SELECT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id GROUP BY t3.city ORDER BY COUNT(*) DESC LIMIT 1
Di kota mana yang tinggal di sebagian besar pelanggan?
CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR)