RobotError: Correctly initialize exception message
RobotError: Correctly initialize exception message

Regression introduced by 788b3fd2cdfa8cae360bd2553ca838096efc30a8.

While setting self.message is documented for setting user-defined
exceptions, it might be a misunderstanding by me and it's *not* about
the printed result of the exception but about setting custom attributes
for an exception.

After digging a bit deeper on this, I found that both Python 2.7 and 3.x
simply accumulate all arguments passed to __init__() to self.args, see:

https://github.com/python/cpython/blob/2.7/Objects/exceptions.c#L65
https://github.com/python/cpython/blob/3.6/Objects/exceptions.c#L66

Testing this with the following example leads to the expected result:

    class Foo(Exception):
        def __init__(self):
            super(Foo, self).__init__(111, "bar")

    raise Foo()

Result for Python 2.7.13:

    Traceback (most recent call last):
      File "exctest.py", line 5, in <module>
        raise Foo()
    __main__.Foo: (111, 'bar')

Result for Python 3.6.1:

    Traceback (most recent call last):
      File "exctest.py", line 5, in <module>
        raise Foo()
    __main__.Foo: (111, 'bar')

So the self.args attribute is just passed to repr() and/or str() and
that's about it.

Signed-off-by: aszlig <ee1aa092358634f9c53f01b5a783726c9e21b35a@redmoonstudios.org>
Issue: #23
Cc: da39a3ee5e6b4b0d3255bfef95601890afd80709@nh2

RedMoonStudios/hetzner