Where do Electrons escape from ?
ionic counting : H contributes 0 electrons ( H + ) , C4 - contributes 2 electrons ( per H ) , 0 + 1 (2) = 2 valence electrons conclusion : Methane follows the octet - rule for carbon , and the duet rule for hydrogen , and hence is expected to be a stable molecule ( as we see from daily life ) H2S , for the central S neutral counting : S contributes 6 electrons , each hydrogen radical contributes one each : 6 +2 (1) = 8 valence electrons ionic counting : S2 - contributes 8 electrons , each proton contributes 0 : 8 +2 (0) = 8 valence electrons conclusion : with an octet electron count ( on sulfur ) , we can anticipate that H2S would be pseudotetrahedral if one considers the two lone pairs .