SELECT COUNT(*), T1.blockcode FROM BLOCK AS T1 JOIN room AS T2 ON T1.blockfloor = T2.blockfloor AND T1.blockcode = T2.blockcode GROUP BY T1.blockcode
Temukan jumlah kamar untuk kode blok yang berbeda?
CREATE TABLE room (blockfloor VARCHAR, blockcode VARCHAR); CREATE TABLE BLOCK (blockcode VARCHAR, blockfloor VARCHAR)