package com.fishercoder.solutions;

import com.fishercoder.common.classes.TreeNode;

import java.util.ArrayList;
import java.util.Collections;
import java.util.LinkedList;
import java.util.List;
import java.util.Queue;

/**
 * 103. Binary Tree Zigzag Level Order Traversal
 *
Given a binary tree, return the zigzag level order traversal of its nodes' values.
 (ie, from left to right, then right to left for the next level and alternate between).

For example:
Given binary tree [3,9,20,null,null,15,7],
    3
   / \
  9  20
    /  \
   15   7
return its zigzag level order traversal as:
[
  [3],
  [20,9],
  [15,7]
]
*/
public class _103 {
    public static class Solution1 {
        public List<List<Integer>> zigzagLevelOrder(TreeNode root) {
            Queue<TreeNode> q = new LinkedList();
            List<List<Integer>> levels = new ArrayList();
            if (root == null) {
                return levels;
            }
            q.offer(root);
            boolean forward = true;
            while (!q.isEmpty()) {
                int size = q.size();
                List<Integer> level = new ArrayList();
                for (int i = 0; i < size; i++) {
                    TreeNode curr = q.poll();
                    level.add(curr.val);
                    if (curr.left != null) {
                        q.offer(curr.left);
                    }
                    if (curr.right != null) {
                        q.offer(curr.right);
                    }
                }
                if (forward) {
                    forward = false;
                    levels.add(level);
                } else {
                    Collections.reverse(level);
                    levels.add(level);
                    forward = true;
                }
            }
            return levels;
        }
    }
}

@@ -217,409 +217,8 @@
 e;%0A%0A
-/**%0A * 103. Binary Tree Zigzag Level Order Traversal%0A *%0AGiven a binary tree, return the zigzag level order traversal of its nodes' values.%0A (ie, from left to right, then right to left for the next level and alternate between).%0A%0AFor example:%0AGiven binary tree %5B3,9,20,null,null,15,7%5D,%0A    3%0A   / %5C%0A  9  20%0A    /  %5C%0A   15   7%0Areturn its zigzag level order traversal as:%0A%5B%0A  %5B3%5D,%0A  %5B20,9%5D,%0A  %5B15,7%5D%0A%5D%0A*/%0A
 publ

refactor 103