query: Is this proposition about polynomials obvious or not?
positive_passages.docid: 29452
positive_passages.text: Divisor in $\mathbb{C}[X]$ $\implies$ divisor in $\mathbb{R}[X]$?
negative_passages.docid: 133312
negative_passages.text: Are these polynomials irreducible in $\mathbb{Q}[x]$?
negative_passages.docid: 111569
negative_passages.text: Property of a polynomial with no positive real roots
negative_passages.docid: 156034
negative_passages.text: sufficient condition for a polynomial to have roots in $[0,1]$
negative_passages.docid: 121304
negative_passages.text: Is the set of polynomials of degree less than or equal to $n$ closed?
negative_passages.docid: 112334
negative_passages.text: Real roots of a polynomial of real co-efficients , with the co-efficients of $x^2 , x$ and the constant term all $1$
negative_passages.docid: 42265
negative_passages.text: A proof that $\displaystyle\sum_{i=1}^{n}P''(r_i)/P'(r_i)=0$ for a degree $n$ polynomial
negative_passages.docid: 127304
negative_passages.text: Understanding the algebra of polynomials on a linear space
negative_passages.docid: 51769
negative_passages.text: If $x,y,z\in[-1,1]$ and $1+2xyz\geq x^2+y^2+z^2$, then can we infer $1+2(xyz)^n\geq x^{2n}+y^{2n}+z^{2n}$?
negative_passages.docid: 41810
negative_passages.text: Should all polynomial functions from F to F (F is a field) have coefficients in F?
negative_passages.docid: 1962
negative_passages.text: Polynomial $P(a)=b,P(b)=c,P(c)=a$
negative_passages.docid: 56068
negative_passages.text: What actually is a polynomial?
negative_passages.docid: 154393
negative_passages.text: Roots of polynomial with real coefficients appear in conjugate pairs.
negative_passages.docid: 3036
negative_passages.text: Is a polynomial equation of degree $\ge 5$ not solvable by any way?
negative_passages.docid: 4885
negative_passages.text: Polynomials with integer coefficients such that $p(a)=b,p(b)=c,p(c)=a$
negative_passages.docid: 147047
negative_passages.text: Does there exist a polynomial $p(x) \in \mathbb C[x]$ such that $p(x) \notin \mathbb R[x]$ and $p(x)p(-x)=p(x^2)$?
negative_passages.docid: 62239
negative_passages.text: For a polynomial $p(z)$, prove there exist $R>0$, such that if $|z|=R$, then $|p(z)|\geq |a_n|R^n/2$