Take a wild guess based on some dodgy geometric arguments what the subcv  volume fractions are for the p2 tet. This being:
Take a wild guess based on some dodgy geometric arguments what the subcv 
volume fractions are for the p2 tet. This being:

The tet can be broken up to have smaller four corner tets plus 
something in the middle.

The volume of a ideal tet (from wiki) is (sqrt(2)/12)*a^3, where a is the 
side length

The 4 smaller corner tets have side length (a/2) such that they are 
(1/2)^3 smaller in volume, being 1/8. 

Breaking the small corner tets up into subcv the one on the outer corner then 
has a fractional volume of 1/4 * 1/8 = 1/32.

The large original tet is symmetric such that the subcv volume fraction 
of the remaining 6 nodes (10 to start with taking away the 4 corners) is

(1 - 4 * 1/32) / 6 = 1.4583333333333333e-01

Is this correct????

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