Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
area of circlewith radius 5 = 78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
hypotenuse of righttrianglewithlegs 24 and 9= 25.63
| 25.63 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(24² + 9²) = sqrt(576 + 81) = sqrt(657) = 25.63
|
area ofcirclewithradius 7=153.94
| 153.94 |
Step 1: Area formula is π × r².
Step 2: π × 7² = 3.14 × 49 = 153.94
|
hypotenuse of right trianglewith legs 24and 22 =32.56
| 32.56 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(24² + 22²) = sqrt(576 + 484) = sqrt(1060) = 32.56
|
perimeterof circle with radius 10 = 62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
areaoftriangle withbase11 andheight9 =49.50
| 49.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 11 × 9 = 49.50
|
areaoftrianglewith base 35 and height 24 = 420.00
| 420 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 35 × 24 = 420.00
|
hypotenuseof righttriangle with legs 30 and15 = 33.54
| 33.54 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(30² + 15²) = sqrt(900 + 225) = sqrt(1125) = 33.54
|
area oftrianglewithbase28 andheight10= 140.00
| 140 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 28 × 10 = 140.00
|
area of rectanglewith width 7 andheight 11=77
| 77 |
Step 1: Area formula is width × height.
Step 2: 7 × 11 = 77
|
15/ 5 = 3
| 3 |
Step 1: Compute 15 / 5.
Step 2: The result is 3.
|
perimeter of circle with radius 9= 56.55
| 56.55 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 9 = 56.55
|
50/5= 10
| 10 |
Step 1: Compute 50 / 5.
Step 2: The result is 10.
|
perimeter of rectangle with width 8 and height 19 =54
| 54 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (8 + 19) = 2 × 27 = 54
|
(8) ** 2= 64
| 64 |
Step 1: Compute 8 ** 2.
Step 2: The result is 64.
|
perimeter of rectangle with width5and height44= 98
| 98 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (5 + 44) = 2 × 49 = 98
|
(3)**3 = 27
| 27 |
Step 1: Compute 3 ** 3.
Step 2: The result is 27.
|
52 + 43 = 95
| 95 |
Step 1: Compute 52 + 43.
Step 2: The result is 95.
|
perimeter ofcircle with radius18 =113.10
| 113.1 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 18 = 113.10
|
(10) /2= 5
| 5 |
Step 1: Compute 10 / 2.
Step 2: The result is 5.
|
59 +83= 142
| 142 |
Step 1: Compute 59 + 83.
Step 2: The result is 142.
|
area ofcircle with radius18= 1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
perimeterof triangle with sides6,6,32 = 44
| 44 |
Step 1: Perimeter formula is a + b + c.
Step 2: 6 + 6 + 32 = 44
|
14 - 84=-70
| -70 |
Step 1: Compute 14 - 84.
Step 2: The result is -70.
|
perimeterofrectangle with width35 and height36 = 142
| 142 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (35 + 36) = 2 × 71 = 142
|
area of circle with radius 3= 28.27
| 28.27 |
Step 1: Area formula is π × r².
Step 2: π × 3² = 3.14 × 9 = 28.27
|
perimeter of circle with radius5 = 31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
79 +20= 99
| 99 |
Step 1: Compute 79 + 20.
Step 2: The result is 99.
|
area ofrectangle withwidth39 and height 22 =858
| 858 |
Step 1: Area formula is width × height.
Step 2: 39 × 22 = 858
|
perimeterof circlewith radius 20=125.66
| 125.66 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 20 = 125.66
|
perimeter of circle withradius 19 = 119.38
| 119.38 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 19 = 119.38
|
38 *(16) =608
| 608 |
Step 1: Compute 38 * 16.
Step 2: The result is 608.
|
area of circlewith radius 16 =804.25
| 804.25 |
Step 1: Area formula is π × r².
Step 2: π × 16² = 3.14 × 256 = 804.25
|
80 / 10 =8
| 8 |
Step 1: Compute 80 / 10.
Step 2: The result is 8.
|
areaof rectangle with width 23 and height 38 = 874
| 874 |
Step 1: Area formula is width × height.
Step 2: 23 × 38 = 874
|
areaof circle with radius 12=452.39
| 452.39 |
Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39
|
area of trianglewith base 35 and height 15 =262.50
| 262.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 35 × 15 = 262.50
|
38 - 13 =25
| 25 |
Step 1: Compute 38 - 13.
Step 2: The result is 25.
|
92 % (11) =4
| 4 |
Step 1: Compute 92 % 11.
Step 2: The result is 4.
|
(19) * 42=798
| 798 |
Step 1: Compute 19 * 42.
Step 2: The result is 798.
|
63/ 7= 9
| 9 |
Step 1: Compute 63 / 7.
Step 2: The result is 9.
|
74 -18 = 56
| 56 |
Step 1: Compute 74 - 18.
Step 2: The result is 56.
|
perimeter of triangle with sides11,12,22 =45
| 45 |
Step 1: Perimeter formula is a + b + c.
Step 2: 11 + 12 + 22 = 45
|
(26) % 15 = 11
| 11 |
Step 1: Compute 26 % 15.
Step 2: The result is 11.
|
perimeterofrectanglewithwidth 43 andheight 18 = 122
| 122 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (43 + 18) = 2 × 61 = 122
|
area of circlewithradius13 =530.93
| 530.93 |
Step 1: Area formula is π × r².
Step 2: π × 13² = 3.14 × 169 = 530.93
|
30 / 15 =2
| 2 |
Step 1: Compute 30 / 15.
Step 2: The result is 2.
|
areaofcircle withradius5= 78.54
| 78.54 |
Step 1: Area formula is π × r².
Step 2: π × 5² = 3.14 × 25 = 78.54
|
70/ 14 = 5
| 5 |
Step 1: Compute 70 / 14.
Step 2: The result is 5.
|
33- 83 = -50
| -50 |
Step 1: Compute 33 - 83.
Step 2: The result is -50.
|
42/14 = 3
| 3 |
Step 1: Compute 42 / 14.
Step 2: The result is 3.
|
80 / (16)= 5
| 5 |
Step 1: Compute 80 / 16.
Step 2: The result is 5.
|
areaof circle with radius15= 706.86
| 706.86 |
Step 1: Area formula is π × r².
Step 2: π × 15² = 3.14 × 225 = 706.86
|
perimeterof rectangle with width15 and height 27 = 84
| 84 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (15 + 27) = 2 × 42 = 84
|
52%11 = 8
| 8 |
Step 1: Compute 52 % 11.
Step 2: The result is 8.
|
79 - 37= 42
| 42 |
Step 1: Compute 79 - 37.
Step 2: The result is 42.
|
89- 36= 53
| 53 |
Step 1: Compute 89 - 36.
Step 2: The result is 53.
|
8%(19) = 8
| 8 |
Step 1: Compute 8 % 19.
Step 2: The result is 8.
|
area of circle with radius 6= 113.10
| 113.1 |
Step 1: Area formula is π × r².
Step 2: π × 6² = 3.14 × 36 = 113.10
|
61 * 54 =3294
| 3,294 |
Step 1: Compute 61 * 54.
Step 2: The result is 3294.
|
perimeterof circlewithradius 18 =113.10
| 113.1 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 18 = 113.10
|
80+ 76 =156
| 156 |
Step 1: Compute 80 + 76.
Step 2: The result is 156.
|
area of circle with radius 8= 201.06
| 201.06 |
Step 1: Area formula is π × r².
Step 2: π × 8² = 3.14 × 64 = 201.06
|
(93) % 2 = 1
| 1 |
Step 1: Compute 93 % 2.
Step 2: The result is 1.
|
areaofrectangle with width26and height 32 = 832
| 832 |
Step 1: Area formula is width × height.
Step 2: 26 × 32 = 832
|
80 + 98= 178
| 178 |
Step 1: Compute 80 + 98.
Step 2: The result is 178.
|
60 - 20 = 40
| 40 |
Step 1: Compute 60 - 20.
Step 2: The result is 40.
|
73-1= 72
| 72 |
Step 1: Compute 73 - 1.
Step 2: The result is 72.
|
perimeter of rectangle with width 16and height23= 78
| 78 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (16 + 23) = 2 × 39 = 78
|
35 / (7)= 5
| 5 |
Step 1: Compute 35 / 7.
Step 2: The result is 5.
|
area of rectangle with width33 and height 29=957
| 957 |
Step 1: Area formula is width × height.
Step 2: 33 × 29 = 957
|
area of rectanglewith width 42 and height 20 = 840
| 840 |
Step 1: Area formula is width × height.
Step 2: 42 × 20 = 840
|
4** (2) = 16
| 16 |
Step 1: Compute 4 ** 2.
Step 2: The result is 16.
|
area of trianglewithbase37andheight 10 = 185.00
| 185 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 37 × 10 = 185.00
|
74 *33= 2442
| 2,442 |
Step 1: Compute 74 * 33.
Step 2: The result is 2442.
|
41-15=26
| 26 |
Step 1: Compute 41 - 15.
Step 2: The result is 26.
|
perimeter ofrectangle withwidth5 and height8 = 26
| 26 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (5 + 8) = 2 × 13 = 26
|
(9)+ 3= 12
| 12 |
Step 1: Compute 9 + 3.
Step 2: The result is 12.
|
hypotenuse of right triangle withlegs19 and27 =33.02
| 33.02 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(19² + 27²) = sqrt(361 + 729) = sqrt(1090) = 33.02
|
areaofcircle with radius 14 =615.75
| 615.75 |
Step 1: Area formula is π × r².
Step 2: π × 14² = 3.14 × 196 = 615.75
|
area oftriangle withbase 33 and height 34 =561.00
| 561 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 33 × 34 = 561.00
|
perimeteroftriangle with sides 31, 7, 50= 88
| 88 |
Step 1: Perimeter formula is a + b + c.
Step 2: 31 + 7 + 50 = 88
|
45- 46= -1
| -1 |
Step 1: Compute 45 - 46.
Step 2: The result is -1.
|
42 / 7 =6
| 6 |
Step 1: Compute 42 / 7.
Step 2: The result is 6.
|
4 ** 4 =256
| 256 |
Step 1: Compute 4 ** 4.
Step 2: The result is 256.
|
area of rectangle with width7 andheight26 =182
| 182 |
Step 1: Area formula is width × height.
Step 2: 7 × 26 = 182
|
areaofcircle with radius 7= 153.94
| 153.94 |
Step 1: Area formula is π × r².
Step 2: π × 7² = 3.14 × 49 = 153.94
|
50 - 73 = -23
| -23 |
Step 1: Compute 50 - 73.
Step 2: The result is -23.
|
31 + 40 =71
| 71 |
Step 1: Compute 31 + 40.
Step 2: The result is 71.
|
31 * 80 =2480
| 2,480 |
Step 1: Compute 31 * 80.
Step 2: The result is 2480.
|
98 + 98 =196
| 196 |
Step 1: Compute 98 + 98.
Step 2: The result is 196.
|
6 ** (3)= 216
| 216 |
Step 1: Compute 6 ** 3.
Step 2: The result is 216.
|
(49) +(39) = 88
| 88 |
Step 1: Compute 49 + 39.
Step 2: The result is 88.
|
hypotenuseof right triangle with legs 9and 25 =26.57
| 26.57 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(9² + 25²) = sqrt(81 + 625) = sqrt(706) = 26.57
|
hypotenuseof right triangle with legs10 and 24= 26.00
| 26 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(10² + 24²) = sqrt(100 + 576) = sqrt(676) = 26.00
|
68 *38 = 2584
| 2,584 |
Step 1: Compute 68 * 38.
Step 2: The result is 2584.
|
171 / (19) = 9
| 9 |
Step 1: Compute 171 / 19.
Step 2: The result is 9.
|
(65) /13 =5
| 5 |
Step 1: Compute 65 / 13.
Step 2: The result is 5.
|
(4) ** 3= 64
| 64 |
Step 1: Compute 4 ** 3.
Step 2: The result is 64.
|
(97) % 12 =1
| 1 |
Step 1: Compute 97 % 12.
Step 2: The result is 1.
|
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