Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
(20) + (9) =29
| 29 |
Step 1: Compute 20 + 9.
Step 2: The result is 29.
|
16/(4) = 4
| 4 |
Step 1: Compute 16 / 4.
Step 2: The result is 4.
|
area of circlewith radius11 = 380.13
| 380.13 |
Step 1: Area formula is π × r².
Step 2: π × 11² = 3.14 × 121 = 380.13
|
(13)-95= -82
| -82 |
Step 1: Compute 13 - 95.
Step 2: The result is -82.
|
perimeter ofrectangle with width 42 and height8= 100
| 100 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (42 + 8) = 2 × 50 = 100
|
5**4 = 625
| 625 |
Step 1: Compute 5 ** 4.
Step 2: The result is 625.
|
(43)+4 =47
| 47 |
Step 1: Compute 43 + 4.
Step 2: The result is 47.
|
perimeter of rectangle with width10andheight12= 44
| 44 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (10 + 12) = 2 × 22 = 44
|
90/10 = 9
| 9 |
Step 1: Compute 90 / 10.
Step 2: The result is 9.
|
171/ (19) = 9
| 9 |
Step 1: Compute 171 / 19.
Step 2: The result is 9.
|
hypotenuse of right triangle with legs 3 and 28=28.16
| 28.16 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(3² + 28²) = sqrt(9 + 784) = sqrt(793) = 28.16
|
perimeter oftriangle with sides 11, 43, 29=83
| 83 |
Step 1: Perimeter formula is a + b + c.
Step 2: 11 + 43 + 29 = 83
|
84 - 18 = 66
| 66 |
Step 1: Compute 84 - 18.
Step 2: The result is 66.
|
(46) * 45=2070
| 2,070 |
Step 1: Compute 46 * 45.
Step 2: The result is 2070.
|
(14) - 55 =-41
| -41 |
Step 1: Compute 14 - 55.
Step 2: The result is -41.
|
areaof triangle with base 15 andheight 6= 45.00
| 45 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 15 × 6 = 45.00
|
(32)+(100)= 132
| 132 |
Step 1: Compute 32 + 100.
Step 2: The result is 132.
|
10 ** (2) = 100
| 100 |
Step 1: Compute 10 ** 2.
Step 2: The result is 100.
|
hypotenuse of righttriangle with legs 5 and 22 =22.56
| 22.56 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(5² + 22²) = sqrt(25 + 484) = sqrt(509) = 22.56
|
area of rectanglewithwidth46 and height48 = 2208
| 2,208 |
Step 1: Area formula is width × height.
Step 2: 46 × 48 = 2208
|
area of circle with radius16= 804.25
| 804.25 |
Step 1: Area formula is π × r².
Step 2: π × 16² = 3.14 × 256 = 804.25
|
perimeter of triangle with sides 27, 4, 43 = 74
| 74 |
Step 1: Perimeter formula is a + b + c.
Step 2: 27 + 4 + 43 = 74
|
areaofcircle withradius 10 =314.16
| 314.16 |
Step 1: Area formula is π × r².
Step 2: π × 10² = 3.14 × 100 = 314.16
|
area of circle withradius 10 =314.16
| 314.16 |
Step 1: Area formula is π × r².
Step 2: π × 10² = 3.14 × 100 = 314.16
|
hypotenuseof right trianglewith legs27 and 21 =34.21
| 34.21 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(27² + 21²) = sqrt(729 + 441) = sqrt(1170) = 34.21
|
hypotenuseof righttriangle with legs 25 and 20 = 32.02
| 32.02 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(25² + 20²) = sqrt(625 + 400) = sqrt(1025) = 32.02
|
9 ** 2 = 81
| 81 |
Step 1: Compute 9 ** 2.
Step 2: The result is 81.
|
hypotenuse of righttriangle with legs 3 and 13 = 13.34
| 13.34 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(3² + 13²) = sqrt(9 + 169) = sqrt(178) = 13.34
|
perimeteroftriangle with sides24, 38, 1= 63
| 63 |
Step 1: Perimeter formula is a + b + c.
Step 2: 24 + 38 + 1 = 63
|
74 - 59 =15
| 15 |
Step 1: Compute 74 - 59.
Step 2: The result is 15.
|
(8) ** (4) = 4096
| 4,096 |
Step 1: Compute 8 ** 4.
Step 2: The result is 4096.
|
hypotenuse of righttrianglewithlegs25 and 1= 25.02
| 25.02 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(25² + 1²) = sqrt(625 + 1) = sqrt(626) = 25.02
|
area ofcircle with radius 15 =706.86
| 706.86 |
Step 1: Area formula is π × r².
Step 2: π × 15² = 3.14 × 225 = 706.86
|
perimeterofrectanglewithwidth41and height 19 =120
| 120 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (41 + 19) = 2 × 60 = 120
|
hypotenuseofright triangle with legs 5 and 11 = 12.08
| 12.08 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(5² + 11²) = sqrt(25 + 121) = sqrt(146) = 12.08
|
areaof circle with radius3 = 28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
2** 2= 4
| 4 |
Step 1: Compute 2 ** 2.
Step 2: The result is 4.
|
perimeterof rectanglewith width 27 andheight 42 =138
| 138 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (27 + 42) = 2 × 69 = 138
|
perimeter of circlewith radius 10=62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
170 / 17 = 10
| 10 |
Step 1: Compute 170 / 17.
Step 2: The result is 10.
|
perimeter ofcircle with radius1 =6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
(41) % 19 = 3
| 3 |
Step 1: Compute 41 % 19.
Step 2: The result is 3.
|
hypotenuse ofrighttriangle with legs 18and15 = 23.43
| 23.43 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(18² + 15²) = sqrt(324 + 225) = sqrt(549) = 23.43
|
areaof circle withradius5=78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
74% 9 = 2
| 2 |
Step 1: Compute 74 % 9.
Step 2: The result is 2.
|
9 % 4 =1
| 1 |
Step 1: Compute 9 % 4.
Step 2: The result is 1.
|
(34) +(48) =82
| 82 |
Step 1: Compute 34 + 48.
Step 2: The result is 82.
|
50-86= -36
| -36 |
Step 1: Compute 50 - 86.
Step 2: The result is -36.
|
area of circlewith radius 1= 3.14
| 3.14 |
Step 1: Area formula is π × r².
Step 2: π × 1² = 3.14 × 1 = 3.14
|
hypotenuse of righttriangle with legs 21 and7= 22.14
| 22.14 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(21² + 7²) = sqrt(441 + 49) = sqrt(490) = 22.14
|
perimeterofrectangle withwidth 17and height 45 =124
| 124 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (17 + 45) = 2 × 62 = 124
|
28-32 = -4
| -4 |
Step 1: Compute 28 - 32.
Step 2: The result is -4.
|
74* 47 = 3478
| 3,478 |
Step 1: Compute 74 * 47.
Step 2: The result is 3478.
|
(12)/3 = 4
| 4 |
Step 1: Compute 12 / 3.
Step 2: The result is 4.
|
87 %3 = 0
| 0 |
Step 1: Compute 87 % 3.
Step 2: The result is 0.
|
54- 57= -3
| -3 |
Step 1: Compute 54 - 57.
Step 2: The result is -3.
|
74 * 26=1924
| 1,924 |
Step 1: Compute 74 * 26.
Step 2: The result is 1924.
|
4** 4=256
| 256 |
Step 1: Compute 4 ** 4.
Step 2: The result is 256.
|
area of circle withradius 17= 907.92
| 907.92 |
Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92
|
area of rectanglewith width38 andheight 13= 494
| 494 |
Step 1: Area formula is width × height.
Step 2: 38 × 13 = 494
|
hypotenuseof righttriangle with legs 12 and 10= 15.62
| 15.62 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(12² + 10²) = sqrt(144 + 100) = sqrt(244) = 15.62
|
perimeter of triangle withsides 40,39, 33= 112
| 112 |
Step 1: Perimeter formula is a + b + c.
Step 2: 40 + 39 + 33 = 112
|
86 % (3)= 2
| 2 |
Step 1: Compute 86 % 3.
Step 2: The result is 2.
|
(1) ** (3)= 1
| 1 |
Step 1: Compute 1 ** 3.
Step 2: The result is 1.
|
(73) * (92)= 6716
| 6,716 |
Step 1: Compute 73 * 92.
Step 2: The result is 6716.
|
hypotenuseof right triangle with legs 29and 25 = 38.29
| 38.29 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(29² + 25²) = sqrt(841 + 625) = sqrt(1466) = 38.29
|
perimeter oftriangle with sides 5, 45,4 = 54
| 54 |
Step 1: Perimeter formula is a + b + c.
Step 2: 5 + 45 + 4 = 54
|
perimeter ofrectangle with width 40andheight 48 = 176
| 176 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (40 + 48) = 2 × 88 = 176
|
10 /1 = 10
| 10 |
Step 1: Compute 10 / 1.
Step 2: The result is 10.
|
area of triangle with base25 and height33 = 412.50
| 412.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 25 × 33 = 412.50
|
(6)*43= 258
| 258 |
Step 1: Compute 6 * 43.
Step 2: The result is 258.
|
9 ** 4= 6561
| 6,561 |
Step 1: Compute 9 ** 4.
Step 2: The result is 6561.
|
98 - (76)=22
| 22 |
Step 1: Compute 98 - 76.
Step 2: The result is 22.
|
hypotenuseofright triangle with legs 26and 11 = 28.23
| 28.23 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(26² + 11²) = sqrt(676 + 121) = sqrt(797) = 28.23
|
(17) -44=-27
| -27 |
Step 1: Compute 17 - 44.
Step 2: The result is -27.
|
38 +15 = 53
| 53 |
Step 1: Compute 38 + 15.
Step 2: The result is 53.
|
area ofrectangle withwidth 8 andheight36 =288
| 288 |
Step 1: Area formula is width × height.
Step 2: 8 × 36 = 288
|
area of triangle with base39andheight 43 = 838.50
| 838.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 39 × 43 = 838.50
|
7** 4 =2401
| 2,401 |
Step 1: Compute 7 ** 4.
Step 2: The result is 2401.
|
(9) **4 =6561
| 6,561 |
Step 1: Compute 9 ** 4.
Step 2: The result is 6561.
|
perimeterof circlewith radius 10 = 62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
99 - 73= 26
| 26 |
Step 1: Compute 99 - 73.
Step 2: The result is 26.
|
47 + (10) = 57
| 57 |
Step 1: Compute 47 + 10.
Step 2: The result is 57.
|
30 /(5)= 6
| 6 |
Step 1: Compute 30 / 5.
Step 2: The result is 6.
|
areaoftrianglewithbase32and height 8 = 128.00
| 128 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 32 × 8 = 128.00
|
hypotenuse of right triangle withlegs 11 and29= 31.02
| 31.02 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(11² + 29²) = sqrt(121 + 841) = sqrt(962) = 31.02
|
perimeter of circle withradius17 =106.81
| 106.81 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 17 = 106.81
|
126 / 18= 7
| 7 |
Step 1: Compute 126 / 18.
Step 2: The result is 7.
|
perimeter of triangle withsides42, 14, 49 = 105
| 105 |
Step 1: Perimeter formula is a + b + c.
Step 2: 42 + 14 + 49 = 105
|
hypotenuse ofright triangle withlegs 25 and26 = 36.07
| 36.07 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(25² + 26²) = sqrt(625 + 676) = sqrt(1301) = 36.07
|
67 + 1 = 68
| 68 |
Step 1: Compute 67 + 1.
Step 2: The result is 68.
|
perimeter oftriangle with sides 50, 23, 26= 99
| 99 |
Step 1: Perimeter formula is a + b + c.
Step 2: 50 + 23 + 26 = 99
|
45+38 = 83
| 83 |
Step 1: Compute 45 + 38.
Step 2: The result is 83.
|
area of circlewith radius 10= 314.16
| 314.16 |
Step 1: Area formula is π × r².
Step 2: π × 10² = 3.14 × 100 = 314.16
|
24+ 7 = 31
| 31 |
Step 1: Compute 24 + 7.
Step 2: The result is 31.
|
(100) % 15= 10
| 10 |
Step 1: Compute 100 % 15.
Step 2: The result is 10.
|
(7) * 22= 154
| 154 |
Step 1: Compute 7 * 22.
Step 2: The result is 154.
|
2 * 5 =10
| 10 |
Step 1: Compute 2 * 5.
Step 2: The result is 10.
|
5 ** 4 =625
| 625 |
Step 1: Compute 5 ** 4.
Step 2: The result is 625.
|
area ofcircle withradius 1=3.14
| 3.14 |
Step 1: Area formula is π × r².
Step 2: π × 1² = 3.14 × 1 = 3.14
|
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