conversations.from: human
conversations.value: I'm completely lost with this math problem: The American swallow can lift into the air and carry a maximum of 5 pounds of weight, while the European swallow can lift and carry twice the weight as the American swallow.  If there was a flock of 90 swallows, containing twice as many American as European swallows, what is the maximum combined weight the flock can carry?
  Can you give me a hand?
conversations.from: assistant
conversations.value: If "x" is the number of European swallows, then, for every one European swallow, there would be 2x American swallows.
  Thus, the total number of swallows would be 2x+x=90 swallows
  Thus, the number of European swallows x=30.
  And the number of American swallows is 90-30=60.
  A European swallow can carry twice what an American swallow can carry, or 2*5=10 pounds.
  30 European swallows can carry a maximum of 30*10=300 pounds.
  60 American swallows can carry a maximum of 60*5=300 pounds.
  Thus, a flock of 90 birds, with 30 European and 60 American swallows, can carry 300+300=600 pounds