conversations.from: human
conversations.value: Can you break down the solution for me for this math problem: Mrs.  Fredrickson has 80 chickens where 1/4 are roosters and the rest are hens. Only three-fourths of those hens lay eggs. How many chickens does Mr. Fredrickson have that do not lay eggs?
conversations.from: assistant
conversations.value: Mrs. Fredrickson has 80 x 1/4 = 20 roosters.
  So he has 80 - 20 = 60 hens.
  Only 60 x 3/4 = 45 of the hens lay eggs.
  Thus, 60 - 45 = 15 hens do not lay eggs.
  Therefore, Mr. Fredrickson has a total of 15 hens + 20 roosters = 35 chickens that do not lay eggs.