SELECT T1.engineer_id, T1.first_name, T1.last_name FROM Maintenance_Engineers AS T1 JOIN Engineer_Visits AS T2 ON T1.engineer_id = T2.engineer_id GROUP BY T1.engineer_id ORDER BY COUNT(*) LIMIT 1
Di antara para insinyur yang telah berkunjung, insinyur mana yang melakukan kunjungan paling sedikit?Sebutkan ID insinyur, nama depan dan nama belakang.
CREATE TABLE Engineer_Visits (engineer_id VARCHAR); CREATE TABLE Maintenance_Engineers (engineer_id VARCHAR, first_name VARCHAR, last_name VARCHAR)