def sort_io_dict(performance_utilization: dict):
    """
    Sorts io dict by max_io in descending order.
    """
    sorted_io_dict = {
        'io_all': dict(sorted(performance_utilization['io'].items(), key=lambda x: x[1], reverse=True))
    }
    performance_utilization.update({**sorted_io_dict})
    del performance_utilization['io']
    return performance_utilization