# Time:  O(m * C(n, m))
# Space: O(m)
# 
# Given a collection of candidate numbers (C) and a target number (T), 
# find all unique combinations in C where the candidate numbers sums to T.
# 
# Each number in C may only be used once in the combination.
# 
# Note:
# All numbers (including target) will be positive integers.
# Elements in a combination (a1, a2, ... , ak) must be in non-descending order. (ie, a1 <= a2 <= ... <= ak).
# The solution set must not contain duplicate combinations.
# For example, given candidate set 10,1,2,7,6,1,5 and target 8, 
# A solution set is: 
# [1, 7] 
# [1, 2, 5] 
# [2, 6] 
# [1, 1, 6]
#

class Solution:
    # @param candidates, a list of integers
    # @param target, integer
    # @return a list of lists of integers
    def combinationSum2(self, candidates, target):
        result = []
        self.combinationSumRecu(sorted(candidates), result, 0, [], target)
        return result
    
    def combinationSumRecu(self, candidates, result, start, intermediate, target):
        if target == 0:
            result.append(list(intermediate))
        prev = 0
        while start < len(candidates) and candidates[start] <= target:
            if prev != candidates[start]:
                intermediate.append(candidates[start])
                self.combinationSumRecu(candidates, result, start + 1, intermediate, target - candidates[start])
                intermediate.pop()
                prev = candidates[start]
            start += 1

if __name__ == "__main__":
    candidates, target = [10, 1, 2, 7, 6, 1, 5], 8
    result = Solution().combinationSum2(candidates, target)     
    print result       

@@ -8,17 +8,17 @@
   O(
-m
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 m))%0A
@@ -13,17 +13,17 @@
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@@ -28,17 +28,17 @@
 pace: O(
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Update combination-sum-ii.py