

lowercase_       		=  "Alexander Joslin"

import operator as op

from .stack import Stack
def 						_snake_case(    SCREAMING_SNAKE_CASE__			:	str      )							->      int:





    '''simple docstring'''






    A__          =   {'*': op.mul, '/': op.truediv, '+': op.add, '-': op.sub}

    A__          =   Stack()
    A__          =   Stack()

    for i in equation:
        if i.isdigit():
            # RULE 1
            operand_stack.push(int(SCREAMING_SNAKE_CASE__      )      )
        elif i in operators:
            # RULE 2
            operator_stack.push(SCREAMING_SNAKE_CASE__      )
        elif i == ")":
            # RULE 4
            A__          =   operator_stack.peek()
            operator_stack.pop()
            A__          =   operand_stack.peek()
            operand_stack.pop()
            A__          =   operand_stack.peek()
            operand_stack.pop()

            A__          =   operators[opr](SCREAMING_SNAKE_CASE__    ,			SCREAMING_SNAKE_CASE__      )
            operand_stack.push(SCREAMING_SNAKE_CASE__      )

    # RULE 5
    return operand_stack.peek()


if __name__ == "__main__":
     lowercase_       		=  "(5 + ((4 * 2) * (2 + 3)))"
     # answer = 45
     print(f"""{equation} = {dijkstras_two_stack_algorithm(equation)}""")









"""simple docstring"""



def 						_SCREAMING_SNAKE_CASE (    __snake_case			:  int = 1_00    ):





  '''simple docstring'''





  lowercase							    =       0
  lowercase							    =       0
  for i in range(1		,					n + 1    ):
    sum_of_squares += i**2
    sum_of_ints += i
  return sum_of_ints**2 - sum_of_squares


if __name__ == "__main__":
    print(F'''{solution() = }''')


