def find_circle_size(v):
    """
    Determines the dimension of the square in which the number is
    ex: 4 is a number on the outer layer of the 3x3 circle => 3
    """
    for i in range(1, v, 2):
        if i ** 2 < v and (i+2) ** 2 >= v:
            return i+2
    return 1