2 × 72 = 144
|
(28) / 7=4
| 4 |
Step 1: Compute 28 / 7.
Step 2: The result is 4.
|
(65) % (10) =5
| 5 |
Step 1: Compute 65 % 10.
Step 2: The result is 5.
|
48 / 8 = 6
| 6 |
Step 1: Compute 48 / 8.
Step 2: The result is 6.
|
8** 2= 64
| 64 |
Step 1: Compute 8 ** 2.
Step 2: The result is 64.
|
hypotenuse of righttrianglewithlegs12 and 9 =15.00
| 15 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(12² + 9²) = sqrt(144 + 81) = sqrt(225) = 15.00
|
areaof circle with radius 14 = 615.75
| 615.75 |
Step 1: Area formula is π × r².
Step 2: π × 14² = 3.14 × 196 = 615.75
|
(77) / (11)= 7
| 7 |
Step 1: Compute 77 / 11.
Step 2: The result is 7.
|
(6) / 1=6
| 6 |
Step 1: Compute 6 / 1.
Step 2: The result is 6.
|
hypotenuse of righttrianglewithlegs4and 5 = 6.40
| 6.4 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(4² + 5²) = sqrt(16 + 25) = sqrt(41) = 6.40
|
perimeterof rectangle with width 22andheight29 = 102
| 102 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (22 + 29) = 2 × 51 = 102
|
perimeteroftriangle with sides 40, 37,23 =100
| 100 |
Step 1: Perimeter formula is a + b + c.
Step 2: 40 + 37 + 23 = 100
|
perimeter of circlewith radius 11 = 69.12
| 69.12 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 11 = 69.12
|
area oftrianglewithbase 50andheight 16 = 400.00
| 400 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 50 × 16 = 400.00
|
perimeterof rectangle with width 22and height 27 = 98
| 98 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (22 + 27) = 2 × 49 = 98
|
96 /16 =6
| 6 |
Step 1: Compute 96 / 16.
Step 2: The result is 6.
|
(153) /17 = 9
| 9 |
Step 1: Compute 153 / 17.
Step 2: The result is 9.
|
hypotenuse ofright trianglewithlegs6and11= 12.53
| 12.53 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(6² + 11²) = sqrt(36 + 121) = sqrt(157) = 12.53
|
46 - 11 = 35
| 35 |
Step 1: Compute 46 - 11.
Step 2: The result is 35.
|
(51) +59 = 110
| 110 |
Step 1: Compute 51 + 59.
Step 2: The result is 110.
|
(5)**2=25
| 25 |
Step 1: Compute 5 ** 2.
Step 2: The result is 25.
|
area of triangle withbase 18and height5 = 45.00
| 45 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 18 × 5 = 45.00
|
perimeter of triangle with sides 48,35, 35=118
| 118 |
Step 1: Perimeter formula is a + b + c.
Step 2: 48 + 35 + 35 = 118
|
area ofrectanglewith width 40 andheight 43 = 1720
| 1,720 |
Step 1: Area formula is width × height.
Step 2: 40 × 43 = 1720
|
1 ** (3)=1
| 1 |
Step 1: Compute 1 ** 3.
Step 2: The result is 1.
|
(2)** 2 = 4
| 4 |
Step 1: Compute 2 ** 2.
Step 2: The result is 4.
|
15 / 5 = 3
| 3 |
Step 1: Compute 15 / 5.
Step 2: The result is 3.
|
hypotenuseof right trianglewith legs 26 and22 =34.06
| 34.06 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(26² + 22²) = sqrt(676 + 484) = sqrt(1160) = 34.06
|
3 **2 = 9
| 9 |
Step 1: Compute 3 ** 2.
Step 2: The result is 9.
|
95 * (67) = 6365
| 6,365 |
Step 1: Compute 95 * 67.
Step 2: The result is 6365.
|
hypotenuse of right trianglewithlegs5 and29 =29.43
| 29.43 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(5² + 29²) = sqrt(25 + 841) = sqrt(866) = 29.43
|
areaof rectanglewith width2 and height 43 = 86
| 86 |
Step 1: Area formula is width × height.
Step 2: 2 × 43 = 86
|
3 **(3)= 27
| 27 |
Step 1: Compute 3 ** 3.
Step 2: The result is 27.
|
(9) / (1) = 9
| 9 |
Step 1: Compute 9 / 1.
Step 2: The result is 9.
|
hypotenuse of righttriangle withlegs9 and 13 =15.81
| 15.81 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(9² + 13²) = sqrt(81 + 169) = sqrt(250) = 15.81
|
47* 28 =1316
| 1,316 |
Step 1: Compute 47 * 28.
Step 2: The result is 1316.
|
hypotenuseofright triangle with legs18 and30 = 34.99
| 34.99 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(18² + 30²) = sqrt(324 + 900) = sqrt(1224) = 34.99
|
7 ** (2) = 49
| 49 |
Step 1: Compute 7 ** 2.
Step 2: The result is 49.
|
perimeter ofrectangle with width 48and height 3 =102
| 102 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (48 + 3) = 2 × 51 = 102
|
17- (36)= -19
| -19 |
Step 1: Compute 17 - 36.
Step 2: The result is -19.
|
47 - 97 =-50
| -50 |
Step 1: Compute 47 - 97.
Step 2: The result is -50.
|
perimeter ofrectanglewith width 2and height45= 94
| 94 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (2 + 45) = 2 × 47 = 94
|
16* 82 =1312
| 1,312 |
Step 1: Compute 16 * 82.
Step 2: The result is 1312.
|
area ofcirclewithradius8 = 201.06
| 201.06 |
Step 1: Area formula is π × r².
Step 2: π × 8² = 3.14 × 64 = 201.06
|
44* (55) = 2420
| 2,420 |
Step 1: Compute 44 * 55.
Step 2: The result is 2420.
|
area ofcircle with radius 1= 3.14
| 3.14 |
Step 1: Area formula is π × r².
Step 2: π × 1² = 3.14 × 1 = 3.14
|
(36) *17 =612
| 612 |
Step 1: Compute 36 * 17.
Step 2: The result is 612.
|
perimeter of circlewith radius17 = 106.81
| 106.81 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 17 = 106.81
|
(6)+ 95=101
| 101 |
Step 1: Compute 6 + 95.
Step 2: The result is 101.
|
(52) / 13 =4
| 4 |
Step 1: Compute 52 / 13.
Step 2: The result is 4.
|
58 - 100 = -42
| -42 |
Step 1: Compute 58 - 100.
Step 2: The result is -42.
|
(16) /2 = 8
| 8 |
Step 1: Compute 16 / 2.
Step 2: The result is 8.
|
90 - 78 = 12
| 12 |
Step 1: Compute 90 - 78.
Step 2: The result is 12.
|
perimeter of rectangle withwidth 34 and height42 = 152
| 152 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (34 + 42) = 2 × 76 = 152
|
(89) -47=42
| 42 |
Step 1: Compute 89 - 47.
Step 2: The result is 42.
|
hypotenuse of righttriangle with legs 17 and1 =17.03
| 17.03 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(17² + 1²) = sqrt(289 + 1) = sqrt(290) = 17.03
|
perimeter of circlewith radius 9 = 56.55
| 56.55 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 9 = 56.55
|
area of circle with radius 3= 28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
(91)+ 78 = 169
| 169 |
Step 1: Compute 91 + 78.
Step 2: The result is 169.
|
13 -(7) = 6
| 6 |
Step 1: Compute 13 - 7.
Step 2: The result is 6.
|
(10) ** 2 =100
| 100 |
Step 1: Compute 10 ** 2.
Step 2: The result is 100.
|
area of trianglewith base31 andheight 17 = 263.50
| 263.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 31 × 17 = 263.50
|
areaofcircle with radius 10 = 314.16
| 314.16 |
Step 1: Area formula is π × r².
Step 2: π × 10² = 3.14 × 100 = 314.16
|
area of circle withradius 5 =78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
56 /8= 7
| 7 |
Step 1: Compute 56 / 8.
Step 2: The result is 7.
|
4% 19 =4
| 4 |
Step 1: Compute 4 % 19.
Step 2: The result is 4.
|
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.