def find_common_words(frequency_dictionary,cutoff):
    """
    <find_common_words> will take a frequency dictionary that describes how many times
    a word has occurred in a sting, and return a list of the words that have occurred
    more than or equal to <cutoff> times.

    Parameters:
        - frequency_dict (dict): A dictionary of the form {<word (str)> :
                <number of occurances of word (int)>}. The returned object from <word_frequency>
                should work here.
        - cutoff (int): The minimum number of occurances of a word in order for it to be included
                in the returned list.

    Returns:
        - (list): A list of the words that occured more than or equal to <cutoff> times.
    """

    common_words = []
    for word,freq in frequency_dictionary.items():
        if freq >= cutoff:
            common_words.append(word)

    return common_words