<p>This is done in order to make the solution more general. If you use specific utility function you prove your result only for that specific utility function and not for other ones.</p>
<p>You can still derive Euler equation. For example in a simple 2-period consumption model where agents maximize their expected utility</p>
<p><span class="math-container">$$E[u]=E[\sum_{t=1}^T u(C)_t]$$</span></p>
<p>where <span class="math-container">$t=1,2$</span>. Given this, the Euler equation would be simply:</p>
<p><span class="math-container">$$u'(C_1)=u'(E[C_2])$$</span></p>
<p>you could insert some specific utility function into the problem. For example, you could use quadratic utility <span class="math-container">$E[u] = E[\sum_{t=1}^T C_t-\frac{a}{2} C^2_t]$</span> (as in Romer's Advanced Macroeconomic handbook) which would give you Euler equation <span class="math-container">$C_1=E_1[C_2]$</span> and continue using that but in the first case you prove your result for whole range of utility function whereas in the second case only for single 1 quadratic utility. In science we like to make results as general as possible so usually the first approach would be preferred.</p>
<p>In a typical IS-LM model you will actually want to substitute some utility function because for derivation of the model its important to know what optimal consumption <span class="math-container">$C^*$</span> is. However, you might not substitute it right away. You are completely vague about your citation of Woodford (2003) which could refer to multiple sources. For example, in his 2003 book Interest and Prices, on PP 145 where he builds New-Keynesian style macro model he actually makes explicit assumptions about consumption and in these macro models utility is usually kept simple such as <span class="math-container">$U=C-\frac{1}{\gamma}L^{\gamma}$</span> (See for example again above mentioned Romer's handbook).</p>

CC BY-SA 4.0
2020-07-07T14:24:49.233Z
@Tomcat yes that’s completely correct and excellent addition. By the way, that’s why I mentioned in my answer that it will be valid for a range of utility functions instead of all but I should have been more explicit.
1muflon1
CC BY-SA 4.0
2020-07-07T12:23:28.057Z
2020-07-07T12:29:23.503Z
2020-07-07T12:29:23.503Z
1muflon1
<p>Why do many papers write the intertemporal maximisation problem for the household as</p>
<p><span class="math-container">\begin{equation}E_{0} \sum_{t=0}^{\infty} \beta^{t} U\left(C_{t}, N_{t}\right)\end{equation}</span></p>
<p>and then do not write the actual utility function that could be something like
<span class="math-container">\begin{equation}U\left(C_{t}, N_{t}\right)=\frac{C_{t}^{1-\sigma}}{1-\sigma}-\frac{N_{t}^{1+\varphi}}{1+\varphi}? \end{equation}</span></p>
<p>Many papers state that they are following woodford (2003) for the microfundations. However also in that book there is no explicit utility function.</p>
<p>How is it possible to get the Euler equation or the IS curve without the actual functon?</p>

<macroeconomics><utility>
Why do many papers not write the actual utility function?
bdvse
# Why do many papers not write the actual utility function?

(Asked by: username_0 on 2020-07-07)

Why do many papers write the intertemporal maximisation problem for the household as

\begin{equation}E\_{0} \sum\_{t=0}^{\infty} \beta^{t} U\left(C\_{t}, N\_{t}\right)\end{equation}

and then do not write the actual utility function that could be something like
\begin{equation}U\left(C\_{t}, N\_{t}\right)=\frac{C\_{t}^{1-\sigma}}{1-\sigma}-\frac{N\_{t}^{1+\varphi}}{1+\varphi}? \end{equation}

Many papers state that they are following woodford (2003) for the microfundations. However also in that book there is no explicit utility function.

How is it possible to get the Euler equation or the IS curve without the actual functon?

**Tags:** macroeconomics, utility

---

## 1 answers

### Answer by username_1 on 2020-07-07. Score: 5

This is done in order to make the solution more general. If you use specific utility function you prove your result only for that specific utility function and not for other ones.

You can still derive Euler equation. For example in a simple 2-period consumption model where agents maximize their expected utility

$$E[u]=E[\sum\_{t=1}^T u(C)\_t]$$

where $t=1,2$. Given this, the Euler equation would be simply:

$$u'(C\_1)=u'(E[C\_2])$$

you could insert some specific utility function into the problem. For example, you could use quadratic utility $E[u] = E[\sum\_{t=1}^T C\_t-\frac{a}{2} C^2\_t]$ (as in Romer's Advanced Macroeconomic handbook) which would give you Euler equation $C\_1=E\_1[C\_2]$ and continue using that but in the first case you prove your result for whole range of utility function whereas in the second case only for single 1 quadratic utility. In science we like to make results as general as possible so usually the first approach would be preferred.

In a typical IS-LM model you will actually want to substitute some utility function because for derivation of the model its important to know what optimal consumption $C^\*$ is. However, you might not substitute it right away. You are completely vague about your citation of Woodford (2003) which could refer to multiple sources. For example, in his 2003 book Interest and Prices, on PP 145 where he builds New-Keynesian style macro model he actually makes explicit assumptions about consumption and in these macro models utility is usually kept simple such as $U=C-\frac{1}{\gamma}L^{\gamma}$ (See for example again above mentioned Romer's handbook).

> **Comments:**
> **username_1**: @Tomcat yes that’s completely correct and excellent addition. By the way, that’s why I mentioned in my answer that it will be valid for a range of utility functions instead of all but I should have been more explicit.  

---

