Expression
stringlengths 5
66
| Result
float64 -99
10k
| Steps
stringlengths 47
107
|
|---|---|---|
1 - 4 = -3
| -3 |
Step 1: Compute 1 - 4.
Step 2: The result is -3.
|
20 *97 = 1940
| 1,940 |
Step 1: Compute 20 * 97.
Step 2: The result is 1940.
|
(31)* 98 =3038
| 3,038 |
Step 1: Compute 31 * 98.
Step 2: The result is 3038.
|
76 % (16) = 12
| 12 |
Step 1: Compute 76 % 16.
Step 2: The result is 12.
|
98 * (10)= 980
| 980 |
Step 1: Compute 98 * 10.
Step 2: The result is 980.
|
(5) ** (4) =625
| 625 |
Step 1: Compute 5 ** 4.
Step 2: The result is 625.
|
78 - 57=21
| 21 |
Step 1: Compute 78 - 57.
Step 2: The result is 21.
|
perimeter of circle withradius3 =18.85
| 18.85 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85
|
perimeter of circle with radius9 = 56.55
| 56.55 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 9 = 56.55
|
perimeteroftriangle with sides43,4, 2= 49
| 49 |
Step 1: Perimeter formula is a + b + c.
Step 2: 43 + 4 + 2 = 49
|
perimeterofcirclewith radius 1 = 6.28
| 6.28 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 1 = 6.28
|
50 * 51= 2550
| 2,550 |
Step 1: Compute 50 * 51.
Step 2: The result is 2550.
|
12/3=4
| 4 |
Step 1: Compute 12 / 3.
Step 2: The result is 4.
|
perimeter of circle with radius 15=94.25
| 94.25 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 15 = 94.25
|
areaoftrianglewith base 8 and height 40 =160.00
| 160 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 8 × 40 = 160.00
|
hypotenuseof righttriangle withlegs 4 and16 = 16.49
| 16.49 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(4² + 16²) = sqrt(16 + 256) = sqrt(272) = 16.49
|
areaoftriangle withbase 2andheight 3 = 3.00
| 3 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 2 × 3 = 3.00
|
perimeter ofcirclewithradius 10 =62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
hypotenuseofright triangle with legs1 and13=13.04
| 13.04 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(1² + 13²) = sqrt(1 + 169) = sqrt(170) = 13.04
|
10 * (87)= 870
| 870 |
Step 1: Compute 10 * 87.
Step 2: The result is 870.
|
(72) * 64=4608
| 4,608 |
Step 1: Compute 72 * 64.
Step 2: The result is 4608.
|
39 %(11) = 6
| 6 |
Step 1: Compute 39 % 11.
Step 2: The result is 6.
|
79%5 = 4
| 4 |
Step 1: Compute 79 % 5.
Step 2: The result is 4.
|
area oftriangle withbase24and height 39 = 468.00
| 468 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 24 × 39 = 468.00
|
(36) /6 = 6
| 6 |
Step 1: Compute 36 / 6.
Step 2: The result is 6.
|
hypotenuseof righttrianglewith legs 29 and 9 =30.36
| 30.36 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(29² + 9²) = sqrt(841 + 81) = sqrt(922) = 30.36
|
100 + (48) = 148
| 148 |
Step 1: Compute 100 + 48.
Step 2: The result is 148.
|
4 * 85= 340
| 340 |
Step 1: Compute 4 * 85.
Step 2: The result is 340.
|
(75)/ 15 =5
| 5 |
Step 1: Compute 75 / 15.
Step 2: The result is 5.
|
(5) + 66 = 71
| 71 |
Step 1: Compute 5 + 66.
Step 2: The result is 71.
|
11+ 42 = 53
| 53 |
Step 1: Compute 11 + 42.
Step 2: The result is 53.
|
75 % 11= 9
| 9 |
Step 1: Compute 75 % 11.
Step 2: The result is 9.
|
hypotenuse of right trianglewith legs 2and 3 =3.61
| 3.61 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(2² + 3²) = sqrt(4 + 9) = sqrt(13) = 3.61
|
perimeterof circle withradius10 = 62.83
| 62.83 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 10 = 62.83
|
area of circlewith radius9 = 254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
perimeterof circle with radius19= 119.38
| 119.38 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 19 = 119.38
|
area ofrectangle withwidth1and height9=9
| 9 |
Step 1: Area formula is width × height.
Step 2: 1 × 9 = 9
|
(27)- (9) =18
| 18 |
Step 1: Compute 27 - 9.
Step 2: The result is 18.
|
area ofcircle with radius9 = 254.47
| 254.47 |
Step 1: Area formula is π × r².
Step 2: π × 9² = 3.14 × 81 = 254.47
|
perimeter oftriangle withsides26, 40, 45 = 111
| 111 |
Step 1: Perimeter formula is a + b + c.
Step 2: 26 + 40 + 45 = 111
|
area of rectanglewithwidth 27and height 8 = 216
| 216 |
Step 1: Area formula is width × height.
Step 2: 27 × 8 = 216
|
72+(48) = 120
| 120 |
Step 1: Compute 72 + 48.
Step 2: The result is 120.
|
perimeter of triangle with sides 13,27, 12 =52
| 52 |
Step 1: Perimeter formula is a + b + c.
Step 2: 13 + 27 + 12 = 52
|
perimeteroftrianglewith sides16, 47, 3 = 66
| 66 |
Step 1: Perimeter formula is a + b + c.
Step 2: 16 + 47 + 3 = 66
|
perimeterof circlewithradius4=25.13
| 25.13 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 4 = 25.13
|
49 + (24)=73
| 73 |
Step 1: Compute 49 + 24.
Step 2: The result is 73.
|
area ofcircle withradius 14=615.75
| 615.75 |
Step 1: Area formula is π × r².
Step 2: π × 14² = 3.14 × 196 = 615.75
|
(64)+12 = 76
| 76 |
Step 1: Compute 64 + 12.
Step 2: The result is 76.
|
areaof triangle with base 35 and height36 =630.00
| 630 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 35 × 36 = 630.00
|
hypotenuse of right triangle with legs 20 and 21 =29.00
| 29 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(20² + 21²) = sqrt(400 + 441) = sqrt(841) = 29.00
|
57 / 19 =3
| 3 |
Step 1: Compute 57 / 19.
Step 2: The result is 3.
|
(17)- (14) =3
| 3 |
Step 1: Compute 17 - 14.
Step 2: The result is 3.
|
area ofcircle with radius17=907.92
| 907.92 |
Step 1: Area formula is π × r².
Step 2: π × 17² = 3.14 × 289 = 907.92
|
perimeter of circlewith radius 3 = 18.85
| 18.85 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 3 = 18.85
|
area of rectangle with width 33 and height25 = 825
| 825 |
Step 1: Area formula is width × height.
Step 2: 33 × 25 = 825
|
perimeter of triangle withsides 22, 47, 5 = 74
| 74 |
Step 1: Perimeter formula is a + b + c.
Step 2: 22 + 47 + 5 = 74
|
perimeterof triangle with sides 11, 37, 38 = 86
| 86 |
Step 1: Perimeter formula is a + b + c.
Step 2: 11 + 37 + 38 = 86
|
79+1 = 80
| 80 |
Step 1: Compute 79 + 1.
Step 2: The result is 80.
|
(96) % (5)= 1
| 1 |
Step 1: Compute 96 % 5.
Step 2: The result is 1.
|
89 *(66) = 5874
| 5,874 |
Step 1: Compute 89 * 66.
Step 2: The result is 5874.
|
98% 19 =3
| 3 |
Step 1: Compute 98 % 19.
Step 2: The result is 3.
|
60/ 20 =3
| 3 |
Step 1: Compute 60 / 20.
Step 2: The result is 3.
|
5 ** 4 = 625
| 625 |
Step 1: Compute 5 ** 4.
Step 2: The result is 625.
|
7 -49 = -42
| -42 |
Step 1: Compute 7 - 49.
Step 2: The result is -42.
|
areaof trianglewithbase 43 and height2=43.00
| 43 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 43 × 2 = 43.00
|
(7)**2 = 49
| 49 |
Step 1: Compute 7 ** 2.
Step 2: The result is 49.
|
perimeter of rectangle with width 48 andheight25= 146
| 146 |
Step 1: Perimeter formula is 2 × (width + height).
Step 2: 2 × (48 + 25) = 2 × 73 = 146
|
perimeter of triangle with sides41, 11, 26= 78
| 78 |
Step 1: Perimeter formula is a + b + c.
Step 2: 41 + 11 + 26 = 78
|
hypotenuseof right triangle with legs 23 and7=24.04
| 24.04 |
Step 1: Hypotenuse formula is sqrt(a² + b²).
Step 2: sqrt(23² + 7²) = sqrt(529 + 49) = sqrt(578) = 24.04
|
perimeter oftriangle with sides 43,28, 34 =105
| 105 |
Step 1: Perimeter formula is a + b + c.
Step 2: 43 + 28 + 34 = 105
|
perimeter of circlewith radius 5 = 31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
3** 2 =9
| 9 |
Step 1: Compute 3 ** 2.
Step 2: The result is 9.
|
120/(20) = 6
| 6 |
Step 1: Compute 120 / 20.
Step 2: The result is 6.
|
perimeter of circle with radius 9= 56.55
| 56.55 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 9 = 56.55
|
(60) -75= -15
| -15 |
Step 1: Compute 60 - 75.
Step 2: The result is -15.
|
area of rectangle with width 31andheight3 = 93
| 93 |
Step 1: Area formula is width × height.
Step 2: 31 × 3 = 93
|
81 *(83)= 6723
| 6,723 |
Step 1: Compute 81 * 83.
Step 2: The result is 6723.
|
10 ** 2 = 100
| 100 |
Step 1: Compute 10 ** 2.
Step 2: The result is 100.
|
perimeter oftriangle withsides 1, 15,45 = 61
| 61 |
Step 1: Perimeter formula is a + b + c.
Step 2: 1 + 15 + 45 = 61
|
perimeter of circle with radius 20 = 125.66
| 125.66 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 20 = 125.66
|
4 *(47)= 188
| 188 |
Step 1: Compute 4 * 47.
Step 2: The result is 188.
|
89 % (6) = 5
| 5 |
Step 1: Compute 89 % 6.
Step 2: The result is 5.
|
perimeterof triangle with sides 26, 17, 4 = 47
| 47 |
Step 1: Perimeter formula is a + b + c.
Step 2: 26 + 17 + 4 = 47
|
58-96 = -38
| -38 |
Step 1: Compute 58 - 96.
Step 2: The result is -38.
|
perimeter of circle withradius15= 94.25
| 94.25 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 15 = 94.25
|
areaoftriangle with base13 and height3 =19.50
| 19.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 13 × 3 = 19.50
|
areaof circle with radius 18 = 1017.88
| 1,017.88 |
Step 1: Area formula is π × r².
Step 2: π × 18² = 3.14 × 324 = 1017.88
|
perimeterofcircle with radius19 = 119.38
| 119.38 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 19 = 119.38
|
area of trianglewithbase 3andheight 37 = 55.50
| 55.5 |
Step 1: Area formula is 0.5 × base × height.
Step 2: 0.5 × 3 × 37 = 55.50
|
5 % (14)= 5
| 5 |
Step 1: Compute 5 % 14.
Step 2: The result is 5.
|
108/ (18) = 6
| 6 |
Step 1: Compute 108 / 18.
Step 2: The result is 6.
|
71 + 41=112
| 112 |
Step 1: Compute 71 + 41.
Step 2: The result is 112.
|
perimeterof triangle withsides16, 34, 7 = 57
| 57 |
Step 1: Perimeter formula is a + b + c.
Step 2: 16 + 34 + 7 = 57
|
perimeterof circle withradius5= 31.42
| 31.42 |
Step 1: Perimeter formula is 2 × π × r.
Step 2: 2 × 3.14 × 5 = 31.42
|
area of circle with radius 12=452.39
| 452.39 |
Step 1: Area formula is π × r².
Step 2: π × 12² = 3.14 × 144 = 452.39
|
8 % (5) =3
| 3 |
Step 1: Compute 8 % 5.
Step 2: The result is 3.
|
(16)/(16) = 1
| 1 |
Step 1: Compute 16 / 16.
Step 2: The result is 1.
|
area of circlewith radius 14 = 615.75
| 615.75 |
Step 1: Area formula is π × r².
Step 2: π × 14² = 3.14 × 196 = 615.75
|
94- 55=39
| 39 |
Step 1: Compute 94 - 55.
Step 2: The result is 39.
|
36 + 34 = 70
| 70 |
Step 1: Compute 36 + 34.
Step 2: The result is 70.
|
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