query: Why does a the addition of a total derivative to the Lagrangian leave the equations of motion invariant?
positive_passages.docid: 29329
positive_passages.text: Does a four-divergence extra term in a Lagrangian density matter to the field equations?
negative_passages.docid: 9735
negative_passages.text: Why does a change of direction imply an acceleration?
negative_passages.docid: 142821
negative_passages.text: Why?$\int_0^1\int_{u(t)}^{u(t)+w(t)} f(t,v(t)) dv dt = \int_0^1 f(t,u(t)+\theta w(t))w(t) dt; ~~\theta\in[0,1] $
negative_passages.docid: 3603
negative_passages.text: Lagrangian and Hamiltonian EOM with dissipative force
negative_passages.docid: 150133
negative_passages.text: Why is work scalar and the dot product of force and displacement?
negative_passages.docid: 99285
negative_passages.text: Why is the change in Hamiltonian for an active infinitesimal canonical transformation defined the way it is?
negative_passages.docid: 130623
negative_passages.text: Why does this consider the center of mass instead of the end? (RIGID BODY MOTION)
negative_passages.docid: 105660
negative_passages.text: Invariance of action $\Rightarrow$ covariance of field equations?
negative_passages.docid: 28935
negative_passages.text: Lagrangian of the Euler equations
negative_passages.docid: 34788
negative_passages.text: Lagrangian for relativistic massless point particle
negative_passages.docid: 96880
negative_passages.text: How to obtain Hamiltonian formalism and phase space for Lagrangian with second-derivatives?
negative_passages.docid: 152446
negative_passages.text: Noether's Theorem and scale invariance
negative_passages.docid: 112209
negative_passages.text: Landau's argument for dependence of Lagrangian on magnitude of velocity
negative_passages.docid: 116427
negative_passages.text: $(c^{\mu}\partial_{\mu}-m)\phi(x)=0$ not Lorentz-invariant?
negative_passages.docid: 155913
negative_passages.text: Lagrangian for free particle in special relativity
negative_passages.docid: 112187
negative_passages.text: Is there a way to see that $ \nabla_\mu g_{\nu \rho} = 0 $ without explicit computation, where $\nabla_\mu$ refers to the covariant derivative?
negative_passages.docid: 109364
negative_passages.text: What exactly is the difference between a derivative and a total derivative?