<p>Matrix <span class="math-container">$B$</span> cannot be full rank. If this were the case, then <span class="math-container">$A=0$</span>, which is apparently excluded.</p>

CC BY-SA 4.0
2021-11-24T07:24:05.303Z
I got a solution by John D'Errico  B=null(A')' which gives B=(0 1 0 0). it gives B*A=0
anamika
CC BY-SA 4.0
2021-11-24T06:59:41.063Z
2021-11-24T06:59:41.063Z
Bertrand
<p>Suppose I have a matrix A= g=[Vfc/(x1<em>Cdc),x4/(x1</em>Cdc),-x3/Cdc;0 0 0;0 0 x1/Lcpl;0 -1/Cb 0] and I want to find the full rank left annihilator matrix B such that B*A=0. I am using MATLAB.</p>

<statistics><matlab>
full rank left annihilator matrix
anamika
# full rank left annihilator matrix

(Asked by: username_0 on 2021-11-23)

Suppose I have a matrix A= g=[Vfc/(x1*Cdc),x4/(x1*Cdc),-x3/Cdc;0 0 0;0 0 x1/Lcpl;0 -1/Cb 0] and I want to find the full rank left annihilator matrix B such that B\*A=0. I am using MATLAB.

**Tags:** statistics, matlab

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## 1 answers

### Answer by username_1 on 2021-11-24. Score: 0

Matrix $B$ cannot be full rank. If this were the case, then $A=0$, which is apparently excluded.

> **Comments:**
> **username_0**: I got a solution by John D'Errico  B=null(A')' which gives B=(0 1 0 0). it gives B*A=0  

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