



'''simple docstring'''



_lowercase       :						List[Any]						={
    0: "underwear",
    1: "pants",
    2: "belt",
    3: "suit",
    4: "shoe",
    5: "socks",
    6: "shirt",
    7: "tie",
    8: "watch",
}

_lowercase       :						Tuple						=[[1, 4], [2, 4], [3], [], [], [4], [2, 7], [3], []]

_lowercase       :						Dict						=[0 for x in range(len(graph))]
_lowercase       :						Any						=[]


def 							__UpperCAmelCase				(				UpperCamelCase__				:int   ,				UpperCamelCase__				:Dict			)		->						Any:
				snake_case__      :   Union[str, Any]      =    1
				while stack:
								snake_case__      :   int      =    stack.pop()
								print(UpperCamelCase__   ,				clothes[current_clothing]			)
								order += 1


def 							__UpperCAmelCase				(				UpperCamelCase__				:List[Any]   ,				UpperCamelCase__				:Dict   ,				UpperCamelCase__				:Optional[int]			)		->						str:
				snake_case__      :   Dict      =    1
				for v in graph[u]:
								if not visited[v]:
												depth_first_search(UpperCamelCase__   ,				UpperCamelCase__   ,				UpperCamelCase__			)

				stack.append(UpperCamelCase__			)


def 							__UpperCAmelCase				(				UpperCamelCase__				:Optional[Any]   ,				UpperCamelCase__				:Union[str, Any]			)		->						int:
				for v in range(len(UpperCamelCase__			)			):
								if not visited[v]:
												depth_first_search(UpperCamelCase__   ,				UpperCamelCase__   ,				UpperCamelCase__			)


if __name__ == "__main__":
				topological_sort(graph, visited)
				print(stack)
				print_stack(stack, clothes)









'''simple docstring'''



def 							__UpperCAmelCase				(				UpperCamelCase__				:int   ,				UpperCamelCase__				:list			)		->						list:
				snake_case__      :   List[str]      =    sorted(UpperCamelCase__   ,				key=lambda UpperCamelCase__			: value[2]   ,				reverse=UpperCamelCase__			)

				# Create a list of size equal to the maximum deadline
				# and initialize it with -1
				snake_case__      :   Any      =    max(UpperCamelCase__   ,				key=lambda UpperCamelCase__			: value[1]			)[1]
				snake_case__      :   str      =    [-1] * max_deadline

				# Finding the maximum profit and the count of jobs
				snake_case__      :   List[str]      =    0
				snake_case__      :   Optional[Any]      =    0
				for job in jobs:
								# Find a free time slot for this job
								# (Note that we start from the last possible slot)
								for i in range(job[1] - 1   ,				-1   ,				-1			):
												if time_slots[i] == -1:
																snake_case__      :   Optional[Any]      =    job[0]
																count += 1
																max_profit += job[2]
																break
				return [count, max_profit]


if __name__ == "__main__":
				import doctest

				doctest.testmod()




