<doocs>1832.Check if the Sentence Is Pangram_1.py
def checkIfPangram( sentence: str) -> bool:
    res = 0
    for c in sentence:
        res |= 1 << (ord(c) - ord('a'))
        if res == 0x3FFFFFF:
            return True
    return False
def sample_funcname ( var_0 : str ) -> bool :
    var_4 = 0
    for var_5 in var_0 :
        var_4 |= 1 << ( ord ( var_5 ) - ord ( 'a' ) )
        if var_4 == 0x3FFFFFF :
            return True
    return False
