<jupyter_start><jupyter_text>n=b<jupyter_code>a=int(input())
c=int(input())
if (a+c)>=20 and (a+c)<=40:
    print(42)
else:
    print(a+c)
'''
Given a non-negative number n, print True if n is within 2 of a multiple of 10,  else print false.  For example 22 is within 2 of a multiple of 10 (the multiple here is 20) and 23 is not within 2 of a multiple of 10 (it is within 3 of multiple 20).

Input Format:
The first line of input contains T denoting the number of testcases. T testcases follow. Each testcase contains a number n.

Output Format:
For each testcase, in a new line, print True if conditions are met; else print False.

Your Task:
This is a function problem. Do not take any input. Just complete the function isNeighbor

Constraints:
1 <= T <= 100
3 <= n <= 1018

Example:
Input:
4
3
9
13
22
Output:
False
True
False
True
'''

def near_ten(num):

    a = num % 10
    if  a <= 2 or (10 - a) <= 2:
        return True
    else:
        return False
near_ten(int(input()))
s=input()
c=0
for i in range(26):
    c+=s.count('do'+chr(97+i)+'e')
c
ord('a')
chr(97)
(7**100)%5<jupyter_output><empty_output>
StarcoderdataJupyterStructuredCleanDedup