How are electrons used in acid and basic medium ?
" Unbalanced reaction " : KMnO4 + Na2SO3 + H2O → MnO2 + Na2SO4 + KOH " Reduction " : 3 e – + 2 H2O + MnO4 – → MnO2 + 4 OH – " Oxidation " : 2 OH – + SO32 – → SO42 – + H2O + 2 e – The same procedure as followed on acid medium by multiplying electrons to opposite half reactions solve the equation thus balancing the overall reaction .