query: A question in the proof that Lipchitz continuous functions implies $W^{1,\infty}$.
positive_passages.docid: 156727
positive_passages.text: A step in the proof of Characterization of $W^{1,\infty}$
negative_passages.docid: 31741
negative_passages.text: Show for $f:A \to Y$ uniformly continuous exists a unique extension to $\overline{A}$, which is uniformly continuous
negative_passages.docid: 131992
negative_passages.text: A problem on continuous functions
negative_passages.docid: 31548
negative_passages.text: Proof of "every convex function is continuous"
negative_passages.docid: 66630
negative_passages.text: Proof of Mazurkiewicz theorem
negative_passages.docid: 43874
negative_passages.text: Differentiability implies continuity - A question about the proof
negative_passages.docid: 40297
negative_passages.text: Proof of uniform limit of Continuous Functions
negative_passages.docid: 110458
negative_passages.text: Show that if $f$ is continuous on $(0,1)$ and $\lim_{x \to 0}f(x) = + \infty$ then $f$ is not uniformly continuous
negative_passages.docid: 150770
negative_passages.text: Why is $f^n(\xi(x))$ continuous over $x$?
negative_passages.docid: 118272
negative_passages.text: Show that $L^1$ is strictly contained in $(L^\infty)^*$
negative_passages.docid: 107842
negative_passages.text: Behaviour of ($\overline{a}_n)_{n=1}^{\infty}$ and ($\underline{a}_n)_{n=1}^{\infty}$
negative_passages.docid: 97104
negative_passages.text: Proof that continuous function on $ [0, 2]$ has $f(x) = f(x-1)$ for some $ x$
negative_passages.docid: 118628
negative_passages.text: Is the function $f(x)=|x|^{1/2}$ Lipschitz continuous?
negative_passages.docid: 80559
negative_passages.text: In $C[0,1]$ prove that the subset of Lipschitz functions is dense
negative_passages.docid: 100740
negative_passages.text: proof of that a continuous function has a fixed point
negative_passages.docid: 118207
negative_passages.text: Prove that the product of two continuous functions is continuous
negative_passages.docid: 143708
negative_passages.text: $L^1$ and $L^{\infty}$ are not reflexive