How many electrons are lost by sodium metal in a redox reaction ?
For instance , when manganese ( II ) reacts with sodium bismuthate:The reaction is balanced by scaling the two half - cell reactions to involve the same number of electrons ( multiplying the oxidation reaction by the number of electrons in the reduction step and vice versa ) : 8 (l) + 2 ( aq ) → 2 ( aq ) + 16 ( aq ) + 10 10 + 30 + 5 (s) → 5 ( aq ) + 15 (l) Adding these two reactions eliminates the electrons terms and yields the balanced reaction : 14 ( aq ) + 2 ( aq ) + 5 (s) → 7 (l) + 2 ( aq ) + 5 ( aq ) + 5 ( aq )