<p>I don't think any conclusion is possible without more detail, but if we make a few assumptions we can see where they lead us.</p>

<p>Assume $a,b &gt; 0$ and $z &lt; 0$</p>

<p>Assume the consumer in question has well-behaved preferences and therefore their indifference curves must be monotonic and convex</p>

<p>Given these assumptions (which I think are fairly reasonable, although I'd want to see them explicitly stated if this was a formal question) then the answer should be that the post-exchange indifference curve is different from the earlier one.</p>

<p>Given that $a$ and $b$ are greater than zero, we know that the consumer has lost some of the first good and gained some of the second. Examining all possibilities they could be in one of three positions relative to their original indifference curve:</p>

<ol>
<li>Above the original curve</li>
<li>On the original curve at a different point</li>
<li>Below the original curve</li>
</ol>

<p>Neither Case 2 nor Case 3 are plausible. We know that the slope of the new curve at $(x-a, y+b)$ is three times shallower than the that of the original curve at $(x, y)$. The assumptions of convexity and monotonicity require that the original indifference curve become steeper as it approaches the y-axis. See below for a colourfully-amateurish representation.</p>

<p><a href="https://i.sstatic.net/VagdJ.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/VagdJ.png" alt=""></a></p>

<p>Note that in the example pictured above the resulting indifference curve is impossible as it crosses the original indifference curve - a situation that can never arise. </p>

<p>That leaves us with Case 1 as the sole possibility, which means that $(x-a, y+b)$ must be on a new indifference curve as per the illustration below. 
<a href="https://i.sstatic.net/bflJs.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/bflJs.png" alt=""></a></p>

CC BY-SA 3.0
2015-11-22T23:26:36.930Z
2015-11-22T23:26:36.930Z
Dewirix
<p>If you are at a point $(x,y)$ where your $MRS(x,y)=3z$, and you later exchange goods to be at point $(x-a,y+b)$, where your $MRS(x-a,y+b)=z$, can you conclude that you are one the same indifference cure, different one, or is there no conclusion possible?</p>

<microeconomics>
How does Marginal rate of substitution change?
Zoe
# How does Marginal rate of substitution change?

(Asked by: username_0 on 2015-11-05)

If you are at a point $(x,y)$ where your $MRS(x,y)=3z$, and you later exchange goods to be at point $(x-a,y+b)$, where your $MRS(x-a,y+b)=z$, can you conclude that you are one the same indifference cure, different one, or is there no conclusion possible?

**Tags:** microeconomics

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## 1 answers

### Answer by username_1 on 2015-11-22. Score: 1

I don't think any conclusion is possible without more detail, but if we make a few assumptions we can see where they lead us.

Assume $a,b > 0$ and $z < 0$

Assume the consumer in question has well-behaved preferences and therefore their indifference curves must be monotonic and convex

Given these assumptions (which I think are fairly reasonable, although I'd want to see them explicitly stated if this was a formal question) then the answer should be that the post-exchange indifference curve is different from the earlier one.

Given that $a$ and $b$ are greater than zero, we know that the consumer has lost some of the first good and gained some of the second. Examining all possibilities they could be in one of three positions relative to their original indifference curve:

1. Above the original curve
2. On the original curve at a different point
3. Below the original curve

Neither Case 2 nor Case 3 are plausible. We know that the slope of the new curve at $(x-a, y+b)$ is three times shallower than the that of the original curve at $(x, y)$. The assumptions of convexity and monotonicity require that the original indifference curve become steeper as it approaches the y-axis. See below for a colourfully-amateurish representation.

[![](https://i.sstatic.net/VagdJ.png)](https://i.sstatic.net/VagdJ.png)

Note that in the example pictured above the resulting indifference curve is impossible as it crosses the original indifference curve - a situation that can never arise.

That leaves us with Case 1 as the sole possibility, which means that $(x-a, y+b)$ must be on a new indifference curve as per the illustration below.
[![](https://i.sstatic.net/bflJs.png)](https://i.sstatic.net/bflJs.png)


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