SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY COUNT(*) DESC LIMIT 3
Temukan 3 produk teratas yang memiliki jumlah masalah terbesar?
CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)