Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
perimeter ofcircle with radius 3 =18.85
| 18.85 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85
|
perimeter of circle with radius1 =6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
14+ 14 =28
| 28 |
Step 1: Compute 14 + 14.
Step 2: The result is 28.
|
hypotenuse ofrighttriangle with legs 3 and13 = 13.34
| 13.34 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(3² + 13²) = sqrt(9 + 169) = sqrt(178) = 13.34
|
14 / 7 =2
| 2 |
Step 1: Compute 14 / 7.
Step 2: The result is 2.
|
98 - (20) = 78
| 78 |
Step 1: Compute 98 - 20.
Step 2: The result is 78.
|
area ofcircle withradius 1 =3.14
| 3.14 |
Step 1: Area formula is π × r².
Step 2: π × 1² = 3.14 × 1 = 3.14
|
perimeter ofrectanglewith width42and height39=162
| 162 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (42 + 39) = 2 × 81 = 162
|
9 ** 3 = 729
| 729 |
Step 1: Compute 9 ** 3.
Step 2: The result is 729.
|
64 / 16=4
| 4 |
Step 1: Compute 64 / 16.
Step 2: The result is 4.
|
perimeter ofrectangle with width 27and height 10 =74
| 74 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (27 + 10) = 2 × 37 = 74
|
hypotenuseof right triangle with legs 13and14 = 19.10
| 19.1 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(13² + 14²) = sqrt(169 + 196) = sqrt(365) = 19.10
|
97*9 =873
| 873 |
Step 1: Compute 97 * 9.
Step 2: The result is 873.
|
4**2=16
| 16 |
Step 1: Compute 4 ** 2.
Step 2: The result is 16.
|
perimeterof rectangle with width 4andheight14=36
| 36 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (4 + 14) = 2 × 18 = 36
|
(64)+65 = 129
| 129 |
Step 1: Compute 64 + 65.
Step 2: The result is 129.
|
area ofrectangle withwidth 29 andheight 17=493
| 493 |
Step 1: Area formula is width × height.
Step 2: 29 × 17 = 493
|
(1) ** 4 =1
| 1 |
Step 1: Compute 1 ** 4.
Step 2: The result is 1.
|
(71)- (8)=63
| 63 |
Step 1: Compute 71 - 8.
Step 2: The result is 63.
|
perimeter of rectangle with width49 and height 47=192
| 192 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (49 + 47) = 2 × 96 = 192
|
area of circlewith radius20 =1256.64
| 1,256.64 |
Step 1: Area formula is π × r².
Step 2: π × 20² = 3.14 × 400 = 1256.64
|
49 + (29)=78
| 78 |
Step 1: Compute 49 + 29.
Step 2: The result is 78.
|
area of rectanglewith width 4andheight4= 16
| 16 |
Step 1: Area formula is width × height.
Step 2: 4 × 4 = 16
|
areaofrectangle with width18 and height8 = 144
| 144 |
Step 1: Area formula is width × height.
Step 2: 18 × 8 = 144
|
perimeter of rectangle withwidth 13 and height 28 = 82
| 82 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (13 + 28) = 2 × 41 = 82
|
90 / 10 =9
| 9 |
Step 1: Compute 90 / 10.
Step 2: The result is 9.
|
areaof triangle withbase37 and height 3 = 55.50
| 55.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 37 × 3 = 55.50
|
perimeter of triangle withsides 13, 20,50= 83
| 83 |
Step 1: Perimeter formula is a + b + c.
Step 2: 13 + 20 + 50 = 83
|
perimeterof rectanglewith width 47and height 40 = 174
| 174 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (47 + 40) = 2 × 87 = 174
|
area ofcircle withradius 18= 1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
area of triangle with base 30 and height 17= 255.00
| 255 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 30 × 17 = 255.00
|
hypotenuseofright triangle withlegs 13 and 28 = 30.87
| 30.87 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(13² + 28²) = sqrt(169 + 784) = sqrt(953) = 30.87
|
69 + (45) =114
| 114 |
Step 1: Compute 69 + 45.
Step 2: The result is 114.
|
(34) + 26 = 60
| 60 |
Step 1: Compute 34 + 26.
Step 2: The result is 60.
|
areaof rectangle with width 40 and height 32=1280
| 1,280 |
Step 1: Area formula is width × height.
Step 2: 40 × 32 = 1280
|
area ofrectangle withwidth 34 and height 21= 714
| 714 |
Step 1: Area formula is width × height.
Step 2: 34 × 21 = 714
|
perimeter of trianglewith sides 39, 10, 3 =52
| 52 |
Step 1: Perimeter formula is a + b + c.
Step 2: 39 + 10 + 3 = 52
|
hypotenuseof righttrianglewithlegs21and 24 = 31.89
| 31.89 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(21² + 24²) = sqrt(441 + 576) = sqrt(1017) = 31.89
|
133 /19= 7
| 7 |
Step 1: Compute 133 / 19.
Step 2: The result is 7.
|
perimeterofrectangle withwidth33andheight 6=78
| 78 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (33 + 6) = 2 × 39 = 78
|
57+ (61)= 118
| 118 |
Step 1: Compute 57 + 61.
Step 2: The result is 118.
|
10 ** 2 =100
| 100 |
Step 1: Compute 10 ** 2.
Step 2: The result is 100.
|
80 %(1) = 0
| 0 |
Step 1: Compute 80 % 1.
Step 2: The result is 0.
|
66* 15 =990
| 990 |
Step 1: Compute 66 * 15.
Step 2: The result is 990.
|
perimeterof triangle with sides10, 2,1 =13
| 13 |
Step 1: Perimeter formula is a + b + c.
Step 2: 10 + 2 + 1 = 13
|
34 /17 = 2
| 2 |
Step 1: Compute 34 / 17.
Step 2: The result is 2.
|
8-54= -46
| -46 |
Step 1: Compute 8 - 54.
Step 2: The result is -46.
|
perimeterof trianglewithsides 42, 28, 26 = 96
| 96 |
Step 1: Perimeter formula is a + b + c.
Step 2: 42 + 28 + 26 = 96
|
(6) - (43)= -37
| -37 |
Step 1: Compute 6 - 43.
Step 2: The result is -37.
|
perimeter of rectangle withwidth41 andheight 8 =98
| 98 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (41 + 8) = 2 × 49 = 98
|
5*73 =365
| 365 |
Step 1: Compute 5 * 73.
Step 2: The result is 365.
|
(24) / (4) = 6
| 6 |
Step 1: Compute 24 / 4.
Step 2: The result is 6.
|
(30)%12 =6
| 6 |
Step 1: Compute 30 % 12.
Step 2: The result is 6.
|
(5)%3= 2
| 2 |
Step 1: Compute 5 % 3.
Step 2: The result is 2.
|
area of triangle with base42 and height30= 630.00
| 630 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 42 × 30 = 630.00
|
perimeterofrectangle with width 8and height 21= 58
| 58 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (8 + 21) = 2 × 29 = 58
|
88 % 2=0
| 0 |
Step 1: Compute 88 % 2.
Step 2: The result is 0.
|
6 ** 2 = 36
| 36 |
Step 1: Compute 6 ** 2.
Step 2: The result is 36.
|
area of circle withradius 8 = 201.06
| 201.06 |
Step 1: Area formula is π × r².
Step 2: π × 8² = 3.14 × 64 = 201.06
|
perimeterof rectangle with width 42 andheight45 = 174
| 174 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (42 + 45) = 2 × 87 = 174
|
(9) ** (2)= 81
| 81 |
Step 1: Compute 9 ** 2.
Step 2: The result is 81.
|
67 + 82 = 149
| 149 |
Step 1: Compute 67 + 82.
Step 2: The result is 149.
|
perimeterof trianglewithsides 6,24, 34 = 64
| 64 |
Step 1: Perimeter formula is a + b + c.
Step 2: 6 + 24 + 34 = 64
|
100 % 11 = 1
| 1 |
Step 1: Compute 100 % 11.
Step 2: The result is 1.
|
area of rectangle withwidth 20and height40 =800
| 800 |
Step 1: Area formula is width × height.
Step 2: 20 × 40 = 800
|
2 - (84) = -82
| -82 |
Step 1: Compute 2 - 84.
Step 2: The result is -82.
|
8 ** 4 = 4096
| 4,096 |
Step 1: Compute 8 ** 4.
Step 2: The result is 4096.
|
area of triangle with base 20andheight 14 = 140.00
| 140 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 20 × 14 = 140.00
|
hypotenuse ofright triangle withlegs 3 and 16 = 16.28
| 16.28 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(3² + 16²) = sqrt(9 + 256) = sqrt(265) = 16.28
|
(5) ** 3 = 125
| 125 |
Step 1: Compute 5 ** 3.
Step 2: The result is 125.
|
3** (2) = 9
| 9 |
Step 1: Compute 3 ** 2.
Step 2: The result is 9.
|
perimeterofcircle with radius 6 = 37.70
| 37.7 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 6 = 37.70
|
(18) - 12 =6
| 6 |
Step 1: Compute 18 - 12.
Step 2: The result is 6.
|
120 / (12) = 10
| 10 |
Step 1: Compute 120 / 12.
Step 2: The result is 10.
|
perimeterof triangle with sides 41, 50, 8 = 99
| 99 |
Step 1: Perimeter formula is a + b + c.
Step 2: 41 + 50 + 8 = 99
|
perimeter of rectangle with width 46 andheight 41 = 174
| 174 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (46 + 41) = 2 × 87 = 174
|
91* 14= 1274
| 1,274 |
Step 1: Compute 91 * 14.
Step 2: The result is 1274.
|
perimeterofrectangle withwidth 8 andheight29 = 74
| 74 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (8 + 29) = 2 × 37 = 74
|
18 - 20 =-2
| -2 |
Step 1: Compute 18 - 20.
Step 2: The result is -2.
|
hypotenuse of right triangle withlegs 14and 3 = 14.32
| 14.32 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(14² + 3²) = sqrt(196 + 9) = sqrt(205) = 14.32
|
area oftriangle with base10 andheight 40 = 200.00
| 200 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 10 × 40 = 200.00
|
7 ** 4 = 2401
| 2,401 |
Step 1: Compute 7 ** 4.
Step 2: The result is 2401.
|
3-(64) = -61
| -61 |
Step 1: Compute 3 - 64.
Step 2: The result is -61.
|
area of triangle withbase31andheight 30 = 465.00
| 465 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 31 × 30 = 465.00
|
33% 14 = 5
| 5 |
Step 1: Compute 33 % 14.
Step 2: The result is 5.
|
perimeterof triangle with sides18, 47, 33 = 98
| 98 |
Step 1: Perimeter formula is a + b + c.
Step 2: 18 + 47 + 33 = 98
|
perimeter of circlewith radius13= 81.68
| 81.68 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 13 = 81.68
|
areaof triangle with base 8 and height 26 =104.00
| 104 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 8 × 26 = 104.00
|
perimeter of circle with radius 11 = 69.12
| 69.12 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 11 = 69.12
|
area ofrectangle with width44 and height31 = 1364
| 1,364 |
Step 1: Area formula is width × height.
Step 2: 44 × 31 = 1364
|
area of triangle with base 48 andheight32 =768.00
| 768 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 48 × 32 = 768.00
|
95*47= 4465
| 4,465 |
Step 1: Compute 95 * 47.
Step 2: The result is 4465.
|
7 * 75=525
| 525 |
Step 1: Compute 7 * 75.
Step 2: The result is 525.
|
72 * (68)=4896
| 4,896 |
Step 1: Compute 72 * 68.
Step 2: The result is 4896.
|
perimeter ofcircle withradius 10 = 62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
areaofcircle withradius20 =1256.64
| 1,256.64 |
Step 1: Area formula is π × r².
Step 2: π × 20² = 3.14 × 400 = 1256.64
|
areaof triangle withbase 44 andheight18= 396.00
| 396 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 44 × 18 = 396.00
|
86 * (19) = 1634
| 1,634 |
Step 1: Compute 86 * 19.
Step 2: The result is 1634.
|
area of rectangle withwidth 3and height32 = 96
| 96 |
Step 1: Area formula is width × height.
Step 2: 3 × 32 = 96
|
perimeter ofcircle with radius19 = 119.38
| 119.38 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 19 = 119.38
|
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