query: Surjective function from $\mathbb{N}$ to $\mathbb{Q}$
positive_passages.docid: 20199
positive_passages.text: Find a surjective function $f:\mathbb{N}\to \mathbb{Q}$
negative_passages.docid: 3801
negative_passages.text: Functions that take rationals to rationals
negative_passages.docid: 117793
negative_passages.text: Finding a function $\mathbb{N} \to \mathbb{N}$ that is surjective but not injective.
negative_passages.docid: 2072
negative_passages.text: Demonstrate that if $f$ is surjective then $X = f(f^{-1}(X))$
negative_passages.docid: 20303
negative_passages.text: A function $f\colon E\to F$ between finite sets is injective iff it is surjective iff it is bijective
negative_passages.docid: 6023
negative_passages.text: Surjectivity of Composition of Surjective Functions
negative_passages.docid: 102299
negative_passages.text: Bijection between $\mathbb{R}^n$ and $\mathbb{R}^m$
negative_passages.docid: 157597
negative_passages.text: Homeomorphism between $\mathbb{Q}$ and $\mathbb{Q}(>0)$, and $\mathbb{Q}(\ge 0)$
negative_passages.docid: 15909
negative_passages.text: Bijection from $\mathbb R$ to $\mathbb {R^N}$
negative_passages.docid: 42810
negative_passages.text: Is $(\mathbb{Q},+)$ isomorphic to $(\mathbb{Q}^n,+)$?
negative_passages.docid: 93964
negative_passages.text: Proving that $f$ is a bijection from $N$x$N$ to $N$.
negative_passages.docid: 118154
negative_passages.text: $f: \mathbb{R} \to \mathbb{R}$ that takes each value in $\mathbb{R}$ twice
negative_passages.docid: 83446
negative_passages.text: bijective continuous function on $\mathbb R^n$ not homeomorphism?
negative_passages.docid: 51334
negative_passages.text: Does there exist any surjective group homomorphism from $(\mathbb R^* , .)$ onto $(\mathbb Q^* , .)$?
negative_passages.docid: 93776
negative_passages.text: Bijective mapping between $\mathbb{R}^2$ and $\mathbb{R}$?
negative_passages.docid: 36325
negative_passages.text: Embedding ordinals in $\mathbb{Q}$
negative_passages.docid: 38549
negative_passages.text: $\mathbb{Q}(\sqrt{n}) \cong \mathbb{Q}(\sqrt{m})$ iff $n=m$