SELECT T2.city, COUNT(*), T1.city_id FROM address AS T1 JOIN city AS T2 ON T1.city_id = T2.city_id GROUP BY T1.city_id ORDER BY COUNT(*) DESC LIMIT 1
Kota mana yang paling banyak alamat?Sebutkan nama kota, jumlah alamat, dan ID kota.
CREATE TABLE address (city_id VARCHAR); CREATE TABLE city (city VARCHAR, city_id VARCHAR)