query: Show that a double-periodic and entire function is a constant function
positive_passages.docid: 7878
positive_passages.text: Proving that a doubly-periodic entire function $f$ is constant.
negative_passages.docid: 139614
negative_passages.text: Polynomial bounded real part of an entire function
negative_passages.docid: 109091
negative_passages.text: Why do non-constant periodic functions have no limit at infinity?
negative_passages.docid: 56127
negative_passages.text: Prove a function is constant under certain conditions
negative_passages.docid: 82745
negative_passages.text: Showing Entire Function is Bounded
negative_passages.docid: 39921
negative_passages.text: show that f is constant on I
negative_passages.docid: 132113
negative_passages.text: Does $f(x) = f(2x)$ for all real $x$, imply that $f(x)$ is a constant function?
negative_passages.docid: 82367
negative_passages.text: Prove that a holomorphic function with postive real part is constant
negative_passages.docid: 32789
negative_passages.text: Show bounded harmonic function on $\mathbb{C}$ is constant.
negative_passages.docid: 39386
negative_passages.text: Harmonic non-surjective functions are constant
negative_passages.docid: 97371
negative_passages.text: Proving a function is constant, under certain conditions?
negative_passages.docid: 75638
negative_passages.text: Let $u:\mathbb{C}\rightarrow\mathbb{R}$ be a harmonic function such that $0\leq f(z)$ for all $ z \in \mathbb{C}$. Prove that $u$ is constant.
negative_passages.docid: 54297
negative_passages.text: Is $f(x)=10$ a periodic function?
negative_passages.docid: 64172
negative_passages.text: Show that if $f$ is analytic in a domain $D$ and $|f(z)|$ is constant in $D$, then the function $f(z)$ is constant in $D$
negative_passages.docid: 33489
negative_passages.text: |f| is periodic implies f is periodic
negative_passages.docid: 103285
negative_passages.text: Limit of a periodic function
negative_passages.docid: 62268
negative_passages.text: Doubly periodic entire function with periods that are linearly independent over $\mathbb{Q}$ is constant.