SELECT T2.first_name, T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING COUNT(*) > 2
Daftar nama depan dan nama belakang pelanggan yang memiliki lebih dari 2 pembayaran.
CREATE TABLE Customers (first_name VARCHAR, last_name VARCHAR, customer_id VARCHAR); CREATE TABLE Customer_Payments (customer_id VARCHAR)