import requests


def get_response(url, payload=None):
    """
    :param url: -address to be scrapped
    :param payload: - None by default
    :return: page content if status == 200 else a message with status code
    """
    headers = {'Accept-Language': 'en-US,en;q=0.5'}
    r = requests.get(url, headers=headers, params=payload)
    if r.status_code == 200:
        return r.content
    return f"\nThe URL returned {r.status_code}!"