def filter_cve_content(sources):
    """
    去除cve数据中type字段不是“CVE和安全问题”的元素
    Args:
        sources: cve响应数据

    Returns:
        filter_source
    """
    filter_source = []
    for _index, response in enumerate(sources):
        if response.get("type") == "CVE和安全问题":
            filter_source.append(response)
    return filter_source