def parse_image_url(url):
  """
  Parses a url continaing the image id to return the image id.
  """
  # Check if it was a url or actual image id
  # eg: https://map.openaerialmap.org/#/.../59e62b9a3d6412ef7220a51f?_k=vy2p83
  image_id = url.split("/")[-1].split("?")[0]
  return image_id