question: What shows for thurs 25 aug when fri 26 aug is 19' 30.70 116.023mph?
answer: SELECT thurs_25_aug FROM table_30058355_2 WHERE fri_26_aug = "19' 30.70 116.023mph"
context: CREATE TABLE table_30058355_2 (thurs_25_aug VARCHAR, fri_26_aug VARCHAR)