query: If $Y=F(X)$ is $U[0,1]$ where $F$ is cdf of continuous $X$ then shouldn't its plot be rectangular?
positive_passages.docid: 148888
positive_passages.text: How does the inverse transform method work?
negative_passages.docid: 150770
negative_passages.text: Why is $f^n(\xi(x))$ continuous over $x$?
negative_passages.docid: 135092
negative_passages.text: How exactly can't $\delta$ depend on $x$ in the definition of uniform continuity?
negative_passages.docid: 14516
negative_passages.text: The space of continuous functions $C([0,1])$ is not complete in the $L^2$ norm
negative_passages.docid: 82930
negative_passages.text: Why do we say a probability integral transformed variable is uniform on the interval [0, 1]?
negative_passages.docid: 121198
negative_passages.text: $W^{1,1}(\mathbb{R}^n)$ is not compactly embedded in $L^1(\mathbb{R}^n)$?
negative_passages.docid: 1162
negative_passages.text: Why $\{\mathbf{0}\}$ has dimension zero?
negative_passages.docid: 131060
negative_passages.text: Is $\sqrt{x}$ uniformly continuous in $\mathbb{R}^+$?
negative_passages.docid: 47410
negative_passages.text: How to plot the contour of f[x,y]==0 if always f[x,y]>=0
negative_passages.docid: 44057
negative_passages.text: Pointwise but not uniform convergence of continuous functions on $[0,1]$
negative_passages.docid: 131992
negative_passages.text: A problem on continuous functions
negative_passages.docid: 91682
negative_passages.text: Graph of a continuous function is closed
negative_passages.docid: 29227
negative_passages.text: Why the CDF for the Normal Distribution can not be expressed as a closed form function?
negative_passages.docid: 83648
negative_passages.text: How to plot functions with large slope on a compact domain?
negative_passages.docid: 85092
negative_passages.text: Proving $ f(x) = x^2 $ is not uniformly continuous on the real line
negative_passages.docid: 28289
negative_passages.text: Show that $Kf(x,y)=\int_0^1k(x,y) f(y) \,dy\\$ is linear and continuous
negative_passages.docid: 88640
negative_passages.text: Is $\sqrt x$ continuous at $0$? Because it is not defined to the left of $0$