question: What was the surface when the result was 6–7 (6–7) , 7–6 (9–7) , 6–7 (4–7) , 7–5, 3–6?
answer: SELECT surface FROM table_name_82 WHERE result = "6–7 (6–7) , 7–6 (9–7) , 6–7 (4–7) , 7–5, 3–6"
context: CREATE TABLE table_name_82 (surface VARCHAR, result VARCHAR)