query: $\delta Q = dU + \delta W$. Why is it $dU$ while others are partial differentials?
positive_passages.docid: 27862
positive_passages.text: Symbols of derivatives
negative_passages.docid: 31102
negative_passages.text: Why does $\frac{1}{r}\frac{dr}{d\theta} = \cot \psi$?
negative_passages.docid: 153794
negative_passages.text: What is the meaning of $1/(D+a)$, where $D$ is the derivative operator?
negative_passages.docid: 68310
negative_passages.text: Why can partial derivatives be exchanged?
negative_passages.docid: 89185
negative_passages.text: The notation for partial derivatives
negative_passages.docid: 38839
negative_passages.text: Exponential of the differential operator
negative_passages.docid: 65659
negative_passages.text: Partial derivative paradox
negative_passages.docid: 73099
negative_passages.text: Why is $d(x^2)= 2xdx$?
negative_passages.docid: 123911
negative_passages.text: Why is the derivative of a vector orthogonal to the vector itself?
negative_passages.docid: 142821
negative_passages.text: Why?$\int_0^1\int_{u(t)}^{u(t)+w(t)} f(t,v(t)) dv dt = \int_0^1 f(t,u(t)+\theta w(t))w(t) dt; ~~\theta\in[0,1] $
negative_passages.docid: 13020
negative_passages.text: Proof for the funky trace derivative : $d (\operatorname{trace} (ABA'C))$?
negative_passages.docid: 56275
negative_passages.text: Vector derivative w.r.t its transpose $\frac{d(Ax)}{d(x^T)}$
negative_passages.docid: 98303
negative_passages.text: Ward identity derived from global symmetry and SDE, different from that derived from gauge symmetry?
negative_passages.docid: 90325
negative_passages.text: Why use the derivative and not the symmetric derivative?
negative_passages.docid: 885
negative_passages.text: Why is the 2nd derivative written as $\frac{\mathrm d^2y}{\mathrm dx^2}$?
negative_passages.docid: 111611
negative_passages.text: When can we add a total time derivative of $f(q, \dot{q}, t)$ to a Lagrangian?
negative_passages.docid: 16644
negative_passages.text: Why does cancellation of dots $\frac{\partial \dot{\mathbf{r}}_i}{\partial \dot{q}_j} = \frac{\partial \mathbf{r}_i}{\partial q_j}$ work?