import zipfile


def create_xml_list_from_zip(filepath):
    """
    Opens the .zip file and extracts a list of .xml filenames
    :param filepath: filepath to the .zip file
    :return: list of .xml filenames
    """

    return list(filter(lambda x: x[-3:] == 'xml', zipfile.ZipFile(filepath, 'r').namelist()))