package com.fishercoder.solutions;

import com.fishercoder.common.classes.TreeNode;

/**
 * 437. Path Sum III
 *
 * You are given a binary tree in which each node contains an integer value.

 Find the number of paths that sum to a given value.

 The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes).

 The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to 1,000,000.

 Example:

 root = [10,5,-3,3,2,null,11,3,-2,null,1], sum = 8

      10
     /  \
    5   -3
   / \    \
  3   2   11
 / \   \
3  -2  1

 Return 3. The paths that sum to 8 are:

 1.  5 -> 3
 2.  5 -> 2 -> 1
 3. -3 -> 11
 */

public class _437 {

    public static class Solution1 {
        public int pathSum(TreeNode root, int sum) {
            if (root == null) {
                return 0;
            }
            return pathSumFrom(root, sum) + pathSum(root.left, sum) + pathSum(root.right, sum);
        }

        private int pathSumFrom(TreeNode root, int sum) {
            if (root == null) {
                return 0;
            }
            return (root.val == sum ? 1 : 0) + pathSumFrom(root.left, sum - root.val) + pathSumFrom(root.right, sum - root.val);
        }
    }

}

@@ -82,630 +82,8 @@
 e;%0A%0A
-/**%0A * 437. Path Sum III%0A *%0A * You are given a binary tree in which each node contains an integer value.%0A%0A Find the number of paths that sum to a given value.%0A%0A The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes).%0A%0A The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to 1,000,000.%0A%0A Example:%0A%0A root = %5B10,5,-3,3,2,null,11,3,-2,null,1%5D, sum = 8%0A%0A      10%0A     /  %5C%0A    5   -3%0A   / %5C    %5C%0A  3   2   11%0A / %5C   %5C%0A3  -2  1%0A%0A Return 3. The paths that sum to 8 are:%0A%0A 1.  5 -%3E 3%0A 2.  5 -%3E 2 -%3E 1%0A 3. -3 -%3E 11%0A */%0A%0A
 publ

refactor 437