conversations.from: human
conversations.value: Can you break down the solution for me for this math problem: There are 360 balls in the ball pit. If a quarter of the balls in the ball pit are red and a fifth of the remaining balls are blue. How many of the balls are neither red nor blue?
conversations.from: assistant
conversations.value: A quarter of the balls are red and therefore there are 360 x (1 / 4) = 90 red balls.
  When you remove the red balls from the ball pit there are 360 - 90 = 270 remaining balls
  A fifth of the remaining balls are blue, and therefore there are 270 x (1 / 5) = 54 blue balls.
  The total of red and blue balls equals 90 + 54 = 144 balls
  When you remove the red and blue balls from the total there are 360 - 144 = 216 balls that are neither red nor blue.