SELECT COUNT(*) FROM institution AS T1 JOIN protein AS T2 ON T1.institution_id = T2.institution_id JOIN building AS T3 ON T3.building_id = T1.building_id WHERE T3.floors >= 20
Berapa banyak protein yang dikaitkan dengan lembaga di gedung dengan setidaknya 20 lantai?
CREATE TABLE institution (institution_id VARCHAR, building_id VARCHAR); CREATE TABLE building (building_id VARCHAR, floors VARCHAR); CREATE TABLE protein (institution_id VARCHAR)