Does NP-hardness imply P-hardness? If a problem is NP-hard (using polynomial time reductions), does that imply that it is P-hard (using log space or NC reductions)?  It seems intuitive that if it is as hard as any problem in NP that it should be as hard as any problem in P, but I don't see how to chain the reductions and get a log space (or NC) reduction.
No such implication is known.  In particular it may be that $L \ne P = NP$ in which case all problems (including trivial ones) are NP-hard under poly-time reductions (as the reduction can just solve the problem), but trivial ones (in particular ones that lie in L) are surely not P-hard under logspace reductions (as otherwise L=P).  

The same goes for NC instead of L.