import re


def find_url(string):
    """Find if a string contains an URL"""
    # findall() has been used
    # with valid conditions for urls in string
    url = re.findall('http[s]?://(?:[a-zA-Z]|[0-9]|[$-_@.&+]|[!*\(\), ]|(?:%[0-9a-fA-F][0-9a-fA-F]))+',string)
    if len(url) > 0:
        return True