query: Find the sum of the following inﬁnite series:
positive_passages.docid: 145322
positive_passages.text: Sum of a Hyper-geometric series. (NBHM 2011)
negative_passages.docid: 70018
negative_passages.text: Sum of series (telescoping)
negative_passages.docid: 142985
negative_passages.text: Finding sum of series $\sum^{\infty}_{k=0}\frac{(k+1)(k+2)}{2^k}$
negative_passages.docid: 55339
negative_passages.text: Find the sum $\sum_{n=1}^{\infty}\frac{ 1}{n^{2}(2n-1)}$
negative_passages.docid: 113189
negative_passages.text: Find the sum of the series $1^2-2^2+3^2-4^2+...-(2n)^2$
negative_passages.docid: 122445
negative_passages.text: Sum of the series:$\frac{1}{1\cdot 2}+\frac{1\cdot3}{1\cdot2\cdot3\cdot4}+\cdots$
negative_passages.docid: 30895
negative_passages.text: Compute the sum of the series $\sum_{n=1}^{\infty} \frac{1}{n \cdot 2^n}$
negative_passages.docid: 81589
negative_passages.text: Find the sum of $\sum_{k=0}^{\infty} 1/[(r+2k+2)(s+2k+2)]$
negative_passages.docid: 152227
negative_passages.text: How to sum this series to infinity: $\sum_{n=0}^{\infty} \frac1{2^{2^n}}$
negative_passages.docid: 153409
negative_passages.text: Sum of $1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}+\frac{1}{8}+\frac{1}{9}+\frac{1}{12}+\cdots$
negative_passages.docid: 33986
negative_passages.text: Calculate $\sum_{n=1}^{\infty}(\frac{1}{2n}-\frac{1}{n+1}+\frac{1}{2n+4})$
negative_passages.docid: 112950
negative_passages.text: Find the value of infinite series $\sum_{n=1}^{\infty} \tan^{-1}(2/n^2)$
negative_passages.docid: 134361
negative_passages.text: Calculating the sum of a binomial coefficient series
negative_passages.docid: 87976
negative_passages.text: How to solve these series?
negative_passages.docid: 74117
negative_passages.text: Find the sum of series $\sum_{n=0}^{\infty}\frac{z^{kn}}{(kn)!}$
negative_passages.docid: 14223
negative_passages.text: Find the infinite sum $\sum_{n=1}^{\infty}\frac{1}{2^n-1}$
negative_passages.docid: 43903
negative_passages.text: Find the sum for $\sum_{n=1}^{\infty}(-1)^{(n+1)}\frac{2n+1}{3^n} $