def getCopyright( lang=None ):
    """
        Returns copyright information of this package.

        'lang' must be either None, "bash" or "python"

        This function just returns the lines of the copyright notice,
        no leading or trailing '#' lines. Use getCopyrightHeader()
        when generating code files.
    """
    lines = ( 'Copyright (C)',
              'Honda Research Institute Europe GmbH',
              'Carl-Legien-Str. 30',
              '63073 Offenbach/Main',
              'Germany',
              '',
              'UNPUBLISHED PROPRIETARY MATERIAL.',
              'ALL RIGHTS RESERVED.' )


    if lang == 'bash' or lang == 'python':
        text = ''

        for line in lines:
            if line:
                text += '#  %s\n' % line
            else:
                text += '#\n'
    else:
        text = '\n'.join( lines )

    return text