def isPal(word):
    """
    Test if a word or phrase is a palindrome (same backward or forward).

    Assume it must have more than 2 letters, and that only letters and digits count.
    """
    ### keep only letters or numbers
    w = ''.join([l for l in word.lower() if l.isalnum()])
    ### check if it is the same as its reverse
    return len(w) > 1 and w == w[::-1]