<p>Hint: This suggests <span class="math-container">$y=\dfrac{U}{\sqrt{x}}$</span>  </p>

<p>so draw the three curves in the usual way</p>

<ul>
<li><p><span class="math-container">$y=\dfrac{10}{\sqrt{x}}$</span>; three of the points are <span class="math-container">$(1,10)$</span> and <span class="math-container">$(4,5)$</span> and <span class="math-container">$(9,3.333)$</span></p></li>
<li><p><span class="math-container">$y=\dfrac{15}{\sqrt{x}}$</span>; three of the points are <span class="math-container">$(1,15)$</span> and <span class="math-container">$(4,7.5)$</span> and <span class="math-container">$(9,5)$</span></p></li>
<li><p><span class="math-container">$y=\dfrac{20}{\sqrt{x}}$</span>; three of the points are <span class="math-container">$(1,20)$</span> and <span class="math-container">$(4,10)$</span> and <span class="math-container">$(9,6.667)$</span></p></li>
</ul>

CC BY-SA 4.0
2019-10-15T23:12:26.107Z
Many thanks henry, this is correct! Was also wondering how you got to this answer from: U(x,y) = y√x. Why did you change the U over the square root of X? I'd love to know this for future reference.
alz
CC BY-SA 4.0
2019-10-15T23:41:17.047Z
@alz -  I divided both sides of $U=y \sqrt{x}$ by $\sqrt{x}$
Henry
CC BY-SA 4.0
2019-10-14T21:04:15.203Z
2019-10-14T21:04:15.203Z
Henry
<p>Draw the indifference curve for U= 10, U=15, U=20.</p>

<p>My knowledge of algebra has deteriorated over the last few years of being out of school and I am really unsure of how to answer this.</p>

<p>The X value is going up in the standard 1 to 10.</p>

CC BY-SA 4.0
2019-10-15T21:59:46.303Z
Hello! Could you try to make the title of your question more informative about what you are looking for? :)
Arthur
<decision-theory>
Consider the utility function U(x,y) = y√x
alz
# Consider the utility function U(x,y) = y√x

(Asked by: username_0 on 2019-10-14)

Draw the indifference curve for U= 10, U=15, U=20.

My knowledge of algebra has deteriorated over the last few years of being out of school and I am really unsure of how to answer this.

The X value is going up in the standard 1 to 10.

**Tags:** decision-theory
> **Comments:**
> **username_1**: Hello! Could you try to make the title of your question more informative about what you are looking for? :)  

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## 1 answers

### Answer by username_2 on 2019-10-14. Score: 2 | Accepted answer

Hint: This suggests $y=\dfrac{U}{\sqrt{x}}$

so draw the three curves in the usual way

* $y=\dfrac{10}{\sqrt{x}}$; three of the points are $(1,10)$ and $(4,5)$ and $(9,3.333)$
* $y=\dfrac{15}{\sqrt{x}}$; three of the points are $(1,15)$ and $(4,7.5)$ and $(9,5)$
* $y=\dfrac{20}{\sqrt{x}}$; three of the points are $(1,20)$ and $(4,10)$ and $(9,6.667)$

> **Comments:**
> **username_0**: Many thanks henry, this is correct! Was also wondering how you got to this answer from: U(x,y) = y√x. Why did you change the U over the square root of X? I'd love to know this for future reference.  
> **username_2**: @alz -  I divided both sides of $U=y \sqrt{x}$ by $\sqrt{x}$  

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