def get_info(information):
    """
    Retrieves title of the source
    For example, from the information below,
    HYPERLINK("https://drive.google.com/open?id=0B9q-Bz2y-5byRWZwRHptZmk0eU0","Baby And Her Health")
    Returns `Baby And Her Health`
    """
    information = information.lower()
    if information.startswith("=hyperlink"):
        splits = information.split(",")
        return splits[1].split("\"")[1].strip()
    return information.strip()