SELECT T1.student_id, T2.first_name FROM Student_Addresses AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY AVG(monthly_rental) DESC LIMIT 1
Apa ID dan nama depan siswa yang alamatnya memiliki sewa bulanan rata -rata tertinggi?
CREATE TABLE Students (first_name VARCHAR, student_id VARCHAR); CREATE TABLE Student_Addresses (student_id VARCHAR)