package com.fishercoder.solutions;

import java.util.HashMap;
import java.util.Map;
import java.util.Stack;

/**
 * 496. Next Greater Element I
 *
 * You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2.
 * Find all the next greater numbers for nums1's elements in the corresponding places of nums2.
 * The Next Greater Number of a number x in nums1 is the first greater number to its right in nums2. If it does not exist, output -1 for this number.

 Example 1:
 Input: nums1 = [4,1,2], nums2 = [1,3,4,2].
 Output: [-1,3,-1]
 Explanation:
 For number 4 in the first array, you cannot find the next greater number for it in the second array, so output -1.
 For number 1 in the first array, the next greater number for it in the second array is 3.
 For number 2 in the first array, there is no next greater number for it in the second array, so output -1.

 Example 2:
 Input: nums1 = [2,4], nums2 = [1,2,3,4].
 Output: [3,-1]
 Explanation:
 For number 2 in the first array, the next greater number for it in the second array is 3.
 For number 4 in the first array, there is no next greater number for it in the second array, so output -1.

 Note:
 All elements in nums1 and nums2 are unique.
 The length of both nums1 and nums2 would not exceed 1000.
 */
public class _496 {

    public static class Solution1 {
        public int[] nextGreaterElement(int[] findNums, int[] nums) {
            Stack<Integer> stack = new Stack();
            Map<Integer, Integer> map = new HashMap();
            for (int i = 0; i < nums.length; i++) {
                while (!stack.isEmpty() && nums[i] > stack.peek()) {
                    map.put(stack.pop(), nums[i]);
                }
                stack.push(nums[i]);
            }

            while (!stack.isEmpty()) {
                map.put(stack.pop(), -1);
            }

            int[] result = new int[findNums.length];
            for (int i = 0; i < findNums.length; i++) {
                result[i] = map.get(findNums[i]);
            }
            return result;
        }
    }

}

@@ -106,1206 +106,8 @@
 k;%0A%0A
-/**%0A * 496. Next Greater Element I%0A *%0A * You are given two arrays (without duplicates) nums1 and nums2 where nums1%E2%80%99s elements are subset of nums2.%0A * Find all the next greater numbers for nums1's elements in the corresponding places of nums2.%0A * The Next Greater Number of a number x in nums1 is the first greater number to its right in nums2. If it does not exist, output -1 for this number.%0A%0A Example 1:%0A Input: nums1 = %5B4,1,2%5D, nums2 = %5B1,3,4,2%5D.%0A Output: %5B-1,3,-1%5D%0A Explanation:%0A For number 4 in the first array, you cannot find the next greater number for it in the second array, so output -1.%0A For number 1 in the first array, the next greater number for it in the second array is 3.%0A For number 2 in the first array, there is no next greater number for it in the second array, so output -1.%0A%0A Example 2:%0A Input: nums1 = %5B2,4%5D, nums2 = %5B1,2,3,4%5D.%0A Output: %5B3,-1%5D%0A Explanation:%0A For number 2 in the first array, the next greater number for it in the second array is 3.%0A For number 4 in the first array, there is no next greater number for it in the second array, so output -1.%0A%0A Note:%0A All elements in nums1 and nums2 are unique.%0A The length of both nums1 and nums2 would not exceed 1000.%0A */%0A
 publ

refactor 496