conversations.from: human
conversations.value: Can you provide an in-depth solution for: Ten stalls have 20 cows each. Mr. Sylas buys 40 cows and divides them equally, putting an equal number of the new cows into each of the twenty stalls. How many cows are in 8 of the stalls?Hey there, could you help me solve this math problem: Ten stalls have 20 cows each. Mr. Sylas buys 40 cows and divides them equally, putting an equal number of the new cows into each of the twenty stalls. How many cows are in 8 of the stalls?
conversations.from: assistant
conversations.value: When Mr. Sylas puts an equal number of the cows he bought into the stalls, each stall gets 40/10 = 4 new cows.
  Each of the stalls gets four cows, meaning a total of 8*4 = 32 cows are placed into eight of the stalls.
  Since each stall had 20 cows before Mr. Sylas added four into each of the stalls, the total number of cows in eight of the stalls was 8*20= 160 cows.
  There are 160+32 = 192 cows in eight stalls after Mr. Sylas adds four into each of the stalls.