def get_media_resource_upload_path(item, filename):
    """
    Get the path to upload a media resource's file to.

    Args:
        item:
            The media resource whose file is being uploaded.
        filename (str):
            The original name of the file being uploaded.

    Returns:
        str:
            The original filename prefixed with
            ``know-me/users/{id}/media-resources/``.
    """
    return "know-me/users/{id}/media-resources/{file}".format(
        file=filename, id=item.km_user.id
    )