query: $AB - BA$ can't equal to Unit matrix
positive_passages.docid: 7622
positive_passages.text: $AB-BA=I$ having no solutions
negative_passages.docid: 103665
negative_passages.text: Product of matrices of different order is not invertible
negative_passages.docid: 88349
negative_passages.text: Are the eigenvalues of $AB$ equal to the eigenvalues of $BA$? (Citation needed!)
negative_passages.docid: 56312
negative_passages.text: Why can this product of rectangular matrices not be the identity matrix?
negative_passages.docid: 136448
negative_passages.text: $ABAB=0_{n\times n}$, then must $BABA$ be $0_{n\times n}$?
negative_passages.docid: 83475
negative_passages.text: Prove Or Disprove: tr(AB)=tr(A)*tr(B)
negative_passages.docid: 72092
negative_passages.text: If $A^2 = I$, $B^2=I$ and $(AB)^2=I$, then $AB = BA$
negative_passages.docid: 89177
negative_passages.text: $\operatorname{adj}(AB) = \operatorname{adj} B \operatorname{adj} A$
negative_passages.docid: 150287
negative_passages.text: Spectral radii and norms of similar elements in a C*-algebra: $\|bab^{-1}\|<1$ if $b=(\sum_{n=0}^\infty (a^*)^n a^n)^{1/2}$
negative_passages.docid: 26570
negative_passages.text: Prove $\operatorname{rank}(AB) = \operatorname{rank}(B)$
negative_passages.docid: 99585
negative_passages.text: Do the non-zero eigenvalues of AB and BA have the same algebraic multiplicity (for AB and BA not square)?
negative_passages.docid: 144151
negative_passages.text: An orthonormal set cannot be a basis in an infinite dimension vector space?
negative_passages.docid: 43570
negative_passages.text: Finding two non-zero matrices where $AX = BA$
negative_passages.docid: 3918
negative_passages.text: How do I get the Unitary matrix of a circuit without using the 'unitary_simulator'?
negative_passages.docid: 58021
negative_passages.text: Finding matrix $B$ is not zero matrix where $AB= 0$
negative_passages.docid: 80623
negative_passages.text: Must $S$ be a unitary matrix?
negative_passages.docid: 133482
negative_passages.text: $AB-BA$ is a nilpotent matrix if it commutes with $A$