<p>I guess you mean that the condition $-\beta +\lambda w =0$ does not include labor. But you have the profit maximizing wage relation that includes labor and wage, and so combining, you can obtain an expression that includes the marginal product of labor, and the multiplier lambda, which can be expressed in terms of the other decision variables.</p>

<hr>

<p>Ok, I see you got lost in running around your equations.</p>

<p>Profits are zero since the firm is a price taker and the production function is homogeneous of degree one (constant returns to scale).</p>

<p>$$ \frac{\alpha}{1-\alpha}n_2 w = k q \implies n_2\frac{\beta}{\lambda} = \frac{1-\alpha}{\alpha} kq$$</p>

<p>Since $\lambda = 1/c_1p_1$, $q=p_1$ and $k = \bar y -c_1$we get </p>

<p>$$n_2\beta c_1p_1 = \frac{1-\alpha}{\alpha} (\bar y -c_1)p_1$$</p>

<p>$$\implies n_2 = \frac{1-\alpha}{\alpha\beta } \left(\frac{\bar y}{c_1} -1\right)$$.</p>

<p>Now, go back to the budget constraint</p>

<p>$$c_1 p_1 + c_2 p_2 = p_1 ( \bar y - x ) + qx + wn_2 + \pi$$</p>

<p>Inserting the various optimal conditions, you should arrive at </p>

<p>$$c_1 = \frac {\bar y}{1+\alpha \beta}$$</p>

<p>which leads to $n_2 = 1-\alpha$.</p>

CC BY-SA 3.0
2017-10-22T17:32:15.567Z
You exactly understood my issue, except that you used a langragian which I did not. I simply remplaced c2 in the utility function and derives from this.
I added in an edit my profit maximisation and I do have labor and wage.
If I remplace the wage in this expression by $ \frac{\beta}{\lambda} $ , I still have the capital and labor to determine. I thought I'd be able to determine the labor supply through household optimization and use it to determine the required capital , since I have the relation between them.

And I don't see how to express lambda in terms of $ c_1 $ or $ c_2 $

Thanks
Ayman Makki
CC BY-SA 3.0
2017-10-22T17:37:20.097Z
@AymanMakki Use the Lagrangian then. Substitute for $\lambda$. Once $c_1$ is determined, $k$ is determined also, in terms of $c_1$,  since $\bar y$ is exogenous. Then $n_2$ is determined for the profit maximization condition, in terms of $c_1$.
Alecos Papadopoulos
CC BY-SA 3.0
2017-10-22T18:19:06.117Z
I updated in a new edit if you can have a look, thanks :)
Ayman Makki
CC BY-SA 3.0
2017-10-22T18:42:48.720Z
@AymanMakki I expanded the answer.
Alecos Papadopoulos
CC BY-SA 3.0
2017-10-22T19:07:52.050Z
Went until the end thanks to you, have a good evening
Ayman Makki
CC BY-SA 3.0
2017-10-22T19:15:25.840Z
@AymanMakki You're welcome.
Alecos Papadopoulos
CC BY-SA 3.0
2017-10-22T17:24:56.300Z
2017-10-22T18:42:24.210Z
2017-10-22T18:42:24.210Z
Alecos Papadopoulos
<p>I have been working the afternoon on an intertemporal exercise where I'm blocking on something very basic. Have been looking on previous posts but didn't find a similar question.</p>

<p>We have the utility function of the household : $ U(C_1,C_2,n_2)= \log(c_1) + \beta \log(c_2) - \beta n_2 $ </p>

<p>We have an allocation $ \bar y $ for period 1 and none for period 2, the household can only work in period two.</p>

<p>Here is the budget constraint : $ c_1 p_1 + c_2 p_2 = p_1 ( \bar y - x ) + qx + wn_2 + \pi  $ </p>

<p>And the production function of the firm : $ f(k) = k^\alpha n_2^{1-\alpha} $</p>

<p>What I did until now is replacing $ c_2 $ in the utility function to have it depending on $c_1$,$ n_2$ and $ x $ only. Then I derive it for each variable and I can get the optimal condition for consumption : 
$ \frac{c_2}{c_1} = \beta \frac{p_1}{p_2} $, the other derivatives gives me : $ w = p_2 c_2 $ and $ q = p_1 $ .
By replacing $c_2$ in the budget constraint, I can determine $ c_1$ and then $c_2$, and x is given by the market clearing condition $ \bar y = c_1 + x $.</p>

<p>But I can't find anyway to determine $n_2$, it's usually in a logarithm so we can find it in our First Order Conditions...</p>

<p>Edit : 
$ x $ is the amount of capital given to the firm by the household, so we sould have $ x=k $ on capital market</p>

<p>$ q $ is the price of capital per unit</p>

<p>$ \pi $ is the profit of the firm , i.e. $ \pi(k,n_2) = p_2 k^\alpha n_2^{1-\alpha} - kq - wn_2 $</p>

<p>Edit 2 :
Rereading my question, I realize I should precise : 
The household can only consume the firm production in period 2, which is why he contributes to the capital and labor of the firm, earning wages and profits.
Therefore, we should also have $ f(k,n_2) = c_2 $ I believe</p>

<p>Edit 3 : 
My profit maximisation gives me : 
$ \frac{\alpha}{1-\alpha} n_2 w = k q $</p>

<p>Edit 4 after @X recommendation : 
So I do the lagrangian and derivatives, which gets me : </p>

<p>$ \frac{1}{c_1} = \lambda p_1 $</p>

<p>$ \frac{\beta}{c_2} = \lambda p_2 $</p>

<p>$ \beta = \lambda w $</p>

<p>$ p_1 = q $</p>

<p>After computing, I find : $ c_1 = \frac{p_1 \bar y + w n_2 - \pi}{p_1(1+\beta)} $ and $ x = k = \bar y - c_1 = \frac{\beta p_1 \bar y - w n_2 + \pi}{p_1(1+\beta)} $</p>

<p>But still having trouble regarding my original issue, $ n_2 $ : I did , according to your advices : 
$ \frac{\alpha}{1-\alpha} n_2 w = k q $</p>

<p>$ \frac{\alpha}{1-\alpha} n_2 \frac{\beta}{\lambda} = \frac{\beta p_1 \bar y - w n_2 + \pi}{p_1(1+\beta)} p_1 $</p>

<p>$ \frac{\alpha}{1-\alpha} n_2 \beta p_1 c_1 = \frac{\beta p_1 \bar y - w n_2 + \pi}{(1+\beta)} $</p>

<p>$ \frac{\alpha}{1-\alpha} n_2 \frac{\beta}{1+\beta}(p_1 \bar y + w n_2 - \pi) = \frac{\beta p_1 \bar y - w n_2 + \pi}{(1+\beta)} $</p>

<p>$ \frac{\alpha}{1-\alpha} n_2 \beta(p_1 \bar y + w n_2 - \pi) = \beta p_1 \bar y - w n_2 + \pi $</p>

<p>$  n_2 \beta(p_1 \bar y + w n_2 - \pi) = \frac{1-\alpha}{\alpha} \frac{\beta p_1 \bar y - w n_2 + \pi}{\beta(p_1 \bar y + w n_2 - \pi)} $</p>

<p>Still pretty stupid as results ... I also used the central planner way and found $ n_2 = 1 - \alpha $ , which is weird..
I'd still like to go at the end of this way if someone has an idea.</p>

<p>Any idea ? 
Thanks.</p>

<microeconomics><labor-economics>
Find the optimal labor supply when labor utility is linear
Ayman Makki
# Find the optimal labor supply when labor utility is linear

(Asked by: username_0 on 2017-10-22)

I have been working the afternoon on an intertemporal exercise where I'm blocking on something very basic. Have been looking on previous posts but didn't find a similar question.

We have the utility function of the household : $ U(C\_1,C\_2,n\_2)= \log(c\_1) + \beta \log(c\_2) - \beta n\_2 $

We have an allocation $ \bar y $ for period 1 and none for period 2, the household can only work in period two.

Here is the budget constraint : $ c\_1 p\_1 + c\_2 p\_2 = p\_1 ( \bar y - x ) + qx + wn\_2 + \pi $

And the production function of the firm : $ f(k) = k^\alpha n\_2^{1-\alpha} $

What I did until now is replacing $ c\_2 $ in the utility function to have it depending on $c\_1$,$ n\_2$ and $ x $ only. Then I derive it for each variable and I can get the optimal condition for consumption :
$ \frac{c\_2}{c\_1} = \beta \frac{p\_1}{p\_2} $, the other derivatives gives me : $ w = p\_2 c\_2 $ and $ q = p\_1 $ .
By replacing $c\_2$ in the budget constraint, I can determine $ c\_1$ and then $c\_2$, and x is given by the market clearing condition $ \bar y = c\_1 + x $.

But I can't find anyway to determine $n\_2$, it's usually in a logarithm so we can find it in our First Order Conditions...

Edit :
$ x $ is the amount of capital given to the firm by the household, so we sould have $ x=k $ on capital market

$ q $ is the price of capital per unit

$ \pi $ is the profit of the firm , i.e. $ \pi(k,n\_2) = p\_2 k^\alpha n\_2^{1-\alpha} - kq - wn\_2 $

Edit 2 :
Rereading my question, I realize I should precise :
The household can only consume the firm production in period 2, which is why he contributes to the capital and labor of the firm, earning wages and profits.
Therefore, we should also have $ f(k,n\_2) = c\_2 $ I believe

Edit 3 :
My profit maximisation gives me :
$ \frac{\alpha}{1-\alpha} n\_2 w = k q $

Edit 4 after @X recommendation :
So I do the lagrangian and derivatives, which gets me :

$ \frac{1}{c\_1} = \lambda p\_1 $

$ \frac{\beta}{c\_2} = \lambda p\_2 $

$ \beta = \lambda w $

$ p\_1 = q $

After computing, I find : $ c\_1 = \frac{p\_1 \bar y + w n\_2 - \pi}{p\_1(1+\beta)} $ and $ x = k = \bar y - c\_1 = \frac{\beta p\_1 \bar y - w n\_2 + \pi}{p\_1(1+\beta)} $

But still having trouble regarding my original issue, $ n\_2 $ : I did , according to your advices :
$ \frac{\alpha}{1-\alpha} n\_2 w = k q $

$ \frac{\alpha}{1-\alpha} n\_2 \frac{\beta}{\lambda} = \frac{\beta p\_1 \bar y - w n\_2 + \pi}{p\_1(1+\beta)} p\_1 $

$ \frac{\alpha}{1-\alpha} n\_2 \beta p\_1 c\_1 = \frac{\beta p\_1 \bar y - w n\_2 + \pi}{(1+\beta)} $

$ \frac{\alpha}{1-\alpha} n\_2 \frac{\beta}{1+\beta}(p\_1 \bar y + w n\_2 - \pi) = \frac{\beta p\_1 \bar y - w n\_2 + \pi}{(1+\beta)} $

$ \frac{\alpha}{1-\alpha} n\_2 \beta(p\_1 \bar y + w n\_2 - \pi) = \beta p\_1 \bar y - w n\_2 + \pi $

$ n\_2 \beta(p\_1 \bar y + w n\_2 - \pi) = \frac{1-\alpha}{\alpha} \frac{\beta p\_1 \bar y - w n\_2 + \pi}{\beta(p\_1 \bar y + w n\_2 - \pi)} $

Still pretty stupid as results ... I also used the central planner way and found $ n\_2 = 1 - \alpha $ , which is weird..
I'd still like to go at the end of this way if someone has an idea.

Any idea ?
Thanks.

**Tags:** microeconomics, labor-economics

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## 1 answers

### Answer by username_1 on 2017-10-22. Score: 0 | Accepted answer

I guess you mean that the condition $-\beta +\lambda w =0$ does not include labor. But you have the profit maximizing wage relation that includes labor and wage, and so combining, you can obtain an expression that includes the marginal product of labor, and the multiplier lambda, which can be expressed in terms of the other decision variables.

---

Ok, I see you got lost in running around your equations.

Profits are zero since the firm is a price taker and the production function is homogeneous of degree one (constant returns to scale).

$$ \frac{\alpha}{1-\alpha}n\_2 w = k q \implies n\_2\frac{\beta}{\lambda} = \frac{1-\alpha}{\alpha} kq$$

Since $\lambda = 1/c\_1p\_1$, $q=p\_1$ and $k = \bar y -c\_1$we get

$$n\_2\beta c\_1p\_1 = \frac{1-\alpha}{\alpha} (\bar y -c\_1)p\_1$$

$$\implies n\_2 = \frac{1-\alpha}{\alpha\beta } \left(\frac{\bar y}{c\_1} -1\right)$$.

Now, go back to the budget constraint

$$c\_1 p\_1 + c\_2 p\_2 = p\_1 ( \bar y - x ) + qx + wn\_2 + \pi$$

Inserting the various optimal conditions, you should arrive at

$$c\_1 = \frac {\bar y}{1+\alpha \beta}$$

which leads to $n\_2 = 1-\alpha$.

> **Comments:**
> **username_0**: You exactly understood my issue, except that you used a langragian which I did not. I simply remplaced c2 in the utility function and derives from this. I added in an edit my profit maximisation and I do have labor and wage. If I remplace the wage in this expression by $ \frac{\beta}{\lambda} $ , I still have the capital and labor to determine. I thought I'd be able to determine the labor supply through household optimization and use it to determine the required capital , since I have the relation between them.  And I don't see how to express lambda in terms of $ c_1 $ or $ c_2 $  Thanks  
> **username_1**: @AymanMakki Use the Lagrangian then. Substitute for $\lambda$. Once $c_1$ is determined, $k$ is determined also, in terms of $c_1$,  since $\bar y$ is exogenous. Then $n_2$ is determined for the profit maximization condition, in terms of $c_1$.  
> **username_0**: I updated in a new edit if you can have a look, thanks :)  
> **username_1**: @AymanMakki I expanded the answer.  
> **username_0**: Went until the end thanks to you, have a good evening  
> **username_1**: @AymanMakki You're welcome.  

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