package com.fishercoder.solutions;

/**
 * 925. Long Pressed Name
 *
 * Your friend is typing his name into a keyboard.
 * Sometimes, when typing a character c, the key might get long pressed,
 * and the character will be typed 1 or more times.
 *
 * You examine the typed characters of the keyboard.
 * Return True if it is possible that it was your friends name,
 * with some characters (possibly none) being long pressed.
 *
 * Example 1:
 *
 * Input: name = "alex", typed = "aaleex"
 * Output: true
 * Explanation: 'a' and 'e' in 'alex' were long pressed.
 * Example 2:
 *
 * Input: name = "saeed", typed = "ssaaedd"
 * Output: false
 * Explanation: 'e' must have been pressed twice, but it wasn't in the typed output.
 * Example 3:
 *
 * Input: name = "leelee", typed = "lleeelee"
 * Output: true
 * Example 4:
 *
 * Input: name = "laiden", typed = "laiden"
 * Output: true
 * Explanation: It's not necessary to long press any character.
 *
 * Note:
 * name.length <= 1000
 * typed.length <= 1000
 * The characters of name and typed are lowercase letters.
 * */
public class _925 {
    public static class Solution1 {
        public boolean isLongPressedName(String name, String typed) {
            int i = 0;
            for (int j = 0; i < name.length() && j < typed.length(); i++) {
                if (name.charAt(i) != typed.charAt(j)) {
                    return false;
                } else if (i < name.length() - 1 && name.charAt(i) != name.charAt(i+1)) {
                    j++;
                    while (j < typed.length() && name.charAt(i) == typed.charAt(j)) {
                        j++;
                    }
                } else {
                    j++;
                }

            }
            return i == name.length();
        }
    }
}

@@ -1459,17 +1459,19 @@
 charAt(i
-+
+ + 
 1)) %7B%0A  

fix build