question: Which mean interview number had an average of more than 9.233, a swimsuit stat of more than 9.473, and an evening gown score of more than 9.671?
answer: SELECT AVG(interview) FROM table_name_79 WHERE average > 9.233 AND swimsuit = 9.473 AND evening_gown > 9.671
context: CREATE TABLE table_name_79 (interview INTEGER, evening_gown VARCHAR, average VARCHAR, swimsuit VARCHAR)