import re


def get_links(text):
    """
         It will return website links from the text

         :param text: string
         :return: list

         example
         >>> message = 'http://twitter.com Project URL: https://app.grepsr.com/app/project/message/70454'
         >>> get_links(message)
        ['http://twitter.com', 'https://app.grepsr.com/app/project/message/70454']

         """
    result = re.findall(r"(?P<url>https?://[^\s]+)", text)
    return result