conversations.from: human
conversations.value: Find the answer to the math problem: A special balloon increases by two-fifths of its previous volume every hour when placed under water. If its original volume is 500cm³, what will its volume be after 2 hours underwater?
conversations.from: assistant
conversations.value: In the first hour, the balloon will increase in volume by two-fifths of 500cm³ which is (2/5)*500cm³ = 200cm³
  After the first hour, it will have a volume of (500+200)cm³ = 700cm³
  In the second hour, it will increase in volume by two-fifths of 700cm³ which is (2/5)*700cm³ = 280cm³
  After the second hour, it's volume will be (700+280)cm³ = 980cm³