def pipe_friction_loss(pipe_friction_const, L):
    """ 
    Function takes piping friction loss per x amount of feet and returns 
    the head for pipe friction
    
    Ex:
    x = pipe_friction_loss(2.25/100.0, 5.0)
    """
    
    hpipe = pipe_friction_const*L
    print('hpipe (Piping friction loss) = {} ft'.format(hpipe))
    
    return hpipe