query: Solving $\int \frac{6x^{3}+7x^2-12x+1}{\sqrt{x^2+4x+6}}dx$
positive_passages.docid: 145907
positive_passages.text: How do you evaluate this integral $\int \frac{6x^{3}+7x^2-12x+1}{\sqrt{x^2+4x+6}}dx$
negative_passages.docid: 61339
negative_passages.text: Integrating trigonometric function problem $\int \frac{3\sin x+2\cos x}{2\sin x+3\cos x}dx$
negative_passages.docid: 117101
negative_passages.text: Integrate $\int \frac{dx}{\sqrt{-ax^2 + bx +c}} $
negative_passages.docid: 68639
negative_passages.text: given $I_{n}=\int^1_{0}x^n\sqrt{1-x^2}dx$, then finding value of $ \frac{I_{n}}{I_{n-2}}$
negative_passages.docid: 49944
negative_passages.text: Integral $\int_1^3 \frac{\log x}{x^2+3}dx$
negative_passages.docid: 39629
negative_passages.text: Indefinite integration of $\int \frac{1}{1+\sqrt{x^2+2x+2}}dx$
negative_passages.docid: 149254
negative_passages.text: Solving $y^3=x^3+8x^2-6x+8$
negative_passages.docid: 69682
negative_passages.text: Roots of $y=x^3+x^2-6x-7$
negative_passages.docid: 31852
negative_passages.text: An elegant way to solve $\frac {\sqrt3 - 1}{\sin x} + \frac {\sqrt3 + 1}{\cos x} = 4\sqrt2 $
negative_passages.docid: 61443
negative_passages.text: So close yet so far Finding $\int \frac {\sec x \tan x}{3x+5} dx$
negative_passages.docid: 83801
negative_passages.text: Finding $\int \frac {dx}{\sqrt {x^2 + 16}}$
negative_passages.docid: 32312
negative_passages.text: Evaluating the integral $\int \frac{x^2+x}{(e^x+x+1)^2}dx$
negative_passages.docid: 31529
negative_passages.text: Integrating $\int^2_{-2}\frac{x^2}{1+5^x}$
negative_passages.docid: 46706
negative_passages.text: Integral $\int_0^2 \frac{\arctan x}{x^2+2x+2}dx$
negative_passages.docid: 9730
negative_passages.text: Solve the integral $\int_0^\infty x/(x^3+1) dx$
negative_passages.docid: 55738
negative_passages.text: Evaluating $\int _0^{\frac{\pi }{2}}\:\frac{\sqrt[3]{\sin^2\left(x\right)}}{\sqrt[3]{\sin^2\left(x\right)}+\sqrt[3]{\cos^2\left(x\right)}}dx$
negative_passages.docid: 67326
negative_passages.text: How to solve $ \int \limits _0 ^{2\pi} \dfrac{dx}{(\alpha +\beta\cos x)^2} $