def divide(n, iterable):
    """Divide the elements from *iterable* into *n* parts, maintaining
    order.

        >>> group_1, group_2 = divide(2, [1, 2, 3, 4, 5, 6])
        >>> list(group_1)
        [1, 2, 3]
        >>> list(group_2)
        [4, 5, 6]

    If the length of *iterable* is not evenly divisible by *n*, then the
    length of the returned iterables will not be identical:

        >>> children = divide(3, [1, 2, 3, 4, 5, 6, 7])
        >>> [list(c) for c in children]
        [[1, 2, 3], [4, 5], [6, 7]]

    If the length of the iterable is smaller than n, then the last returned
    iterables will be empty:

        >>> children = divide(5, [1, 2, 3])
        >>> [list(c) for c in children]
        [[1], [2], [3], [], []]

    This function will exhaust the iterable before returning and may require
    significant storage. If order is not important, see :func:`distribute`,
    which does not first pull the iterable into memory.

    """
    if n < 1:
        raise ValueError('n must be at least 1')

    try:
        iterable[:0]
    except TypeError:
        seq = tuple(iterable)
    else:
        seq = iterable

    q, r = divmod(len(seq), n)

    ret = []
    stop = 0
    for i in range(1, n + 1):
        start = stop
        stop += q + 1 if i <= r else q
        ret.append(iter(seq[start:stop]))

    return ret